1.

Prove: (1 + cot2θ) sin2θ = 1

Answer»

(1 + cot2θ) sin2θ = 1

L.H.S. = (1 + cot2θ) × sin2 θ

= (cosec2 θ) × sin2 θ

(Using identity 1 + cot2 θ = cosec2 θ)

= 1/ sin2θ × sin2 θ

= 1

= R.H.S.

Hence Proved.



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