Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the reaction, Fe(OH)_(3)(s)hArrFe^(3+)(aq)+3OH^(-)(aq) if the concentration of OH^(-) ions is decreased by 1//4 times , then the equilibrium concentration of Fe^(3+) will

Answer»

not changed
also DECREASED by `1//4` TIMES
INCREASE by 4 times
increase by 64 time

Answer :D
Discussion
2.

In the reaction C(s) + CO_(2)(g)hArr2CO(g) the following amounts of sbstance were formed in 0.2 litre flask CO_(2) = 0.06 mole. The equilibrium constant is

Answer»

`0.208`
`4.10`
`0.30`
`0.416`

SOLUTION :`K = ([CO]^(2))/([CO_(2)]) = (((0.05)/(0.2))^(2))/(((0.06)/(0.2))`
`K = 0.208`
Discussion
3.

In the reaction, C_((s)) + CO_(2(g)) harr 2CO_((g)) the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(P). If K_(P)= y^(2) then what is 'y" ?

Answer»

<P>

Solution :
total PRESSURE = `(3P)/(2)=12 IMPLIES P=8` atm
`:. K_(P)=((8)^(2))/((4))=4`
Discussion
4.

In the reaction Cr_(2) O_(7)^(2-) + 14 H^(+) + 6I^(-) to 2 Cr^(3+) + 3H_(2)O + I_(2)Wchich element is reduced?

Answer»

H
Cr
O
I

Answer :B
Discussion
5.

In the reaction : Cl_2 + OH^(-) rarr Cl^(-) +ClO_(4)^(-) +H_(2)O chlorine is :

Answer»

OXIDIZED
REDUCED
DISPROPORTIONATE
NEITHER oxidized nor reduced

SOLUTION :
Discussion
6.

In the reaction, Cl_(2)+CH_(4)overset(hv)toCH_(3)Cl+HCl presence of a small amount of oxygen

Answer»

increases the rate of reaction for a brief period of time
decreases the rate of reaction for a brief period of time
does not affect the rate of reaction
completely STOPS the reaction

Solution :Halogenation of alkanes follows FREE radical mechanism and presence of a smal amount of OXYGEN can slow down the reaction for a period of time depending upon the amount of oxygen. Oxygen reacts with METHYL free radical to form LESS reactive free radical and acts as an inhibitor.
Discussion
7.

In the reaction : Cl_(2)+H_(2)S to 2HCl+S, the oxidation number of S changes from

Answer»

0 to 2
2 to ZERO
`-2` to zero
`-2" to -1"`

Answer :C
Discussion
8.

In the reaction, CH_(3)OH rarr HCOOH, the number of electrons that must be added to the right is :

Answer»

4
3
2
1

Solution :`{:(CH_3OH RARR,HCOOH),(+H_2O,+4H^(+)),(,+4E^(-)):}`
Discussion
9.

In the reaction- CH_(3)CN rarr CH_(3)COOH + NH_(3) The hybridisation of carbon in carbonyl group changes from-

Answer»

sp to `sp^(3)`
`sp^(2) " to " sp`
`sp^(3)` to sp
sp to `sp^(2)`

Solution :`underset("ethane NITRILE")(H_(3)C- underset(underset(sp)(uarr))(C )-= N) rarr underset("ethanoic ACID")(CH_(3)- underset(underset(sp^(2))(uarr))OVERSET(overset(OH)(|))(C )=O)`
Discussion
10.

In the reaction CH_(3)CN+2H underset("ether")overset(HCl)rarr X underset(Delta)overset(H_(2)O)rarr Y, Y is

Answer»

acetaldehyde
ethanamine
dimethylamine
acetone

Answer :A
Discussion
11.

In the reaction CH_(3)-Br+2Na+Br-CH_(3) rarr, the reaction is called

Answer»

WURTZ reaction
Aldol condensation
Perkin's reaction
Levit reaction

Answer :A
Discussion
12.

In the reaction, C_(6)H_(6)+ RCOCl overset(AlCl_(3))to C_(6)H_(5)COR+ HCl the attacking electrophile is:

Answer»

`AICI_(2)^(+)`
`R^(+)`
`RCO^(+)`
`AICI_(4)`

ANSWER :C
Discussion
13.

In the reaction C_6H_5CH_3 overset"Oxidation"to A overset"NaOH"to B overset"Soda-lime"to C the product C is

Answer»

`C_6H_5OH`
`C_6H_6`
`C_6H_5COONa`
`C_6H_5ONa`

Solution :`C_6H_5-CH_3overset"[O]"to underset"(A)"(C_6H_5-COOH)OVERSET"NaOH"to underset"(B)"(C_6H_5COONa)overset"SODA lime " to underset"(C )"(C_6H_6)`
Discussion
14.

In the reaction C_(3)H_(6)(g)+nO_(2)(g)toCO_(2)(g)+H_(2)O(l). The ratio of the coefficients of CO_(2) and H_(2)O is

Answer»

`1:1`
`1:3`
`2:3`
`3:2`

ANSWER :C
Discussion
15.

In the reaction, C_(2)O_(4)^(2-)+MnO_(4)^(-)+H^(+)toMn^(2+)+CO_(2), the reducing agent is ..........

Answer»

SOLUTION :`C_(2)O_(4)^(2-)`
Discussion
16.

In the reaction : C_(2)O_(4)^(2-)+MnO_(4)^(-)+H^(+) to Mn^(2+)+CO_(2)+H_(2)O, the oxidising agent is

Answer»

`MnO_(4)^(-)`
`C_(2)O_(4)^(-)`
`MN^(2+)`
`H^(+)`

ANSWER :A
Discussion
17.

In the reaction , C_2H_5Br underset((ii)CuI)overset((i)Li)to"(X)" overset(CH_3Br)to (Y) , the products X and Y are ________ and ____________ respectively.

Answer»


ANSWER :`(C_2H_5)_2 CULI, CH_3C_2H_5`
Discussion
18.

In the reaction C_(2)H_(4)overset(x)rarr Product, if the hybridization of carbon atom (s) in the product is sp^(3), X is not

Answer»

`H_(2)//NI`
`HCl//AlCl_(3)`
`O_(3)//Zn+H_(2)O`
`Br_(2)//C Cl_(4)`

ANSWER :C
Discussion
19.

In the reaction, C + 4HNO_(3) rarrCO_(2) + 2H_(2)O + 4NO_(2), HNO_3acts as

Answer»

An oxidising AGENT
an acid
an acid as WELL as oxidising agent
a reducing agent

SOLUTION :`overset(+5)(HNO_3)` as O.A
Discussion
20.

In the reaction BF_3 + NH_3 to BF_3 larr NH_3 BF_3 and NH_3are …..

Answer»

CONJUGATE ACID, BASE.
LEWIS base, lewis acid.
acid, conjugate base.
lewis acid, lewis base.

Answer :D
Discussion
21.

In the reaction between strong acid and strong base, 1.8 g of water is formed. The heat evolved is used to raise the temperature of one kg of water at 25^@C. What is the final temperature of water?

Answer»

Solution :Number of moles of water formed
`= ("WEIGHT of water")/("gram molecular weight") = (1.8)/18 = 0.1`
Heat liberated `= 13.7 xx 0.1 = 1.37 K`. Cal. Heat (q) is given as, `q = ms q 1.37 xx 1000 = 1000 xx 1 xx q`.
The RISE in temperature of water `q = 1.37^@`. Final temperature of water = `25 + 1.37^@ = 26.37^@C`
Discussion
22.

In the reaction between I_2 and H_2O_2 in alkaline medium, what is the oxidant and reductant?

Answer»

Solution :`I_2 + H_2O_2 + 2OH^(-) to 2I^(-) + 2H_2O + O_2`
HYDROGEN peroxide is oxidised to oxygen and IODINE is reduced to iodide ion. THUS `H_2O_2`is reductant and `l_2` is OXIDANT
Discussion
23.

In the reaction between hydrogen and oxygen gives water vapour, the ratio of volumes is 2:1:2. This illustrates the law of

Answer»

conservation of MASS 
combining weights 
combining VOLUMES 
all the above 

ANSWER :C
Discussion
24.

In the reaction between dilute nitric acid and magnesium metal, (a) how many moles of HNO_(3) reacts with a gram atom of metal? and (b) how many moles of HNO_(3) is oxidised by a gram atom of metal?

Answer»

Solution :The skeleton equation is
`MG+HNO_(3) to Mg(NO_(3))_(2)+NH_(4)NO_(3)+H_(2)O`
The BALANCED equation is
`4Mg +10HNO_(3) to 4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O`
(a) NUMBER of MOLES of `HNO_(3)` that reacts with a gram atom of Mg=10/4=2.5
(b) `NO_(3)^(-)` is a spectator ion. It is NEGLECTED in the equation.
`4Mg+NO_(3)^(-)+10H^(+) to 4Mg^(2+)+NH_(4)^(+)+3H_(O)`
Number of moles of `HNO_(3)` that is reduced by a gram atom of Mg=0.25.
Discussion
25.

In the reaction between BF_(3) and NH_(3), BF_(3) acts as ...........whereas NH_(3) acts as ...........

Answer»


ANSWER :LEWIS ACID, Lewis BASE
Discussion
26.

In the reaction between BF_(3) and C_(2)H_(5)OC_(2)H_(5) which one of them will act as an acid ?Justify your answer.

Answer»

SOLUTION :The reaction between `BF_(3) and C_(2)H_(5)OC_(2)H_(5)` is

As `BF_(3) ` accepts a pair of electrons, hence `BF_(3)` is the LEWIS acid.
Discussion
27.

In the reaction between acidified KMnO_(4) and FeSO_(4) solution, the number of electrons involved in the process is

Answer»

2
5
10
6

Answer :B
Discussion
28.

In the reaction below, X is Neopentyl alcohol overset(H_2SO_4)to X

Answer»

2-methylpentane
2-methylpent-2-ene
2-methylbut-2-ene
neopentane

Solution :
Discussion
29.

In the reaction , As_(2)S_(3) + HNO_3 rarr H_3AsO_(4) +H_(2)SO_(4) +NO , the element oxidised is/are :

Answer»

As only
S only
N only
As and S both

Solution :`OVERSET(+3)(As_2)S_3+HNO_3rarrH_3overset(+5)(ASO_4)+H_(2)overset(+6)(SO_4)+NO`
Both As & S
Discussion
30.

In the reactionAl + Fe_(3)O_(4) rarr Al_(2) O_(3) + Fe (a) Which element is oxidized and which is reduced? (b) Total no. of elecetros transferred during the change.

Answer»


Answer :`AL` is oxidized and `FE^(8//3+)` is reduced, (B) `24`
Discussion
31.

In the reaction AB_(2)(l)+3X_(2)(g)hArrAX_(2)(g)+2BX_(2)(g) DeltaH=-2700 kcal per mole. Of AB_(2)(l). The entalpies of formation of AX_(2)(g) and BX_(2)(g) are in the ratio of 4 : 3 and have opposite sign. The value of DeltaH_(f)^(@)(AB_(2)(l))=30 kcal//mol. Then :

Answer»

`DeltaH_(f)^(@)(AX_(2))=-96kcal//mol`
`DeltaH_(f)^(@)(BX_(2))=+480kcal//mol`
`K_(p)=K_(C)` and `DeltaH_(f)^(@)(AX_(2))=+480kcal//mol`
`K_(p)=K_(c) " RT"` and `DeltaH_(f)^(@)(AX_(2))+DeltaH_(f)^(@)(BX_(2)=-240kcal//mol`

ANSWER :C
Discussion
32.

In the reaction , Ag_(2)O+ H_(2)O_(2) to 2Ag + H_(2)O+ O_(2)H_(2)O_(2) acts as

Answer»

REDUCING AGENT
oxidising agent
BLEACHING agent
NONE of these

Answer :A
Discussion
33.

In the reactionAB (g) hArr A(g) + B (g)"at " 30^(@) C,K_(p)for the dissociation equilibrium is2*56 xx 10^(-2) atm. If the dissociation of AB is

Answer»

0.87
0.13
`43*5 %`
0.06

Solution :`{:(AB (g),HARR,A(g),+,B (g) ), (1 "mole",,,,), (1-alpha,,alpha,,alpha" Total moles"1+alpha),("If P is total pressure,",,,,):}`
`p_(AB)=(1-alpha)/(1+alpha) P,p_(A)= alpha/(1+alpha)P,p_(B)=alpha/(1+alpha)P`
`K_(p)=(alpha^(2)P)/(1-alpha^(2))=alpha^(2)/(1-alpha)" " ( :'P=1 "atm")cong alpha^(2)`
`alpha = sqrt(K_(p)) = sqrt (2*56 xx 10^(-2))=0.16, i.e., 16 % `
Discussion
34.

In the reaction : A overset("HBr") to B overset( "alc. KOH") to C underset(Zn, H_(2)O)overset(O_(3))to CH_(3)CHO+ CO_(2)the compound A is

Answer»

Ethylene
Acetic acid
PROPENE
1-Butene.

Solution :`underset("Propene")(CH_(3)CH=CH_(2)) OVERSET(HBr) to underset(Br)underset(|)CH_(3)CHCH_(3)overset("alc. KOH")to CH_(3)CH=CH_(2) underset( Zn, H_(2)O)overset(O_(3))to CH_(3)CHO+CO_(2)`
Discussion
35.

In the reaction A + B rArr C + D, what will happen to the equilibrium is concentration of A is increased ? The equilibrium constant for a reaction is 2 xx 10^(-23) at 25^@C and 2 xx 10^(-2) at 50^(@). Is the reaction endothermic or exothermic ? (c) Mention at least three ways by which the concetration of SO_(3) can be increased in the following reaction in a state of equilibrium. 2SO_(2)(g) + O_(2)(g) hArr (g)

Answer»

Solution :The reaction will shift in the forward direction.
(b) ENDOTHERMIC
(c) (i) INCREASING concentration of `SO_2`
(ii) incrasing PRESSURE.
(iii) increasing concentration of oxygen.
Discussion
36.

In the reaction A^(+) + B rarr A+ B^(+) , there is no entropy change. Enthalpy change, Delta Hequals 22 kJ mol^(-1) of A^(+) . Calculate the DeltaG for the reaction . Under what condition free energy change will have negative value ?

Answer»


Solution :`DeltaS= 0, DeltaH = 22kJ mol^(-1)`. H ENCE, `DELTAG = DeltaH - T DeltaS = DeltaH = 22kJ mol^(-1)`.
Discussion
37.

In the reaction A + 2B hArr2C, if 2 moles of A, 3.0 moles of B and2.0 moles of C are placed in a 2.0 L flask and equilibrium constant (K_(c)) for the reaction is

Answer»

`0.073`
`0.147`
`0.05`
`0.026`

Solution :`{:(,A,"+",2B,hArr,2C),("Initial conc.",2,,3,,2),("at etq.",2.5,,4,,1),("MOLAR",2.5/2=1.25,,4/2=2,,1/2=0.5):}`
`K = ([0.5]^(2))/([1.25]XX[2]^(2)) = 0.05`
Discussion
38.

In the reaction 8Al+3Fe_(3)O_(4)rarr 4Al_(2)O_(3)+9Fe the number of electrons transferred from the reductant to the oxidant is

Answer»

8
4
16
24

Answer :D
Discussion
39.

In the reaction, 4Zn + NO_(3)^(-) + 7H_(2)O rarr 4Zn^(2+) + NH_(4)^(+) + 10OH^(-), the substance which gets reduced is "______________".

Answer»

`Zn` is REDUCED to `Zn^(2+)`
`H_(2)O`
`NO_(3)^(-)`
`NH_(4)^(-)`

ANSWER :C
Discussion
40.

In the reaction 4A+2B+3CrarrA_(4)B_(2)C_(3), what will be the number of moles of product formed, starting from one mole of A, 0.6 moles of B and 0.72 moles of C

Answer»

`0.25`
`0.3`
`0.24`
`2.32`

Solution :`4A+2B+3CrarrA_(4)B_(2)C_(3)`
`(1)/(4),(0.6)/(2)(0.72)/(3)`
`(0.72)/(3)lt(1)/(4)lt(0.6)/(2)`
implies C is LIMITING reagent
implies AMOUNTOF product = `(0.72)/(3)=0.24`
Discussion
41.

In the reaction 3Mg+N_(2)rarrMg_(3)N_(2)

Answer»

Magnesium is REDUCED
Magnesium is OXIDIZED
Nitrogen is oxidized
Nitrogen is reduced

SOLUTION :`3MG+N_(2)rarr Mg_(3)N_2`
`3Mg rarr3Mg^(+2)+2e^(-), Mg`is oxidised.
Discussion
42.

In the reaction 3Br_(2)+6CO_(3)^(2-)+3H_(2)Oto5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-)

Answer»

BROMINE is oxidized and carbonate is reduce
Bromine is REDUCED and WATER is oxidized
Bromine is NEITHER reduced nor oxidized
Bromine is both reduced and oxidized

Answer :D
Discussion
43.

In the reaction 3Br_(2) + 6CO_(3)^(2-) + 3H_(2)OrarrBr^(-) + BrO_3+ 6HCO_(3)^(+)

Answer»

BROMINE is oxidised and CARBONATE is REDUCED
Bromine is reduced and WATER is oxidised
Bromine is NEITHER reduced nor oxidised
Bromine is both reduced and oxidised

Answer :D
Discussion
44.

In the reaction : 3Br_2+6CO_3^(2-)+3H_2O rarr 5Br^(-) +BrO_3^(-) +6HCO_3^(-)

Answer»

`Br_2` is oxidised and CARBONATE is REDUCED .
BROMINE is reduced and WATER is oxisised.
Bromine is NEITHER reduced nor oxidised .
Bromine is both reduced and oxidised.

Answer :D
Discussion
45.

In the reaction2X+B_(2)H_(6)rarr [BH_(2)X_(2)]^(+)[BH_(4)]^(-) the amines (s) X is/are

Answer»

`NH_3`
`CH_3NH_2`
`(CH_3)_2NH`
`(CH_3)_3N`

Solution :X is `NH_3`
`2NH_(3)+B_(2)H_(6)rarr[BH_(2)(NH_3)_2]^(+)[BH_(4)]^(-)`
`CH_(3)NH_3:2CH_(3)NH_(2)+B_(2)H_(6)rarr [BH_(2)(CH_3NH_2)_(2)]^(+)[BH_4]^(-)`
`(CH_3)_2NH:2(CH_3)_(2)NH+B_(2)H_(6)rarr[BH_(2)(CH_3NH_2)_(2)]^(+)[BH_4]^(-)`
with `(CH_3)_3N,B_(2)H_6` forms an adduct
`(CH_3)_3N+B_(2)H_(6)rarr2[(CH_3)_3N rarrBH_(3)]`
Discussion
46.

In the redox reaction2S_(2)O_(3)^(2-)+I_(2) rarrS_(4)O_(6)^(2-)+2I^(-)

Answer»

M
M/2
M/4
M/3

Solution :`2overset(2.0)(S_(2))O_3^(2-)OVERSET(1)RARROVERSET(2.5)(S_(2))O_(6)^(2-),2xx0.5=1, E=M/1`
Discussion
47.

In the reaction , 2NH_(3) (g) hArr N_(2) (g) + 3H_(2) (g)

Answer»

`K_(P) = K_(C)`
`K_(P) LT K_(C)`
`K_(P) gt K_(C)`
`K_(P) = (1)/(K_(C))`

Solution :`K_(P) = K_(C) (RT)^(Deltan_(G)) = 4 - 2 = 2`
`THEREFORE K_(P) = K_(C) (RT)^(2) = K_(P) gt K_(C)`
Discussion
48.

In the reaction , 2Na+ Cl_(2) rarr 2NaCl, "_______________".

Answer»

Na GETS OXIDIZED while `Cl_(2)` gets REDUCED
Na gets reduced while `Cl_(2)` gets oxidized
only `Na` gets reduced
only `Cl_(2)` gets oxidised.

Answer :A
Discussion
49.

In the reaction : 2H_2O_2 to 2H_2O + O_2

Answer»

`H_2O_2` UNDERGOES only OXIDATION.
`H_2O_2` undergoes both oxidation and REDUCTION.
`H_2O_2` undergoes NEITHER oxidation nor reduction.
`H_2O_2` undergoes only oxidation.

Solution :
Discussion
50.

In the reaction 2H_(2) (g) + O_(2) (g) hArr 2 H_(2) O (g) , the K_(p) value is equal to ……….

Answer»

Solution :`lt K_(C)`
`Deltan_(g) = 2 - 3= -1`
`K_(p) = K_(C) (RT)^(DELTA n_(g))= K_(C) (RT)^(-1) IMPLIES K_(P) lt K_(C)`
Discussion