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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the phase current IY.(a) (10-j0) A(b) (10+j0) A(c) (-10+j0) A(d) (-10-j0) AThe question was posed to me in semester exam.My query is from Three-Phase Unbalanced Circuits in chapter Polyphase Circuits of Network Theory

Answer»

The correct answer is (C) (-10+j0) A

The BEST I can explain: The VOLTAGE VYB is VYB = 400∠-120⁰V. The impedance Z2 is Z2 = 40∠60⁰Ω => IY = (400∠-120^o)/(40∠60^o)=(-10+j0)A.



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