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The probability of occurrence of an event A is ¼ and that of event B is ½. The probability that both will occur is \(\frac{1}{8}\). What is the probability that either A or B must occur?1). \(\frac{5}{8}\)2). \(\frac{1}{64}\)3). \(\frac{7}{8}\)4). \(\frac{7}{64}\) |
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Answer» P(B) = $(\frac{1}{2})$ $(P\left( {A \cap B} \right) = \frac{1}{8})$ P(A or B) = P(A ∪ B) = P(A) + P(B) - P(A ∩ B) $(\Rightarrow \frac{1}{4} + \frac{1}{2} - \frac{1}{8} = \frac{5}{8})$ |
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