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Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?

Answer» Let the cistern be filled by pipe A alone in x hours. Then, pipe B will fill it in (x + 6) hours. 1 + 1 = 1 x (x + 6) 4 x + 6 + x = 1 x(x + 6) 4 x2 - 2x - 24 = 0 (x -6)(x + 4) = 0 x = 6.     [neglecting the negative value of x]


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