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Prove the following trigonometric identities:\(\frac{cosθ}{1+sinθ}=\frac{1-sinθ}{cosθ}\) |
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Answer» \(\frac{cosθ}{1+sinθ}=\frac{cosθ}{1+sinθ}\times\frac{1-sinθ}{1-sinθ}\) = \(\frac{cosθ(1-sinθ)}{1-sin^2θ}\) = \(\frac{cosθ(1-sinθ)}{cos^2θ}\) = \(\frac{1-sinθ}{cosθ}\) Hence Proved. |
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