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Prove: (1 + cot2θ) sin2θ = 1 |
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Answer» (1 + cot2θ) sin2θ = 1 L.H.S. = (1 + cot2θ) × sin2 θ = (cosec2 θ) × sin2 θ (Using identity 1 + cot2 θ = cosec2 θ) = 1/ sin2θ × sin2 θ = 1 = R.H.S. Hence Proved. |
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