52671 + Interview Questions in Chemistry in Class 11

1.	During setting of plaster of paris which of the following process takes place
Answer» Hydration Hydrolysis CRYSTALLISATION Evoluation of heat Solution :During the setting of PLASTER of paris, hydration, hydrolysis and crystallisation PROCESS are observed.

Discussion

2.	During setting of Plaster of Paris. Its volume
Answer» Decreases Increases Remains the same FIRST increases and then decreases Solution :During the SETTING of PLASTER of paris HYDRATION will TAKES place. So volumeincreases

Discussion

3.	During reversible adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature.The ratio (C_(p))/(C_(v)) for the gas is
Answer» `3/2` `7/2` `5/3` `9/7` Solution :According to the PROBLEM, `P infty T^(3)` or `P = KT^(3) or PT^(-3) = K` ....(i) For a reversible adiabatic process. `T^(GAMMA) P^(1-gamma) = k` `(gamma)/(T^(1 - gamma)) P = k`...(II) Compairing eq.(i) and (ii) `(gamma)/(1 - gamma) = -3` or `gamma = -3 + 3gamma` or `-2gamma = -3 or gamma = 3/2`.

Discussion

4.	During pyrolysis of alkanes, C - C bonds rather than C – H bonds are Preferentially broken because
Answer» the activation energy of C - C bonds is very high C-C bonds are weaker than C – H bonds the polarity of C – H bonds is LOWER than that of bonds all the THREE above Solution :C-C bonds are weaker than C-H bonds

Discussion

5.	During photosynthesis H_2O is __________.
Answer» ANSWER :Oxidised

Discussion

6.	During estimation of nitrogen present in an organic compound by Kjeldahl’s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of 1 M H_(2)SO_(4). Find out the percentage of nitrogen in the compound.
Answer» SOLUTION :`N = 56%`

Discussion

7.	During nitrogen estimation present in an organic compound by Kjeldahl.s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl.s estimation of nitrogen neutralised 10 ml of 1 M H_(2)SO_(4). Find the percentage of nitrogen in the compound.
Answer» SOLUTION :`N = 56%`

Discussion

8.	During neutralisation of an acid by a base, the end point refers for the completion of reaction. The detection of end point in acid -base neutralisation is usually made by an acid-base indicator. An acid-base indicator is itself a weak acid (Phenolphthlein) or a weak base (Mrthyl orange). At about 50% ionisation which depends on the medium, the anion furnished by an indicator (acid) or cation furnished by indicator (basic) imparts its characteristic colour to solution at point. For example phenolphthalein, the dissociation is underset("Colourless")(H In hArr H^(+))+underset("Pink")(In^(-)), K_(H In)= ([H^(+)][In^(-)])/([H In]) favoured in presence of alkali and pink colour of phenolphalein ion is noticed as soon as the medium changes to alkaline nature. The end point of acid-base neutralisation not necessarily coincides with equivalent point but it is closer and closer to equivalence point. Also at equivalence point of acid-base neutralisation pH is not necessarliy equal to 7. The indicator phenolphalein is a tautomeric mixture of two forms as given below: Which of the following statements are correct ? (1) The form I is referred as quinonoid form and is deeper in colour (2) The form I is referred as quinonoid form and is lighter in colour (3) The form II is more stable in alkaline solution (4) The change in pH form acidic to alkaline solution brings in the more and more conversion of I form to II form (5) The form I is more stable in acidic medium
Answer» `1,2,3,4` `1,3,4,5` `3,4,5` `2,3,4,5` SOLUTION :All are FACTS.

Discussion

9.	During neutralisation of an acid by a base, the end point refers for the completion of reaction. The detection of end point in acid -base neutralisation is usually made by an acid-base indicator. An acid-base indicator is itself a weak acid (Phenolphthlein) or a weak base (Mrthyl orange). At about 50% ionisation which depends on the medium, the anion furnished by an indicator (acid) or cation furnished by indicator (basic) imparts its characteristic colour to solution at point. For example phenolphthalein, the dissociation is underset("Colourless")(H In hArr H^(+))+underset("Pink")(In^(-)), K_(H In)= ([H^(+)][In^(-)])/([H In]) favoured in presence of alkali and pink colour of phenolphalein ion is noticed as soon as the medium changes to alkaline nature. The end point of acid-base neutralisation not necessarily coincides with equivalent point but it is closer and closer to equivalence point. Also at equivalence point of acid-base neutralisation pH is not necessarliy equal to 7. Which of the following statements are correct ? (1) Phenolphthalein is not a good indicator for weak alkali titrations (2) Phenolphthalein does not give pink colour with weak alkalies as NH_(4)OH (3) Phenolphthalein is an acid indicator and imparts colour in basic medium (4) Phenolphthalein isa basic indicator and imparts colour in basic medium (5) Phenolphthalein furnishes coloured cation
Answer» `1,2,4,5` `1,2,3,4` `1,3` `2,4` SOLUTION :`HPh HARR H^(+) + UNDERSET("Pink")(Ph^(-))`

Discussion

10.	During nitrogen estimation present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.5 g of the compound in Kjeldahl's estimation of nitrogen neutralised 10 ml of 1 M H_(2)SO_(4). Find the percentage of nitrogen in the compound.
Answer» SOLUTION :`N = 56%`

Discussion

11.	During monoalkylation of Benzene with CH_3Cl in presence of anhydrous AlCl_3, an excess ofC_6H_6 must be used because this will.
Answer» Increase the CHANCE for collision between `CH_3^(+) and C_6H_6` Decrease the collision betweeen `CH_3^(oplus) and C_6H_5CH_3` both a and b Decrease the chancefor collision between `CH_3^(oplus) and C_6H_6` SOLUTION :SINCE `CH_3` group is an activating group , the mono methylated product is more REACTIVE than benzene itself leading to formation of `C_6H_4(CH_3)_2 and C_6H_3(CH_3)_3`. Excess of `C_6H_6` is used to increase the chance for collision between andto minimize collision between `CH_2^(oplus) and C_6H_5CH_3`.

Discussion

12.	During millotary operation hydrogen is generally obtained by the action of H_(2)O on
Answer» `BeH_(2)` `CaH_(2)` `NaBH_(4)` `LiA//H_(4)` Solution :`CaH_(2)` is called hydrolit `CaH_(2)+2H_(2)O to Ca(OH)_(2)+2H_(2)uarr`

Discussion

13.	During military operation hydrogen is generally obtained by the cation of water on
Answer» `BeH_(2)` `CaH_(2)` `NaBH_(4)` `LiA//H_(4)` SOLUTION :`CaH_(2)` is CHEAP and is easy to HANDLE.

Discussion

14.	During its reaction with Cl_(2) , X acts as
Answer» OXIDANT REDUCTANT ACID base Answer :B

Discussion

15.	During isothermal expansion of an ideal gas, its internal energy
Answer» Decreases Increases May increase or decrease Remains unchanged Solution :Isothermal `RARR DELTA E = 0`

Discussion

16.	During hydrolysis of P_(4) O_(10), products is/are:
Answer» <P>Tetrametaphosphoric acid `(H_(4) P_(2)O_(12))` Hypopho!iphoric acid `(H_(4)P_(2)O_(6))` Pyrophosphoric acid `(H_(4)P_(2)O_(7))` Tetrapolyohosphoric acid `(H_(6)P_(4)O_(13))` Answer :A::C::D

Discussion

17.	During hydrate formation from aqueous solution, water can be associated in different forms. Indicate the wrong combination.(i) Coordinated water -[Cr(H_(2)O)_(6)]^(3+)3CI^(-) (ii)Interstitial water -BaCI_(2).2H_(2)O(iii)Hydrogen bonded water -[Cu(H_(2)O)_(4)]^(2+)SO_(4)^(2-). H_(2)O
Answer» (i) (II) (III) NONE of these. Solution :All COMBINATIONS are CORRECT.

Discussion

18.	During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results ?
Answer» COLUMN CHROMATOGRAPHY Solvent extraction Distillation THIN layer chromatography Solution :The CONSTITUENTS of ink can be identified with the help of thin layer chromatography.

Discussion

19.	During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results?
Answer» Column chromatography solvent extraction Distillation Thin LAYER chromatography Solution :Thin layer chromatography METHOD can give the BEST RESULTS as it can be used to separate the COMPONENTS present ina small amount of the sample.

Discussion

20.	During hearing a court case, the judge suspected that some changes in the original documents has been deliberately made. He asked the forensic department to check the ink used at two different places. After reading the above passage, answer the following questions : (i) What technique do you think can be ued to ascertain whether the ink used at two places was the same or different ? (ii) What is the principle of this technique appiled ?
Answer» Solution :(i) This layer chromatography (TLC) can be used to identify the components in a small sample such as ink. (ii) This technique is based upon the principle of adsorption. To carry out this technique, a glass or a PLASTIC side coated with a suitable adsorbent usually silica GEL is taken. Two pencil lines are DRAWN on this plate-one little above the BOTTON and the other near the top of the plate. With the help of a suitable solvent, the samples of ink used at two different places are applied on the pencil line near the botom of the TLC plate little away from each other. The plate is then placed in a closed jar containing a suitable solvent and allowed to stay till the solvent reaches the top pencil line. The plate is then removed from the jar and dried in air. If both the samplex of ink show a single SPOT on the plate at the same height from the bottom then the same ink is used and if single spots are either seen at different heights or one sample shows a single spot while the other sample shows two or more spots, then different inks are used.

Discussion

21.	During hearing of a court case, the judge suspected that some changes in the decuments had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results ?
Answer» Column chromatography Solvent extraction Distillation Thin layer chromatography Solution :This layer chromatography is used to SEPARATE the COMPONENTS present in a SMALL amount of the SAMPLE.

Discussion

22.	During halogenation of alkanes the halogens and alkane show a specific treand. Which of the following statements is not correct?
Answer» The reactivity of halogens is in the order `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)` For a GIVEN halogen the reactivity of hydrocarbon is in the order of `3^(@) gt 2^(@) gt 1^(@)` Bromine is less reactive than chlorine towards a particular alkane. On chlorination monosubstituted product is FORMED while on bromination disubstituted products are formed. Solution :Number of monohalogen products of alkane depends upon the number of different types of replaceable hydrogen ATOMS in the alkene.

Discussion

23.	During expansion of a gas into vaccum (P_("ext")=0), Work done is zero if the process is (A) Reversible (B) Irreversible (C ) Isothermal
Answer» A,B & C are true A,B,&C are false A & C are true B & C are false Answer :A

Discussion

24.	During exchange process the energy is ______.
Answer» RELEASED GAINED Returned refuse ANSWER :A

Discussion

25.	During estimation of nitrogen present in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5 g of the compound neutralized 10 mL of 1 M H_(2)SO_(4). Find the percentage of nitrogen in the compound.
Answer» SOLUTION :Volume of `H_(2)SO_(4)` used = 10 mL of `1 M H_(2)SO_(4)` Now`H_(2)SO_(4) + 2NH_(3) rarr (NH_(4))_(2)SO_(4)` Now 1 mole of `H_(2)SO_(4)` reacts with 2 moles of `NH_(3)`. `:.` 1- mL of `1M H_(2)SO_(4) -= 20 mL` of `1 M NH_(3)` Now 1000 mL of `1 M NH_(3)` contains `N = 14 g :. 20 mL` of `1 M NH_(3)` will contain `N =(14)/(1000) xx 20` But this amount of nitrogen is present in 0.5 g of the organic compound. `:.` Percentage of nitrogen `= (14 xx 20)/(1000) xx (100)/(0.5) = 56.0`. Alternatively, % age of `N = (1.4 xx "Vol. of acid used" xx "BASICITY of acid" xx "Molarity of acid")/("Mass of the SUBSTANCE taken") = (1.4 xx 10 xx 2 xx 1)/(0.5) = 56.0`

Discussion

26.	During estimation of nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.5g of the compound in Kjeldahl's estimation of nitrogen, neutralized 10 mL of 1M H_(2)SO_(4). Find out the percentage of nitrogen in the compound
Answer» Solution :Mass of compound = m= 0.5g 10 ML 1M `H_(2)SO_(4)` = 20 mL 1M `NH_(3)` 100ML `1M NH_(3)`= 14 nitrogen `:.` 20 mL `1M NH_(3) = (20 mL xx 14g)/(1000 mL)` = 0.28g nitrogen `:. % N = ("weight of " N xx 100)/("mass of compound")` `= (0.28 xx 100)/(0.5) = 56%`

Discussion

27.	During electrolytic refining of copper some metals , present as impurity settle as anode mud. These are
Answer» SN and Ag Pb and Zn Ag and Au Fe and Ni Solution :N//A

Discussion

28.	During electrolytic refining of copper, some metals present as impurity settle as anode mud. These are
Answer» SN and Ag Pb and Zn Ag and Au Fe and NI SOLUTION :N//A

Discussion

29.	During delocalization, which statement is INCORRECT :
Answer» Net charge remains same Number of PAIRED electrons ramains same Number of unpaired electrons remain same Energy of RESONATING STRUCTURES always remains same Answer :D

Discussion

30.	During dehydration of alcohols to alkenes by heating with conc. H_(2)SO_(4), the initial step is
Answer» FORMATION of an ester protonation of ALCOHOL molecule formation of carbocation elimination of water Answer :B

Discussion

31.	During decomposition of H_(2)O_(2), its undergoes
Answer» OXIDATION Reduction Hydrolysis DISPROPORTIONATION ANSWER :D

Discussion

32.	During day time plants, absorb
Answer» CO `N_(2)` `CO_(2)` `O_(2)` SOLUTION :PLANTS absorb `.CO_(2).` gas.

Discussion

33.	During complete combustion of one mole of butane, 2658kJ of heatis released. The thermochemical reaction for above changeis
Answer» `2C_(4)H_(10)(G)+13O_(2)(g) rarr 8 CO_(2)(g) +10 H_(2)O(l) Delta_(c) H=- 2658.0 kJ mol^(-1)` `C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(g) Delta_(c)H=- 1329.0 kJ mol^(-1)` `C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(l) Delta_(c)H=- 2658.0 kJ mol^(-1)` `C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(l) Delta_(c)H=+ 2658.0 kJ mol^(-1)` Solution :We have to take the combustion of one mole of `C_(4)H_(10)` and `Delta_(c) H`should be `-ve` and have a value of 2658 kJ mol`^(-1)`

Discussion

34.	During complete combustion of one mole of butane, 2658 kJ of heat is released. The thermochemical reaction for above change is
Answer» `2C_(4) H_(10(g))+ 13O_(2(g)) to 8CO_(2(g)) + 10H_(2) O_((l)) , Delta_(c) H= - 2658.0 "kJ mol"^(-1)` `C_(4) H_(10(g))+ (13)/(2)O_(2(g)) to 4CO_(2(g)) + 5H_(2) O_((l)) , Delta_(c) H= - 1329.0 "kJ mol"^(-1)` `C_(4) H_(10(g))+ (13)/(2)O_(2(g)) to 4CO_(2(g)) + 5H_(2) O_((l)) , Delta_(c) H= - 2658.0 "kJ mol"^(-1)` `C_(4) H_(10(g))+ (13)/(2)O_(2(g)) to 4CO_(2(g)) + 5H_(2) O_((l)) , Delta_(c) H= + 2658.0 "kJ mol"^(-1)` SOLUTION :GIVEN that, the complete combustion reaction of one MOLE of butane is represented thermodynamically as : `C_(4) H_(10(g)) + (13)/(2) O_(2(g)) to 4CO_(2(g)) to 4CO_(2(g)) + 5H_(2) O_((l))` We have to take the combustion of one mole of `C_(4) H_(10) and Delta_( C) H` should be negative and have a value of 2658 `"kJ mol"^(-1)`

Discussion

35.	During complete combustion of one mole of butane, 2658 kJ of heat is released.The termochemical reaction for above change is
Answer» `2C_(4)H_(10)(g) + 13O_(2)(g) to 8CO_(2)(g) + 10H_(2)O(l)`, ` Delta_(c)H = -2658.0 kJ"mol"^(-1)` `C_(4)H_(10)(g) + 13/2O_(2)(g) to 4CO_(2)(g) + 5H_(2)O(g)` `Delta_(c)H = -1329.0 kJ"mol"^(-1)` `C_(4)H_(10)(g) + 13/2 O_(2)(g) to 4CO_(2)(g) + 5H_(2)O(l)` `Delta_(c)H = -2658.0 kJ"mol"^(-1)` `C_(4)H_(10)(g) + 13/2O_(2)(g) to 4CO_(2)(g) + 5H_(2)O(l)` `Delta_(c)H = + 2658.0 kJ"mol"^(-1)` ANSWER :C

Discussion

36.	During chemical bond formation the potential energy of the bonding atoms decreases. According to VBT bond strength depends on extent of over lapping. Shapes and bond angles of the molecules were explained by VSEPR theory. This theory explains the Geometry of the molecules based on the repulsions among the valance shell electron pairs. As number of lone pairs increases repulsions increases apd the shape is altered accordingly. Katio of lone pairs and bond pair electrons in H_(2) O molecule respectively
Answer» `2:3` `1:1` `1:3` `1:2` ANSWER :B

Discussion

37.	During chemical bond formation the potential energy of the bonding atoms decreases. According to VBT bond strength depends on extent of over lapping. Shapes and bond angles of the molecules were explained by VSEPR theory. This theory explains the Geometry of the molecules based on the repulsions among the valance shell electron pairs. As number of lone pairs increases repulsions increases apd the shape is altered accordingly. AB_(4) E_(2) type of molecule with square planar shape is
Answer» `CIF_(3)` `SF_(4)` `H_(2)O` `XeF_(4)` ANSWER :D

Discussion

38.	During change of O_(2)" to " O_(2)^(-) ion, the electron adds on which one of the following orbitals ?
Answer» `PI` ORBITALS `SIGMA` - orbitals `pi^()` orbitals `sigma^()`-orbitals ANSWER :C

Discussion

39.	During bottlinga carbonated beverage was made by saturatingflavoured water at 0^(@)C with CO_(2) at a pressure of 4.0 atm. Later ,the bottle was opened and the softdrink allowed to come to equilibrium at 25^(@)C with air containing CO_(2) at a pressure of 4.3xx10^(-4) atm. Find the concentration of CO_(2) in the freshly bottled sodaand in the soda after it hadstood open and come to the equilibrium. The Henry's law constants for aqueous solutions fo CO_(2) are : at 0^(@)C, K =7.7xx10^(-2) "mol " L^(-1) "atm"^(-1) "and at" 25^(@)C, k=3.2xx10^(-2) " mol " L^(-1) " atm "^(-1).
Answer» Solution :According to Henry'sLaw , C `PROP P " or " C=kp,`where C is the concentration of the gas inthe solution, P is the partialpressure of the gas and K is a constant. (i) For freshly BOTTLED soft drink at `0^(@)C` `p=4.0 atm, k = 7.7 XX 10^(-2) mol L^(-1) atm^(-1)` `:.C= kp = (7.7 xx 10^(-2) mol L^(-1) atm^(-1) ) xx (4.0 atm )=0.31 mol L^(-1)` (ii) For opened soft dring at `25^(@)C` `p=4.0 xx 10^(-4) atm, k = 3.2 xx 10^(-2) mol L^(-1) atm^(-1)` `:.C=kp =(3.2 xx 10^(-2) mol L^(-1) atm^(-1)) xx (4.0 xx 10^(-4) atm) =1.3 xx 10^(-5) mol L^(-1)`

Discussion

40.	During an educational trip, a student of botany saw a beautiful lake in a village. She collected man plants from that area. She noticed that villagers were washing clothes around the lake and at some places waste material from houses was destroying its beauty. After few years, she visited the same lake again. She was surprised to find that the lake was covered with algae, stinking smell was coming out and its water has become unusable. Can you explain the reason for this condition of the lake ?
Answer» Solution :The inflow of the WASTE material from houses and fertilizers of the plants and the entry of detergents into Water results in the INCREASE of phosphate into water. As a result, formation of algae is accelerated which covers the water surface and CONCENTRATION of DISSOLVED oxygen decreases, i.e. process called eutrophication OCCURS

Discussion

41.	During an educational trip, a student of botany saw a beautiful lake in a village. She collected many plants from that area. She noticed that villagers were washing clothes around the lake and at some places waste material from houses was destroying its beauty. After few years, she visited the same lake again. She was surprised to find that the lake was covered with algae, stinking smell was coming out and its water had become unusable. Can you explain the reason for this condition of the lake ?
Answer» Solution :Disposing of waste material and washing clothes in lake WATER makes the water rich in nutrients like PHOSPHATE. It enhances algae growth. Such profuse algal growth COVERS the water surface which reduces oxygen concen-tration in water. This lead to anaerobic conditions with accumulation of dead and decaying water animals, THUS, leaving the water with stinking smell and making it unusable.

Discussion

42.	During adsorption of a gas on the surface of a solid which of the following is true
Answer» `DeltaG LT 0, DeltaS gt 0, DeltaH LT0` `DELTA G gt 0,Delta H lt 0, Delta S lt 0` `Delta G lt 0, Delta H lt 0, Delta S lt 0` `Delta G lt 0, Delta H lt 0, Delta S gt 0` Answer :C

Discussion

43.	During adiabatic process, the system ........ .
Answer» GAINS energy LOSES energy loses mass neither gains nor loses energy Answer :D

Discussion

44.	During adiabatic expansion of an ideal gas, 100J work is done, DeltaE of system is
Answer» ZERO 100J 200J `-100J` ANSWER :B

Discussion

45.	During a process work equivalent to 400J is done on a system, which gives out of 125J of energy. The change in internal energy is
Answer» 525J 375J 275J 200J ANSWER :C

Discussion

46.	Duralumin is an alloy of
Answer» Al and MG Mg and Cu AI, Mg, MN and Cu Al and Cu SOLUTION : Duralumin is an alloy of Al+Mg+Mn+Cu

Discussion

47.	Dunstan's test is used for identification of
Answer» Acetone Ethanol GLYCEROL Glycol Solution :Glycerol

Discussion

48.	In the Duma's method for the estimation of nitrogen in an organic compound, nitrogen is determined in the form of
Answer» `NH_(3)` `N_(2)` NACN `(NH_(4))_(2)SO_(4)` Answer :B

Discussion

49.	Due to which depletion of ozone layer take place?
Answer» CFC `O_2` COC FCC Solution :CFC

Discussion

50.	Due to pressence of an unpaired electron, free radicals are…..
Answer» CHEMICALLY reactive chemically inactive anions cations Answer :A

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

During setting of plaster of paris which of the following process takes place

During setting of Plaster of Paris. Its volume

During reversible adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature.The ratio (C_(p))/(C_(v)) for the gas is

During pyrolysis of alkanes, C - C bonds rather than C – H bonds are Preferentially broken because

During photosynthesis H_2O is __________.

During estimation of nitrogen present in an organic compound by Kjeldahl’s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of 1 M H_(2)SO_(4). Find out the percentage of nitrogen in the compound.

During nitrogen estimation present in an organic compound by Kjeldahl.s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl.s estimation of nitrogen neutralised 10 ml of 1 M H_(2)SO_(4). Find the percentage of nitrogen in the compound.

During nitrogen estimation present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.5 g of the compound in Kjeldahl's estimation of nitrogen neutralised 10 ml of 1 M H_(2)SO_(4). Find the percentage of nitrogen in the compound.

During monoalkylation of Benzene with CH_3Cl in presence of anhydrous AlCl_3, an excess ofC_6H_6 must be used because this will.

During millotary operation hydrogen is generally obtained by the action of H_(2)O on

During military operation hydrogen is generally obtained by the cation of water on

During its reaction with Cl_(2) , X acts as

During isothermal expansion of an ideal gas, its internal energy

During hydrolysis of P_(4) O_(10), products is/are:

During hydrate formation from aqueous solution, water can be associated in different forms. Indicate the wrong combination.(i) Coordinated water -[Cr(H_(2)O)_(6)]^(3+)3CI^(-) (ii)Interstitial water -BaCI_(2).2H_(2)O(iii)Hydrogen bonded water -[Cu(H_(2)O)_(4)]^(2+)SO_(4)^(2-). H_(2)O

During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results ?

During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results?

During hearing of a court case, the judge suspected that some changes in the decuments had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results ?

During halogenation of alkanes the halogens and alkane show a specific treand. Which of the following statements is not correct?

During expansion of a gas into vaccum (P_("ext")=0), Work done is zero if the process is (A) Reversible (B) Irreversible (C ) Isothermal

During exchange process the energy is ______.

During estimation of nitrogen present in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5 g of the compound neutralized 10 mL of 1 M H_(2)SO_(4). Find the percentage of nitrogen in the compound.

During estimation of nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.5g of the compound in Kjeldahl's estimation of nitrogen, neutralized 10 mL of 1M H_(2)SO_(4). Find out the percentage of nitrogen in the compound

During electrolytic refining of copper some metals , present as impurity settle as anode mud. These are

During electrolytic refining of copper, some metals present as impurity settle as anode mud. These are

During delocalization, which statement is INCORRECT :

During dehydration of alcohols to alkenes by heating with conc. H_(2)SO_(4), the initial step is

During decomposition of H_(2)O_(2), its undergoes

During day time plants, absorb

During complete combustion of one mole of butane, 2658kJ of heatis released. The thermochemical reaction for above changeis

During complete combustion of one mole of butane, 2658 kJ of heat is released. The thermochemical reaction for above change is

During complete combustion of one mole of butane, 2658 kJ of heat is released.The termochemical reaction for above change is

During change of O_(2)" to " O_(2)^(-) ion, the electron adds on which one of the following orbitals ?

During adsorption of a gas on the surface of a solid which of the following is true

During adiabatic process, the system ........ .

During adiabatic expansion of an ideal gas, 100J work is done, DeltaE of system is

During a process work equivalent to 400J is done on a system, which gives out of 125J of energy. The change in internal energy is

Duralumin is an alloy of

Dunstan's test is used for identification of

In the Duma's method for the estimation of nitrogen in an organic compound, nitrogen is determined in the form of

Due to which depletion of ozone layer take place?

Due to pressence of an unpaired electron, free radicals are…..