1.

Write the last two digits of the number 3400

Answer»

Given, 3400 

= (1 + 2)400 

=400 C0 (1)400 – 0 (2)0 + 400 C1 (1)400 – 1 (2)1 + 400C2 (1)400 – 2 (2)2 +…+ 400 C400 (1)400 – 400(2)400 

We observe that all term expect the first one are divisible by 100, so the remainder when 3 400 + 100 is same as the [ 400 C0 (1)400 (2)400  ] ÷ 100 = 1 ÷ 100



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