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The readings of the two watt meters used to measure power in a capacitive load are -3000W and 8000W respectively. Calculate the input power. Assume RYB sequence.(a) 5(b) 50(c) 500(d) 5000I have been asked this question in a national level competition.My doubt is from Power Measurement in Three-Phase Circuits in division Polyphase Circuits of Network Theory

Answer»

Right OPTION is (d) 5000

Explanation: Toatal POWER is the sum of the power in R and power in Y. So total power = WR+WY = -3000+8000 = 5000W



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