InterviewSolution
Saved Bookmarks
| 1. |
What is the coefficient of x5 in the expansion of (1 – 2x + 3x2 – 4x3 + ..... ∞) –5. (a) \(\frac{10!}{(5!)^2}\)(b) 5–5 (c) 55 (d) \(\frac{10!}{6!\,4! }\) |
|
Answer» Answer: (a) \(\frac{10!}{(5!)^2}\) (1 – 2x + 3x2 – 4x3 + ..... ∞) –5 = {(1 + x)–2}–5 = (1 + x)10 ∴ Coefficient of x5 = 10C5 = \(\frac{10!}{5!\,5!}\) = \(\frac{10!}{(5!)^2}\) (∵ (1 + x)n = 1 + nC1 x + nC2 x2 + nC3 x2 + ....) |
|