Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Give the IUPAC name of

Answer»

4-ethyl-3-methylpene-4-en-1-yne
2-ethyl-3-methylpenet-1-en-4-yne
4-ethyl-3-methylpent-1-yne-1-en
2-ethyl-3-methylpent-4-yne-1-en

Answer :B
Discussion
2.

Givethe IUPAC name for the followingalkane (a) CH_(3)-CH-CH_(2)-CH_(2)-cH-CH_(3) (b)underset(CH_(2))underset(|)CH_(3)underset(|)CH_(3)-CH-underset(CH_(3)underset(|)CH-underset(CH_(2))underset(|)CH-CH_(2)-CH_(2)-CH_(2)-CH_(3)

Answer»

SOLUTION :`(a) CH_(3) -underset( CH_(3))underset(|) (C H) - CH_(2)- CH_(2)-underset( CH_(2))underset(|) (C H)- CH_(3)`
3.6dimethyloctane
`(b)CH_(3) - underset(CH_(2)) underset( |) (C H) - underset( CH_(3))underset(|) (C H)- underset(CH_(3)) underset(|) (C H) - CH_(2)- CH_(2) - CH_(2) - CH_(3)`
4- Ethly2.3dimethyloctane
Discussion
3.

Give the IUPAC name for the amine. {:(""CH_(3)),("|"),(CH_(3)-N-C-CH_(2)CH_(3)),("|""|"),(""CH_(3)C_(2)H_(5)):}

Answer»

<P>

Solution :N, N, 3-Trimethylpentan-3-amine (Alphabets are GIVEN perference over numericals).
(Please remember that CAPITALS (i.e., N, S, O, etc) and lower case letters (i.e. n, o, m, p, etc.) have higher priority of citation than Greek letters, i.e., `alpha, beta, gamma`,.....etc.) which, in turn, have higher priority of citation than ARABIC numerals (i.e., 1, 2, 3, 4,........etc.). For example, N, `alpha`, 1, 2 have priority of citation than 1, 2, 3, 4,.......... .
Discussion
4.

Give the IUPAC name for {:(""CH_(3)),("|"),(CH_(3)CH_(2)OCHCH_(2)CH_(2)CH_(2)Cl):}

Answer»

2-ethyoxy-5-chloropentane
1-chloro-4-ethyl-4-methylpentane
1-chloro-4-ethoxypentane
ethyl-1-chloropentyl ETHER

SOLUTION :`{:("".^(5)CH_(3)),("|"),(CH_(3)CH_(2)O-overset(4)(C)H-overset(3)(C)H_(2)overset(2)(C)H_(2)overset(1)(C)H_(2)Cl):}`
1-Chloro-4-ehtoxypentane and not 2-ethoxy-5-chloropentane (LOWEST set of locants rule is followed)
Discussion
5.

Give the IUPAC name and structure and the states of carbon in it ?

Answer»

SOLUTION :Structure : * FORMS of carbon : As seen in the structure :
There are 4 `(-CH_(3))` group, that carbon is `1^(@)` (primary) in STATE. (Terminal carbon). Carbon of `CH_(2)` is `2^(@)` (SECONDARY). attached to 2 carbon atoms). Other carbon is attached to 4 carbons, therefore it is `4^(@)` (QUATERNARY) in state.
Discussion
6.

Give the isomers of aromatic hydrocarbon havig molecular formula of C_(8)H_(10).

Answer»

SOLUTION :
Discussion
7.

Give the information about structure of alkene.

Answer»

Solution :In alkene, ethene `(C_(2)H_(4))` and propene `(C_(3)H_(6))` has 1 double bond. They do not have isomers.
Carbon ATOM 4 or more carbon atom, they do not have any isomers and shows structural isomers.
(a) Position isomers : Butene `(C_(4)H_(8))` has 2 position isomers (I) nad (II).
`{:(underset((I))underset("But-2-ene")(OVERSET(1)(C)H_(2)=overset(2)(C)H-overset(3)(C)H_(2)-overset(4)(C)H_(3)),|,underset((II))underset("But-2-ene")(overset(1)(C)H_(3)-overset(2)(C)H-overset(3)(C)H-overset(4)(C)H_(3)),):}`
Position isomers are in DIFFERENT position of `pi`-bond in (I) and (II).
(I) and (II) are SIMPLE chain carbon structure.
(b) Alkene chain isomers : Butene `(C_(4)H_(8))` isomers are as follows :
e.g., 1 `underset("(I) but-1-ene")(CH_(2)=CH-CH_(2)-CH_(3))` and `underset("(I) Methyl-prop-1-ene")underset(CH_(2)=underset(CH_(3))underset(|)(C)-CH_(3))`
(I) and (III) are both chain isomers.
e.g, 2 `underset("(II) But-2-ene")(CH_(3)-CH=CH-CH_(3))` and `underset("(III) Methyl prop-1-ene")(CH_(2)-overset(CH_(3))overset(|)(C)-CH_(3))`
(II) and (III) are both chain isomers.
Chain isomers has same molecular formula.
Discussion
8.

Give the important uses of the following compounds NaHCO_3

Answer»

Solution :Uses of NaHCO_(3)`
It is used in fire extinguisher. .
It is used as MILD antiseptic for skin infections.
• It is used as antacid.
(ii) Uses of NAOH .
It is used in soap industry.
It is used in TEXTILE industry. •
It is used as reagent in laboratory.
• It is used in absorbing poisonous gases
Discussion
9.

Give the important uses of the following compounds. i) NaHCO_(3) (ii) NaOH

Answer»

Solution :Uses of NaHCO_(3)`
It is used in fire extinguisher. .
It is used as MILD antiseptic for skin INFECTIONS.
• It is used as antacid.
(ii) Uses of NaOH .
It is used in soap industry.
It is used in TEXTILE industry. •
It is used as REAGENT in laboratory.
• It is used in absorbing poisonous gases
Discussion
10.

Give the important uses of plaster of paris.

Answer»

SOLUTION :(i)In SURGERY for SETTING
(II) In making BLACKBOARD chalks.
Discussion
11.

Give the importance of buffer solution.

Answer»

Solution :Buffer solution can be used in chemical and biochemical reactions and espectially in analytical chemistry .
(i)In biological process : e.g., The pH of our blood :7.36 to 7.42 `(H_2CO_3 + NaHCO_3)` . In human body buffer solutions CONTAINING `[HCO_3^-]`and `[CO_3^(-2)]`as well as `[H_2PO_4^-]` and `[HPO_4^(2-)]` are present .
(ii) In industrial process :The use of buffers is an important part of many industrial process. (i)In electroplating (ii) In the manufacture of leather,photographic materia and dyes , (iii) In the preservation of food articles.
(iii)In preparation of medicines : In preparation of medicine the definite pH value is very effective , therefore use of buffer is essential.
(iv) In COSMETIC items: By buffer formation pH is maintain and COSMETICS do not become harmful , that care is taken.
(v) In agriculture : In agriculture , the formation of buffer for crop is carried out by carbonate , bicarbonate , phosphate and organic acid.
(vi) In industries : In production of paper , dyes , ink, drugs , paints etc. By formation of buffer pH is maintain.
(vii) In analytical chemistry : In group-II `(HCl+ H_2S)`, In group-III `(NH_4Cl+ NH_4OH)` , In group-IV`(NH_4Cl + NH_4OH + (NH_4)_2CO_3)`from buffer solution, which maintain definite pH and selective precipitation of positive ions take PLACE.
Discussion
12.

Give the importance of chemistry.

Answer»



Solution :Science can be viewed as a continuing human EFFORT to systematize knowledge for describing and UNDERSTANDING nature.
For the sake of convenience science is sub-divided into various disciplines: CHEMISTRY, physics, biology, geology etc.
Chemistry is the branch of science that studies the composition, properties and interaction of matter.
Chemistry is to know how chemical transfromations occur. Chemistry PLAYS a central role branches of science like physics, biology, geology etc. Chemistry also plays an important role in daily life.
Example: weather patterns, functioning of brain and operation of a computer.
Similarly many life saving drugs such as cisplatin and taxol, are effective in cancer therapy and AZT ( Azidothymidine) is used for helping AIDS victims,
Safer alternatives to environmentally hazardous refrigerants like CFCs ( chlorofluorocarbons), have been successfully synthesised.
Discussion
13.

Give the hybridisation and shape of (i) NO_(3)^(-) ion (ii) CO_(3) ^(2-) ion.

Answer»

SOLUTION :Both have `sp^(2)` HYBRIDISATION and truangular planar shape.
Discussion
14.

Give the idealgas equation for n moles of a gas.

Answer»


ANSWER :`PV=nRT`
Discussion
15.

Give the general formula of alkyl group with examples up to four carbon.

Answer»

Solution :* The GENERAL formula of ALKYL group is `C_(n)H_(2n+1)` which is DENOTED by R.
* Alkyl group having one hydrogen less than alkane group. EXAMPLES are shown in given table.
Discussion
16.

Give the general formula for the following classes of organic compounds. (a) Aliphatic monohydric alcohol (b) Aliphatic ketones (c) Aliphatic amines.

Answer»

Solution :(a) Aliphatic monohydric ALCOHOL `C_(N)H_(2n+1)OH`
(b) Aliphatic KETONES `C_(n)H_(2n)O`
(c) Aliphatic amines `C_(n)H_(2n+1)NH_(2)`
Discussion
17.

Give the general formula of alkane series and discuss about eh structure of methane.

Answer»

Solution :* The general FORMULA for alkanes is `C_(n)H_(2n+2)`, where n = no. of carbon atoms and (2n +2) = no. of hydrogen atoms in the moelcule. E.g., Butane has 4 carbon and 10 hydrogen and therefore formula is `C_(4)H_(10)`.
* Bonding and structure : Methane has a tetrahedral structure which multiplanar, in which carbon atom lies at the CENTRE and the four hydrogen atoms lie at the four corners of regular tetrahedron.

(i) In methane H-C-H bond angles are `109.5^(@)`.
(ii) In methane C-H bond lengths are 112 pm.
(iii) In methane C-H bond is from.
(iv) C-C and C-H `sigma` bonds are formed by head-on overlapping of `sp^(3)` hybridisation orbitals of carbon and 1s orbitals of hydrogen atoms.
* In alkenes, tetrahedral are joined together in which C-C and C-H bond lengths are 154 pm and 112 pm repsectively. In which all of them are sigma bonds. C-C sigma bond, both carbon has `sp^(3)-sp^(3)` hybridized and 1s overlaps and formation of the hybridization.
Discussion
18.

Give the general formula for the following classes of organic compounds (a) Aliphatic monohydric alcohol (b) Aliphatic ketones (c) Aliphatic amines.

Answer»

SOLUTION :
Discussion
19.

Give the general electronic configuration of lanthanides and actinides,

Answer»

SOLUTION : The ELECTRONIC configuration of lanthanides is `4f^(-14)d^(0-1)6s^(2)`
The electronic configuration of actinides is`5F^(-14)d^(0-1)7s^(2)`
Discussion
20.

Give the general electronic configuration of lanthanides and actides?

Answer»

Solution :(i) The ELECTRONIC configuration of LANTHANIDES is `4f^(1-14)5D^(0-1)6s^(2)`
(ii) The electronic configuration of actinides is `5f^(1-14)6d^(0-1)7s^(2)`
Discussion
21.

Give the general electron configuration of d-block and f -block elements respectively.

Answer»

`(N - 1) d^(1" to " 10)ns^(2) " and " (n -2) f^(n) . (n - 1) d^(1) ns^(2)`
`(n -1) d^(1" to " 10) ns^(1-2) " and " (n - 2) f^(n). (n - 1) d^(1) ns^(2)`
`(n -1) d^(1" to "10) ns^(1-2) " and " (n -2) f^(n+1). ns^(2)`
`(n -1) d^(1" to "10) ns^(1-2) " and " (n -2) f^(1-14) . (n -1) d^(0-1) . ns^(2)`

SOLUTION :`(n -1) d^(1" to "10) ns^(1-2) " and " (n -2) f^(1-14) . (n -1) d^(0-1) . ns^(2)`
Discussion
22.

Give the formulas of followings: (i) Sodium nitropruside (ii) The purple solution made in test of sulphur. (iii) Sodiumhexacyno-ferrate (II) (iv) Iron (III) hexacynoferrate (II) (v) Feriferrocynide (vi) Sodium thiocynate (vii) Ammonium molibled (viii) Ammonium phosphomolibladate (ix) Ferric thiocynate iron (x) Sodium sulphide.

Answer»

Solution :FORMULAS are as under: (i) `Na_(2)[FE(CN)_(5)NO]` (ii) `[Fe(CN)_(5)NOS]^(4-)` (iii) `Na_(4)[Fe(CN)_(6)]` (iv) `Fe_(4)[Fe(CN)_(6)]_(3)`
(v) `Fe_(4)[Fe(CN)_(6)]_(3)` (VI) NaSCN (vii) `(NH_(4))_(2) MoO_(4)` (viii) `(NH_(4))_(3) PO_(4) 12 MoO_(3)` (ix) `[Fe(SCN)]^(2+)` (x) `Na_(2)S`
Discussion
23.

Give the formula, structure, IUPAC names and common name of alkene having carbon = 1, 2, 3, 4 ?

Answer»

SOLUTION :
Discussion
24.

Give the forms of carbons with examples.

Answer»

SOLUTION :* No. of carbons attached to a carbon ATOM, then that carbon is termed as primary `(1^(@))`, secondary `(2^(@))`, tertiary `(3^(@))` and quaternary `(4^(@))`.
Note : FORM of hydrogen is attached having same form carbon.
* Primary `(1^(@))` : Carbon atom attached to no other carbon atom as in METHANE or to only one carbon atom as in ethane is called primary carbon atom.
* Secondary `(2^(@))` : Carbon atom attached to two carbon atoms is known as secondary carbon.
* Tertiary `(3^(@))` : Carbon attached to three carbon is known as tertiary carbon.
* Quaternary `(4^(@))` : Carbon atom attached to other four carbon atoms is known as quaternary or `(4^(@))` carbon.
Discussion
25.

Give the formation of alkane by Kolbe's electrolysis method with its examples.

Answer»

Solution :* An aqueous solution of sodium or potassium salt of a CARBOXYLIC acid on electrolysis gives alkane containing even NUMBER of carbon atoms
Example : Salt of Na of acetic, ethane is obtained by the electrolysis of sodium acetate is as follows.

In this reaction there is ALWAYS a formation of even carbon product of alkane.
Reaction :
(a) In aqueous solution of sodium salt of acid, `CH_(3)COO^(-)` is anion and `Na^(+)` is cation in a solution.
`2CH_(3)COO^(-)Na^(+) hArr 2CH_(3)COO_((aq))^(-) + 2Na_((aq))^(+)` ...(a)
(b) (i) Oxidation at anode : Anion `CH_(3)COO^(-)` goes to the anode, LOSSES its electon and doesoxidation and `CH_(3)` is formed.

(ii) `H_(3)overset(.)(C)+overset(.)(C)H_(3) rarr underset("Ethane(gas)")(CH_(3)-CH_(3))uarr`
(c) Reduction at cathode : Cation does not reduced at cathode but `H_(2)O` gets reduced and hydrogen `(H_(2))` is being released.
(i) `H_(2)O + e^(-) rarr ""^(-)OH + overset(.)(H)`
(ii) `2overset(.)(H)rarr H_(2) uarr`
`2Na^(+) + 2H_(2)O + 2e^(-) rarr 2NaOH + H_(2(g))` ...(c)
(d) Total reaction = (a) + (b) + (c) are as follows

Limitations : MEthane cannot be prepared by this by this method.
Discussion
26.

Give the expressions of crticial constants.

Answer»

Solution :The critical constants can be CALCULATED USING the values of van DER waals constant of a GAS and VICE versa.
`a=3V_(C)^(2)P_(C) and b=(V_(C))/(3)`
Discussion
27.

Give the expression for Van der Waal's equation for n moles of a gas

Answer»

<P>

ANSWER :`P+(an^(2))/(V^(2))(v-nb)=NRT`
Discussion
28.

Give the expression for Compressibility factor (z)

Answer»


ANSWER :`Z=(PV)/(NRT)`
Discussion
29.

Give the expression and illustration for the following concentration terms. (i) Molarity(ii) Formality(iii ) Mass Percentage (iv) Volume Percentage (v) Mass by volume

Answer»

SOLUTION :` (##SUR_CHE_XI_V02_C09_E06_004_S01.png" WIDTH="80%">
Discussion
30.

Give the examples of insecticides.

Answer»

SOLUTION :DDT , ALDRIN , DIELDRIN
Discussion
31.

Give the examples of particulates pollutants.

Answer»

SOLUTION :The examples of PARTICULATES pollutants are dust, mist, fumes, SMOKE, smog etc.
Discussion
32.

Give the examples and name.

Answer»

Solution :(i) Linear alkane (II) Cyclo alkane
(III) AROMATIC HYDROCARBON
(iv) Unsaturated hydrocarbon
Discussion
33.

Give the example of preparation of alkane from the alkyl halide ?

Answer»

Solution :Alkyl halides (except fluorides) on reduction with zinc and dilute hydrochloric acid give alkanes. <BR> `R-X+H_(2)overset(Zn+H^(+)("for HCl"))rarr R-H+HCl`
Example of REACTION :
(i) `underset("Chloromethane")(H_(3)C)-Cl+H_(2)overset(Zn+H^(+))rarr underset("Methane")(CH_(4))+HCl`
(ii) `underset("Chloromethane")(CH_(3)CH_(2))-Cl-H_(2)overset(Zn+H^(+))rarr underset("Ethane")(C_(2)H_(6))+HCl`
(iii) `underset("1-Chloropropane")(CH_(3)CH_(2)CH_(2)Cl)+H_(2) overset(Zn +H^(+))rarr underset("PROPANE")(CH_(3)CH_(2)CH_(3))+HCl`
(iv) `CH_(3)CH_(2)Br +H_(2) overset(Zn+H^(+))rarr CH_(3)-CH_(3)+HBr`
(v) `underset("2-Bromopropane")(CH_(3)underset(Br)underset(|)(CH))CH_(2)CH_(3)+H_(2)overset(Zn+H^(+))rarr CH_(3)CH_(2)CH_(2)CH_(3) + HBr`
Discussion
34.

Give the example for +R effect

Answer»


ANSWER :`-NH_(2),-OH`………..
Discussion
35.

Give the essential postulates of Bohr's model of an atom. How did it explain. (i) the stability of a atom (ii) origin of spectral lines in hydrogen atom ?

Answer»

SOLUTION :`1s^2 2s^2 2p^6 3s^2, 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2, 1s^2 2s^2 2p^6 4s^1 3D^5, 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^(10) 4p^5`.
Discussion
36.

Give the example for (i) K_P = K_c and (ii) K_p gt K_c

Answer»

<P>

SOLUTION :(i) `K_(P) = K_(c) :"" H_(2(G))+I_(2(g))hArr2HI_((g))`
(ii) `K_(P) GT K_(c): "" PCl_(5(g)) hArr PCl_(3(g))+Cl_(2(g))`
Discussion
37.

Give the equilibrium N_2O_4(g) hArr 2NO_(2)(g) wih K_p=0.15 atm at 298 K (a) What is K_p using pressure in torr ? (b) What is K_C using units of moles per litre.

Answer»

Solution :`K_p = ((760 "torr") XX(0.15 atm ))/(1 atm ) = 1.14 xx 10^(2)` torr
`(b) K_p = K_c(RT)^(Delta N)`
`K_(C) = (K_p)/(RT)^(Deltan) = (0.15 atm)/((0.0821 L atmK^(-1) MOL^(-1) xx 298 K)^(2-1))`
`= 6.13 xx 10^(3) "mol" L^(-1)`
Discussion
38.

Givethe equationtocalculateenergyof one electron.

Answer»

SOLUTION :`E_(n)= -2.18 xx 10^(18) ((z^(2))/( n^(2)))J`
Discussion
39.

Give the equation for the ozonolysis products of 2,3-dimethyl-2-pentene.

Answer»

Solution :Step (i) : WRITE the structure of the given compound `underset(1)CH_(3)-underset(2)overset(H_(3)C)overset(|)C=underset(3)overset(CH_(3))overset(|)C-underset(4)CH_(2)-underset(5)CH_(3)`
Step (ii) : REMOVE the double bond and attach OXYGEN ATOMS on doubly bonded carbon atoms.
`underset("Propanone")(CH_(3)-overset(CH_(3))overset(|)C=O)+O=underset("Butanone")(overset(CH_(3))overset(|)C-CH_(2)-CH_(3)`
Discussion
40.

Give the equation for the formation of the final stable product when propyne adds on hypochlorous acid. Explain.

Answer»

Solution :
In both the steps, addition follows Markovnikov RULE. Whenever two hydoxyl groups are linked to the same CARBON ATOM, it becomes UNSTABLE and at once loses a MOLECULE of water.
Discussion
41.

Give the equation for the formation of main product when hydrogen iodide is added to isobutylene.

Answer»

SOLUTION :
Discussion
42.

Give theequationfor systemsuchasquantumor amoleculewhoseenergydoesnot change withtime.

Answer»

SOLUTION :`BAR(H )=W = E W`
where`bar( H) ` = Machematicaloperator
orHamilthoian
Thesolutionof thisequationgivesE and W
E=energy
W = WAVEFUNCTION.
Discussion
43.

Give theenergyorderof 2sorbitals of H, Li,Na ,K.

Answer»

SOLUTION :`E_(2) (H) lt E_(2) (LI) lt E_(2) (Na) ltE_(2) (K)`
Discussion
44.

Give the empirical formaulae for the ionic compounds formed between K, O and Na, p.

Answer»


ANSWER :A
Discussion
45.

Give the electronic confiuration of Mn^(2+) and Cr^(3+).

Answer»

SOLUTION :`Mn (Z = 25)`
`Mg rarr Mn^(2+) + 2e^(-)`
`Mn^(2+)` Electronic configuration is `1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5`
`Cr (Z = 24)`
`Cr rarr Cr^(3+) + 3E^(-)`
`Cr^(3+)` Electronic configuration is `1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^3`.
Discussion
46.

Give the electronic configurations of the elements : ._(19)K, ._(25)Mn, ._(20)Ca

Answer»

Solution :`._(19)K= 1s^(2) 2s^(2) 2P^(6) 3s^(2) 3p^(6) 4s^(1) : ._(25)Mn=1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(5) 4s^(2), ._(20)Ca=1s^(2) 2s^(2) 2p^(6) 3s^(2)3p^(6) 4s^(2)`
Discussion
47.

Give the electronic configurations of : (i) Scandium (At. No. 21), and (ii) Chromium (At. No. 24).

Answer»

Solution :(i) `1S^(2) 2s^(2) 2p^(6) 3S^(2) 3p^(6) 3d^(1) 4S^(2)` (II) `1s^(2) 2s^(2) 2p^(6) 3s^(2)3p^(6) 3d^(5) 4s^(1)`
Discussion
48.

Give the electronic configuration of the following ions : (i) Cu^(2+)(ii) Cr^(3+)(iii) Fe^(2+) and Fe^(3+)(iv) H^(-)(v) S^(2-)

Answer»

Solution :During the formation of cations, electrons are lost while in the formation of anions, electrons are added to the valence shell. The number of electrons added or lost is equal to the numerical value of the charge present on the ion. FOLLOWING this general concept, we can write the electronic configurations of all the ions given in the question. (i) `Cu^(2+)= ._(29)Cu-2e^(-)=1s^(2) 2s^(2) 2p^(6) 3S^(2) 3p^(6) 3d^(10) 4s^(1) -2e^(-) =1s^(2) 2s^(2) 2p^(6) 3s^(2) 3d^(9)`
(ii) `Cr^(3+)=._(24)Cr-3e^(-)=1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(5) 4s^(1)-3e^(-)=1 s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(3)`
(iii) `Fe^(2+)=._(26)Fe-2e^(-) = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) -2e^(-)=1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(6)`
`Fe^(3+)=._(26)Fe-3e^(-) =1 s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(5)`
(iv) `H^(-)= ._(1)H+1e^(-)=1s^(1)+1e^(1)=1s^(2)`
(v) `S^(2-) =._(16)S+2e^(-)=1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p_(x)^(2) 3p_(y)^(1) 3p_(z)^(1)+2e^(-) = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p_(x)^(2) 3p_(y)^(2) 3p_(z)^(2)`
Discussion
49.

Give the electronic configuration of Mn^(2+) and Cr^(3+)

Answer»

Solution :MN(Z=25)
`MnrarrMn^(2+)+2E^(-)`
`Mn^(2+)` electronic cinfiguration is `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(5)`
Cr(Z=24)
`CrrarrCr^(3+)+3e^(-) `
`Cr^(3+)` electronic CONFIGURATION is`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(3)`
Discussion
50.

Give the electronic configuration of Mn^(2+) and Cr^(3+).

Answer»

Solution :`Mn(Z=25)""MntoMn^(2+)+2E^(-)`
`Mn^(2+)` electronic configuration is `1S^(2)2S^(2)2p^(6)3s^(2)3p^(6)3d^(5)`
`Cr(Z=24)""Cr to Cr^(3+)+3e^(-)`
`Cr^(3+)` electronic configuration is `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(3)`.
Discussion