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The minimum number of flip-flops that can be used to construct a modulus-5 counter is ____________(a) 3(b) 8(c) 5(d) 10The question was asked by my college professor while I was bunking the class.This intriguing question originated from Propagation Delay in Ripple Counter in chapter Counters of Digital Circuits

Answer»

Correct option is (a) 3

The EXPLANATION: The MINIMUM number of flip-flops used in a counter is given by: 2^(N-1)<=N<=2^n.

Thus, for modulus-5 counter: 2^2 <= N <= 2^3, where N = 5 and n = 3.



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