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Write the principal argument of -2. |
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Answer» -2 = -2 + 0i Let -2 + 0i = r(cos θ + i sin θ) ⇒ r cos θ = -2 ….(i) r sin θ = 0 ………(ii) ⇒ tan θ = 0/-2 = 0 Hence, principal argument of -z is π. |
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