1.

What is the value of (1 + cot2θ) sin2θ?

Answer»

To find: (1 + cot2θ) sin2θ 

∵ 1 + cot2 θ = cosec2 θ 

∴ (1 + cot2θ) sin2θ = cosec2θ sin2θ

Also, cosecθ = \(\frac{1}{sinθ}\) 

⇒ cosec2θ = \(\frac{1}{sin^2θ}\)

(1 + cot2θ) sin2θ = cosec2θ sin2θ = \(\frac{1}{sin^2θ}sin^2θ\) = 1



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