The argument of \(\frac{1-i}{1+i}\) isA. \(-\frac{\pi}{2}\)B. \(\

1.	The argument of \(\frac{1-i}{1+i}\) isA. \(-\frac{\pi}{2}\)B. \(\frac{\pi}{2}\)C. \(\frac{3\pi}{2}\)D. \(\frac{5\pi}{2}\)
Answer» \(\frac{1-i}{1+i} = \frac{(1-i)}{(1+i)}\times\frac{(1-i)}{(1-i)}\) =0 + i(-1) arg = tan^-1 \(\frac{-1}{0}\) = \(\frac{-\pi}{2}\)

The argument of \(\frac{1-i}{1+i}\) isA. \(-\frac{\pi}{2}\)B. \(\frac{\pi}{2}\)C. \(\frac{3\pi}{2}\)D. \(\frac{5\pi}{2}\)

Answer»

\(\frac{1-i}{1+i} = \frac{(1-i)}{(1+i)}\times\frac{(1-i)}{(1-i)}\)

=0 + i(-1)

arg = tan^-1 \(\frac{-1}{0}\)

= \(\frac{-\pi}{2}\)