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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the line current I2.(a) (-27.32+j10) A(b) (27.32+j10) A(c) (-27.32-j10) A(d) (27.32-j10) AThe question was posed to me in exam.I'm obligated to ask this question of Three-Phase Unbalanced Circuits in section Polyphase Circuits of Network Theory

Answer»

Correct option is (a) (-27.32+j10) A

For explanation: The line CURRENT I2 is the DIFFERENCE of IY and IR. So the line current I2 is I2 = IY – IR = (-27.32+j10) A.



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