Write the general term in the expansion of (x2 – y)6 – InterviewSolution

InterviewSolution

1.

Write the general term in the expansion of (x2 – y)6

Answer»

To Find : General term, i.e. t_r+1

For (x² - y)⁶

a=x² , b=-y and n=6

General term t_r+1 is given by,

t_r+1 = (_rⁿ) a^n-rb^r

= (⁶_r)(x²)^6-r(-y)^r

Conclusion : General term = (⁶_r)(x²)^6-r(-y)^r

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