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5851.

Forests cannot protect wildlife from the ill-effects of solar radiation.

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ANSWER :F
5852.

Forest and wildlife are nonrenewable natural resources.

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ANSWER :F
5853.

For which of the following reactions would the Ho for the reaction be labeled Delta H_(f)^(0) ?

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`AL (s) + 3//2H_(2) (g) + 3//2 O_(2) (g) rarr Al(OH)_(3) (s)`
`PCl_(3) (g) + 1//2O_(2) (g) rarr POCl_(3) (g)`
`1//2N_(2) O (g) + 1//4O_(2) (g) rarr NO (g)`
`CaO(s) + SO_(2) (g) rarr CaSO_(3) (s)`

Answer :A
5854.

For which of the following element, Mendeleev didn't left gap in his periodic table ?

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Gallium
Beryllium
Germanium
Scandium

ANSWER :B
5855.

For the redox reaction K_(2)Cr_(2)+XH_(2)SO_(4)+YSO_(2) rarr K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+ZH_(2)O What is the sum of x + y + z

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SOLUTION :`K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+3SO_(2)rarrK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+H_(2)O`
`:. x=1 y=3 z=1 :. x+y+z=5`
5856.

For the reason: 2A (g) + B (g) rarr 2D(g), Delta U^(theta) = - 10.5 kJ and Delta S^(theta) = -44.1 JK^(-1) Calculate Delta rG^(@) for the reaction, and predict whether the reaction will occurs spontaneously.

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SOLUTION :Non-spontaneous.
5857.

For the reaction, CuO + H_(2) to Cu + H_(2)O, choose the correct statement.

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CUO is an oxidising agent.
`H_(2)`, UNDERGO oxidation.
It is a DISPLACEMENT reaction.
All of the given

Solution :All of the given
5858.

For the reaction at 298K, 2A + B rarr C, Delta H = 400kJ mol^(-1), Delta S = 0.2 kJ K^(-1) mol^(-1). At what temperature will the reaction become spontaneous considering DeltaH and Delta S to be constant over the temperature range.

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SOLUTION :`T GT 2000 K`
5859.

For the reaction A to B , identify the correct sequence of steps for thecalculation of average rate of reaction. (1) plotting a graph of concentration of 'A' at various time intervals. (2) identification of C_(2) and C_(1) at different time interval t_(2) and t_(1) , respectively by reading the graph (3) Calculation of (C_(2)-C_(1))/(t_(2)-t_(1)) (4) finding out the experimental values of concentratiions of 'A' at regular intervals

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4,2,3,1
4,1,2,3
3,2,1,4
1,2,3,4

Solution :(i) FINDING out the experimental values of the concentrations of A at regular intervals.
(II) plotting a graph of CONCENTRATION of A at various times
(III) identification of `C_(2) and C_(1)` at different time intervals `t_(2) and t_(1)` by reading the graph
(iv) calculation of `(C_(2)-C_(1))/(t_(2)-t_(1))`
5860.

For the following reaction at 25^(@)C, DeltaH^(@) = + 115kJ and Delta S^(@) = +125J//K. Calculate DeltaG^(@) for the reaction at 25^(@)C SBr_(4) (g) rarr S(g) + 2Br_(2)(I)

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`+152kJ`
`-56.7kJ`
`+77.8kJ`
`+37.1 KJ`

ANSWER :C
5861.

For the extraction of iron, the blast furnace is charged with the mixture of ore, coke and limestone.(True / False)

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ANSWER :T
5862.

For the chemical reaction to occur

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the reaching MOLECULES must COLLIDE with ecah other
reacting molecules should have SUFFICIENT enegy at the tie of collision.
reacting molecules must be PROPERLY oriented
all of the above

Answer :D
5863.

For oxidation of iron, 4Fe(s) + 3O_(2)(g) rarr 2Fe_(2)O_(3) (s) entrop change is -549.4 J K^(-1)mol^(-1) at 298K. In spite of negative entropy change of this reaction, why is the reaction spontaneous? (Delta_(r ) H^(theta) for this reaction is -1648 kJ mol^(-1))

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SOLUTION :`DeltaS_("TOTAL") = +4980.6 JK^(-1) mol^(-1)`
5864.

For making ornament 24 carat gold is used which is pure gold

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Solution :For making ORNAMENTS, 22 carat GOLD is used which contains 22 parts of gold by weight and 2 parts of copper by weight.
5865.

For evaporation of water the sign of Delta H is …..and sign of Delta S is ……

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ANSWER :`+ve, +ve`
5866.

For an element with atomic number 19, the 19th electron will occupy

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L-shell
M-shell
N-shell
K-shell

ANSWER :C
5867.

General formula of alkenes is

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SOLUTION :`C_n H_(2N )`
5868.

For a reversible reaction, the activation energy of a forward reaction is 85 KJ/mol . The net reaction is assoicated with the release of 15 KJ/mol . What is the activation energyof the backward reaction ? Explain it on the bais of the collision theory ?

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SOLUTION :(i) relation between activation energy and effective collisions.
(ii) calculation of `E_(a)` of BACKWARD reaction
(iii) COMPARING `E_(a)` of backward and FORWARD reactions and its EFFECT on effective collisions
5869.

For a reaction A + B to C, the rate law is written as r=k[A]^(2)[B]. Doubling the concentration of 'A' without changing concentration of 'B' increases the rate of reaction by

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2 times
4 times
8 times
16 times

Solution :Since the reaction is of `2^(ND)` order with respect to A, doubling the CONCENTRATION of 'A' increases the RATE of reaction by `2^(2)=4` times.
5870.

For a reactionA + B to C , the rate law is written as r=k[A]^(2)[B] . Doubling the concentrations of both of 'A' and 'B' increases the rate of reaction by

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2 times
4 times
8 times
16 times

Solution :Since the reaction is of `2^(nd)` ORDER with RESPECT to A, and `1^(st)` order with respect to B, the RATE of reaction increases by eight times.
5871.

Fora reaction A + B hArr C+D , if the activation energy of backward reaction is more than that of forward reaction, the forward reactionis

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ENDOTHERMIC
exothermic
REACTION need not necessarily INVOLVE heat changes
cannot be predicted

Solution :For a reaction `A+B hArr C+D` , if the activation energy of backward reaction is more than that of forward reaction, then the forward reaction is exothermic .
5872.

For a reaction 2A+ B to 2AB , it is found that doubling the concentration of both the reactants increases the rate to eight times that of initial rate butdoubling the concentration of B alone doubles the rate. Then the order of the reaction with respect to A and B is

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0,3
0,2
2,1
2,2

Answer :C
5873.

For a given value of 'l' the total number of 'm' values is "____________"

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ANSWER :2l+1
5874.

For a gas phase reaction Cl_(2) + CHCl_(3) to HCl+ "CC"l_(4), the rate law is given as r=k[Cl_(2)]^(1//2) [CHCl_(3)] . Explain how the rate of reaction varies when the concentration of chlorine is doubled . Give units of rate constant

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Solution :(i) significant of rate law
(ii) EQUATION for rate constant
(iii) equation for rate constant with DOUBLE the CONCENTRATION of `Cl_(2)`
(IV) COMPARISON of both the equations
5875.

For a dibasic acid, normality is twice the molarity for a given solution

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ANSWER :1
5876.

Foods kept at room temprature spoils faster than that kept in the refrigerator Why?

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Solution :FOOD KEPT at room temprature spoils faster than that kept in the refrigerator.In the refrigerator .the temprature is slower than the room temprature and hence the REACTION RATE is less.
5877.

Food items should be stored in air tight closed containers.

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Solution :When FOOD items are LEFT exposed to air, they react with oxygen and become rancid, As a result taste and SMELL of the food CHANGE. which is HARMFUL to health. Thus, food items should be stored in air tight closed containers to avoid rancidity.
5878.

Food materials can be protected from being rancid by keeping them in refrigerators.

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ANSWER :T
5879.

Foodkept at roomtemperaturespoilsfasterthan thatkeptin refrierator. Givereason .

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SOLUTION :INCREASE in temperatureprovidesenergyto breakbondsand thusspeedsupreaction. Inrefrigerators, THETEMPERATUREIS lowerthan theroomtemperatureand hencereactionratesless .
5880.

Food items on exposure to atmosphere become rancid due to the process of : (i) oxidation (ii) reduction (iii) corrosion (iv) hydrogenation

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SOLUTION :(i) OXIDATION
5881.

Food cans are coated with tin and not with zinc because.

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Zinc is costlier than TIN
Zinc has a higher melting point than tin
Zinc is more REACTIVE than tin
Zinc is LESS reactive than tin

Solution :Zinc is more reactive than tin
5882.

Food cans are coated with tin and not with zinc because ...

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zinc is COSTLIER than tin.
zinc has a HIGHER MELTING POINT than tin.
zinc is more reactive than tin.
zinc is less reactive than tin.

Solution : zinc is more reactive than tin.
5883.

Fly ash obtained from the burning of coal is used to make

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LAMP black
coke
BRICKS
hard stone

ANSWER :C
5884.

Fly ash can be used to make _____

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ANSWER :BRICKS
5885.

Flux + Gangue rightarrow ?

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MINERAL
Matrix
SALG
Smog

Answer :C
5886.

Write True/False: Fluorine cannot have +1 oxidation state.

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ANSWER :1
5887.

Fluorine and chlorine becomenegativeions by _____________ .

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SOLUTION :GAINING and ELECTRON
5888.

Fluorine : 2, 7 :: Chlorine : _________

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Solution :2, 8, 7 - Chlorine.s atomic NUMBER is 17 thereforeits electronic CONFIGURATION is (2, 8, 7)
5889.

Flourine has more negative electron gain enthalpy than chlorine.(T/F)

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ANSWER :FALSE
5890.

Flint glass or optical glass contains

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lead oxide
MANGANESE DIOXIDE
lead dioxide
cobalt chloride

ANSWER :A
5891.

Five solutions A, B, C, D and E when tested with universal indicator showed pH as 4, 1, 11, 7 and 9, respectively. Which solution is : (a) neutral ? (b) strongly alkaline ? (c) strongly acidic ? (d) weakly acidic ? (e) weakly alkaline ? Arrange the pH in increasing order of hydrogen-ion concentration.

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SOLUTION :A solution having pH equal to 7 is neutral. A solution with pH RANGE 0 - 7 is acidic while a solution with pH range 7 – 14 is basic.
Smaller the value of pH in the range 0 – 7, stronger is the acid. Higher the value of pH in range 7 - 14, stronger is the base (alkali).
Based on above, we can DECIDE the acidic or basic nature of A, B, C, D and E:

The pH in increasing ORDER of hydrogen ion concentration are :
5892.

Five solutions A,B,C,D and E when tested universal indicator showed pH as 4,1,11,7 and 9 respectively . Which solution is (a) neutral (b) strongly alkaline ? (c) strongly acidic ? (d) weakly acidic ? (e) weakly alkaline ? Arrange the pH in increasing order of hydrogen ion concentration .

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SOLUTION :
Arrangement of the PH in increasing order of HYDROGEN ion concentration is as follows :
`11 lt 9 lt 7 lt 4 lt 1`
5893.

Five solutions A, B, C, D and E showed pH as 4, 7, 1, 11 and 9 respectively when tested with universal indicator. Which solution is (i) Neutral (ii) Strongly alkaline(iii) Strongly acidic (iv) Weakly acidic and (v) Weakly alkaline ? Arrange the pH in increasing order of hydrogen ion concentration.

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Solution :(i) Solution B is NEUTRAL.
(ii) Solution D is STRONGLY alkaline.
(iii) Solution C is strongly acidic.
(IV) Solution A is weakly acidic.
(v) Solution E is weakly alkaline.
Increasing order of hydrogen ion concentration : D, E, B, A and C.
5894.

First period : ShortestPeriod :: Sixth period :______________

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SOLUTION :LONGEST PERIOD
5895.

Firstperiod containsonly one element

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SOLUTION :First PERIOD contains TWO elements. (Hydrogen & Helium)
5896.

First ionisation enthalpy of Be is higher than B.(T/F)

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ANSWER :TRUE
5897.

First group : Alkali metals :: Second group : ___________

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SOLUTION :ALKALINE EARTH METALS
5898.

First and second ionisation energies of Be_((g)) are 900 kJ mol_(1)and 1750 kJmol_(1) approximately. Claculate approximate percentage of Be^(2+)_((g)) ions, if 1 g of Be_((g)) absorbs 150 kJ of energy [atomic weight of Be is 9].

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Solution :(i) AMOUNT of energy ABSORBED by 1 g of Be to FORM
`Be^(+) and Be^(+2)`
(ii) energy REQUIRED for conversion of 1 g `Be_((g)) into `Be^(+)` ions
(iii) calculation of additional amount of energy
(iv) conversion of `Be^(+)` ions to `Be^(+2)` ions
(v) 25%.
5899.

Five solution A, B, C, D and E when tested with universal indicator showd pH as 4, 1, 11, 7 and 9 respectively. Which solution is (a) neutral ? (b) stongly alkaline ? (c ) strongly acidic ? (d) weakly acidic ? (e) weakly alkaline ? Arrange the pH in increasing order of hydrogen ion concentration.

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SOLUTION :(a) D (B) C (c) B (d ) A (E ) E
`C (10-11M) LT E (10-9M) lt D (10-7 M) lt A (10-4 M) lt B (10-1 M)`
5900.

Find the valency of the first twenty elements.

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SOLUTION :