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Prove the following trigonometric identities:\(\frac{(1+tan^2θ)cotθ}{cosec^2θ}\) = tanθ |
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Answer» \(\frac{(1+tan^2θ)cotθ}{cosec^2θ}\) = \(\frac{sec^2\times θcotθ}{cosec^2θ}\) = \(\frac{sin^2θ}{cos^2θ}\times cotθ\) = tan2θ x cotθ = tan2θ x \(\frac{1}{tanθ}\) = tanθ Hence Proved. |
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