1.

Which term is independent of x in expansion of (3x3 − \(\frac{1}{2x^3}\))10

Answer»

Let (r + 1)th term be independent of in the given expression 

Now Tr + 1 = 10Cr (3x)10 – r ( –\(\frac{1}{2x^3}\))r

= 10Cr (3x)10 – r ( –\(\frac{1}{2}\))r x30 − 6

This term is independent of x, if 

30 – 6r = 0 

⇒ r = 5 

So, (5 + 1)th i.e 6th terms is independent of x



Discussion

No Comment Found