1.

Prove the following trigonometric identities:sin2A cos2B - cos2Asin2B = sin2A - sin2B

Answer»

To prove:  sin2A cos2B - cos2Asin2B = sin2A - sin2B

Proof: Take LHS, Use the identity sin2θ+cos2θ=1

sin2A cos2B - cos2A sin2B

= sin2A(1 – sin2B) – (1 – sin2A)sin2

sin2B – sin2B + sin2A sin2B

= sin2A – sin2B

= RHS Hence Proved



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