Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Mark the correct statement from the following :

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<P>Copper metal can be oxidised by `ZN^(2+)` ions.
Oxidation number of phosphorus in `P_(4)` is 4
An element in the highest oxidation state acts only as a REDUCING agent.
The element which shows highest oxidation number of +8 is Os in `OsO_(4)`

Solution :CU cannot be oxidised by `Zn^(2+)` ion, oxidation number of phosphorus is zero. An element in its highest oxidation state acts as an OXIDISING agent.
2.

Mark the correct statement for viscosity .

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GREATER the viscosity , more slowly the liquid flows .
Viscosity increases with increase in temperature .
Hydrogen bonding and VAN DER Waals forces decrease the viscosity .
Viscosity is the measure of ease with which a liquid flows .

Solution :More viscous liquids FLOW slowly.
3.

Mark the correct statement :

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Group I basic radicals are PRECIPITATED as chlorides
Group IV basic radicals are precipitated as sulphides
Group V basic radicals are precipitated as carbonates
All the STATEMENT are CORRECT.

Solution :All the three statement are correct
4.

Mark the correct order of increasing reactivity

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`CH_(3)CONH_(2) lt CH_(3)COOC_(2)H_(5) lt CH_(3)COCl`
`CH_(3)COOC_(2)H_(5) lt CH_(3)COCl lt CH_(3)CONH_(2)`
`CH_(3)COCl lt CH_(3)CONH_(2) lt CH_(3)COOC_(2)H_(5)`
`CH_(3)COOC_(2)H_(5) lt CH_(3)CONH_(2) lt CH_(3)COCl`

SOLUTION :This can be explained on the basis of basicity of leaving GROUP in each case. For acid chlorides, leaving group is `Cl^(-)` ions and for esters, leaving group is alkoxide. However, in amide, leaving group is `NH_(2)` or amine. Out of these three, `Cl^(-)` ion is weakest BASE hence acid chlorides are most reactive. But `NH_(2)` or amines are strongest bases, hence amides are least reactive
5.

Mark the correct answer. Air which contains…. CO_(2) does not support combustion.

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`15%`
`2%`
`50%`
`75%`

SOLUTION :`CO_(2)` is heavier than air
6.

Mark out the optically active molecule :

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SOLUTION :Alkene with same GROUP at any ONE END does not SHOW Optical isomersim.
7.

Mark out the correct statement (s) :

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Electrons within a SUB shell for which `l gt 0` mean that the RELATIVELY greater electrostatic repulsion between two electrons in the same ORBITAL within a sub shell as compared with occupancy of two orbitals having DIFFERENT `m_(l)` values.
Electrons in singly occupied orbitals tend to have their spins in the same direction so as to maximize the net magnetic moment
In the ground state, an atom adopts a configuration with the greatest number of unpaired electrons.
Electrons in different orbitals with parallel spins show mutual attraction, so electron-nucleus INTERACTION is improved.

Answer :A::B::C
8.

Marbles of diameter 10mm each to be arranged on a flat surface so that their centers lie within the area enclosed by four lines of length each 40 mm. Sketch the arrangement that will given the maximum number of marbles per unit area, that can be enclosed in this manner and deduce the expression to calculate it

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ANSWER :25, 1.804 MARBLES/`CM^(2)`
9.

Mark out the correct increasing order of radius.

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`As^(3-)ltBr^(-) lt K^(+) lt Mg^(2+)`
`Mg^(2+) lt K^(+) lt Br^(-) lt As^(3-)`
`Mg^(2+)ltK^(+)ltAs^(3-) lt Br^(-)`
`K^(+) lt Mg^(2+) lt Br^(-) lt As^(3-)`

ANSWER :B
10.

Mark as true or false : Find the number of false statements.

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ANSWER :6
11.

Many thermodynamically feasible reactions do not occur under ordinary conditions. Why ?

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SOLUTION :Under ORDINARY conditions , the average ENERGY of the reactants MAY be LESS than threshold energy . They require some activation energy to initiate the reaction.
12.

Many real gases behave as ideal gases at "______________".

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0 K and 1 atm
`0^(@)C` AND1 atm
1K and 1 atm
298 K and 10 atm

ANSWER :B
13.

Many ionic crystals dissolve in water because

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Water is an amphiprotic solvent
Water is a high boiling liquid, which has no taste and no odour
The PROCESS is accompanied by a positive heat of solution
Water decreases the inter ionic attraction in the CRYSTAL lattice DUE to solvation.

Answer :D
14.

Many cereals are made with high moisture content so that the product can be formed into various containing 50% H_(2)O by mass is produced at the rate of 1000 kg/hr. How much water (in kg)must b evaporated per hour if final product contains only 20% water? (Fill your answer dividing it by 62.5)

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ANSWER :6
15.

Manmade sillicate is ……

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SOLUTION :GLASS and CEMENT.
16.

Mangoes contain

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SOLUTION :CYCLOHEXANE
17.

Manganese trifluoride can be prepared by the reaction: MnI_(2(s))+13//2F_(2(g))rarrMnF_(3)+2IF_(5) What is the minimum amount of F_(2) that must be used to react with 12 g of MnI_(2) if only 75% F_(2) is utilized to convert all of MnI_(2) to MnF_(3)?

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ANSWER :`12.78g`;
18.

Manganese forms non-stoichiometric oxides having the general formula MnO_(x). The value of x for the compound that analyzed 64% Mn. (At wt Mn=55)

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`1.16`
`1.83`
2
`1.93`

SOLUTION :`1%Mn=64=(55)/(M)XX100`
`%O=36=(16x)/(M)xx100impliesx=1.93`
19.

Manganese dioxide oxidises hydrochloric acid to chlorine and gives manganous chloride and water.

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Solution :(a) The skeleton equation is written as
`MnO_(2)+HCl to MnCl_(2)+Cl_(2)+H_(2)O`
(b) FOCUSING on the oxidation numbers
`overset(+4)(Mn) overset(-2)(O_(2)) +overset(+1)(H) overset(-1)(Cl) to overset(+2)(Mn) overset(-1)(Cl_(2)) +overset(Cl_(2))+overset(+1)(H_(2)) overset(-2)(O)`
(c) Locating atoms undergoing CHANGE in oxidation numbers
`overset(+4)(Mn) O_(2)+H overset(-1)(Cl) to overset(+2)(MnCl_(2))+overset(0)(Cl_(2))+H_(2)O`
(d) Determining the change in oxidation number
(e) Cris-crossing these changes in the oxidation numbers
`MnO_(2)+2HCl to MnCl_(2)+Cl_(2)+H_(2)O`
(F) Balancing the atoms other than hydrogen and OXYGEN
`MnO_(2)+2HCl +2HCl to MnCl_(2)+Cl_(2)+H_(2)PO`
(g) Balancing the atoms hydrogen and oxygen `MnO_(2)+4HCl to MnCl_(2)+Cl_(2)+H_(2)O`
This is balanced equations.
20.

Maneesh , a student of class XII, watched a programme onTV where it was being show how use of polythene bags blocked the sewer system and how sometimes the polythene bags thrown as garbage into the streets were swallowed by the animalsresulting into their death. Maneesh was highly upset and he discussed the problem with the class teacher to creater an awakening among his class-mates. After reading the above paragraph, answer the following question s : (a) What values do you attache to Maneesh's observation on TV and iscussion with his class teacher ? (b)What is the basic reason to the harmful effects of use of polythene bags ? What alternativedo you suggest ?

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Solution :(i) The use of polythene bags should be BANNED.
(ii)Even if we get some materials packed in polythene, the polythene USED in packing should not be thrown into the OPEN but properly disposed off.
(B) The basic reason for harmful effects of polythene is that it is non-biodegradable.The best alternative is to use paper bags or CLOTH bags.
21.

Man made sources of air pollution are ?

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POPULATION INCREASE
Deforestration
War
POLLEN grains

Answer :A::B::C
22.

Man dies in an atmosphere of carbon monoxide, because it

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combine with the `O_(2)` PRESENT in the body to form `CO_(2)`
reduces of the organic matter of tissues
combines with haemoglobin of blood, MAKING it INCAPABLE of binding`O_(2)`
dries up the blood 

Answer :C
23.

Malonic acid and Succinic acid can be distinguised by :

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heat <BR>acidified `KMnO_(4)`
`Br_(2)` water
ammonia

Solution :
24.

Malonic acid on heating gives :

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formic acid
acetic acid
oxalic acid
acetaldehyde

Solution :See some note worthy POINTS of ACIDS
25.

Digital circuits can be made to be respective use of :

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SOLUTION :METAL IONS
26.

Malleability and ductility of metals can be accounted due to

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the CAPACITY of layers of metal ions to slide over the other
the interaction of electrons with metal ions in the other
the presence of electrostatic force
the CRYSTALLINE STRUCTURE in metal

Solution :Melleability (BEATEN into sheets) and ductility (drawn into wires) of metals is due to capacity of layers of metal ions to slids over the other.
27.

Maleic acid and fumaric acids are

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STRUCTURAL isomers
Geometrical isomers
Optical isomers
Conformational isomers

Answer :B
28.

Malachite is basic copper carbonate. The only other elelment forming basic carbonate ore is

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Bi
Ba
Mn
Mo

Answer :B
29.

Major source of methane in India is

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Rice FIELDS
Sugarcane PLANTATION
Wheat fields
Fruit orchards

Solution :Main sourceof METHANE in INDIA is reice fields
30.

major products formed are ?

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Solution :electron WITHDRAWING GROUP activate RING towards ACCEPTING HYDRIDE
31.

Major product of the reaction

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ANSWER :C
32.

Major product of the given reaction is :

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ANSWER :C
33.

Major product of the below mentioned rectionis …………… (CH_(3))_(2)C=CH_(2)overset(ICI)rarr

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2-chloro-1-iodo -2-METHYLPROPANE
1-chloro -2-iodo -2-methypropane
1,2 -dichloro-2-methypropane
1,2 - DIODO -2 -methylpropane

ANSWER :a
34.

Major product of the below mentioned reaction is ….. (CH_(3))_(2)C=CH_(2)overset(ICI)to

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2-chloro-1-iodo-2-methypropane
1-chloro-iodo-2-methylpropane
1,2-dichloro-2-methylpropane
1,2-diiodo-2-mrthylpropane

Answer :A
35.

Major product of given reaction is - O_2N-CH_2-undersetunderset(Cl)(|)CH-CH_3overset(overset(Theta)(O)H)underset(Delta)to Major product

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`O_2N-CH=CH-CH_3`
`O_2N-CH_2-CH=CH_2`
`O_2N-CH=undersetunderset(CL)(|)C-CH_3`
`CH_2=undersetunderset(NO_2)(|)C-CH_3`

ANSWER :A
36.

Major Product is :

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ANSWER :B
37.

Major component present in producer gas

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`H_(2)`
`N_(2)`
`CO`
`CO_(2)`

ANSWER :B
38.

Mainly……….types of bond are present in organic compound

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ionic
co-ordinat covalent
metallic
covalent

Answer :D
39.

Magnitude of surface tension is depend upon ?

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SOLUTION :Magnitude of INTERMOLECULAR ATTRACTION FORCE increases, surface tension increases.
Temperature increases surface tension decreases because kinetic energy of the molecules increases with temperature and effective intermolecular attraction decreases.
So, surface tension decreases.
40.

Magnitude of london force is depend upon ?

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Solution :(i) London FORCE is inversely proportional to distance between MOLECULES. (ii) Its MAGNITUDE is depend upon polarisability of PARTICLE.
41.

magnitude of enthalpy of neutralization is minimum for:

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`HCN+KOH`
`HCl+KOH`
`HCl+NH_(4)OH`
`HCN+NH_(4)OH`

ANSWER :d
42.

Magnitudeof K.E. in anorbitis equal to

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Halfof thepotentialenergy
Twiceof thepotentialenergy
One fourththepotentialenergy
Noneof these

SOLUTION :K.E. of `e^(-)=(1)/(2)` of P.E.K.Eis alwayspositiveor K.E. `-((1)/(2) P.E)` = - Total energyof system
43.

Magnisium powder burns in air to give:

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MgO only
MgO and `Mg(NO_(3))_(2)`
MgO and `Mg_(3)N_(2)`
`Mg(NO_(3))_(2)` and `Mg_(3)N_(2)`

Solution :`Mg+underset(O_(2)//N_(2))("AIR") OVERSET(Delta)to MgO +Mg_(3)N_(2)`
44.

Magnetite is _______ regards magnetic behaviour.

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ANSWER :FERRIMAGNETIC
45.

Magnetite, Fe_(3)O_(4) can be reduced to iron by heating with carbon monoxide according to the equation : Fe_(3)O_(4) + 4CO rightarrow 3Fe + 4CO_(2) {:("Molar mass", (g mol^(-1))), (Fe_(3)O_(4) , 232):} What mass of Fe_(3)O_(4) is required in order to obtain 5.0kg of iron if the process is 88% efficient?

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6.1kg
6.9kg
7.9kg
18kg

Answer :C
46.

Magnetic susceptibility of a paramagnetic substance:

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is INDEPENDENT of temperature
increases with DECREASE of temperature
attain the maxima at null point
increases rapidly above Curie temperature

Answer :C
47.

Magnetic moment of Cr^(+2)(Z=24),Mn^(+2)(Z=25) and Fe^(2+)(Z=26) are x,y,z. they are in order:

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xltyltz
xgtygtz
zltx=y
x=zlty

Answer :D
48.

Magnesium reacts with an element (X) to form an ionic compound . If the ground state electronic configuration of (X) is 1s^(2) 2s^(2) 2p^(3) , the simplest formula of this compound is

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`Mg_(2)X_(3)`
`MgX_(2)`
`Mg_(2)X`
`Mg_(3)X_(2)`

Solution :`Mg^(2+) X^(+3) ` i.e., `Mg_(3)X_(2)`
THUS , OPTION (d) is CORRECT .
49.

Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s^(2) 2s^(2) 2p^3, the simplest formula for this compound is

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`Mg_3X_2`
`Mg_2X_3`
`Mg_2X`
`MgX_2`

Solution :`X 1s^(2) 2s^(2) 2p^3`
So it is NITROGEN atom and its valency = 5,3
Mg is in SECOND group, So its valency = 2
` therefore `Formula will be `Mg_3N_2`
50.

Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s^2 2s^2 2p^3 the simplest formula for this compound is-

Answer»

`Mg_3X_2`
`Mg_2X_3`
`Mg_2X`
`MgX_2`

SOLUTION :ELECTRONIC configuration of X: `1s^2 2s^2 2p^3`
`:.` Valency of X = 3
Here, valency of MG = 2
Thus the COMPOUND will be `Mg_3X_2`.