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The input power to a three-phase load is 10kW at 0.8 Pf. Two watt meters are connected to measure the power. Find the reading of higher reading wattmeter.(a) 7.165(b) 6.165(c) 6.165(d) 4.165I got this question in semester exam.Enquiry is from Power Measurement in Three-Phase Circuits in chapter Polyphase Circuits of Network Theory

Answer» RIGHT choice is (a) 7.165

Explanation: WR + WY = 10KW. Ø = cos^-10.8=36.8^o => tanØ = 0.75 = √3 (WR-WY)/(WR+WY)=(WR-WY)/10. WR-WY=4.33kW. WR+WY=10kW. WR=7.165kW.


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