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Is * defined on the set {1, 2, 3, 4, 5} by a * b = LCM of a and b a binary operation? Justify your answer. |
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Answer» Consider the composition table :
In the given composition table, all the elements are not in the set {1, 2, 3, 4, 5}. If we consider a = 2 and b = 3, a * b = LCM of a and b = 6 ∉ {1, 2, 3, 4, 5}. Thus, * is not a binary operation on {1, 2, 3, 4, 5}. |
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