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26901.

The optically active species among the following is:

Answer»

`[CR(NH_(3))_(6)]^(3+)`
`[Co(CN)_(6)]^(3-)`
`[Co(gly)_(3)]`
`[Ru(NH_(3))_(6)]^(3+)`

ANSWER :C
Discussion
26902.

The number of molecules of the reactants taking part in a single step of the reaction tells about:

Answer»

MOLECULARITY of the reaction
Mechanism, of the reaction
Order of reaction
All

Answer :A
Discussion
26903.

The optically active molecule is-

Answer»




Solution :AMONG the given compounds only ( C ) is chiral and hence OPTICALLY active. REST of the compounds are optically inactive meso compounds as they have PLANE of symmetry.
Discussion
26904.

The number of molecules of CO_(2) present in 44 g of CO_(2) is

Answer»

`6 xx 10^(23)` APPROXIMATELY
`3 xx 10^(10)` approximately
`10^(30)` approximetely
`12 xx 10^(23)` approximately

Answer :A
Discussion
26905.

Theoptically activemolecule is .

Answer»




Solution :OTHERS are MESO - COMPOUND due to PRESECE ofplane ofsymmetry.
Discussion
26906.

The number of molecules of an ideal gas in a 8.2 L container at 380 torr and 27^(@)C will be

Answer»

`6.02 XX 10^(23)`
`1.0 xx 10^(22)`
`1.0 xx 10^(23)`
`1.204xx 10^(24)`

Solution :Number of MOLECULES`= ( PV)/( RT) xx N_(0)`
`= ( 380 //760 xx 8.2)/( 0.082 xx 300) xx 6.02 xx 10^(23)`
`= 1.0 xx 10^(23)`
Discussion
26907.

The optically active co-ordination complex ion among the following is

Answer»

`TRANS-[CO(en)_2Cl_2]^+`
`Cis-[Co(en)(NH_3)_2Cl_2]^+`
`[Co(NH_3)_6]^(3+)`
`[Co(NH_3)_4 Cl_2]^+`

ANSWER :B
Discussion
26908.

The number of molecules of an ideal gas in a 4.1 L container at 760 torr and 27^(@)C will be

Answer»

`6.02 xx 10^(23)`
`1.0 xx 10^(23)`
`1.204 xx 10^(24)`
`1.204 xx 10^(23)`

Solution :Number of MOLES
`pV = nRT`
or ` n = ( pV)/( RT )`
`:. n = ( 1 ( atm ) xx 4.1 ( L))/( 0.082 xx 300)`
`:.` Number of molecules
`= ( 4.1 )/( 0.082 xx 300) xx 6.02 xx 10^(23)`
`= 1.0 xx 10^(23)`
Discussion
26909.

The optical rtation of an optically active compound is

Answer»

Directly PROPORTIONAL to LENGTH of the POLARIMETER tube only
Directly proportional to the molar concentration of the compound
Independent of the length of the polarimeter tube and concentration of the compound
Directly proportional to both the length of the polarimeter tube and molar concentration of the compound

ANSWER :C
Discussion
26910.

The number of molecules in 89.6 litre of a gas at NTP are:

Answer»

`6.02xx10^(23)`
`2xx6.02xx10^(23)`
`3xx6.02xx10^(23)`
`4xx6.02xx10^(23)`

ANSWER :D
Discussion
26911.

The optical inactivity of meso - tartaric acid is because of

Answer»

absence of CHIRAL carbon atoms
EXTERNAL COMPENSATION
internal compensation
PRESENCE of asymmetrical will not carbon atoms

Answer :C
Discussion
26912.

The number of molecules in 89.6 L of a gas at0^@Cand 1 atm pressure is :

Answer»

`6.02 xx 10^23`
`12.04 xx 10^23`
`18.06 xx 10^23`
`24.08 xx 10^23`

SOLUTION :22.4 L of a GAS contain ` = 6.02 xx 10^23`
MOLECULES 89.6 L of gas contain
` = (6.02 xx 10^23 xx 89.6)/(22.4)= 24.08 xx 10^23` molecules
Discussion
26913.

The opiates are drugs that cause addition Heroin and cocaine are among the most famous example. The chemistry of the brain adapts to the presence of the opiate in such a way that the person taking the drug feels an uncontrollable need to take more of it. Owing to their ability to induce an artificial feeling of well being, the person taking heroin (or) cocaine quickly becomes addicted to them once this happens the craving for the drug often causes the person. (i) Neglect ordinary rules of hygiene (ii) Enter into a life of crime As a result of drug addict becomes thin and susceptible illness. Morphine on Alkylation and acetylation gives respectively

Answer»

CODEINE, heroine
HEROIN, codeine
Heroin, meperidine
Meperidine, heroin

Solution :Methylmorphine is codeine, ACETYL MORPHINE in heroin
Discussion
26914.

The number of molecules in 4.25 g of ammonia in approximately :

Answer»

`3.5 XX 10^23`
`1.5 xx 10^23`
`0.5 xx 10^23`
`2.5 xx 10^23`

ANSWER :B
Discussion
26915.

The opiates are drugs that cause addition Heroin and cocaine are among the most famous example. The chemistry of the brain adapts to the presence of the opiate in such a way that the person taking the drug feels an uncontrollable need to take more of it. Owing to their ability to induce an artificial feeling of well being, the person taking heroin (or) cocaine quickly becomes addicted to them once this happens the craving for the drug often causes the person. (i) Neglect ordinary rules of hygiene (ii) Enter into a life of crime As a result of drug addict becomes thin and susceptible illness. Cocaine is

Answer»

Vitamin
Hormone
Medicine
ANTI pyritic

SOLUTION :COCAIN is medicine used to cure SEVERE PAINS
Discussion
26916.

The number of molecules in 4.25 g of ammonia are approximately

Answer»

`0.5 XX 10^23`
`1.5 xx 10^23`
`2.5 xx 10^23`
`3.5 xx 10^23`

SOLUTION :No. of MOLECULES of `NH_3` in 17G ` = 6.02 xx 10^23`
No. of molecules of `NH_3` in 4.25g
` = (6.02 xx 10^23)/(17) xx 4.25 = 1.5 xx 10^23`
Discussion
26917.

The opiates are drugs that cause addition Heroin and cocaine are among the most famous example. The chemistry of the brain adapts to the presence of the opiate in such a way that the person taking the drug feels an uncontrollable need to take more of it. Owing to their ability to induce an artificial feeling of well being, the person taking heroin (or) cocaine quickly becomes addicted to them once this happens the craving for the drug often causes the person. (i) Neglect ordinary rules of hygiene (ii) Enter into a life of crime As a result of drug addict becomes thin and susceptible illness. Heroin is a derivative of

Answer»

MORPHINE
NICOTINE
benzene
COCAINE

SOLUTION :Heroin is morphine diacetate
Discussion
26918.

The number of molecules in 27 g of water is :

Answer»

`9.033 XX 10^23`
`6.022 xx 10^23`
27
`3.011 xx 10^22`

ANSWER :A
Discussion
26919.

The operating temperature of a fuel cell is

Answer»

`60^(@)C`
`80^(@)C`
`252 ^(@)C`
`120 ^(@)C`

SOLUTION :It is FACT .
Discussion
26920.

The open-chain glucose,(an aldohexose) and fructose (an 2-oxohexose) have…..and…. Chiral carbons respectively

Answer»

4,4
4,3
3,3
3,4

Answer :B
Discussion
26921.

The number of molecules in 16 g of methane is

Answer»

`3.0 xx 10^(23)`
`(16)/(6.02) xx 10_(23)`
`6.023 xx 10^(23)`
`(16)/(3.0) xx 10^(23)`

Solution :16 G `CH_(4)` is 1 MOL. Hence number of MOLECULES = `"AVOGADRO number" =6.023 xx 10^(23)`
Discussion
26922.

The open glucose and fructose have _____ and _____ chiral centre

Answer»

4,4
4,3
3,3
3,4

Answer :B
Discussion
26923.

The number of molecules in 100 ml of 0.02 N H_(2)SO_(4) is

Answer»

`6.02xx10^(22)`
`6.0xx10^(21)`
`6.02xx10^(20)`
`6.02xx10^(18)`

Solution :`0.02N H_(2)SO_(4)=0.01M H_(2)SO_(4)`
1000 mL of `0.01 M H_(2)SO_(4)` contains `H_(2)SO_(4)`
`="0.01 mole"`
`therefore 100mL" of "0.01M H_(2)SO_(4)" contains "H_(2)SO_(4)`
`=0.001" mole"=10^(-3)"mole"`
`"Molecules PRESENT"=10^(-3)xx6.02xx10^(23)`
`=6.02xx10^(20)`
Discussion
26924.

The only type of attraction existing between molecules of Halogenes are

Answer»

HYDROGEN bond
Ion-dipole ATTRACTION
VANDERWAALS forces
covalent bonds

Answer :C
Discussion
26925.

The number of molecules in 1 kg mole is ……………… .

Answer»

SOLUTION :`6.022xx10^(26)`
Discussion
26926.

The only vitamin with a metal atom in it is :

Answer»

VITAMIN A
Vitamin C
Vitamin D
Vitamin `B_(12)`.

ANSWER :D
Discussion
26927.

The number of molecule at NTP in 1 ml of an ideal gas will be

Answer»

`6XX10^(23)`
`2.69xx10^(19)`
`2.69xx10^(23)`
NONE of these

Solution :`:' 22400` ML at NTP has `6.023xx10^(23)` molecule
`:.` 1 ml at NTP has `=(6.023xx10^(23))/22400`
`=0.0002688xx10^(23)=2.69xx10^(19)`.
Discussion
26928.

._(11)^(23)Na is the most stable isotope of Na. Find the process by which._(11)^(24) Na can undergo radioactive decay :

Answer»

`._(11)Na^(23)`
`._(10)NE^(22)`
`._(9)F^(18)`
`_(12)Mg^(22)`

Solution :`[._(11)Na^(23)` stable isotope i. e. `._(11)Na ^(22) ` has n/p ratio lesser than REQUIRED To increase n/p ratio
`{:(._(11)Na ^(22),rarr,._(10)Ne^(22),+,._(1)e^(0)),(,,,,("positron emission")):}`
Or
`{:(._(-1)e^(0),+,._(11)Na^(22),rarr,._(10)Ne^(22)),(("k-electron caputre"),,,,):}`
Discussion
26929.

The number of molecular present in a drop of water, if its volume is 0.05mL, are:

Answer»

`1.66xx10^(21)`
`1.66xx10^(22)`
`1.66xx10^(23)`
`1.66xx10^(23)`

ANSWER :A
Discussion
26930.

The number of mole of water in 488 g BaCl_2 ,2H_2O are :

Answer»

2
3
4
5

Answer :C
Discussion
26931.

The only primary alcohol that can be prepared by the indirect hydration of alkene is

Answer»

ethyl alcohol
n-propyl alcohol
isobutyl alcohol
methyl alcohol

SOLUTION :`CH_2=CH_2+H_2SO_4 overset("COLD")to CH_3CH_2OSO_3H`
`CH_3CH_2OSO_3H + HOH overset(DELTA)to CH_3CH_2OH + H_2SO_4`
Except ethanol, no other `1^@` alcohol can be prepared by this method as the addition of `H_2SO_4` , FOLLOWS Markownikoffs of rule. Generally `2^@` and `3^@` ALCOHOLS are obtained
Discussion
26932.

The only non-metal, which is liquid at room temperature

Answer»

`O_(2)`
`F_(2)`
`N_(2)`
`Br_(2)`

SOLUTION :`Br_(2)` is LIQUID non-metal
Discussion
26933.

The number of mole of oxalate icons oxidised by one mole of acidified MnO_4^-is:

Answer»

`1//5`
`2//5`
`5//2`
5

Answer :C
Discussion
26934.

The number of modes of As_(2)S_(3) oxidised to H_(3)AsO_(4) " and "H_(2)SO_(4)by one mode of HNO_(3) (reduced to NO) is .

Answer»

`3/2`
`5/2`
`2/3`
`3/28`

Solution :`{:((As^(3+))_(2) to 2As^(5+) + 4E),(ul((S^(2-))_(3) to 3S^(6+) + 24E)),([As_(2)S_(3) to 2As^(5+). + 3S^(6+) + 28e] xx 3),([N^(5+) + 3e to N^(2+) ] xx 28):}`
` :. ` 28 mole of `HNO_(3)` oxidises 3 mol `As_(2)S_(3)`.
Discussion
26935.

The only metal which has a positive standard reductions potential in the first transition series is "…................"

Answer»


ANSWER :COPPER
Discussion
26936.

The only, most stable nucleus formed by bombarding either ._(13)^(27)Al by neutrons of ._(11)^(23)Na by deutrons is

Answer»

`._(15)^(30)P`
`._(14)^(30)Si`
`._(12)^(24)Mg`
`._(56)^(137)BA`

Answer :d
Discussion
26937.

The number of moles of KMnO_4 that will be needed to react with one mole of sulphite ion in acidic solution is :

Answer»

2
5
`2//5`
`3//5`

ANSWER :C
Discussion
26938.

The only incorrect combination is

Answer»

(I)(i) (S)
(II)(iv) (R )
(III) (iv) (Q)
(IV) (ii) (P)

Answer :D
Discussion
26939.

The only incorrect combination is-

Answer»

(II)(ii)(R)
(I)(i)(S)
(IV)(iii)(Q)
(III)(iv)(P)

SOLUTION :`SO_3^(-2)+H_2SO_4(dil.)toSO_2(UARR)+H_2O`
`SO_2` turns baryata water milky
`Cr_2O_7^(-2)+3SO_2+2H^(+)tounderset(Green)(2Cr^(+3)darr)+SO_4^(-2)+H_2O`
`SO_2+[Fe(CN)_5NO]^(-2)TOX`
`2MnO_4^(-)+5SO_2+2H_2Oto5SO_4^(-2)+2MN^(+2)+4H^(+)`
Discussion
26940.

The number ofmillimolse of sodium chloride and each of two sols . S and Y are as follows : {:(,X,Y),(NaCl,51,46),(Mgcl_(2),71,23):} Which of the following would not be reasonalbe value to expect for the amout of the other salt required to cause precipitation .

Answer»

X will be PRECIPITATED by `90` MILLIMOLES of ` AlCl_3`
` Y` will be precipitated by `20` millimoles of ` AlCl_3`
`X` will be precipitated by `25` millimoles of ` Na_2SO_4`
` Y` will be precipitated by `20` millimoles of ` MgSO_4`

SOLUTION :The EFFICIENCY orbder for -ve sol is :
` Na^+ gt Mg^(2+) lt Al^(3+)`
Discussion
26941.

The number of millimoles of ""_(6)^(14) C equivalent to one milicurie , if t_(1//2) = 5570 year and1 curie = 3.7 xx 10^(10) dps is

Answer»

`1.56 xx 10^(-2)`
`3.12 xx 10^(-2)`
`4.34 xx 10^(-2)`
`7.80 xx 10^(-2)`

SOLUTION :`A = lamdaN,1 xx 10^(-3)xx 3.7xx 10^(10)= ((0.693 )/(5570 xx 365 xx 24 xx 60 xx 60 )) xxN_t`
`N_t= ((1 xx 10^(-3) xx 3.7 xx 10^(10) xx 5570 xx 365 xx 24 xx 60 xx 60 )/( 0.693 )) =((7522.285 )/( 0.693 )) xx 86400 xx 10^(10)`
`=(( 7.522285 xx 10^3 xx 8.64 xx 10^4 xx 10^(10))/( 0.693 )) =( 7.522285 xx 8.64 )/( 0.693 )xx 10^(17)= 93.784 xx 10^(17)= 9.3784 xx 10^(18)`
Discussion
26942.

The only incorrect combination is :

Answer»

<P>(III)(II)(P)
(I)(IV)(Q)
(IV)(iv)(Q)
(II)(iii)(Q)

SOLUTION :NA
Discussion
26943.

The only incorrect combination is :

Answer»

(I)(II)(P)
(I)(iv)(R)
(III)(i)(S)
(IV)(ii)(Q)

Solution :NA
Discussion
26944.

The number of millimoles of H_(2)SO_(4) present in 5 litres of 0.2N H_(2)SO_(4) solution is

Answer»

500
1000
250
`0.5xx10^(-3)`

ANSWER :A
Discussion
26945.

The only element with positive E^(@)(M^(2+)|M) potential in 3d series is…..

Answer»

Zn
CU
Mn
Cr

Solution :`E^(@) (Cu^(2+)|Cu) = +0.34V`
Discussion
26946.

The number of milligram of KOH required to neutralize 1 g of the oil or fat is called :

Answer»

SAPONIFICATION VALUE
IODINE value
ACETYL value
Acid value

Answer :A
Discussion
26947.

The only halous acid known is of:

Answer»

`I_2`
`Cl_2`
`Br_2`
all`

ANSWER :B
Discussion
26948.

The only element in VIB group of group 16 elements, which is definitely a metal is"

Answer»

Tellurium
Selenium
Sulphur
Polonium

Answer :D
Discussion
26949.

The only element in group 16 whose hydride is colourless liquid is

Answer»

SULPHUR
SELENIUM
OXYGEN
Tellerium

Solution :HYDRIDE of oxygen is `H_2O` which is colourlessliquid
Discussion
26950.

The number of methoxy groups in a compound can be determined by treating it with

Answer»

ACETIC acid
Sodium carbonate
Sodium hydroxide
HI and `AgNO_(3)`

ANSWER :D
Discussion