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Prove the following trigonometric identities:\(\frac{1}{secA-1}+\frac{1}{secA+1}\) = 2cosec A cot A |
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Answer» \(\frac{1}{secA-1}+\frac{1}{secA+1}\) = \(\frac{secA+1+secA-1}{sec^2A-1}\) = \(\frac{2secA}{tan^2A}\) = \(\frac{2}{cosA}\times\frac{cosA}{sin^2A}\) = 2cosec A cot A Hence Proved. |
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