The group of bits 10110111 is serially shifted (right-most bit first) into an 8-bit parallel output shift register with an initial state 11110000. After two clock pulses, the register contains ______________(a) 10111000(b) 10110111(c) 11110000(d) 11111100I had been asked this question in class test.My question comes from Shift Register Counters topic in portion Registers of Digital Circuits

The group of bits 10110111 is serially shifted (right-most bit first)

1.	The group of bits 10110111 is serially shifted (right-most bit first) into an 8-bit parallel output shift register with an initial state 11110000. After two clock pulses, the register contains ______________(a) 10111000(b) 10110111(c) 11110000(d) 11111100I had been asked this question in class test.My question comes from Shift Register Counters topic in portion Registers of Digital Circuits
Answer» The correct option is (d) 11111100 The best I can EXPLAIN: After first clock pulse, the register CONTAINS 11111000. After second clock pulse, the register would contain 11111100. Since the BITS are SHIFTED to the right at every clock pulse.

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