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8651.

35. In hydrogen atom, energy of first excited stateis-3.4 eV. Then find out K.E. of same orbitof hydrogen atom(a) +3.4 ev(c) 13.6 eV(b) +6.8 eV(d) +13.6 eV (2002)

Answer»

option a is the answer.KE is the energy with which the electron moves in the orbit hence The energy is same but positive so answer is 3.4eV

8652.

73. The number of atoms in 4.25 g of NH3 is approximately(c) 4x 102(a) 1 1023(b) 2 x 10236 x 1023

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1 mole of Ammonia is 17gm.

{NH3= N(14gm)+ H(1gm)+H(1gm)+H(1gm)}

Now 1 mole of any substance at STP always has Avogadro's number of molecules i.e. 6.023*10^23.

So 1 mole or 17gm of Ammonia will have 6.023*23 molecules of NH3.

Here it's 4.25gm or 4.25/17= 0.25moles of Ammonia.

Therefore 0.25 moles of Ammonia will have 0.25*6.023*10^23 molecules.

As 1 molecule has 4 atoms. (1 of Nitrogen and 3 hydrogen),

We will have 4* 0.25* 6.023*10^23 atoms in 0.25 moles of Ammonia.

Answer is 4.25gms will have 6.023*10^23 number of atoms in it.

8653.

La:Whichone of the following statements is incomect ?A) One gram atom of carbon contains Avogadro's number of atoms.B) One mole of oxygen gas contains Avogadro's number of moiecules.C) One mole of hydrogen contains Avogadro's number of atoms.) One mole of electrons stands for 6.02 x 1023 electrons

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the third statement is incorrect because one mole of hydrogen gas contain 12.04*10^23 atoms.and Avogadro's number of molecules.

8654.

51. The 2. of a photon (in Å) having energy equal toone electron volt is

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12400/E(in eV) =12400A

8655.

.ean GI om contains one electronand one proton uill it carry anycharge or nor?2.

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8656.

tell me 5points about bases

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Bases change the colour of litmus from red to blue.

They are bitter in taste.

Bases lose their basicity when mixed with acids.

Bases react with acids to form salt and water. This process is calledNeutralisation Reaction

They can conduct electricity.

Bases feel slippery or soapy.

Some bases are great conductors of electricity.

Bases like sodium hydroxide, potassium hydroxide, etc are used as electrolytes.

Alkalis are bases that produce hydroxyl ions (OH-) when mixed with water.

Strong alkalis are highly corrosive in nature whereas other alkalis are mildly corrosive.

The pH value of bases ranges from 8-14.

8657.

One mark questionsName the prokaryotic cell lacking cell wall?hat is the phenomenon knownas?

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All prokaryotic cells have a stiffcell wall, located underneath the capsule (if there is one). This structure maintains the cell’s shape, protects the cell interior, and prevents the cell from bursting when it takes up water.

The cell wall of most bacteria containspeptidoglycan, a polymer of linked sugars and polypeptides. Peptidoglycan is unusual in that it contains not only L-amino acids, the type normally used to make proteins, but also D-amino acids ("mirror images" of the L-amino acids). Archaeal cell walls don't contain peptidoglycan, but some include a similar molecule called pseudopeptidoglycan, while others are composed of proteins or other types of polymers

8658.

10. Which of the following reactions matches the following sentence: Whenhydrogen peroxide is violently shaken, it forms gaseous oxygen and water. Twomolecules of hydrogen peroxide (H2O2) decompose into two molecules of H,0 andone molecule of o, 24,0+02->24_02© 2H,0 + 20,->H,02© 240-24_0+02H,->H,0+02

Answer»

answer (d) is thecorrect answer

option (D) is a correct answer

answer D is the correct answer

8659.

Q. 24 One electron is present in the outermost shell of the atom of an elementX. What would be the nature and value of charge on the ion formed ifthis electron is removed from the outermost shell?

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The ion formed by losing that one electron will be a positive ion with +1 chargeexplanation- an atom contains equal amount of positive proton and negative electron .now 1 electron get removed which means that no. of proton is one more than no. of electron and so, it will form positive ion with +1 charge .

8660.

Short Answer Type Questions -IIBond angle in PH: is higher than in PH3-Why?

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PH3(Phosphine) is a hydride of Phosphorus. Phosphine is a gas and has pyramidal structure. Phosphorus involved is sp3hybridized.

Now both PH4+and PH3have sp3hybridization state for phosphorous .In PH4+,all the four orbitals are bonded, whereas in PH3,there is a lone pair of electrons on Phosphorous .In PH4+, the HPH bond angle is tetrahedral angle of 109.5°.But in PH3,lone pair- bond pair repulsion is more than bond pair-bond pair repulsion so that bond angles become less than normal tetrahedral angle .The bond angle in PH3is about 93.6°.

8661.

balance the equation by ion electron methodP4+oh- gives ph3+ h2po2-in basic medium

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Balanced chemical equation is:

4P4+ 12OH-+ 12H2O= 4PH3+ 12H2PO2-

8662.

24) Discuss the shapes of the following moleculesusing the VSEPR model.BeCl2, BCl3, SiCL4, PH3, H2S

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8663.

36. Why is the bond angle in PH3 moleculelesser than that in NH3 molecule?(412008)

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Thebondpair inNH3is close to N in N-Hbond thanthebondpair in P-HbondinPH3. This is because the size of the nitrogen is smallthanphosphorus . As a result , the force of repulsion between the bonded pair of electrons inPH3is morethaninNH3. Therefore thebond angle in PH3molecule lesserthaninNH3.

8664.

How many carbon atoms in the moleculeHOOC-(CHOH)2-COOH are asymmetric :(MP PMT 2001)(2) 2(4) of these(3)3

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asymmetric carbons are chiral carbons having all the valancy different

so, here the structure is OH OH | | HOOC-C-C-COOH | | H H

=> both the centre carbons are chiral so, 2 is ✓

8665.

(a) CH,CH,OH(q) (CH,),COH(3) CH,OH),CHOH)

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CH3OHas in alcohols primary alcohols more acidic than rest.This is because the strength of thealcoholas anacidis dependent on the corresponding strength of its conjugate base, the alkoxide ion.

8666.

1 1/2 moles of oxygen combine with Aluminimum to form AL O, then weight of Aluminium metal used in thereaction is (al = 27) -2A1+ 02 —>A1,02(440 cm

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The balanced reaction is 4Al + 3O2= 2Al2O3

​3moles of O2requires 4 moles of Al0.5 moles of O2requires = 4 X 0.5/3 = 2/3 moles of Al

Mass of 2/3 mol of Al = 2/3 mol X 27g/mol= 18 g

Where 27 is the mass of 1 mole Al

Answer:18gm

8667.

\begin{array}{l}{\text { Calculate the bond enthalpy of } \mathrm{N}-\mathrm{H} \text { in } \mathrm{NH}_{3}(\mathrm{g})} \\ {\text { Given } \frac{1}{2} \mathrm{N}_{2}(\mathrm{g})+\frac{3}{2} \mathrm{H}_{2}(\mathrm{g}) \rightarrow \mathrm{NH}_{3} ;(\mathrm{g}) \mathrm{D}_{f} \mathrm{H}^{\circ}=-46 \mathrm{kJmol}^{-1}} \\ {\frac{1}{2} \mathrm{H}_{2}(\mathrm{g}) \rightarrow \mathrm{H}(\mathrm{g}) ; \Delta r H^{\ominus}=218 \mathrm{kJmCl}^{-1}} \\ {\frac{1}{2} \mathrm{N}_{2}(\mathrm{g}) \rightarrow \mathrm{N}(\mathrm{g}) ; \Delta r H^{\ominus}=973 \mathrm{kJmol}^{-1}}\end{array}

Answer»

To find the bond enthalpy, you subtract the energy of the bonds formed (since they release energy) and add the energy of the bonds broken (since you need to supply energy).

1/2 an N2 bond is 941/2 = 470.5 kJ/mol3/2 H2 bonds = 3×436/2 = 654 kJ/molTotal energy = bonds broken-bonds formed = (470.5 + 654) - 3(N-H)

Total energy = -46.3 kJ/mol

Therefore, -3(N-H) + 1124.5 = -46.3

3(N-H) = 1124.5 + 46.3 = 1170.8

(N-H) = 1170.8/3 = 390.2667 ≈ 390 kJ/mol

Remember: total energy of reaction = (total energy of bonds broken) - (total energy of bonds formed)

8668.

(D) 0.2 and 3.1 × 102365Calculate the weight of nitrogenpresent in 0.5 moles of NH(A) 8 g(C) 1 g3'(B) 9 g(D) 7 gClass IX -Chemist

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Nitrogen present in 1 mole ammonia =1 mole=14gSo nitrogen present in 0.5 mole ammonia =14g×0.5=7g

8669.

B2C) NHC() + Ca(OH), (s) - CaCl, (8) + NH, (g) + H20 (1)

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Balanced Chemical equation:

2NH4Cl(s) + Ca(OH)2(s) -----> CaCl2(s) + 2NH3(g) + 2H2O(l)

8670.

9 Whichof the folliowing is the best option to stop the burning sensation when you eat something spicy(a) Water(b) Milk(c) Soft Drink(d) Ice

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Water is the best option to stop the burning sensation

8671.

9. Which of the following is the best option to stop the burning sensation when you eat something spicy?(a) Water(c) Soft Drink(b) Milk(d) Ice

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milk is the best option, as it will neutralize the effect.

thanks

8672.

56. 20.0 kg of N2 (g) and 3.0 kg of H2(8) are mixed to produce NHs (g). The amount of I(NH 31 )(g) formed isA) 17 kgB) 34 kgC) 20 kgD) 3 kg

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8673.

Problem 1.550.0 kg of N2 (g) and 10.0 kg of H2 (g) aremixed to produce NH, (g). Calculate theNH, (g) formed. Identify the limitingreagent in the production of NH, in thissituation.3

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thanks

8674.

50.0 kg of N, (g) and 10.0 kg of H, (g) aremixed to produce NH, (g). Calculate theNH, (g) formed. Identify the limitingreagent in the production of NH, in thissituation.

Answer»

Let us write the balanced equationN2 + 3H2 → 2NH3Now calculate the number of molesNumber of moles of N2 = 50 kg of N2 = 50 X 10 3 g/1 kg x 28g = 17.86 x 10 2 mole

Number of moles of H2 = 10 kg of N2 = 10 X 103 g/ 1 kg x 2 = 4.96X 103 mol

According to the above equation 1 mole of N2 reacts with 3 moles H2.That is 17.86 x 10 2 mole of N2 reacts with ------moles of H2= 3/1 X 17.86 x 10 2 = 5.36 x 103 moles.Here we have 4.96X 103 mol of hydrogen. Hence Hydrogen is the limiting reagent.Let us calculate the amount ammonia formed by reacting 4.96X103 moles Hydrogen 3 moles of hydrogen -------2 moles of NH34.96 x103 moles Hydrogen -----?= 4.96 x103 X ⅔= 3.30 x 103 moles of NH3

8675.

50.0 kg of N2 (g) and 10.0 kg of H, (g)are mixed to produce NH, (g). Calculatethe NH, (g) formed. Identify the limitingreagent in the production of NH, in thissituation.

Answer»

part 1

8676.

In the above reaction is - 2SO2+ O2 2SO3,(Irreversible), for the formation of one ton of SO,what would be the quantity of O2 required?(A) 0.20 Ton(C) 2.0 Ton(B) 0.02 Ton(D) 0.002 Ton

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160 gram of 2SO2 = 32 gram of O2Therefore , 1gram of SO2 = 32?160?1tonne=0.2 tonne

8677.

96. In stainless steel alloy, iron metal is mixed with:1. Cu and C 2. Cr and Ni 3.Cr and Sn 4. Cu and Niw w w. nfeiler metal hecome dark on prolonged exposure to air. This is

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Option b)Chromium and Nickel.

8678.

An alloy of Copper and Zinc is(1) Lead(2) Brass(3) Stainless Steel(4) Bronze

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Brass

8679.

What is the Willamson synthesis ?

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Ans :- The Williamson ether synthesis is an organic reaction, forming an ether from an organohalide and a deprotonated alcohol. This reaction was developed by Alexander Williamson in 1850. Typically it involves the reaction of an alkoxide ion with a primary alkyl halide via an SN2 reaction.

8680.

Toyully Il Cole. A reaction is first order in A and second order in B.(0) Write the differential rate equation(ii) How is the rate affected on increasing the concentration of B three times?(iii) How is the rate affected when the concentrations of both A and B are doubled?..

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8681.

What is the Willamson synthesis?

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Ans :- TheWilliamsonethersynthesisis an organicreaction, forming an ether from an organohalide and a deprotonated alcohol (alkoxide). Thisreactionwas developed by AlexanderWilliamsonin 1850. Typically it involves thereactionof an alkoxide ion with a primary alkyl halide via an SN2reaction.

8682.

y Short Answer Type Questions1. Name the commercial unit of measurement of energy

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Commercial unit of energy is the kilowatt-hour (kWh).

8683.

Very Short Answer Type Questions1. What are the conditions for something to be called 'matter?

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8684.

,CuSO4 .+ 2NaOH--> Na2SO4 + Cu(OH)2ψWord equation:State the colour of the products.

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copper sulfate + sodium hydroxide → copper hydroxide + sodium sulfate

CuSO4+ 2NaOH → Cu(OH)2+ Na2SO4

(blue solution +colourless solution → blue precipitate +colourless solution)

Like if you find it useful

8685.

b Write the steps involved in the preparation of KMnO, from pyrolusite ore

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hit like if you find it useful

8686.

Vrite the steps involved in writing a word equation' of a reaction ?

Answer»

Steps of Balancing a Chemical Equation

Identifyeach elementfound inthe equation. The number of atoms of each type of atom must be the same on each side of the equation once it has been balanced.

What is the net charge on each side of the equation? The net charge must be the same on each side of the equation once it has been balanced.

If possible, start with an element found in one compound on each side of the equation. Change the coefficients (the numbers in front of the compound or molecule) so that the number of atoms of the element is the same on each side of the equation. Remember, to balance an equation

8687.

How will you bring about the following conversions in not more than two steps?(i) Propanone to propane. (ii) Benzoic acid to benzaldehyde.(c)

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8688.

. Curved surface area of a cone is 308 cm and its slant height is 14 cm. Find(i) radius of the base and (ii) total surface area of the cone.

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8689.

n the position of the element having outer electronic configuration,(0 n st npt for n 3, Assign-1) d2 ns for n 4 and() -2)f (1) d ns for n-6 in the periodic tableIm) (n-

Answer»
8690.

why does dogs generally hang out their tongue in summer

Answer»

Dogs have high body temperature.To regulate their body temperature dogs hang out tongue in summer.Dogs have fewer sweat glands to sweat and regulate the temperature.

8691.

A metal x when dipped in aqueous solution of Aluminium sulphate, no reaction is observed whereas when dipped it aqueous solution of FeSO4, pale green solution turns colourless . Identify x and write the chemical equation for the reaction.

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The metals copper, platinum, silver gold are also less reactive when compared to hydrogen even they do not replace hydrogen from water or acid.

For Examples for metal-displacement reactions: iron from ferrous sulphate solution and Zinc can displace copper from copper sulphate solution, hence zinc is more reactive than iron and copper.

Al2 (SO4)3 + Zn ---- No reaction. FeSO4 + Zn ------------ ZnSO4 + Fe

8692.

4Theon of three elements in the periodic table is shown belowGroup 1Group 18A.Giving reasons, explain the following:(a) Element A is a non-metal.(b) Element C has a smaller atomic size than element B.

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Element A is a Non-Metal because group 18 contain all Noble elements.

b- Atomic radius decreases in moving left to right in a period . this is due to increse in nuclear charge which tends to pull the electron closer to the nucleus and reduce the size of the atom.

8693.

Write scientific reasons.Lemon or tamarind is used forcleaning copper vessels turnedgreenish.

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Copper reacts with carbon dioxide in air to form copper carbonate. As a result, copper looses its shiny brown surface forming a green layer of copper carbonate.

The citric acid present in the lemon or tamarind neutralizes the basis copper carbonate and dissolves the layer. Therefore, tarnished copper vessels are cleaned with lemon pr tamarind juice to give lusture to the surface of the copper vessel.

8694.

Give scientific reasonsWhile preparing dil. Sulphuric acid from concentrated conc. Sulphuric acid in thelaboratory the concentrated sulphuric acid is, add slowly to water with constantstrirring.iv.

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While Preparing Dilute Sulphuric Acid ina Laboratory,Acidisadded slowlytowater(Wateris neveraddedto theacidas it will be the exothermic process which can cause Fatal to the person) with constant stirring because it will not cause any harm to the Person or any Apparatusinthe laboratory.

8695.

give reason conc hno3 can be stored in aluminum container

Answer»

Ans :- Nitric acidreacts withaluminiumand forms a protective layer i.e. Al2O3. This protective layer makesaluminium unreactive towardsHNO3and therefore, itcan be stored in aluminium containers.

8696.

balance the equation. Cu+HNO3--> Cu(NO3)2+H2O+NO2

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8697.

1. A redox reaction is shown in the diagrams. Identifythe reaction.A metal rodai: : : :Blue solution:::DESea-Brown deposition2十(a)(b)(e)Zn(s) + Cu(aq) → Zr ) + Cu(s)Cu(s) + 2Ag(aq)-→ Cu )+2Ag(s)2Ago + )Cuo

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8698.

CAREER INSTICE, Which of the followin29Which of the following change represents adisproportionation reaction (s):(1) Cl2 + 2OH-→ ClO-+ Cl+ H2O(2) Cu2O +2H->Cu+ Cu?* + H2O(3)2HCuC, ㅡ dilution with→ Cu+Cu2++4Ct + 2H+Water(4) All of the above

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option 4 is correct.

in all the case one element is reducing and oxidizing. this is called as disproportionation

8699.

For a cell the cell reaction isMg(s) + Cu (aq) -Cu(s) + Mg' (aq).If the S.R.P. values of Mg and Cu are -2.37vand +0.34v respectively, the e.m.f. of the cellis1) +2.03V3) +2.71V.2) -2.03V4)-2.71V

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8700.

surface of water remaining together?The above three activities (1.6, 1.7 and 1.8)suggest that particles of matter have forceacting between them. This force keeps theparticles together. The strength of this force ofattraction varies from one kind of matter toanother,uestionsWhich of the following arematter?Chair: air, love, smell hate.almonds, thought, cold. lemonsmell of perfume.

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chair.almond.air. lemon. perfume

chair,air,love,smell,almonds,lemon,smell of perfume

chair,air,almonds,lemon, smell of perfume

chair,air, almonds,lemon, smell of perfume

chair,slmond,leamon,perfume

chair, air, almonds, lemon

chair. almond. air. lemon. perfume

chair,air, almond,lemon, perfume