52671 + Interview Questions in Chemistry in Class 11

1.	On heating C_(2)H_(2) in red hot copper tube, the compound formed is :
Answer» Ethylene Benzene Ethane Methane Answer :B

Discussion

2.	On heating ammonium dichromate and barium azide separately we get
Answer» `N_(2)` in both CASES `N_(2)` with ammonium dichromate and NO with barium azide `N_(2)O` with ammonium dichromate and `N_(2)` with barium azide `N_(2)O` with ammonium dichromate and `N_(2)O)` with barium azide Solution :`(NH_(4))_(2)Cr_(2)O_(7)overset(Delta)toN_(2)+Cr_(2)O_(3)+4H_(2)O,BA(N_(3))_(2)overset(Delta)toBa+3N_(2)`

Discussion

3.	On heating, a mixture of potassium cyanate and ammonium chloride gives :
Answer» Urea Methanamide Ethanamide Ethanamine Solution :Urea is formed `KCNO+NH_(4)CL overset("Heat")(rarr) NH_(3)CNO+KCl` `NH_(4)CNO overset("Heat")(rarr) UNDERSET("Urea")(NH_(2)CONH_(2))`

Discussion

4.	On heating a gas, pressure and volume both become double. By lowering temperature, one fourth of initial number of moles of air are taken in tomaintain the double pressure and volume. Calculate by what fraction, the temperature must have been raised finally.
Answer» Solution :INITIALLY,`P_(1)=P,V_(1)=V`, Then after heating,`P_(2)=2P, V_(2)=2V` `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)) :. (PV)/(T_(1))=(2Pxx2V)/(T_(2)) "or" T_(2)=4T_(1)` New P and V are kept constant (double values) when air is taken in. If initialy, npo of moles of air `(n_(1))=n` Then now no. of moles `=n+(n)/(5)=(5)/(4)n` Now TEMPERATURE is raised from 4 `T_(1)` to `T_(f)` (final temperature) ApplyingPV=nRT As P and V are kept constant, `n_(i)T_(i)=n_(f)T_(f)` `:. ""nxx4T_(1)=(5)/(4)nxxT_(f)"or" T_(f)=(16)/(5)T_(1)`

Discussion

5.	On heating a liquid, its surface tension
Answer» Increases DECREASES REMAINS same Is reduced to ZERO ANSWER :B

Discussion

6.	On heating 4.9 g of KClO_(3) , it shows a weight loss of 0.384 g . What percentage of KClO_(3) has decomposed ?
Answer» `83.6 %` `75 % ` `41.8 %` `20 %` ANSWER :D

Discussion

7.	On heating 8 moles each of Li_(2)CO_(3) and K_(2)CO_(3), how many moles of CO_(2) evolved
Answer» Solution :On HEATING olnly `Li_(2)CO_(3)` DECOMPOSED `Li_(2)CO_(3)rarrLi_(2)O+CO_(2)` `k_(2)CO_(3)` is thermally stables does not undergo DECOMPOSTION

Discussion

8.	On heating 0.32g of an organic compound with concentrated nitric acid and barium chloride, 0.932g barium sulphate was obtained. Calculate the percentage of sulphur in the given compound.
Answer» Solution :Mass of organic compound, `W = 0.32g` Mass of barium sulphate, `W_(1) = 0.932g` `underset(233g)(BaSO_(4))-= underset(32g)(S)` Percentage of sulphur `= (32)/(233) XX (W_(1))/(W) xx 100` `= (32)/(233) xx (0.932)/(0.32) xx 100 = 40%`

Discussion

9.	On heating 0.2g of an organic compound with a mixture of barium chloride and nitric acid, 0.466 g of barium sulphate was obtained. Calculate the percentage of sulphur
Answer» Solution :WEIGHT of substance = w = 0.2g , weight of barium SULPHATE `= w_(4) = 0.466g` weight PERCENTAGE of sulphur = `(w_(4)XX32XX100)/(wxx233) =(0.466xx32xx100)/(0.2xx233) = 32%`

Discussion

10.	On halogenation, an alkane gives only one monohalogenated product. The alkane may be:
Answer» 2-methyl butane 2,2-dimethyl propane CYCLOPENTANE both (2) and (3) SOLUTION :alkane properties

Discussion

11.	On going down a main subgroup in the periodic table (example Li to Cs in IA or Be to Ra in IIA) the expected trend of change in atomic radius is a
Answer» CONTINUOUS INCREASE Continuous DECREASE An increase FOLLOWED by decrease A decrease followed by increase ANSWER :A

Discussion

12.	On exposure to air, alkali metals get tranished due to formation of oxides, hydroxides and carbonates on their surface. When heated in air or oxygen they burn vigourously forming different types of oxides depending upon the nature of the metal.The formation and stability of these metals can be explained on the basis of size of alkali metal ion and the anion. Peroxides are colourless, while superoxides are coloured. The normal oxides are basic while peroxides and superoxides act as oxidising agents. Na_(2)O_(2) has light yellow colour. This is due to
Answer» Presence of TRACES of `NaO_(2)` Presence of unpaired electron in the molecule. Presence of traces of `Na_(2)O`. NONE of the above. Solution :Factual STATEMENT.

Discussion

13.	On exposure to air, alkali metals get tarnished due to formation of oxides, hydroxides and carbonates on their surface. When heated in air or oxygen they burn vigorously forming different types of oxides depending upon the nature of the metal. The formation and stability of these metals can be explained on the basis of size of alkali metal ion and the anion. Peroxides are colourless, while superoxides are coloured. The normal oxides are basic while peoxides and superoxides act as oxidising agents Na_(2)O_(2) has light yellow colour. This is due to
Answer» PRESENCE of unpaired ELECTRON in the moleucle Presence of traces of NaO2 Presence of traces of Na2O All Solution :DUE to presence of unpaired electron `Na_(2)O_(2)` has light yellow coloru

Discussion

14.	On exposure to air, alkali metals get tarnished due to formation of oxides, hydroxides and carbonates on their surface. When heated in air or oxygen they burn vigorously forming different types of oxides depending upon the nature of the metal. The formation and stability of these metals can be explained on the basis of size of alkali metal ion and the anion. Peroxides are colourless, while superoxides are coloured. The normal oxides are basic while peoxides and superoxides act as oxidising agents On heating in excess of oxygen, lithium gives
Answer» `Li_(2)O` LIO `Li_(2)O_(2)` `LiO_(2)` Solution :On heatingin EXCESS of air LI forms OXIDE `4Li+O_(2)rarr2Li_(2)O_(s)`

Discussion

15.	On electrolysis of sodium chloride ....... gas is produce on anode.
Answer» `O_(2)` `Cl_(2)` `H_(2)` `N_(2)` Answer :B

Discussion

16.	On dividing 0.25 by 22.1176, the actual answer is 0.011303. The correctly reported answer will be
Answer» 0.011 0.01 0.0113 0.013 Answer :A

Discussion

17.	On dissolving sugar in water at room temperature solution feels cool to touch. Under which of the following cases dissolution of sugar will be most rapid ?
Answer» Sugar crystals in cold WATER Sugar crystals in HOT water POWDERED sugar in cold water Powdered sugar in hot water ANSWER :D

Discussion

18.	On dissolving moderate amount of sodium metal in liquid NH_(3) at low temperature , which one of the following does not occur ?
Answer» BLUE coloured SOLUTION is obtained `Na^(+)` IONS are formed in the solution Liquid ammonia becomes a good CONDUCTOR of ELECTRICITY Liquid ammonia remains diamagnetic . Solution :It is not liquid ammonia but the solution which becomes good conductor of electricity .

Discussion

19.	On dissolving moderate amount of sodium metal in liquid NH_(3)at low temperature, which one of the following does not occur
Answer» Blue coloured solution is obtained. Nations are formed in the solution. LIQUID `NH_(3)`becomes good CONDUCTOR of clectricity Liquid ammonia remains diamagnetic. Solution :Due to free ELECTRON liquid ammonia becomes paramagnetic.

Discussion

20.	On dissolving Aluminum hydroxide in excess of alkali produces ...... ions.
Answer» `[Al(OH)_(4)]^(-)` `Al(OH)_(3)` `[Al(OH)_(5)]^(-)` `[Al_(2)(OH)_(4)]^(-)` ANSWER :A

Discussion

21.	On dissolving 2.0 g of a metal in sulphuric acid, 4.51 grams of the metal sulphate was formed. The specific heat of the metal is 0.057 cal/g. What is the valency of the metal and its exact atomic weight?
Answer» SOLUTION :LET the formula of the metal sulphate be `M_(2)(SO_(4))_(x)` ( x being the valency of the metal M) `:. X xx` moles of M = `2xx ` moles of `SO_(4)^(-2)` or `x xx "(wt.of M")/("ATOMIC weight of M ") = 2 xx ("wt. of sulphate ion ")/(" ionic wt. of "SO_(4)^(2-))` `x xx (2)/(112) = 2 xx((4.51-2))/(96)` `x= 2.85 =3` { at wt. of M = `(6.4)/(0.057) =112 ` (APPROX).} The valency is, therefore, 3. Now, SUBSTITUTE the valency of x as 3 in eqn. (1) again to calculate the accurate value of the atomic weight of the metal.

Discussion

22.	On dissolving 1 mole of each of the following acids in one litre water, the acid which does not give a solution of strength 1 N is :
Answer» HCl `HClO_(4)` `HNO_(3)` `H_(3)PO_(4)` SOLUTION :N//A

Discussion

23.	On dipping a loop of platinum wire in borax paste and heating the wire subsequently in hotoxidising flame, produces a colourless, transparent, glass-like bead. The bead contains:
Answer» `H_(3)BO_(5)` `NaBO_(2)` `B_(2)O_(3)` `Na_(2)B_(4)O_(7)` ANSWER :B::C

Discussion

24.	On diluting a buffer solution, its pH :
Answer» is increased is decreased remains CONSTANT will CHANGE which be PREDICTED UNLESS dissociation of its weak acid (or base )is provided. Solution :`pH =pK_a +log ""([S])/([A])` on dilution. [S] and [A] DECREASE bysame factor

Discussion

25.	On condensation of BeCl_(2)vapor it forms BeCl_(6)dimeric with coordination number of....
Answer» TWO FOUR THREE SIX SOLUTION :

Discussion

26.	On complete combustion, 0.246g of an organic compound gave 0.198g of CO_(2) and 0.1014g of H_(2)O. The ratio of carbon and hydrogen atoms in the compound is:
Answer» `1:3` `1:2` `2:5` `2:7` ANSWER :C

Discussion

27.	On complete combustion, 0.246g of an organic compound gave 0.198 g of carbon dioxide and 0.1014 g of water. Determine the percentage composition of carbon and hydrogen in the compound.
Answer» Solution :Here, mass of the organic substance taken = 0.246 g Mass of `CO_(2)` FORMED = 0.198 g Mass of `H_(2)O` formed = 0.1014 g (i) Percentage of Carbon. One mole of `CO_(2)` contains one gram atom of carbon. i.e. 44 g of `CO_(2)` contain carbon = 12g `:.` 0.198 g `CO_(2)` will contain carbon `= (12)/(44) XX 0.198 g` This is the mass of carbon present in 0.246 g of the compound. `:.` % age of carbon in the compound `= (12)/(44) xx 0.198 xx (100)/(0.246) = 21.95` (II) Percentage of Hydrogen One mole of `H_(2)O` contains two gram atoms of hydrogen. i.e. 18G of `H_(2)O` contain hydrogen = 2g `:.` 0.1014 g of `H_(2)O` will contain hydrogen `= (2)/(18) xx 0.1014` This is the mass of hydrogen present in 0.246g of the compound. `:.` % age of hydrogen in the compound `= (2)/(18) xx 0.1014 xx (100)/(0.246) = 4.58`

Discussion

28.	On complete combustion, 0.246g of an organic compound gave 0.198g of carbon dioxide and 0.1014g of water, Determine the percentage composition of carbon and hydrogen in the compound.
Answer» Solution :`{:(%C= (12)/(44) xx (m_(2) xx 100)/(m)),(=(12)/(44) xx (0.198 xx 100)/(0.246)),(=21.95%):}\|{: ("where, m = mass ofcomp" =0.246gm ),(m_(2) = "mass of "CO_(2)),(=0.198 gm):}` `{:(%H= (2)/(18) xx (m_(1) xx 100)/(m)),(=(2)/(18) xx (0.1010 xx 100)/(0.246)),(=4.58%):}\|{:(m_(1) = "mass of" H_(2)O= 0.1010gm),("m = mass of COMP"),(= 0.246):}`

Discussion

29.	On complete combustion, 0.246 g of an organic compound gave 0.198g of carbon dioxide and 0.1014g of water.Determine the percentage composition of carbon and hydrogen in the compound.
Answer» SOLUTION :`C = 21.95%, H = 4.58%`

Discussion

30.	On complete combustion, 0.246 g of an organic compound gave 0.198 g of CO_(2) and 0.1014 of H_(2)O. Find the percentage composition of the organic compound.
Answer» SOLUTION :`C = 21.95%, H = 4.58%`

Discussion

31.	On complete combustion, 0.246 g of an organic compound gave 0.198 g of CO_2 and 0.1014 g of H_2 Otha ratio of carbon and hydrogen atoms in the compound is
Answer» `1:3` `1:2` `2:5` `2:7` ANSWER :C

Discussion

32.	On combustion of lithium in presence of air it produces ...... and ......
Answer» SOLUTION :monoxide`Li_(2)O`, NITRITE`Li_(3)N`

Discussion

33.	On catalytic reduction with H/Pt how many alkenes will give n-butane?
Answer» 1 2 3 4 Solution :THREE ALKENES

Discussion

34.	On catalytic hydrogenation how many isomeric alkene will give 2 methyl butane.
Answer» ANSWER :3

Discussion

35.	On boiling 1 litre N/5HCl the volume of the aqueous solution decreases to 250 mL During this reaction 3.65 g of HCl is removed from solution, then the concerntration of resulting solution becomes : [HCl = 36.5 g "mol"^(-1)]
Answer» `N/20` `N/10` `N/2.5` `N/5` Solution :`qm//L = "Normality" xx "G. equivalent wt."` `= N/5 xx36.5 =(36.5)/(5)` `= 7.3 ` gm HCl in `1L N/5` HCl HCl left after boiling `=7.3` g initial HCl `- 3.65` g removed HCl `=3.65g` HCl left in 250 mL solution `N=("wt. of solute" xx 1000)/("gm." - "equivalent wt." xx "volume(mL)")` `= (3.65xx1000)/(36.5xx250)= (10)/(15) = (1)/(1.5) = (N)/(2.5)`

Discussion

36.	On being slowly passed through water, PH_(3) forms bubbles but NH_(3) dissolves. Why is it so ?
Answer» SOLUTION :N-H BOND is more POLAR than P-H bond. Hence, `NH_(3)` forms hydrogenbonds with `H_(2)O` molecules and hence DISSOLVES in it whereas `PH_(3)` does not dissolve and hence forms bubbles.

Discussion

37.	On being heated in oxygen, 3.120 g of a metal M converts to 4.560 g of oxide (atomic weight of M = 52.0). Mark out the correct statement(s)
Answer» Equivalent wt. of metal M = 17.33 Number of equivalents of oxygen REACTED with metal = 0.09 Metal M forms halide `MCI_2` The simplest formula of the metal oxide which it forms is `M_(2)O_3` Solution :WEIGHT of oxygen reacted `= 4.560 - 3.120 = 1.440` No. of equivalents `=(1.440)/8 = 0.18` Equivalent weight of metal = `(3.12 ) /(1.44) XX 8 = 17.33` Valency ` =(52)/(17.33) = 3`

Discussion

38.	On basis of Le-Chatelier principle explain how can the temperature and pressure be adjusted to increase the yield of ammonia in the following reaction. N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) , DeltaH=-92.38 "kJ mol"^(-1) What will be the effect of addition of argon to the above reaction mixture at constant volume ?
Answer» Solution :`N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) , DELTAH =-92.38 "kJ mol"^(-1)` It is an exothermic process as `DeltaH` is negative. Effect of temperature : As per to Le-Chatelier.s principle, low temperature is favourable for high yield of ammonia, but practically very low temperatures slow down the reaction. So, optimum temperature 700 K is favourable in ATTAINMENT of equilibrium. Effect of pressure : Similarly, high pressure about 200 atm is favourable for high yield of ammonia. On increasing pressure, reaction goes in the forward direction because the number of moles DECREASES in the forward direction. Addition of argon : At constant volume addition of argon does not affect the equilibrium because it does not change the partial PRESSURES of the REACTANTS or products involved in the reaction and the equilibrium remains undisturbed.

Discussion

39.	On attachment of H and Br from the HBr to C_(6)H_(5) free radical what can be formed ?
Answer» Solution :(i) `OVERSET(.)(C_(6))+H-BR rarr C_(6)H + Boverset(.)(r)` more stable (ii) `overset(.)(C_(6))+H-Br rarr C_(6)H + Br`least stable On REACTION (i) `Boverset(.)(r)` free RADICAL can be formed and reaction (ii) not occur.

Discussion

40.	On analysis, a certain compound was found to contain iodine and oxygen in the ratio of 254:80. The formula of the compound is (At mass I = 127, O = 16)
Answer» IO `I_(2)O` `I_(5)O_(2)` `I_(2)O_(5)` SOLUTION :I : O 254 : 80 Moles = 2 : 5 implies `I_(2)O_(5)`

Discussion

41.	On an industrial scale, hydrogen peroxide is prepared exclusive by autoxidation of _____________
Answer» 2-alkylanthraquinol 2-quinol 2-anthra quinol 2-alkyl quinol Answer :A

Discussion

42.	On addition of one mL solution of 10% NaCl to 10mL gold solution in the presence of 0.025 g of starch,the coagulation is prevented because starch has the following gold numbers
Answer» 25 0.025 0.25 2.5 Solution :Minium AMOUNT of dryprotective colloid in milligram which can just prevent the coagulation of 10 ML of RED gold SOL. On the addition of 1mL of 10% NACL solution to it.

Discussion

43.	On addition of one ml of 10% NaCl solution of 10ml gold sol in the presence of 0.25 gm of starch. The coagulation is just prevernted, starch had goldnumber
Answer» 0.025 0.25 2.5 None Solution :`0.25xx1000=250`.

Discussion

44.	On adding NaOH to ammonium sulphate, a colourless gas with pungent odour is evolved which forms a blue coloured complex whit Cu^(2+) ion. Identify the gas.
Answer» Solution :AMMONIUM sulphate reacts with NaOH to EVOLVE `NH_(3)` gas which has pungent smell and FORMS blue coloured complex with `Cu^(2+)` ions as shown below : `underset("Amm. Sulphate")((NH_(4))_(2)SO_(4))+2NaOHtounderset("Ammonia")(2NH_(3))uarr+Na_(2)SO_(4)+2H_(2)O` `underset("Copper (II) ion")(Cu^(2+)(aq.))+4NH_(3)(aq.)toundersetunderset(("Bule coloured complex"))("Tetraamminecopper (II) ion")([Cu(NH_(3))_(4)]^(2+)(aq.))`

Discussion

45.	On adding glycerol to water, which of the following behaviour is observed
Answer» water evaporated more easily CAUSES water to BOIL at lower temperature gets hydrolysed by water the freezing point of water is lowered Solution :Glycerol being LESS volatile causes DEPRESSION in the boiling point of water.

Discussion

46.	On adding 0.1 M solution each of Ag^(+), Ba^(2+), Ca^(2+) ions in a Na_(2)SO_(4) solution, species first precipitated is(K_(sp)BaSO_(4)=10^(-11), K_(sp) CaSO_(4)=10^(-6), K_(sp)Ag_(2)SO_(4)=10^(-5))
Answer» `Ag_(2)SO_(4)` `BaSO_(4)` `CaSO_(4)` all of these Solution :`K_(sp)` for `Ag_(2)SO_(4)=[Ag^(+)]^(2)[SO_(4)^(2-)]` `:. [SO_(4)^(2-)]` for precipitation of`Ag_(2)SO_(4) lt (K_(sp))/([Ag^(+)]^(2))=(10^(-5))/((0.1)^(2))=10^(-3)M` SIMILARLY, `[SO_(4)^(2-)]` for precipitation of `BaSO_(4) lt (K_(sp))/([Ba^(2+)])=(10^(-11))/(0.1)=10^(-10)M` `[SO_(4)^(2-)]` for precipitation of `CaSO_(4) lt (K_(sp))/([CA^(2+)])=(10^(-6))/(0.1)=10^(-5)M` Thus, minimum `[SO_(4)^(2-)]` reuired for precipitaion is for `BaSO_(4)`.

Discussion

47.	On adding a catalyst to a reaction, the equilibrium constant ………… .
Answer» ANSWER :REMAINS UNCHANGED

Discussion

48.	On a ship sailing in pacific ocean where temperatures is 23.4^(@)C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches Indian ocean where temperature is 26.1^(@)C?
Answer» Solution :When `T_(1)=23.4^(@)C=(23.4+273) K=296.4 K, V_(1)=2L` When `T_(2)=26.1^(@)C=(26.1+273) K=299.1 K, V_(2)`= To be calculated As pressure above the sea LEVEL is supposed to remain constant, applying CHARLES' law, `(V_(1))/(T_(1))=(V_(2))/(T_(2)), i.e., (2L)/(296 K)=(V_(2))/(299.1 K)" or "V_(2)=2.018 L`

Discussion

49.	On a ship sailing in pacific ocean where temperatureis 23.4^@ C. a ballon is filled with 2L air What will be the volume of the balloon when ship reaches indian ocean where temperature is 26.1^@C?
Answer» SOLUTION :From CHARLE's LAW `(V_(1))/(T_(1))=(V_(2))/(T_(2))"":.V_(2)=(V_(1)T_(2))/(T_(1))+(2Lxx299.1K)/(296.4K)=2.018L`

Discussion

50.	On a ship sailing in pacific ocean where temperature is 23.4 ""(@)C, a balloon is filled with 2L air. What will be the volume of the balloon when the ship reaches Indian ocean, where temperature is 26.1 ""^(@)C ?
Answer» Solution :INITIAL temperature `= 23.4^(@)C=(23.4+272)K` `= 296.4 K = T_(1)` Initial volume of BALLOON `= V_(1)=2L` Volume of balloon the END `= V_(2)= (?)` Temperature of balloon at the end`=(26.1+273)K=299.1 K` GAS is present in balloon is constant. Pressure of gas present on ship of balloon is P. Mass & pressure of gas is constant, according to Charle.s law, `(V_(1))/(T_(1))=(V_(2))/(T_(2))` `therefore V_(2)=((V_(1))/(T_(1)))T_(2)=((2L)(299.1K))/(296.4 K)=2.018 L`

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

On heating C_(2)H_(2) in red hot copper tube, the compound formed is :

On heating ammonium dichromate and barium azide separately we get

On heating, a mixture of potassium cyanate and ammonium chloride gives :

On heating a gas, pressure and volume both become double. By lowering temperature, one fourth of initial number of moles of air are taken in tomaintain the double pressure and volume. Calculate by what fraction, the temperature must have been raised finally.

On heating a liquid, its surface tension

On heating 4.9 g of KClO_(3) , it shows a weight loss of 0.384 g . What percentage of KClO_(3) has decomposed ?

On heating 8 moles each of Li_(2)CO_(3) and K_(2)CO_(3), how many moles of CO_(2) evolved

On heating 0.32g of an organic compound with concentrated nitric acid and barium chloride, 0.932g barium sulphate was obtained. Calculate the percentage of sulphur in the given compound.

On heating 0.2g of an organic compound with a mixture of barium chloride and nitric acid, 0.466 g of barium sulphate was obtained. Calculate the percentage of sulphur

On halogenation, an alkane gives only one monohalogenated product. The alkane may be:

On going down a main subgroup in the periodic table (example Li to Cs in IA or Be to Ra in IIA) the expected trend of change in atomic radius is a

On electrolysis of sodium chloride ....... gas is produce on anode.

On dividing 0.25 by 22.1176, the actual answer is 0.011303. The correctly reported answer will be

On dissolving sugar in water at room temperature solution feels cool to touch. Under which of the following cases dissolution of sugar will be most rapid ?

On dissolving moderate amount of sodium metal in liquid NH_(3) at low temperature , which one of the following does not occur ?

On dissolving moderate amount of sodium metal in liquid NH_(3)at low temperature, which one of the following does not occur

On dissolving Aluminum hydroxide in excess of alkali produces ...... ions.

On dissolving 2.0 g of a metal in sulphuric acid, 4.51 grams of the metal sulphate was formed. The specific heat of the metal is 0.057 cal/g. What is the valency of the metal and its exact atomic weight?

On dissolving 1 mole of each of the following acids in one litre water, the acid which does not give a solution of strength 1 N is :

On dipping a loop of platinum wire in borax paste and heating the wire subsequently in hotoxidising flame, produces a colourless, transparent, glass-like bead. The bead contains:

On diluting a buffer solution, its pH :

On condensation of BeCl_(2)vapor it forms BeCl_(6)dimeric with coordination number of....

On complete combustion, 0.246g of an organic compound gave 0.198g of CO_(2) and 0.1014g of H_(2)O. The ratio of carbon and hydrogen atoms in the compound is:

On complete combustion, 0.246g of an organic compound gave 0.198 g of carbon dioxide and 0.1014 g of water. Determine the percentage composition of carbon and hydrogen in the compound.

On complete combustion, 0.246g of an organic compound gave 0.198g of carbon dioxide and 0.1014g of water, Determine the percentage composition of carbon and hydrogen in the compound.

On complete combustion, 0.246 g of an organic compound gave 0.198g of carbon dioxide and 0.1014g of water.Determine the percentage composition of carbon and hydrogen in the compound.

On complete combustion, 0.246 g of an organic compound gave 0.198 g of CO_(2) and 0.1014 of H_(2)O. Find the percentage composition of the organic compound.

On complete combustion, 0.246 g of an organic compound gave 0.198 g of CO_2 and 0.1014 g of H_2 Otha ratio of carbon and hydrogen atoms in the compound is

On combustion of lithium in presence of air it produces ...... and ......

On catalytic reduction with H/Pt how many alkenes will give n-butane?

On catalytic hydrogenation how many isomeric alkene will give 2 methyl butane.

On boiling 1 litre N/5HCl the volume of the aqueous solution decreases to 250 mL During this reaction 3.65 g of HCl is removed from solution, then the concerntration of resulting solution becomes : [HCl = 36.5 g "mol"^(-1)]

On being slowly passed through water, PH_(3) forms bubbles but NH_(3) dissolves. Why is it so ?

On being heated in oxygen, 3.120 g of a metal M converts to 4.560 g of oxide (atomic weight of M = 52.0). Mark out the correct statement(s)

On attachment of H and Br from the HBr to C_(6)H_(5) free radical what can be formed ?

On analysis, a certain compound was found to contain iodine and oxygen in the ratio of 254:80. The formula of the compound is (At mass I = 127, O = 16)

On an industrial scale, hydrogen peroxide is prepared exclusive by autoxidation of _____________

On addition of one mL solution of 10% NaCl to 10mL gold solution in the presence of 0.025 g of starch,the coagulation is prevented because starch has the following gold numbers

On addition of one ml of 10% NaCl solution of 10ml gold sol in the presence of 0.25 gm of starch. The coagulation is just prevernted, starch had goldnumber

On adding NaOH to ammonium sulphate, a colourless gas with pungent odour is evolved which forms a blue coloured complex whit Cu^(2+) ion. Identify the gas.

On adding glycerol to water, which of the following behaviour is observed

On adding 0.1 M solution each of Ag^(+), Ba^(2+), Ca^(2+) ions in a Na_(2)SO_(4) solution, species first precipitated is(K_(sp)BaSO_(4)=10^(-11), K_(sp) CaSO_(4)=10^(-6), K_(sp)Ag_(2)SO_(4)=10^(-5))

On adding a catalyst to a reaction, the equilibrium constant ………… .

On a ship sailing in pacific ocean where temperatures is 23.4^(@)C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches Indian ocean where temperature is 26.1^(@)C?

On a ship sailing in pacific ocean where temperatureis 23.4^@ C. a ballon is filled with 2L air What will be the volume of the balloon when ship reaches indian ocean where temperature is 26.1^@C?

On a ship sailing in pacific ocean where temperature is 23.4 ""(@)C, a balloon is filled with 2L air. What will be the volume of the balloon when the ship reaches Indian ocean, where temperature is 26.1 ""^(@)C ?