The amplitude of \(\frac{1}{i}\) is equal toA. 0B. \(\frac{\pi}{2}\

1.	The amplitude of \(\frac{1}{i}\) is equal toA. 0B. \(\frac{\pi}{2}\)C. \(-\frac{\pi}{2}\)D. π
Answer» \(\frac{1}{i}=\frac{1}{i}\times\frac{i}{i}\) = \(\frac{i}{-1}\) = 0+i(-1) amp = tan^-1\(\frac{-1}{0}\) = \(\frac{-\pi}{2}\)

The amplitude of \(\frac{1}{i}\) is equal toA. 0B. \(\frac{\pi}{2}\)C. \(-\frac{\pi}{2}\)D. π

Answer»

\(\frac{1}{i}=\frac{1}{i}\times\frac{i}{i}\)

= \(\frac{i}{-1}\)

= 0+i(-1)

amp = tan^-1\(\frac{-1}{0}\)

= \(\frac{-\pi}{2}\)