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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Determine the phase current IR.(a) (17.32-j10) A(b) (-17.32-j10) A(c) (17.32+j10) A(d) (-17.32+j10) AThis question was addressed to me during an online exam.This intriguing question comes from Three-Phase Unbalanced Circuits in division Polyphase Circuits of Network Theory

Answer»

The CORRECT answer is (a) (17.32-j10) A

Explanation: Taking VRY = V∠0⁰ as a reference phasor, and ASSUMING RYB PHASE SEQUENCE, we have VRY = 400∠0⁰V Z1 = 20∠30⁰Ω = (17.32+j10)Ω IR = (400∠0^o)/(20∠30^o) = (17.32-j10) A.



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