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The three impedances Z1 = 20∠30⁰Ω, Z2 = 40∠60⁰Ω, Z3 = 10∠-90⁰Ω are delta-connected to a 400V, 3 – Ø system. Find the line current I3.(a) (24.646+j20) A(b) (-24.646+j20) A(c) (-24.646-j20) A(d) (24.646-j20) AI got this question by my college director while I was bunking the class.My doubt stems from Three-Phase Unbalanced Circuits topic in portion Polyphase Circuits of Network Theory

Answer»

The CORRECT ANSWER is (c) (-24.646-j20) A

The best explanation: The LINE current I3 is the DIFFERENCE of IB and IY.So the line current I3 is I3 = IB – IY = (-24.646-j20) A.



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