1.

What is the coefficient of x5 in the expansion of (1 – 2x + 3x2 – 4x3 + ..... ∞) –5. (a) \(\frac{10!}{(5!)^2}\)(b) 5–5 (c) 55 (d) \(\frac{10!}{6!\,4! }\)

Answer»

Answer: (a) \(\frac{10!}{(5!)^2}\)  

(1 – 2x + 3x2 – 4x3 + ..... ∞) –5 

= {(1 + x)–2}–5 = (1 + x)10 

∴ Coefficient of x5 = 10C5\(\frac{10!}{5!\,5!}\) = \(\frac{10!}{(5!)^2}\) 

(∵ (1 + x)n = 1 + nC1 x + nC2 x2 + nC3 x2 + ....) 



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