

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
8601. |
D 34.2 g of glucose is dissolved in 400 g of water.curate percentage by mass of glucose solution.(7.87 w/w) |
Answer» 7.8765 is the right answer 7.8765 is the right answer 7.876% is the right answer 7.876%is the correct answer |
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8602. |
A Solution is obtained by mixing 300 g of 25% Solution and 400 g of40%Solution by mass. Calculate the mass percentage of the resulting Solution. |
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8603. |
1.7 A solution is obtained by mixing 300 g of 25% solution and 400 g of 40%solution by mass. Calculate the mass percentage of the resulting solution |
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8604. |
12. A pULyB54 diagonals?13. One-fourth of a herd of camels was seen in the forest. Twice the square root of the herdhad gone to mountains and the remaining 15 camels were seen on the bank of a riveFind the total number of camels.8. If the(a) b9. If (1d oos e are the roots of the equation ax2 + bx + c = 0, prove that |
Answer» | |
8605. |
Define Zinc spectrum? Calculate the wavelength of various lines in hydrogen spectrum?Define spectrum? How they can classified explain? with example? |
Answer» Spectrum, inoptics, the arrangement according to wavelength of visible, ultraviolet, and infraredlight. An instrument designed for visual observation of spectra is called aspectroscope;an instrument that photographs or maps spectra is aspectrograph. Spectra may be classified according to the nature of their origin,i.e.,emission or absorption. Anemission spectrumconsists of all the radiations emitted by atoms or molecules, whereas in anabsorption spectrum, portions of a continuous spectrum (light containing all wavelengths) are missing because they have been absorbed by the medium through which the light has passed; the missing wavelengths appear as dark lines or gaps. |
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8606. |
The first ionization enthalpy values (in kJ mol") of group 13 elements are :B Al Ga In Tmol-] of group 13 elements are80w 577d you explain5his deviation from, the general trend579 558 589How would you explain this deviation from the general trend ? |
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8607. |
The wavelength range of the visiblespectrum extends from violet (400 nm)to red (750 nm). Express thesewavelengths in frequencies (Hz)(1nm 10-9 m) |
Answer» We know that v=λf where v is velocity,λ is wavelength and f is frequency. Range of spectrum is 400 nm to 750 nm which equals 400 nm=4×10⁻⁷ m750 nm=7.5*10⁻⁷m Here v=c=3*10⁸ m/s So, Upperlimit v=λf∴3*10⁸=4*10⁻⁷*f∴f=3*10⁸/4*10⁻⁷∴f=0.75*10¹⁵So f=7.5*10¹⁴ Hz Similarly The lower limit will be4*10¹⁴Hz Thus the range of spectrum in frequency is 4*10¹⁴ Hz-7.5*10¹⁴ Hz |
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8608. |
The wavelength range of the visiblespectrum extends from violet (400 nm)to red (750 nm). Express thesewavelengths in frequencies (Hz)(1nm= 10-m) |
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8609. |
(4) All TWhen heating PCl, then it decompose PCl, and Clin form of gas, The vapour density of gas mixture is70.2 and 57.9 at 200° C and 250°C. The degreeof dissociation of PC, at 200°C and 250°C is(1) 48.50% & 80% (2) 60% & 70%(3) 70% & 80%3(4) 80% & 90% |
Answer» | |
8610. |
hand writing questions |
Answer» refer this sitehttps://www.studenthandouts.com/handwriting-worksheets/ |
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8611. |
In nuclear fission process(1) lighter nuclei combine together (ii) heavy nuclei split(ili) heavy nuclei combine together (iv) of the above |
Answer» Theenergy of nuclear fissionisreleasedas kineticenergyof thefissionproducts and fragments, and as electromagnetic radiation in the form of gamma rays; in anuclear reactor, the energyis converted to heat as the particles and gamma rays collide with the atoms that make up thereactorand its working fluid, .. |
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8612. |
In nuclear fission process(i) lighter nuclei combine together (ii) heavy nuclei split(iii) heavy nuclei combine together (iv) of the above |
Answer» Ans :- Innuclear fission, an unstable atom splits into two or more smaller pieces that are more stable, and releases energy in theprocess.. option (2) |
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8613. |
(i) What is entropy of a system?(ii) Define lattice enthalpy.(ii) For the reaction 2Ae) +B 2De), AH12.98 kJ/mol. &ASo=-44. 1 x 10.3 kJ mol-1 K-1 .Calculate ΔGo for the reactionand predict whether the reaction may occur spontaneously. |
Answer» Entropy is an extensive property of a thermodynamic system. The second law of thermodynamics states that the entropy of an isolated system never decreases. Such systems spontaneously evolve towards thermodynamic equilibrium, the state with maximum entropy. The lattice energy of a crystalline solid is a measure of the energy released when ions are combined to make a compound. It is a measure of the cohesive forces that bind ions. Lattice energy is relevant to many practical properties including solubility, hardness, and volatility under numerical is there can u solve |
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8614. |
1. Select the odd one out:itttiie8Uptioncodeandthecorrd) carbon dioxidea) sugarb) sea waterc) distilled water |
Answer» Option Bas a) Sugar : Sugar is a compound as it consists of two or more type of atoms such as Carbon, Hydrogen and Oxygen. b) Sea water is a mixture as it consists of different compounds /ions present in sea but they are not bonded to each other. c) Distilled water : Pure substance is a compound that consists of only Hydrogen and Oxygen which are covalently bonded to each other. d) Carbon Dioxide : It is a covalent compound as it consists of Carbon |
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8615. |
1L capacity is divided into two equal compartments by a thin partition which are filled with 2g H, and 16gmCHrespectively. The pressure in each compartment is recorded as P atm. The total pressure when partition is removed will be(A) P(B) 2P(C) P/2(D) P/4 |
Answer» As pressure in each comparment is P atm . After the partition is removed The Total pressure will be P atm |
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8616. |
48. The rate constant of a first order reaction is10-3 sec-1. At a reactant concentration of0.02 M, the rate of reaction would be-(1) 8 x 10s M sec (2) 4 x 10 M sec(3) 2 x 101 M sec (4) 4 x 101 M sec |
Answer» The rate of reaction is K*[A] here k = 4*10-³ and [A] = 0.02 = 2*10-² so, rate of reaction is 8*10^(-5)M/s option A. |
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8617. |
How many significant figures are their in 210.00?b] Write 0.001625 in scientific notation. |
Answer» 1. 6 significant figures. 2. scientific notation, 1.625 × 10^-3 |
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8618. |
Sample Problem 12. If 1 g of sulphur dioxide contains r molecules, what will be the number of m1 g of methane? (S 32 u, O 16 u, C 12 u, H 1 u) |
Answer» 1 mole of SO2= 64g 1g of SO2= -----mole? = 1/64 mole From the given data 1/64 moles sulphur dioxide contain x molecules We know that equal moles of all gases will have equal number of molecules. Hence 1/64 moles of Methane Contains x molecules of methane Now we should find out the number of moles in 1g of methane 1 mole of methane = 16g 1g of methane = ------Mole? = 1/16 mole Since,1/64 mole of methane = x molecules 1/16 mole of methane contains = -------molecules? = x * 64/16 = 4x molecules |
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8619. |
lain Classificaion af bell & bell dine wwith neat dinguam |
Answer» The most common types of belt drives include: Round belts Round belts are are generally made of rubber. This type of belt is generally used for light loads, such as in a sewing machine or a vacuum cleaner. V belts V belts are arguably the most widely used belts in industry. V belts have a V shaped cross-section, which rests against the side of V pulley under tension. The V shaped cross-section prevents belt from slipping off. Flat belts Flat belts are also used to transmit power from one shaft to another. They are generally classified as either small woven endless belts or higher power flat belts. The woven endless belts are especially useful where minimum vibration is required at the driven pulley due to semi-elastic material used in construction. The higher power flat belts are often useful because they eliminate the need to high belt tension used to grip pulleys, which in turn reduces the load on the shaft bearings. The material used for high power flat belts is sticky yet abrasion-resistant rubber compounds. Timing/toothed belts Timing belts are toothed belts that use their teeth for power transmission, as opposed to friction. This configuration results in no slippage, and therefore, the driving and driven shafts remain synchronized. It’s more expensive to manufacture due to complexity of the belt and pulley shapes. |
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8620. |
6. Four measuring cylinders with least counts1.0mL, 0.5mL, 0.2mL and 2.5mL are given. Which oneamong the following is suitable for finding density of a solid?[a] 0.5mLb] 1.0mL[c] 2.5mL[d] 0.2ml |
Answer» 1. Least count is the smallest value that can be measured accurately by the given instrument 2. For the accurate measurement , the cylinder with minimum value of least count is preferable. 3. Answer : 1ml |
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8621. |
QuoA student carries out the decomposition reaction of leadritrate to form three simples substances. One of thesubstances formed during this reaction is a lonencoloured gas. Write a chemical equation for the reactionand name the substances formed. |
Answer» The yellow gas is NO2. PbNO3 gives PbO+NO2+H2O |
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8622. |
A solution containing 30 g of non-volatile solute exactly in 90 g of water has avapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added tothe solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate() molar mass of the solute (ii) vapour pressure of water at 298 K.19 |
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8623. |
A solution containing 30 g of non-volatilesolute exactly in 90 g of water has a vapourpressure of 2.8 kPa at 298 K. Further 18of water is added to this solution. The newvapour pressure becomes 2.9 kPa at 298 K.Calculate(i) the molecular mass of solute and(ii) vapour pressure of water at 298 K.75. |
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8624. |
I1. Regarding chemicals in a laboratory, the following shouldbe avoided:A. Label all bottlesB. Display the warning chartsC. Dangerous spillable chemicals should be kept at the topD. Everyone should be well trained to handle accidents |
Answer» A. label all bottle s A. label all bottles |
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8625. |
1.State Raoult's law and explain it in case of volatile solute. |
Answer» Raoult's Law: Vapor Pressure andVolatile Solutes(in Ideal Solutions) ... In asolutionwith a nonvolatilesolute, only the pure vapor of the solvent is present above thesolution. 100% of the nonvolatilesolutestays insolution, none of it enters the vapor above thesolution. |
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8626. |
11.8 While separating a mixture of ortho and para nitrophenols by steamdistillation, name the isomer which will be steam volatile. Give rcason. |
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8627. |
Q.6. Name the electrie device that converts mechanical energy into eleetricalenergy. Draw the labelled diagram and explain the principle involved in this device.Ans. An electric generator is the electric device that converts mechanical energy iata |
Answer» Electric generator. Anelectricgenerator is adevice which converts mechanical energy into electrical energy. we Ageneratorconverts mechanical energy into electrical energy, while a motor converts electrical energy into mechanical energy. Both the devices work because ofelectromagneticinduction, which is when a voltage is induced by a changing magnetic field. The modern-daygeneratorworks on theprincipleof electromagnetic induction discovered by Michael Faraday in 1831-32.Faraday discovered that the above flow ofelectriccharges could be induced by moving an electricalconductor, such as a wire that containselectriccharges, in a magnetic field. A generator forces electrons to flow through an externalelectricalcircuit. It is somewhat analogous to a water pump, which creates a flow of water but does not create the water inside. |
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8628. |
Write two main functions of carbohydratesin plants. |
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8629. |
2.5 Explain London forces with the help of suitableexamples. |
Answer» London dispersion forces (LDF, also known as dispersion forces, London forces, instantaneous dipole–induced dipole forces, or loosely van der Waals forces) are a type of force acting between atoms and molecules. They are part of the van der Waals forces. The LDF is named after the German-American physicist Fritz London. The LDF is a weak intermolecular force arising from quantum-induced instantaneous polarization multipoles in molecules. They can therefore act between molecules without permanent multipole moments. |
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8630. |
1The number of molecules in 3 mokes of co, area) 18 x 10b) 6 x 10c) 12 x 10 |
Answer» Number of molecules will be 3*6*10^23=18*10^23 molecules. |
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8631. |
11. If 1021 molecules are removed from 200 mg of CO2, then the number of moles of CO2left are(A) 2.88 x 10(C) 4.54 x 10(D) 1.66 x 102(B) 1.66 x 10 |
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8632. |
3. 100 ml of PHs on heating forms P and H2. The volume change in the reaction isAYan increase of 50 ml B) an increase of 100 ml an increase of 150 ml D) a decrease of S0 ml |
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8633. |
3) 8. From 392 mg of H2S04. 1,204 x 10 molecules are removed. The moles of H2S04 left is20 x 10-B) 1.2 x 10-3C) 4.0 x 10-3D) 1.5 x 10-3 |
Answer» This question applies the concept of Avogadros law. Avogadros constant is as follows : 1 mole of a substance = 6.022 × 10²³ molecules. How many moles are equivalent to 1.2 × 10²¹ molecules We get this by : (1.2 × 10²¹) / (6.022 × 10²³) = 0.001993 molesThe amount of moles in 392mg of H₂SO₄ is : 392 mg = 0.392 g Molar mass of H₂SO₄ = 98g/mol Moles = mass in grams /molar mass = 0.392/98 = 0.004 moles The amount of moles removed = 0.001993moles Remaining moles = 0.004 - 0.001993 = 0.002007 moles |
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8634. |
0.6Concentration of Glucose (CHO) in normal blood is approximately 90 mg per 100 mL. What is themolarity of glucose in blood ?Ans. 0.005 M)of |
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8635. |
pH scale Kya hai |
Answer» किसी भी विलयन का pH मान एक संख्या है जो विलयन की अम्लता और क्षारकता को दर्शाता है| किसी भी विलयन का pH मान संख्यात्मक रूप में द्रवीभूत हाइड्रोजन आयन (H+) के विलोम के लघुगणक के बराबर होता है। इसलिए किसी विलयन के pH को हाइड्रोजन आयन के ऋणात्मक लघुगणक के रूप में जाना जाता है। इस लेख में हम pH स्केल पर आधारित वस्तुनिष्ठ प्रश्न दे रहे हैं जिससे आपको विभिन्न परीक्षाओं की तैयारी करने में मदद मिलेगी, साथ ही pH स्केल की अवधारणा के संबंध में आपकी समझ और भी विकसित होगी| |
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8636. |
hansane wali gas ( laughing gas) ka formula kya hai |
Answer» N2O is the formula of laughing gas |
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8637. |
3.An acid which can decolourise purple coloured potassium permanganate solution is:--/(a) sulphuric acid(c) carbonic acid(b) citric acid(d) hydrochloric acid |
Answer» An acid which can decolourise purple coloured potassium permanganate solution is: (a)sulphuric acid. wrong answe this is question of class 10 not class 8plz not answer again🤓🤓🤓🤓🤓 |
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8638. |
How to prepare 250 ml of O.1 N H2SO4? (Atomic weight: H-1, S 32,0-16) |
Answer» 0.1 equivalent will weights to 4.9g. Hence by adding 4.9g sulphuric acid to water and making the solution to 1000ml we get0.1 N solution of sulphuric acid. |
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8639. |
Mention the name given to the number of 6.022 x 1023 particles. |
Answer» Avogadro number is the name given to the 6.022× 1023 particles.It is the number of units in one mole of any substance. |
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8640. |
29. The mass of oxalic acid crystals (H,C,O, 2H,O) requito prepare 50 mL of a 0.2 N solution is:(a) 4.5 g(c) 0.63 g(b) 6.3 g(d) 0.45 g |
Answer» how did u get 0.5 litres50ml =0.05 litrs 0.2 × 63 × 50/1000 = 0.63g ok got it |
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8641. |
88. What volume is occupied at N.T.P. by(i) 1.4 g of nitrogen(ii) 6.023 × 1021 molecules of oxygen(iii) 0.2 mole of ammonia ? |
Answer» i) Mole = Volume/22.4 (At S.T.P or N.T.P.) So according to this formula 1 Mole of any gas occupies 22.4 litres at N.T.P. For Nitrogen gas 1 mole = 14g so, for given 1.4 g = 1/14 × 1.4 = 0.1 mole Since 1 mole occupies 22.4 L at NTP so, 0.1 mole will occupy 22.4×0.1 L at NTP Hence 1.4 g of Nitrogen gas occupy 2.24 L at NTP. but answer is1.12 L |
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8642. |
(2) Same(4) One fourth(1) Double) TripleWhen x molecules are removed from 200 mg ofN,O, 2.89 x 10-3 moles of N20 are lef. x will be(1) 1020 molecules (2) 1010 molecules(3) 21 moleculesWhich has maximum molecules?n afe(4) 1021 molecules |
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8643. |
15. 112.0 ml of NO, at latm & 273 K was liquefied, the density of the liquid being 1.15 gm/ml. Calculatethe volume of and the number of molecules in the liquid NO(A) 0.10 ml and 3.01 x 1022(C) 0.20 ml and 6.02 x 1023(B) 0.20 ml and 3.01 x 1021(D) 0.40 ml and 6.02 x 1021 |
Answer» no consept |
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8644. |
oxygen.14. How many molecules of water of crystallisation are present in 252 mg of crystalline oxalic acid(H,C,042H2O)?(Ans. 2.4088 x 1021)D15. Find out the number of hydrogen atoms in 0.02 mole of CuSO4.5H,O. (Ans. 1.2044 x 1023)1R Find the number of moles of so 2-in 24. ALSO |
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8645. |
SRI CHAITANYA IIT ACADEMY, INDIAS. Write the IUPAC name of the following.NH2(0) CNO21l |
Answer» i) 3-chloro-propanal ii) 4-nitro-benzene-amine / p-nitro aniline. |
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8646. |
11. The weight of molecule of the compound CoHz2is60(a) 1.4 x 1021 g(c) 5.025 x 1023 g(b) 1.09 x 1021 g(d) 16.023 x 1023 g |
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8647. |
74. One mole of CO2 containsa) 602 x 1023 atoms of Cc) 18.1 x 1023 molecules of CO2b) 6.02 x 10B atoms of Oc) 3 g atoms of CO2 |
Answer» One mole of CO2 contains 6.02 x 10^23 atoms of C12.04 x 10^23 atoms of O6.02 x 10^23 molecules of CO2 |
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8648. |
(b) There are two -NH2 groups in semicarbazide. However, only one is involved in the formation ofsemicarbazones |
Answer» There are two 2NHgroup in semicarbazide. However,onlyone isinvolvedin theformationofsemicarbazone. This is because one N atom isinvolvedin resonance with carbonyl carbon atom and thus its lone pair is not available for bonding 🙂🙂🙂🙂🙂 |
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8649. |
4. A rare and expensive fibre called cashmere is obtained froma. camel.b. rabbitc. goat. |
Answer» c) is the right option |
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8650. |
The energy of electron in first Bohr's orbit of Hatom is -13.6 ev. What will be its potentialenergy in n 4th orbit -(A) 13.6 eV(C) -0.85 ev(B) -3.4 ev(D) -1.70 eV |
Answer» potential energy is 2 times that of the total energy and total energy on nth orbital is given by E = -13.6*z²/n² eV => E = -13.6*1/(4)² = -0.85eV but P.E = 2 T.E = -1.70 eV so, option D |
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