Explore topic-wise InterviewSolutions in .

When one s and one p orbital belonging to the same main shell of an atom mix together to form two new equivalent orbitals, the type ofhybridizationis calledsp hybridization. The new orbitals formed are calledsphybrid orbitals.

But why not on k

IN CASE OF1/12

1/12 mass of a carbon 12 atom is 1 a.m.u

1 a.m.u = 1/12 * 1.99e-23gm = 1.66e-24 gm

Suppose, the substance you are talking about is NITROGEN

mass of 1 nitrogen atom = 14 a.m.u

mass of 1 mole of nitrogen atom = 6.023e23*14*1.66e-24 = 14 gm

IN CASE OF1/6

1/6 mass of a carbon 12 atom will be 1 a.m.u

1 a.m.u = 1/6 * 1.99e-23gm = 3.31e-24 gm

Then,mass of 1 mole of nitrogen atom having 14 a.m.u will be 6.023e23*14*3.31e-24 = 28 gm

NOW......28gm/14gm = 2..........SO,the mass of one mole of the substance will be 2 times of initial.

what is atomic mass unit to in the relation A+B-AB2

b molecular mass because r.m.s is directly depend on it

c) is correct according to formula as it depends on temperature and molecular mass

a-18b-63

a) 18ub) 63u that is answer to your question

Energy flow through an ecosystem is one way, because when theenergyenters the plants (from the sun) during photosynthesis.Thisenergyis then passed on from one organism to another in a food chain but it does not come back. Thus energy flow in an ecosystem is unindirectional.

please give me shorty answer

for zero order reaction the formula for conc. at time t is Ct = C°-kt 0.08 = 0.1 -k(10) => k = 0.02/10 = 0.002M/min now half life is when the conc. of A = 0.05M so t = 0.05/k = 0.05/0.002 = 25min. and completion time is 2times the half life. = 50min. option C.

Only metal liquidat room temperature is Mercury (Hg), andonly non metal liquidat room temperature is Bromine (Br).Answer:MetalMercury andNon-metalBromine exists inliquidstate in room temperature.

bromine is the only liquid non metal

bromine is the right answer.

Onlymetal liquidat room temperature is Mercury (Hg), and onlynon metal liquidat room temperature is Bromine (Br). Answer:MetalMercury andNon-metalBromine exists inliquidstate in room temperature

bromine is the non metal that occurs as liquid

Bromine is the non metal occur in liquid state...

As 4 moles react to form 2 moles of product therefore 20 atm pressure will react to for just 10 atm pressure thus net pressure will 90 atm.

100-20+10=90

N2+3H2=2NH3; As we know N2+H2=100atm then; Partial pressure of N2 &H2 be pN2 +p3H2=P +3P=4P 4P=100P=25 as we know 20% mixture react means α=.2 Acc.to Formula, α=x÷P; x=5 So, N2+3H2=2NH3 Intially. 25 75 0 At Eq. 25-x 75-3x 2x 25-5 75-15 2(5) 20 60 10 P=20+60+10=90

(I) Ammonia- Nitrogen, Hydrogen(ii)Potassium sulphate- Potassium, Sulphur, Oxygen

A option is correct

1.... thermal dissociation ... since heat is there.2. ... decomposition reaction.... 3..... displacement reaction.4..... double decomposition reaction.5...... endothermic reaction ... since ∆ is there..

2^5=2*2*2*2*2=32

this is an example of double displacement reaction

as the following compound both the ions are exchanged hence it is double displacement reaction.

explain it

1.7 g of the ammonia contains (6.022× 10²³) ×1.7/17atoms. Now, 1 atom of the Ammonia contains 7 + 3 electrons = 10 electrons. ∴6.022× 10²² atoms of the Ammonia contains 10 ×6.022× 10²² electrons. Hence, the number of the electrons in 1.7 g of the Ammonia is6.022× 10²³ electrons.

both gases are initially at the same absolute temperature T,

Let Vo=the initial volume of oxygen=1 L=0.001 cubic meters

The #moles of oxygen, No, is then by The Ideal Gas Law

No=PoVo/(RT)

Since Po=1 atm = 101,325 Pascals

No=(101,325 Pa)(0.001 m^3)=101/(RT)

Vn=the initial volume of nitrogen=0.002 m^3

Pn=the initial pressure of nitrogen=101,325/2=50,000 Pa

Nn=the #moles of nitrogen=(PnVn)/(RT)

=(50,000 Pa)(0.002 m^3)/(RT)=50/(RT)

The combination of the two gases forms a new gas with

N=No+Nn moles=150/(RT)

The volume of that gas is given as V=1 L=0.001 m^3

The pressure is then

P=NRT/0.001=(150/RT)(RT)/0.001

=150/0.001=150,000 Pa=1.5 atm

This was probably not the fastest solution but it’s correct

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Convert the KE from eV to Joule.

1eV=1.6⋅10^−19J

500eV=500×1.6⋅10^−19 = 8×10^-17J

While the mass of proton is well defined, we must find its velocity.

m = 1.67×10^-27 kg

KE = 8×10^-17 J

KE = 1/2×m×v^2

v^2 = KE/0.5×m

v = (KE/0.5×m)^1/2

v = (8×10^-17/(0.5×1.67×10^-27))^1/2

v = (16/1.67)^1/2 × 10^5 = 2.4 × 10^5 m/s

The momentum is given as:p= m×v = 1.67×10^-27 × 2.4×10^5 = 4 × 10^-22 kg. m/s

While the Plack constant is defined, the De Broglie wavelength is given as:

λ = h/p

h = 6.63 × 10^-34 m^2⋅kg/s(Planck constant)

λ = 6.63 × 10^-34/4 × 10^-22 m

The De Broglie wavelength of proton with 500 eV kinetic energy is:

λ = 1.657 × 10^-12 m

10 mol hoge 180 gram water par

dash mol hoga 180 gram water💧 par

10 mol h 180 gram water ma

In IF7 out of 7 Flourine atoms 5 of them are placed on a plane in Pentagon shape .In remaining 2 flourines one is placed above the plane and other below the plane each at 90 degrees

(a)-3(b)-5(c)-4(d)-2

Horizontal rows are periodsHelium is in zero group

That completely depends on which C=C are you talking about. If you are talking about the one which is attached to Methyl substitute then there are 3 -alpha Hydrogens otherwise rest have 0-alpha Hydrogen.

you have given initial [NH3].

If [NH3] remaining = 1 mole/L, then 1mole/L reacted2NH3(g) N2(g)+3H2(g).

So change in concentration of NH3 = -1 mole/L.

This means that because 2 mole NH3 make 1 mole of N2, the change in [N2] will +0.5mol/L and that for H2 will be +1.5mol/L. and equilibrium concentration of NH3 will be 1 mole/LPlug into Keq= [N2][H2}^3/[NH3]^2 and find Keq=(1.5^3)(0.5) = 1.687 nearly equal to 1.7

but given answer is B

ethene

but why for addition reaction only

start by looking atalkenes, or organic compounds that have at least one double bond between carbon atoms. The double bonds in alkenes arecovalentbonds, meaning that electrons are shared between the atoms

Double bonds can have sigma and pi bonds. Sigma bonds are pretty strong, whereaspibonds are a little weaker. The electrons in the pi bond move around a little more and are more likely to be attacked byelectrophiles, or things that are attracted to the negative portion of a compound.

Think of electrophiles as the home wreckers of the organic chemistry world. The suffix 'phile' means 'to like' or 'attracted to', and electrons are negative, so you can see how electrophiles get their name. And these electrophiles like to break up those double bonds by attacking the pi bonds. Electrophiles typically have a positive charge. So maybe electrophiles aren't really home wreckers. I mean, they're not breaking up a marriage, but they are breaking up double bonds, so maybe there's some similarity? No? Okay, okay. Let's take a closer look at some reactions.

Addition Reaction

In anaddition reaction, two compounds come together to form one larger compound. Here, we will discuss the addition reactions of alkenes. Let's take a look at a few examples so you can see what an addition reaction looks like.

Let's look at the reaction of hydrogen bromine (HBr) and propene (C_3H_6).

Here, HBr will become the electrophile. Bromine hogs the electrons in the HBr bond, thus making the hydrogen slightly positive and the bromine slightly negative. See image A.

is it correct answer

Henry's law states that the solubility of a gas in a liquid is directly proportional to the pressure of the gas. Further mole fraction of the gas in a solution is proportional to the partial pressure of the gas.Partial pressure of the gas in solution= KH x mole fraction of gas in solutionorwhere KH is Henry's law constant.(i) To increase the solubility of CO2 in soft drinks and soda water, the bottle is sealed under high pressure.(ii) At high altitudes, the partial pressure of oxygen is less than that at the ground level because the atmospheric pressure is less. Low blood oxygen causes anoxia.

High compressibility of gases is very useful to us.

Due to their high compressibility :

1. Gases can be easily liquefied into very small volumes and stored in liquid form Eg in LPGA cylinders and used in homes.

2. Balloons can be easily filled with air.

3. Compressed natural gas is used as fuel in vehicles.

4. A sponge has holes filled with air and this makes it easy to compress it.

Compounds of lithium are partially soluble in water whereas the alkali metals are highly soluble in water.Beryllium: Theanomalous properties of berylliumis mainly due to its small size, high electronegativity, high ionization energy and high polarizing power compared to the other elements in the block.

The coordinate number of beryllium is not more than 4 whereas other alkali metals have coordinate number of 6.• The melting point and boiling points are higher when compared to the other elements of the group.• They form covalent bonds whereas the other members form of the group form ionic bonds.• Be does not react with water like the other companions of the group

thanks

Van der waal’s equation

Thought the equation PV=RT was arrived at first experimentally and then theoretically, yet it fails to explain the behaviour of real gases. van der Waals attributed the deviation of real gases from gas equation to the following faulty assumptions of the kinetic theory:

(i) The actual volume of the gas molecules is negligible as compared with the total volume of the gas.

(ii) The gas molecules do not exert any appreciable attraction on each other.

Both these assumptions are not true at high pressure and low temperature. At high pressure the volume is reduced to a great extent and the actual volume of the molecules cannot be supposed as negligible under such conditions. Moreover, the molecules come closer and the attractive force between them should also be taken into consideration.

Van der Waals introduced the necessary corrections as follows:

(a)Volume correction:At higher pressure, the volume is much reduced and at this state the volume of gas molecules no longer remains negligible in comparison with the total volume V occupied by the gas. Thus the free space available for motion of molecules is reduced. If v be the volume of the molecules at rest, effective volume when they are in motion must be greater. It has been calculated to be approximately four times the actual volume of the molecules.

I. e.

4v and is generally denoted by b. Therefore the actual volume available in which the molecules are free to move will be

= Total volume — Effective volume.

i.e., correct volume(V – b)

(b)Pressure correction:The pressure of a gas is due to the hits of the molecules on the walls of the containing vessel. The attractive force between the molecules comes into play when the molecules are brought close together bycompressing the gas. A molecule in the body of the gas is attracted in all the directions when forces acting in opposite directions cancel out, but a molecule, the boundary of the gas is subjected to an inward pull due to unbalanced molecular attraction.

In this way some of the energy of the molecule about to strike the wall of the vessel is used up in overcoming this inward pull. Therefore, it will not strike the opposite wall with the same force. The observed pressure consequently will be less than the ideal pressure. Therefore the ideal pressure, Pi will be equal to observed pressure P plus a pressure correction, Pa depending upon the attractive forces,

I.e. Pi = P + Pa

The elements in the group to the right of this Boron group is less metallic due to increase in ionization energy.

electronegativity decreases down to group.. and increases from left to right in the periodic table.so, K > Rb and.. Cl > S

but due to d-contraction... electronegativity of Zr<Hf.

so. option 1.

N2 is exist as diatomic molecule in which two nitrogen atoms are attached to each other by triple bond this triple bond is due to p(pie)-p(pie) multiple bonding (sidewise overlapping) and such bonding is not possible in phosphorus due to it's large size but possible in nitrogen due to it's small size.

In case of phosphorus four atoms are associated so it have high molecular mass ,large magnitude of venderwall forces so phosphorus is solid and nitrogen is gas.

Anomalous Behavior of Nitrogen:- Nitrogen, the first member of group 15, differs from others group members because of :-

i)Small size of N atom.

ii)High value of electronegativity of N atom and high ionization energy.

iii)Absence of d-orbitals in the valency shell.

iv)Tendency of form multipole bonds.

The properties in which nitrogen differs from other members of 15 groups are listed below.

i)Nitrogen is gas while others members are solids.

ii)Nitrogen molecule is diatomic while other elements from teratomic molecules such as p4, As4and Sb4.

iii)The catenation property is more pronounced in nitrogen.

iv)Nitrogen forms five oxides of monomeric nature. Others can form at the most three types of oxides, X4O6, X4O10of dimeric nature. N2O4exists in dimeric fronature. N2O4exists in dimeric from and is diamagnetic.

v)Hydride of nitrogen is stable while the hydrides of other elements are not stable and acts as reducing agent. Hydrogen bonding is present in ammonia but not present in other hydrides.

vi)Expect NF3, the halides of nitrogen are unstable and explosive. The halides of other elements are stable. Unlike P, as and Sb, nitrogen does not form pentahalides.

vii)Nitrogen can form trinegative ion N3-. This tendency is less in P but absent in other elements.

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Most acidic sample: G ( Because it has lowest pH)

Most Basic Sample: F(Because it has highest pH)

g is more acidic and f is basic

thank u

Radius of graphite , r = 0.5mm = 0.05cmradius of wooden part of pencil, R = 3.5mm = 0.35cm length of pencil , l = 10cm

now, volume of graphite = πr²l = π(0.05)² × 10 = π × 25 × 10^-3 cm³

weight of graphite = π × 25 × 10^-3 × 2.1 g [ mass = volume × density ] = 22/7 × 25 × 10^-3 × 2.1 g = 165 × 10^-3 = 0.165g

volume of wooden part of pencil = π(R² - r²)l= π(0.35² - 0.05²) × 10= π(0.35 + 0.05)(0.35 - 0.05) × 10= π × 0.4 × 0.30 × 10 = π × 1.2

weight of wooden part , w = π × 1.2 × 0.7 = 22/7 × 1.2 × 0.7 = 2.64g

so, total weight of pencil = 2.64g + 0.165g = 2.805g

Ans :- Most interactions amongatomstake place in the outermost shell of eachatom. The number of each electron in this shell determines how anatom combineswith otheratomsto form compounds. When atoms combinethey gain, lose or share electrons in such a way that the outer shells become chemically complete.

One mole of compound = 6.022 x 10^23 molecules = occupies 22.4 L or 22400 ml volume