InterviewSolution
Saved Bookmarks
| 1. |
Write the last two digits of the number 3400 |
|
Answer» Given, 3400 = (1 + 2)400 =400 C0 (1)400 – 0 (2)0 + 400 C1 (1)400 – 1 (2)1 + 400C2 (1)400 – 2 (2)2 +…+ 400 C400 (1)400 – 400(2)400 We observe that all term expect the first one are divisible by 100, so the remainder when 3 400 + 100 is same as the [ 400 C0 (1)400 (2)400 ] ÷ 100 = 1 ÷ 100 |
|