Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

{:(ul"Compound",ul"Ozonolysis products"),("A) Acetylene","1) Formaldehyde and Acetaldehyde"),("B) Ethylene","2) Acetaldehyde"),("C) Benzene","3) One mole of glyoxal"),("D) 2-Butene","4) 3 moles of glyoxal"),(,"5) Formaldehyde"):} The correct match is

Answer»

`{:(ULA,ULB,ulC,ULD),(3,2,5,4):}`
`{:(ulA,ulB,ulC,ulD),(4,2,1,3):}`
`{:(ulA,ulB,ulC,ulD),(3,5,4,2):}`
`{:(ulA,ulB,ulC,ulD),(5,3,1,4):}`

ANSWER :C
Discussion
2.

Which of the following statements(s) is/are correct regarding the structure of borax ?

Answer»

NUMBER of B - B bonds are ZERO
Hybridization of each boron atom is `sp^2`
Number of B - O bonds are FIVE
BORAX contain two different types of B - O bonds

Solution :
Discussion
3.

What is the total number of orbitals present in the shell with the principal quantum number, n = 3

Answer»

Solution :For n = 3, the possible VALUES of l are 0,1 and 2. Thus, there is one 3S orbital (n = 3, l = 0 and `m_l` = 0), there are three p orbitals (n = 3, l = 1 and ml = -1, 0, 1) there are five 3D orbitals (n = 3, l = 2, ml = -2, -1, 0, 1, 2).
Therefore, the total number of orbitals is 1+3+5 = 9.
Discussion
4.

What is the effect of pressure on (i) visocity, (ii) surface tension,(iii) density of liquid ?

Answer»

Solution :Increase in PRESSURE increases viscoity, surface tension and density becauseinter molecular FORCE of ATTRACTION increases.
Discussion
5.

What will be the products of electrolysis of AgNO_(3) solution in water with platinum electrodes ?

Answer»

Ag is liberatedat cathode and Ag is deposited in anode.
Ag is liberated at cathode and `O_(2)` is liberated at anode.
Ag is liberated at anode and WATER is liberated at cathode.
Ag is liberated at cathode and silver oxide isliberated at anode.

SOLUTION :When electrolysis of `AgNO_(3)` solution iscarried out using platinum electrodes, OXIDATION of water OCCURS at anode since Pt being a noble metal does not undergo oxidation easily. As a result, `O_(2)` is liberated at the anode.
Discussion
6.

Which of the following reactant can react with benzene ?

Answer»

`I_(2)` and sunlight (NORMAL temperature)
With COLD `KMnO_(4)`
With bromine water
With bromine `+ FeBr_(3)`

Solution :(A) Benzene does not REACT with benzene.
(B) Cold `KMnO_(4)` reaction is UNSATURATION bayer test.
(C) Bromine water or `Br_(2)(Cl_(4))` is also unsaturation test. Benzene has characteristic stability so it does not GIVE unsaturation test (B) and (C).
(D) Benzene react with `Br_(2)` in presence of Lewis acid `FeBr_(3)` and form `Br^(+)` which can form bromobenzene from benzene.
Discussion
7.

What is coefficient of Viscosity ?

Answer»

Solution :A force is required of MAINTAIN the flow of layers. This force is proportional to the area of CONTACT of layers and velocity gradient
`F = eta A (dy)/(DZ), eta = (F)/(A((dz)/(dz)))`
`.eta.` is proportionality constant and is called COEFFICIENT of viscosity.
If contact surface area = unit Area (1) and viscosity velocity gradient `((dy)/(dz))=1` then `eta = 1`.
Viscocity CO - efficient is the force when velocity gradient is unity and the area of constant is unit area.
This `.eta.` is measure of viscocity.
Discussion
8.

Which one is Charle.s formula ?

Answer»

`V_(1)T_(2)=T_(2)V_(1)`
`V_(1)T_(1)=V_(2)T_(2)`
V = KP
`V_(1)T_(2)^(-1)=V_(2)T_(2)`

ANSWER :B
Discussion
9.

What is tin plague ?

Answer»

Solution :Tin exist in three ALLOTROPIC forms, i.e,Prey, white and rhombic,
`"Grey" UNDERSET(larr)overset(291K)(rarr)"White"underset(larr)overset(434K)(rarr)"Rhombic"`
In cold countries, the conversion of white tin to grey tin occurs. Since grey tin is quite brittle, it starts CRUMBLING down and hence tin gets corroded. This corroding PROCESS of tin is called tin disease or tin PEST or plague.
Discussion
10.

When ethylene glycol is treated with conc. H_(2)SO_(4) the compound formed is

Answer»

ketal
dioxane
ethane
ethanal

Solution :
Discussion
11.

Writethe complete symbol for theatom with thegivenatomicnumber(z ) andatomicmass ( A) (i) Z= 17 ,A= 35(ii) Z= 92 , A= 233 (iii) Z=4, A=9

Answer»

SOLUTION :CI forZ= 17u For Z = 92Be for Z= 4
Discussion
12.

Which o f the following species is not paramagnetic ?

Answer»

NO
CO
`O_(2)`
`B_(2)`

SOLUTION :CO
Total number of electrons in CO = 6 + 8 = 14 THEREFORE molecular ELECTRONIC CONFIGURATION =
`sigma 1s^(2), sigma^(**) 1s^(2), sigma 2s^(2), sigma^(**) 2s^(2) (pi 2p_(x)^(2)= pi 2p_(y)^(2)) sigma 2P_(2)^(2)`
Therefore all the electrons are paired, So it is diamagnetic rest of all have minimum ONE electron is unpaired
Discussion
13.

Write the IUPAC names of the following compounds. (i) CH_(3)-underset(OH)underset(|)(CH)-CH_(2)-CH=CH-CH_(3) (ii) CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(2)-overset(C_(2)H_(5))overset(|)(CH)-CH_(2)-CH_(3)

Answer»

SOLUTION :(i) Her-4-ene-2-ol
(II) 3-ethyl-5-methyl leptane
Discussion
14.

The relation between pH, pK_(a) and concentration c of the solution of a weak acid is ...........

Answer»


Answer : `PH = (1)/(2) (pK_(a)-log c) `
Discussion
15.

What are the molecular mass and molar mass, if each molecule of a substance contains 9 carbon and 13 hydrogen atom?

Answer»


ANSWER :135u and 135G
Discussion
16.

What is the total number of ions present in one unit cell of sodium chloride lattice ?

Answer»

2
6
12
8

Answer :D
Discussion
17.

What are transuranium elements?

Answer»

Solution :In PERIODIC table the ELEMENTS PLACED BEYOND uranium (Z=92) are all synthetic elements and are called as transuranium elements.
Discussion
18.

What happens when acetyl chloride is treated with excess of CH_3Mgl?

Answer»

Solution :When acetyl chloride is TREATED with excess of Grignard reagent, the PRODUCT formed is TERTIARY butyl ALCOHOL.
Discussion
19.

What is physical equilibrium ?

Answer»

Solution :The TYPE of equilibrium in which only PHYSICAL state CHANGE but the COMPOSITION of system does not change is called physical equilibrium.
Discussion
20.

Which reaction is not feasible?

Answer»

`HCequivCH+LirarrLi^(+)OVERSET(-)Cequivoverset(-)CLi^(+)+H_(2)`
`4NaNO_(3)overset(Delta)rarr2Na_(2)O_(2)+4NO_(2)+O_(2)`
`LiCl+2H_(2)OrarrLiCl.2H_(2)O`
`MgCl_(2)+6H_(2)OrarrMgCl_(2).6H_(2)O`

Solution :(a) LI does not FORM ethynide.
(b) `2NaNO_(3)overset(Delta)rarr2NaNO_(2)+O_(2)`
Discussion
21.

What will be the minimum pressure required to compress 500 dm^(3) of air at 1 bar to 200 dm^(3)" at "30^(@)C.

Answer»

SOLUTION :`2.5` BAR
Discussion
22.

Which of the following is a roleof Ca^(+2) in biology

Answer»

`Ca^(+2)` ions are necessaray for blood CLOTHING
`Ca^(+2)` ions are NECESSARY to MAINTAIN regular heart beating
`Ca^(+2)` ions are necessary for muscle contraction
All of these

Solution :Basing on the uses of `Ca^(+2)` in biology it is necessary for blood clotting , maintain regular heart beatng and muscle contraction.
Discussion
23.

What happens when water is added to ethene and propene?

Answer»

Solution :When WATER is added to ETHENE and propene in presence of sulphuric acid gives alcohols, ACCORDING to Markownikoff RULE.
`underset("ethane")(CH_(2) = CH_(2)) + underset("water")(H_(2)O)rarr underset("ethanol(ethyl alcohol)")(CH_(3) - CH_(2)) - OH`
`CH_(3) - underset("propene")(CH = CH_(2)) + underset("water")(H_(2)O) rarr CH_3 - underset("Propan - 2-01[Isopropy alcohol]")underset(OH)underset(|)(CH) - CH_(3)`
Discussion
24.

Which of the following represent a set of nuclephiles ?

Answer»

` BF_(3), H_(2) O, NH^(2-)`
`AlCl_(3), Bf_(3), NH_(3)`
`CN^(-), RCH_(2)^(-) , ROH `
`H^(+), RNH_(3)^(+), : C Cl_(2)`

Solution :N/A
Discussion
25.

What is value of standard hydrogen potential ?

Answer»

SOLUTION :VALUE of standard HYDROGEN potential is ZERO.
Discussion
26.

Which contains more number of molecules?

Answer»

1 mole of CARBON dioxide
4g of hydrogen
6g of helium
33.6 LITRES of oxygen at STP

Answer :B
Discussion
27.

Which of the following is correctly matched

Answer»

`{:("Element",,"Calcium in flame TEST"),(Ca,HARR,"Apple green"):}`
`{:("Element",,"Calcium in flame test"),(MG,harr,"Reddish colour"):}`
`{:("Element",,"Calcium in flame test"),(Na,harr,"Golden YELLOW spangles"):}`
`{:("Element",,"Calcium in flame test"),(Mn,harr,"VIOLET colour"):}`

Solution :`Ca to `Brick red
`Na harr` Golden yellow spanges
Discussion
28.

What is [Ag^(+) ]in a solution made by dissolving both Ag_2 CrO_4 and Ag_2C_2O_4 until saturation is reached with respect to both salts ?[K_(sp)(Ag_2C_2O_4) =2xx 10 ^(-11), K_(sp)(Ag_2CrO_4) - 2xx10 ^(-12))]

Answer»

` 2.80 xx 10^(-4)`
` 7. 6 xx 10^(-5) `
` 6.63 xx 10^(-6)`
` 3 .52 xx 10 ^(-4) `

Solution :` Ag_2CrO_4 hArr 2Ag^(+) +CrO_4^(_2) `
` "" 2X+2Y"" x`
` Ag_2 C_2O_4hArr 2Ag^(+) C_2O_4^(-2)`
` "" 2y+2x"" y`
` (K_(s_(p1)))/(K_(s_(p2)))=(x)/(y)=(2xx 10^(-12))/(2xx 10^(-11)) =0.1`
` 2xx 10 ^(-11) =(2x + 2y)^(2) .y`
` 2 xx 10^(-11)=4.89 y^(3) `
` "" y= 1.6 xx 10^(4)rArr x= 0.16 xx 10^(-14) `
Total ` [AG^(+) ]=2x +2y =3.52 xx 10 ^(-4)`
Discussion
29.

what is the need for second Law of thermodynamics.

Answer»

Solution :(i) The second law of THERMODYNAMICS helps us to predict whether the reaction is feasible or not
(ii) It tells about the direction of the flow of heat.
(iii) It ALSO tells that energy cannot be COMPLETELY converted into equivalent WORK.
Discussion
30.

What do you mean by strength and reactivity of bond ?

Answer»

SOLUTION :Bond STRENGTH MEANS ENERGY REQUIRED to break the bond or bond formation enthalpy. Reactivity means easiness of reaction by broken down one bond.
Discussion
31.

xCr^(+3) + yH_(2)O_(2)+mOH^(-)rarr zCO_(4)^(-2) +nH_(2)O In the above balance the equation , what is the value of x+y+z is :

Answer»


ANSWER :7
Discussion
32.

The species formed in the depletion of ozone layer by chlorofluorocarbons in free radial mechanism is

Answer»

`CLO^(*)`
`F^(*)`
`O_2F_2`
`ClO_2`

ANSWER :A
Discussion
33.

What do you mean by non-stoichiometric hydrides?

Answer»

Solution :Metallic hydrides whose compositions do not CORRESPOND to SIMPLE whole number ratio are CALLED non-stoichiometric hydrides. Hence alkali metals form only stoichiometric.
Discussion
34.

Which of the following is not a periodic property ?

Answer»

Valency
Speficifc HEAT
IONISATION portential
Atomic size

ANSWER :B
Discussion
35.

Writenumberof nucleonsof the following (i) ._(17) ^(35) CI (ii) ._(19)^(40) K

Answer»

SOLUTION :(i) 35 (II) (40)
Discussion
36.

What is the molality of a solution containing 200 mg of urea (molar mass = 60 g mol^(-1)) ?

Answer»

0.0825
0.825
0.498
0.0014

SOLUTION :No. of moles of UREA `= (0.2g)/(("60 G mol"^(-1)))=0.0022` mol
Mass of water in kg `=(40)/(1000)=0.04kg`
Molality of solution `= (("0.0033 mol"))/(("0.04 kg"))`
`= 0.0825 "mol Kg"^(-1)=0.0825`m .
Discussion
37.

While filling electrons in pi2p x and pi 2py the electronic configuration rules that one to be followed is

Answer»

PAULI's EXCLUSION PRINCIPLE
Aufbau principle
Both Pauli's and Hund's
All

Answer :C
Discussion
38.

Unlike sodium carbonate , potassium carbonate cannot be prepared by Solvay ammonia process . Why is it so ?

Answer»

Solution :The reason being that unlike sodium bicarbonate `(NaHCO_(3))` which is SPARINGLY soluble in water , potassium bicarbonate `(KHCO_(3))` is FAIRLY soluble in water . Thus , when `CO_(2)` is passed through AMMONICAL brine , `NaHCO_(3)` gets precipitated while `KHCO_(3)` does not precipitated when `CO_(2)` is passed through and ammoniacal solution of KCL . Hence , `K_(2)CO_(3)` cannot be prepared by Solvay-ammonia process .
Discussion
39.

The stability of +1 oxidation state in aqueous solution is in the order- AlIn>Tl Tl>In>Ga>Al Al>Tl>Ga>In Tl>Al>Ga>In

Answer»

`AL LT GA gt "In gt Tl`
`Tl gt "In" gt Ga gt Al`
`Al gt Tl gt Ga gt "In"`
`Tl gt Al gt Ga gt "In"`

Solution :`Al lt Ga gt "In gt Tl`
Discussion
40.

What is shape of the orbital with (ii) n = 2 and I = 1?

Answer»

Solution :`n = 2 and I = 1`. The orbital is 2P. Its shape is DUMB bell.
Discussion
41.

The reagent with which both acetaldehyde and acetone react easily is

Answer»

TOLLEN's reagent
Schiffs reagent
Grignard reagent
Fehling reagent

Answer :C
Discussion
42.

Write the electronic configuration of the elements given below and predict their period, group, block and also name the class, i.e., representative, transition etc. to which they belong. ""_(74)E

Answer»

SOLUTION :`""_(74)E=[""_(54)Xe], 4f^(14) 5d^(4) 6S^(2)`
Period=6, Block =d, Group =4+2=6
CLASS =Transition element
Discussion
43.

What is dissociation constant of a weak acid (K_(a)).

Answer»

Solution :DISSOCIATION constant of a weak ACID is the ratio of the product of molar CONCENTRATIONS of the products of ionisation to the molar CONCENTRATION of the un-ionised acid medium. For a reaction
`HA+H_(2)OhArrH_(3)O^(+)+A^(-)`
`K_(a)=([H_(3)O^(+)][A^(-)])/([HA])`.
Discussion
44.

Write the net ionic equation for the reaction of potassium dichromate (VI), K_(2)Cr_(2)O_(7) with sodium sulphite, Na_(2)SO_(3), in an acid solution to give chromium (III) ion and the sulphate ion.

Answer»

Solution :Step-1 : The skeletal ionic equation is :
`Cr_(2)O_(7(aq))^(2-)+SO_(3(aq))^(2-)toCr_((aq))^(3+)+SO_(4(aq))^(2-)`
Step-2 : Assign oxidation numbers for Cr and S.
`OVERSET(+6,-2)(Cr_(2)O_(7(aq))^(2-))+overset(+4,-2)(SO_(3(aq))^(2-))tooverset(+3)(Cr_((aq))^(3+))+overset(+6,-2)(SO_(4(aq))^(2-))`
This indicates that the dichromate ion is the oxidant and the sulphite ion is the reductant.
Step-3 : Calculate the increase and decrease of oxidation number, and make them equal :
`overset(+6,-2)(Cr_(2)O_(7(aq))^(2-))+overset(+4,-2)(3SO_(3(aq))^(2-))tooverset(+3)(2Cr_((aq))^(3+))+overset(+6,-2)(3SO_(4(aq))^(2-))`
Step-4 : As the reaction occurs in the acidic medium, and further the ionic charges are not equal on both the sides, add `8H^(+)` on the left to make ionic charges equal
`Cr_(2)O_(7(aq))^(2-)+3SO_(3(aq))^(2-)+8H^(+)to2Cr_((aq))^(3+)+3SO_(4(aq))^(2-)`
Step-5 : Finally, count the hydrogen atoms, and add appropriate number of water molecules (i.e., `4H_(2)O`) on the right to achieve balanced REDOX change.
`Cr_(2)O_(7(aq))^(2-)+3SO_(3(aq))^(2-)+8H_((aq))^(+)to2Cr_((aq))^(3+)+3SO_(4(aq))^(2-)+4H_(2)O_((L))`
Discussion
45.

What is the difference between heats of reaction at constant volume and constant pressure for the reaction N_(2(g)) + O_(2(g)) rarr 2NO_((g))

Answer»


Solution :`DELTA U - Delta H = - Delta NG RT = 0`
Discussion
46.

Which method can be used to find out strength of reductant/oxidant in a solution ? Explain with an example.

Answer»

Solution :STANDARD half cell potential connected with hydrogen ELECTRODE then measure of completely cell potential `(E_("cell")^(@))`.
If value of `E_("cell")^(@)` is positive obtained then half cell acts as reducing agent if value of `E_("cell")^(@)` is negative then half cell as an oxidising agent.
Using of this type of method calculate half cell potential of another cell. Then calculate strength of oxidising agent and reducing agent. Ex. We can calculate standard electrode potential of `Zn^(+2)//Zn` connected with hydrogen half cell.

GIVEN, `E_("cell")^(@)=0.76"volt"`
`E_("cell")^(@)=0.76=E_("cathode")^(@)-E_("anode")^(@)`
`0.76=0-E_("anode")^(@)`
`E_("anode")^(@)=-0.76"volt"`
`E_(Zn^(+2)//Zn)^(@)=-0.76"volt"`
Discussion
47.

Which of the following species is not paramagnetic ?

Answer»

`O_(2)`
`B_(2)`
`NO`
`CO`

SOLUTION :`O_(2) = 16` electrons . M.O. configuration is
` KK sigma (2S)^(2) sigma^(**)(2s)^(2)sigma (2p_(z))^(2) pi (2p_(X))^(2) pi(2p_(y))^(2)`
`pi^(**) (2p_(x))^(1) pi^(**) (2p_(y))^(1) ` (paramagnetic)
`B_(2) = 10 ` electrons. M. O. configuration is
`KK sigma (2s)^(2) sigma^(**)(2s)^(2) pi (2p_(x))^(1) pi(2p_(y))^(1)` (paramagnetic)
NO = 15 electrons .M.O. configuration is
`KK sigma (2s)^(2) sigma^(**)(2s)^(2) sigma (2p_(z))^(2) pi (2p_(x))^(2) pi (2p_(y))^(2)`
`pi^(**)(2p_(x))^(1) `
CO = 14 electrons . M.O. configuration is
`KK sigma (2s)^(2) pi(2p_(x))^(2)pi(2p_(y))^(2) sigma (2p_(z))^(2) sigma ^(**) (2s)^(2)`
(diamagnetic)
Discussion
48.

The thermal dissociation equilibrium of CaCO_(3) (s) is studied under different conditions CaCO_(3) (s) hArr CaO(s) + CO_(2) (g) For this equilibrium , the correct statement (s) is (are)

Answer»

`DELTAH ` is dependent on T
K is INDEPENDENT of the itial amount of `CaCO_(3)`
K is indepdent of the pressure of `CO_(2)` at a given T
`Delta H` is independent of the catalyst, ifany

SOLUTION :`Delta H` is dependent on . `Delta H` varieswith temperature according to Kirchoff's equation . Hence , (a) is correct .
Equilibrium constant of a reactiondependsonly on temperature and is independent of the amount of `CaCO_(3)` Hence, (B) is correct .
For the given reaction , ` K = p_(CO_(2))`at givenThus, K is independent of pressure . Hence , ( c) is incorrect.
Discussion
49.

Which oxide is formed when potassium is heated in e3xcess of oxygen?

Answer»

`K_(2)O`
`KO`
`K_(2)O_(2)`
`KO_(2)`

ANSWER :D
Discussion
50.

using the data give below findout the strongest reducing agent E_(Cr_(2)O_(7)^(2-))//Cr^(3+)^(@)=1.33 V ,E_(Ci_(2)//CI^(@))=1.36 V E_(MnO_(4)^(-)//Mn^(2+)=1.51 V) , E_(Cr^(3+)//Cr)^(@)=-0.74 V

Answer»

`CI^(-)`
`Mn^(2+)`
Cr
`Cr^(3+)`

Solution :Lower the `E^(@)` STRONGER is the reducing AGENT thus Cr is the STRONGEST reducing agent
Discussion