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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the line current I1.(a) (-51.96-j10) A(b) (-51.96+j10) A(c) (51.96+j10) A(d) (51.96+j10) AThe question was asked by my college professor while I was bunking the class.This intriguing question comes from Three-Phase Unbalanced Circuits topic in section Polyphase Circuits of Network Theory |
Answer» CORRECT option is (c) (51.96+j10) A Best explanation: The LINE CURRENT I1 is the difference of IR and IB. So the line current I1 is I1 = IR – IB = (51.96+j10) A. |
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