

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
8451. |
An organic compound on analysis was found tocontain 0.032% of Sulphur by mass. Themolecular mass of the compound, if its onemolecule contains two sulphur atoms, is(A) 100000 u(C) 20000u(B) 10000 u(D) 200000 u |
Answer» Let the molecular mass of compound be 'X'. Atomic mass of sulphur- 32gatomic mass of 2 sulphur atoms= (32*2)g since 0.032 % sulphur is present in the given compound, percentage of sulphur * total molecular weight of compound = weight of sulphur in compound.0.032 % of X = 32*2 (0.032 / 100) * X = 64 X = (64 * 100)/ 0.032X = 2 * 10^5 g The molecular weight of the 200000 u (D) is correct option |
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8452. |
SU13. Write the chemical formula of washing soda. How can it prepare bySolvay process? Describe the household applications of washing soda? |
Answer» Washing sodais a chemical compound with theformulaNa2CO3, known as sodium carbonate, and it’s a salt of carbonic acid. Some use washing soda to make homemade laundry detergent, to clean especially in hard water, and some even use it as a laundry additive to soften water. Water which is rich in minerals like magnesium and calcium, is known as hard water. Hard water can affect the cleaning power of your detergent, but washing soda can bind to minerals in water allowing homemade detergents to better-absorb into fabric fibres and get on with the cleaning. Washing soda should not be confused with baking soda, even though chemically they are closely related. Na2co3. 10H2o is chemical compound of washing soda |
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8453. |
3. Give reason for the following observations.(a) Naphthalene balls disappear with time without leavinany solid. |
Answer» Naphthalene balls undergo sublimation due to which it converts directly into vapours and disappear into air without leaving any solid. (b) The particles of perfume diffuse rapidly into the air and its smell can be felt while sitting several metres away napthalene balls converts into vapourwithout living solid due to sublimation it convert into direct vapors naphthalene ball disappear sublimation it convert into solid to vaporization without going in the state of liquid that's why I can't convert into liquid form it directly convert into my sweet can't leave any solid material you can leave naphthalene ball for sometime or there is it convert into vapour without leaving a solid substance example example just like water as some water on table and leave sometime it convert into vapour without leaving any liquid form due to you due to it convert with the prices of vaporization vaporization just like when was this season was was this depend on humidity temperature table temperature room temperature how much faster trip your price just like an app clean ball Naphthalene ballsundergo sublimation due to which it converts directly into vapours anddisappearinto air without leaving any solid |
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8454. |
Draw the diagram of the apparatus used to show that water is a compound ofhydrogen and oxygen. Label the following parts.i) The part where oxygen is collectedii) The part where hydrogen is collected |
Answer» The perfect example demonstrating this is the electrolysis of water.If we take some water in a beaker and add sulphuric acid to it then it becomes acidulated water and a great conductor of electricity.Then we pass electric current through them and we see that one test tube has more space than the other.This proves that water has 2 parts of hydrogen and 1 part of oxygen.Oxygen is collected at anode and Hydrogen at Cathode. 2H₂O -------------------> 2H₂ + O₂ In fig. Gas A is hydrogen and gas B is oxygen. |
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8455. |
6 Why do we sce water droplets collected an the outer surface of a glass containing3 mark |
Answer» Water droplets form on the outer surface of the container containing a cold substance due toCondensation.The temperature of the container is cold enough to cool down the water vapor in the surrounding air, so it turns from gaseous to liquid state. Therefore, drops form more steadily during warm weather than cold weather. Condensation is the basic transformation of a substance from gas to liquid. All air in the atmosphere contains some degree of water vapor. If the air is cooled past the dew point of water, which depends on pressure and concentration, condensation will occur. Condensation will occur more easily in saturated air than dry air. |
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8456. |
Mention two reasons which are responsible for the so called "inert paireffect" |
Answer» Inert pair effect. Theinert pair effectis the tendency of thetwoelectrons in the outermost atomic s-orbital to remain unionized or unshared in compounds of post-transition metals. ... As a result, theinert pairof ns electrons remains more tightly held by the nucleus and hence participates less in bond formation . |
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8457. |
15. Calculate the work done when a gas expands at a constant temperature from volume2 x 103m3 to 4 x 10-3m against a constant pressure of 1.2x 105 N m2 |
Answer» initially work done is 120000*2000final work done is 120000*.004now,so work done is 240000000-480 answer is 239999520 work done=pdVwork done=1.2*10^5(2000-0.004)=1.2*10^5(1999.996)=2399*10^5J |
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8458. |
31. Calculate the wavenumber ofyellow radiation having wavelength 5800A.A) 1.724 x 104 crn-1C 4.271 x 10t cm-1B) 2.742 x 104cm-1D) 2.174 x 104 cm-1 |
Answer» wavelength of light =5800*10^10mfrequency is given by=c/wavelength3*10^8/5800*10^-103*10^8/58*10^-80.05*10^16wave number is reciprocal of wavelengthwave number =1/wavelength=1/5800*10^-10=10^10/5800=0.017*10^8m^-1 |
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8459. |
An ideal gas expands in volume from1 x 10-3 m3 to 1 x 10-2 m3 at 300 K against a constant pressure of 1 x 105 Nm2. The work done is -(A) -900J4(B)-900 k(C) 270 k(D) 900 k |
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8460. |
rite two differences between Fibrous and Globular proteins. |
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8461. |
7 Copper crystallises into a fcc lattice with edge length 3.61 × 104 cm·Show that thecalculated density is in agreement with its measured value of 8.92 g em |
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8462. |
this try out following SAQS.SAQ 1ale the potential of a copper electrode immersed in 0.044 M CuSO4.SAO 2 |
Answer» Cu(s) --> Cu+2 + 2e- Eo = 0.337 E= Eo + {(RT)/(nF)}ln[Cu+2] [Cu+2] = 0.0400M E= 0.337 + {(8.314x298)/(2x96485)}ln(0.0400) E= 0.297 |
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8463. |
Write balanced equations for the following reactions-i) When lead nitrate solution and sodium chloride solutionsb)are mixed. |
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8464. |
.12 Write balanced molecular equations for the followingword equations(0) Sodium aluminafe +waterSodium hydroxide +Aluminium hydroxide |
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8465. |
10.wial ale IO11.What is Xylem? Name the four elements of Xylem and write one function of each. |
Answer» Xylem is the plant tissue which transports food material or minerals from root to tip of the plant in upward directionfour elements are : tracheidsxylem vesselsxylem parenchymatracheae 1) The main function of xylem is to carry water and mineral salts upward from the root to different parts of shoots . |
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8466. |
Which is not an element(i) Diamond (ii) Silver (ii) Marble (iv) Iron.11) Marblev) iron. |
Answer» ii) marble is not an element |
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8467. |
ManohThe orbital angular momentum of 3p electron is vx. Then the value of x is 2An ion Mnt has the magnetic moment equal to 4.9 BM. What is the value of a ?compound of vanadium has magnetic moment of 1.73 BM. It suggests the vanadium oxidationstate in the compound is +x. Then the value of x isKEY SHEET (LECTURE SHEET) |
Answer» the correct answer is 4 |
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8468. |
33.What will happen if alkyl halides react withi. Alkali or aq. KOH or aq. Na0Hiii. KCN (alc.)v. Ammoniaii. Moist silver oxideiv. Silver cyanide (AgCN) |
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8469. |
Atomic number of 33, 51 represents the following family:2) 8 , ४(4) गैसीय आयतन का नि(1) carbon family (2) nitrogen familyपरमाण संख्या 33 51 नि रातिा(3) oxygen familyTो । |
Answer» It shows carbon familythanks |
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8470. |
= رررررننرريررنوWhat are the 2 ways in which the physical stateels matter can be changed? |
Answer» The two ways by which the physical state of matter can be changed by the following two methods - By increasing or decreasing the temperature. By increasing of decreasing the pressure. |
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8471. |
Describe Bayer's process for concentration of bauxite. |
Answer» Bayer’s process is used to obtain pure aluminium oxide from bauxite ore. The bauxite ore is concentrated by chemical separation. Bauxite contains impurities like iron oxide and silica. The bauxite ore is powdered and heated with sodium hydroxide under high pressure in the furnace. The aluminium oxide present in bauxite reacts with sodiumMetaaluminate. Silica reacts with sodium hydroxide to form soluble sodium silicate. The basic iron oxide in the gangue remains unaffected, separated by filtration. The filtrate containing sodium meta aluminate and sodium silicate is stirred with a little aluminium hydroxide to induce precipitation of aluminium hydroxide Aluminium hydroxide is then filtered, washed with water, dried and heated to get pure aluminium oxide (alumina) |
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8472. |
The shape of Tobacco Mosaic Virus (TMC) is cylindrical, having length and diameter 3000 Å and170 А, respectively. The density of the virus is 0.08 gm/ml. The molecular weightOf TMC is |
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8473. |
In the Bayer's process of purification of red bauxite leaching agent is1) NaOHWhich of the following is antimicrobial1) RantidineWhich are used is dish-washers1) Cationic detergents3) Soaps2) Na,CO3) NaCN4) KCN2) Lysozyme3) Aspirin4) Equanil2) Anionic detergents4) Non-ionic detergents |
Answer» 1) NaOH2) Aspirin |
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8474. |
48. Calculate the energy in joule corresponding to light of wavelength 45 nm(Plank's constant, h:-6.63 x 10-34Js, speed oflight , cA)6.67 x 10ts 73 x 10"ms-i)B) 6.67 x 1011C) 4.42 x 10-15 |
Answer» E = hc/wavelength = 6.63×3 × 10^(-34+8)/45×10^-9) E = 4.42 × 10^-18 J |
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8475. |
How many electrons will be present in the subshells having ms value of -for n = 4? |
Answer» Number of orbitals in the nth shell = n2 Therefore, the number of orbitals for n = 4 = 42 = 16 If all the orbitals are filled then the total number of electrons = 16 x 2 = 32. Now, in an orbital two electrons have opposite spins, therefore number of electrons with ms= -1/2 = 16. |
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8476. |
60. How many electrons in Argon have m0?A) 12B) 10C) 8D) 6 |
Answer» Argon has the atomic number 18 and the electronic configuration 1s22s22p63s23p6The valence shell configuration is 3s23p6In the p orbital , Angular momentum L has value =1mlvalues are -1, 0 , 1 corresponding to 2 electrons each[ 2 electrons with ml=-1 value, 2 electrons with ml=0 and two electrons with ml=1]{Total =6 electrons in the p orbital}Hence there are 2 electrons in Ar which have mlvalue =0 |
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8477. |
Infrared lamps are used in restaurants to keep the food warm. The infrared radiation isstrongly absorbed by water, raising its temperature and that of the food. If the wavelength ofinfrared radiation is assumed to be 1500nm, then the number of photons per second ofinfrared radiation produced by an infrared lamp that consumes energy at the rate of 100 Wand is 12% efficient only is (xx 1019). The value of x is;(Given : h 6625 x 10-34 J-s) |
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8478. |
Arrange atomic radiiB,Be,Al,Mg |
Answer» Atomic radius in decreasing order.. Mg>Al>Be>B |
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8479. |
Achuamos aj adsm al elem endshos & moss af 16736673x10 24Atomic moss al cammem ele mendS32 |
Answer» You have already provided the solution. |
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8480. |
Linear equations in one variable |
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8481. |
. A pendulum oscillates 40 times in 4 seconds. Find its time period andfrequency |
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8482. |
Question 4:Which gas is produced when dilute hydrochloric acid is added to a reactive metal? Writethe chemical reaction when iron reacts with dilute H2SO4. |
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8483. |
Which gas is produced when dilutebrdrochloric acid is added to a reactivemetal? Write the chemical reaction wheniron reacts with dilute H,SO |
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8484. |
1. 0. 10 g of a metal gave on treatment with a dilute acid 34.2 mL of hydrogen at S.T.P.Calculate the equivalent weight of the metal. (1.0 mL of Hat S.T.P. weighs 0.00009 g). |
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8485. |
Suppose two elements X and Y combine to form two compoundsXY2 and X3 Y2 when 0.1 mol of former weighs 10 g while 0.05mol of the latter weighs 9 g. Find the atomic masses of X and Y |
Answer» Thanks |
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8486. |
Suppose 10-17J of light energy is needed by the interiorof human eye to see an object. The photons of greenlight (A- 550 nm) needed to see the object are:(a) 27(c) 29(b) 28(d) 30 |
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8487. |
e) Glve one Imo21. You are provided with two containers made up of copper and aluminium.You are also provided with solutions of dilute HCl, dilute HNOs, ZnCl2 andH2O. In which of the above containers these solutions can be kept?NCERT Exemplar] |
Answer» Answer:-(A)Copper Reason:-The solution of dilute HCl, dilute HNO3, ZnCl2 and H2O can be kept in the container made of copper. Since copper is a less reactive metal and is placed below the hydrogen in activity series. Hence it does not react with HCl, HNO3 ZnCl2 and H2O. While aluminium is highly reactive metal and can reacts with these solutions |
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8488. |
dropped into two identical vessels A and B each containing500 g of water at 298 K. The coin dropped in vessel A ismade up of aluminium and the coin dropped into vessel Bis made up of silver. The rise in temperature of water incontainer(a) A and B will be same(b) A will be more than B(c) A will be less than B(d) Given data is not complete |
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8489. |
The IUPAC name of the compound with structural formula CH3-CHeCH-CeCH is-(A) pent-2-en-4-yne (B) pent-1-yn-3-ene (C) pent-3-en-1-yne (D) pent-2-en-5-yne3. |
Answer» C is correct answer |
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8490. |
(4) s p< d<12. Which of the following statement is incorrect?() The ionization potential of nitrogen is greater(2) The electron affinity of fluorine is greater than(3) The ionization potential of Mg is greater than(4) The electronegativity of fluorine is greater thanthan that of oxygenthat of chlorine.aluminiumthat of chlorine |
Answer» option B , is incorrect. Fluorine, though higherthan chlorinein the periodic table, has a very small atomic size. This makes the fluoride anion so formed unstable (highly reactive) due to a very high charge/mass ratio. ... As a result,fluorinehas anelectron affinity less thanthat ofchlorine. |
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8491. |
Fluorine does not form polyhalides why? |
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8492. |
d)FluorineVarious successive ionisation enthalpies (in kJ mol-1) of an element are given belowIE IE2 IE577.5 1,810 2,750IE411,580 14,820IE,The element is)phosphorus b) Sodiumc) Aluminiumd) Silicon |
Answer» Hence answer will be Aluminium. |
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8493. |
No til |
Answer» N: -2 → +2 (a change of +4) (times 2 because there are 2N’s) Cl: +5→ -1 (a change of -6) Find the L.C.M. of change. 24 Insert the suitable stoichimetric coefficients: 3N2H4 + 4ClO3- → 6NO + 4Cl- Insert H2O to whichever side that is oxygen deficient and then insert H+ to whichever side that is hydrogen deficient: 3N2H4 + 4ClO3- → 6NO + 4Cl- +6H2O I have not understood...plz solve in easy way..by ion electron method. step by step. 1st page 2nd page 3rd page 4th page 5th page 6th page and last page what is your question? Go and ask this question to your teacher 👌 😎 |
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8494. |
8.11 shous the distance-ttime grapih of three doels AC. Shady the graph and amswet the folliowing questions04 08 1.2 1.8time (hour)--→Fig. 8.11 |
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8495. |
name the process by which a drop of ink spreads in a beaker of water |
Answer» The process of drop of ink spread in a beaker of water is known as "diffusion" |
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8496. |
Chat at lave smell harealmonds, thorath cold fementalent smell of |
Answer» chair,air,lemon water, almond |
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8497. |
0IntegratetanxdxCBSE Sample Paper 2 |
Answer» part 1 Part 2 |
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8498. |
44. The enthalpy and entropy change for a chemical reactionare 2.5 x 10-3 cal and 7.4 cal deg respectively. Predictwhether the nature of reaction at 298 K is: (AFMC 1998)(a) spontaneous(c) irreversibleIS:(b) reversible(d) non-spontaneous |
Answer» spontaneous, option (a) |
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8499. |
uestions1. For the symbol H,D and Ttabulate three sub-atomicparticles found in each of them. |
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8500. |
One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litreThe AE for this process is(A) 163.7 cal(R 2 cal mot1 K-1) -(C) 138.1 cal(B) zero(D) 9 lit atm |
Answer» As given process expanded isothermally means at constant temperature ΔT = constant We known that the internal energy of gases depend on the temperature as we increases the temperature the kinetic energy of molecules increases that increases the internal energy of molecules. Therefore, the internal energy of gases also remained constant at constant temperature So for given isothermal process ΔE = 0 |
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