In a 4-bit Johnson counter sequence, there are a total of how many states or bit patterns?(a) 1(b) 3(c) 4(d) 8I got this question during an interview for a job.I'd like to ask this question from Shift Register Counters in section Registers of Digital Circuits

In a 4-bit Johnson counter sequence, there are a total of how many sta

1.	In a 4-bit Johnson counter sequence, there are a total of how many states or bit patterns?(a) 1(b) 3(c) 4(d) 8I got this question during an interview for a job.I'd like to ask this question from Shift Register Counters in section Registers of Digital Circuits
Answer» Correct option is (d) 8 The EXPLANATION: In JOHNSON COUNTER, total number of states are DETERMINED by 2^N = 24 = 16 Total Number of Used states = 2N = 24 = 8 Total Number of Unused states = 16 – 8 = 8.

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In a 4-bit Johnson counter sequence, there are a total of how many states or bit patterns?(a) 1(b) 3(c) 4(d) 8I got this question during an interview for a job.I'd like to ask this question from Shift Register Counters in section Registers of Digital Circuits

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