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| 1. |
Which term is independent of x in expansion of (3x3 − \(\frac{1}{2x^3}\))10 |
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Answer» Let (r + 1)th term be independent of in the given expression Now Tr + 1 = 10Cr (3x)10 – r ( –\(\frac{1}{2x^3}\))r = 10Cr (3x)10 – r ( –\(\frac{1}{2}\))r x30 − 6 This term is independent of x, if 30 – 6r = 0 ⇒ r = 5 So, (5 + 1)th i.e 6th terms is independent of x |
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