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answer is c) 22.8 cal/g

5.74KJ = 1.372Kcal.

Hence, option (c) is correct.

3 gram of Carbon will react with only 8 gm of oxygen gas to give 11gram of carbon dioxide. 42 gram of oxygen will be left.

law of definite composition states that a given chemical compound always contains the elements in fixed ratio by mass. The ratio is independent of the source and method of preparation.

In nature, most elements occur as mixture of elements.

Mixture is the right answer

in natural most of the element occurs mixture of element

mixture is the right answer

Because manganese is in the +7 oxidation state, thepermanganate(VII) ion is a strong oxidizing agent. The ion has tetrahedral geometry.Permanganatesolutions are purple incolorand are stable in neutral or slightly alkaline media.

Because manganese is in the +7 oxidation state, thepermanganate(VII)ionis a strong oxidizing agent. Theionhas tetrahedral geometry.Permanganatesolutions are purple incolorand are stable in neutral or slightly alkaline media.

Dil Le Koi rokna tha kya hoga hoga Gaya pardesiMera sochna tha

since there are no odd numbers divisible by 2.

so, the set would be a null set ----->>>{}.

2Na+ 2H2O → 2NaOH + H2

According to de Broglie equationWave length = h/mv = 6.255 x 10^-34/(0.1x10) = 6.824 x 10^-34m

Volume = 4.48 dm3 = 4.48 L

gram molecular mass = 22.4 L at STP

so, 4.48 L of ammonia gas weighs= 3.49 g

22.4 L of ammonia weighs = 22.4 x 3.49 /4.48

= 17.45 g

ifthe melting point of a soild is high then its the inter particle force of attraction will be also high

melting point is directly proportional to force of attraction increasing order

C(400) -------------> B(293) ------------>A(193)

In n-octane we find the longest carbon chain of eight carbon atoms so its boiling point will be highest.

It is separation of a liquid mixture into fractions differing in boiling point (and hence chemical composition) by means of distillation, typically using a fractionating column.

Normality = molarity× Valance here valance = 2.

so, M = N/2 = 0.04/2 = 0.02Moles/L

no..of molecules will be 0.02*(6*10^23) = 12.04*(10^20) option A

the temperature at which the vapour pressure of the liquid becomes equal to the atmospheric pressure is called

The compound A is Ethanoic Acid (CH3COOH).

The chemical equation is

CH3COOH + C2H5OH = CH3COOC2H5 + H2O

Hence, compound B is CH3COOC2H5

mass of 1mole H molecule = 2g mass of 1 molecule = 2/(6×10²³) = 10/3 ×10^-²² g = 10/3× 10^-24 kg

so, K.E = 1/2*(m)*(v²) = 1/2*(10/3× 10^-24 kg)×(1900)² = 601 × 10^-24 × 10^4 = 6.01×10^-18J

option D

According to this relation averagekineticenergy of a molecule of an idealgasis proportional to itsabsolute temperature; is indeppendent of the pressure, volume or the nature of the idealgas. This is calledkinetic interpretation of temperature.

गैसों का अणुगति सिद्धान्त(kinetic theory of gases)गैसोंके समष्टिगत (मैक्रोस्कोपिक) गुणों (दाब,तापआदि) को समझने के लिये एक सरलीकृतमॉडलहै। सार रूप में यह सिद्धान्त कहता है कि गैसों का दाब उनके अणुओं के बीच के स्थैतिक प्रतिकर्षण (static repulsion) के कारणनहींहै (जैसा किन्यूटनका विचार था), बल्कि गतिशील अणुओं के आपसी टकराव (collision) का परिणाम है।

9 is 1/2 of18, meaning that 1/2 mole is present in 9 g of water. 1/2 *6.022*10^23=3.011*10^23molecules H2O. However, if you want to know how many ATOMS are present in3.011*10^23, you must then multiply by 3 (2 hydrogen atoms and 1 oxygen atom per molecule), and get9.033*10^23 atoms.

1. C2H2(g) + 5/2 O2(g) à 2 CO2(g) + H2O(l) ΔH = -1299.5 kJ

C(s) + O2(g) à CO2(g) ΔH = -393.5 kJ

H2+ ½ O2(g) à H2O(l) ΔH = -285.8 kJ

Calculate ΔHrxnfor the following reaction:

2 C(s) + H2(g) à C2H2(g) ΔH = ???

2.

Oxidation is a common reaction for many metals. Given the following equations, first balance them, then determine which species are oxidized and which are reduced. Then look at the “activity series” table in your textbook and determine whether the reaction can happen or not.

a) Fe(s) + Ag2SO4(aq) à FeSO4(aq) + Ag(s)

b) Mg(NO3)2(aq) + Li (s) à LiNO3(aq) + Mg(s)

c) Cu(MnO4)2(aq) + K(s) à KMnO4(aq) + Cu(s)

3.The reaction between potassium superoxide, KO2, and CO2is used as a source of O2and absorber of CO2in self-contained breathing equipment used by rescue workers. A) If 40.0 grams of KO2and 40.0 grams of CO2are present in the container, how many grams of O2are produced? B) Calculate the percent yield if 10 g of O2were actually used until the tank was empty.

4 KO2+ 2 CO2à 2 K2CO3+ 3 O2

Best Answer

Given the % of Fe in enzyme is 5.6%

so, in 1 gm , the mass of Fe will be 5.6%*(1) = 0.056gm

so no. of atoms of Fe is. 0.056/56*(Na) = 0.001 × 10²³ = 10^20 atoms

wrong answer

To make a 2 M solution of acetic acid, dissolve 120.1 g acetic acid in 500 mL distilled or deionized water in a 1000-mL volumetric flask. Since acetic acid is a liquid, it may also be measured by volume. Divide the mass of acid by its density (1.049 g/mL) to determine the volume (114 mL). Use either 120.1 g or 114 mL acetic acid to make the solution. Swirl the flask gently to mix the solution. Once the solution is at room temperature, dilute to the mark and invert the flask several times to mix.

1 g ml^-1 = 1000 kg m^-3 Density of water is 1 g ml^-1Water density in kg m^-3 = 1000 kg m^-3

one litre of 1.2 molar solution of glucose weights 1350g. what is notorious of solution

one litre of 1.2 molar solution of glucose weights 1350g. what is molarity of solution??

When potassium iodide is added to a solution of lead nitrate then a yellow precipitate is formed. 2KI + Pb(NO₃) --------> PbI₂ + 2KNO₃ Potassium Lead Lead Potassium Iodide Nitrate Iodide Nitrate

given the w/v is 5% so it means.. in 100ml soln you should have 5g of glucose . so , for 75gm glucose , you should have.. 15*100ml = 1500ml solution.