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In \((3x^2-\frac{1}{x})^{18}\)which term contains x12? |
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Answer» The general term of the expression is Tr + 1 = 18Cr (3x2 )18 – r \((\frac{-1}{x})^{r}\) = 18Cr (-1)r 318-r x 36-3r For coefficient of x12 36 – 3r = 12 ∴ r = 8 ∴ T8 = 18C8 (-1)8 318-8 x36-24 = 18C8310 9 term contains x12 and coefficient is 18C8310 |
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