1.

Prove the following trigonometric identities:\(\frac{(1+tan^2θ)cotθ}{cosec^2θ}\) = tanθ

Answer»

\(\frac{(1+tan^2θ)cotθ}{cosec^2θ}\)   =   \(\frac{sec^2\times θcotθ}{cosec^2θ}\)

=  \(\frac{sin^2θ}{cos^2θ}\times cotθ\)

 = tan2θ x cotθ

 = tan2θ x \(\frac{1}{tanθ}\)

 = tanθ 

Hence Proved.



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