InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1851. |
SOLID STATES11. AgCI has the same structure as that of'NaCl. The edge length of unit cell of AgCl is found to be 555 pm and thedensity of AgClis 5.561 g cm 3. Find the percentage of sites that are unoccupied. |
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Answer» density of a crystal is mass/volume Here mass increases due to filling of impurity thus density increases percentage of site that are unoccupied no of agcl atom in unit cell=4density=5.561g/cm^3volume of unit cell=17*10^-23percentage unoccupied=100-percentage occupied=100-{(4*143.5/Na)/5.561}/17*10^-23= 0.24% |
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| 1852. |
65. The density of air is 0.001293 gm L. ts vapourdensity is( 143 2 14.3 (3) 1.43 (4) 0.143 |
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Answer» (2) 14.3 explain it Please see the solution. how can calculate 4.001293 Sorry, it is a typing error. It is 0.001293. what is full form of ml given in question how can say that 1 mole has 0.001293gm There is no ml in the question.ml in the solution stands for milli litre. 1ml = 10^-3 l one thing what is full form of gm in answer gram Hey gm means gram and ml means millilitres. Us nt it a funny question |
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| 1853. |
The density of air is 0,001293gm/mlatS.1PIt'svapourdensityis- |
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Answer» molecular mass=2×vapour densitygiven density=.001293g/cm³1 ml has .001293 gm22.4 ml has .001293×22.4×10³molecupar mass=28.97vapour density= mol. mass/2 = 14.485 |
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| 1854. |
why does vapour pressure of a liquid decreases with non volatile solid solute |
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Answer» If you add anonvolatile soluteto solvent such as water, youdecreasethe tendency for water molecules to evaporate into the gas phase. ... As a result, fewer molecules change from theliquidto the gas phase, thus reducing the vaporpressure thanku |
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| 1855. |
Whyis urine yellow in colour? |
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Answer» Urinenaturally has someyellow pigments called urobilin or urochrome. The darkerurineis, the more concentrated it tends to be. Darkurine is most commonly due to dehydration. ... For example, dark brownurinemay indicate liver disease due to the presence of bile in theurine. due to presence of the pigments bilirubin and biliverdin. |
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| 1856. |
d) Name the following compounds under IUPAC system K.[Fe(CN)d]and [Co (NH3)4Cl2] |
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Answer» Potassium ferrocyanide is the inorganic compound with formulaK4[Fe(CN)6] ii) Tetraamminedichlorocobalt (III) ion thanks |
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| 1857. |
How many equivalents of sodium sulphate is formed when H2SO4 is completelyneutralized by a base NaOH?) |
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Answer» In this reaction, 2 moles of H+ ions (2 equivalents)from sulfuric acid (H2SO4) react with NaOH to form sodium sulfate and water. |
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| 1858. |
Calculate the number of equivalents present in(A) 0.25L of 5N solution(B) 1.5L of 2.51 solution(C) 0.5L of 0.2N solution (D) 10.0L of 0.65N solution |
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| 1859. |
)olumeİ) 6,022 molecules of NH3ii) 0.1 M of SO2 |
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Answer» in 1 moles the volume of gas is 22.4 L so. 1) 6.022× 10²³ molecules = 1 moles. so volume will be 22.4 L 2) 0.1 M SO2..Volume occupied by 1 mole of SO2= 22.4 LVolume occupied by 0.1 mole = 2.24 L |
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| 1860. |
17. Give IUPAC names ofC111° CII-CI |
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Answer» The commonname of CH2= CH-Cl is vinyl chloride and theIUPAC nameis Chloroethene. |
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| 1861. |
what decomposition |
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Answer» Decomposition is the process by which organic substances are broken down into simpler organic matter. The process is a part of the nutrient cycle and is essential for recycling the finite matter that occupies physical space in the biosphere. Bodies of living organisms begin to decompose shortly after death. |
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| 1862. |
Writethestructuresand give IUPAC namesollowing alkyl groups.a) Isopentylc) Isohexyl(b) tert-Pentyl(d) Neohexyl |
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Answer» “tert-pentyl”: 2-methylbutan-2-yl “isopentyl”: 3-methylbutyl “isohexyl”: 2-methylpentyl“neohexyl”: 2,2-dimethylbutyl |
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| 1863. |
1. Give the IUPAC names of the fo7 CH3 CH CH CH |
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Answer» 2,3-diethyl butane it's wrong and ans.is3,4-Dimethylhexane and thanku for try |
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| 1864. |
17.A colourless and odourless gas P is evolved during thermal decomposition of lead nitrate. P reactswith the main component of biogas to form compounds Q and R. P, Q and R respectively are(A) Со,,02 and C12 (B) N20, 02 andH2O (C) O2,CO2adH,O (D) O,,CO, and H, |
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| 1865. |
Which thermal decomposition will be redox:(1) KNO3(3) Pb(NO)(4) AlQ.5(2)AgNOA |
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Answer» 1 is redox 2KNO3 -> 2KNO2 + O2 2 is redox 2AgNO3→∆→2Ag + 2NO2+ O2 3 is redox 2Pb(NO3)2→∆→2PbO + 4NO2+ O2 option D is correct |
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| 1866. |
4.21 The following data were obtained during the first order thermaldecomposition of so,cl, at a constant volume.so,Cl2 (g)- SO2 (g)+C2 (8)Experiment Time/s Total pressure/atnm00.521000.6Calculate the rate of the reaction when total pressure is 0.65 atm. |
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| 1867. |
Student 'A' adds iron nails in copper sulphate solution taken in test tube 1. Student 'A' adds Cu turnings in ferrous sulphate solution taken in test tube 2. On which of the test tubes, change in colour takes place and why ? Write the reaction involved |
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Answer» 1.Iron nail will become reddish brown in Copper Sulphate solution. CuSO4+Fe------->FeSO4+CuThis is because the Iron is more reactive than copper and displaces copper from copper sulphate solution forming Iron Sulphate. 2.Copper Sulphate solution will change its colour from blue to green because the colour of copper sulphate solution is blue but after reaction it forms iron sulphate solution which is of green colour. |
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| 1868. |
16. The electronic configuration of a dispositive metal inM is 2, 8, 14 and its atomic weight is 56 amu. Thenumber of ncutrons in its nuclcus would be(1) 30(2) 32(3) 34(4) 42 |
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Answer» The correct answer is 30.It's atomic number=2+8+14=24No. of protons= 24+2=26rnSo now no. of neutrons = mass no. - no. of protons=56-26=30 but how can calculate number of protons please tell me immediately |
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| 1869. |
4. If 80g of X combines with 1.5 x 1023 atoms of Y to from X2Y with out any of the other element remaining. What is atomicweight of x? |
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| 1870. |
If 80g of X combines with 1.5 x 1023 atoms of Y to from X2Y with out any of the other element remaining. What is atomicweight of X?34. |
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Answer» No. of moles of X=2x1.5/6.022=0.498 Since 0.498moles of X=80gHence, 1 mole of X=(80/0.498) g=160.64g |
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| 1871. |
Question. 18 What is a homologous series? Whichtwo of the following organic compounds belongto the same homologous: CHs,C2Ho, C2H,0 |
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Answer» CH4O and C2H6O2 belongs to same homologous series because they have difference of -CH2 group and difference. of 14 g in weight. Homologous series. In organic chemistry, ahomologous seriesis aseriesof compounds with the same functional group and similar chemical properties in which the members of theseriesdiffer by the number of repeating units they contain. |
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| 1872. |
101 mole of a carbohydrate with empirical formulaCH20 contains 1 g of hydrogen. What is itsmolecular formula(A)C,H100(C) C4H304(B) C6H 1206(D)C3H60311. A gaseous hydrogosh |
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Answer» option(a) is correct Let molecular formula (CH2o)nIn one mole of carbohydrate there is 2n g of hydrogen present.So, 0.1 mole of carbohydrate there is 2n/1*0.1 g of hydrogen which is equal to 1g (from question)2n * 0.1 = 1n = 5Molecular formula = C5H10O5 |
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| 1873. |
Write the complete structural formulae & bondline formulae of followingorganic compounds.i) 4 - Ethyl-3 - methyloctaneli) 2 Methylpentaneii) 3 Ethyl 2,4-dimethylheptane |
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| 1874. |
thegeneralrepresentation of the followingclasses of organic compoundsi) Alcoholsi) Estersii) Ethersiv) Amines. |
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Answer» i) R-OHii) R-O-R'III) R-COO-R'IV) R-NH2 |
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| 1875. |
URITE IUPAC NAMES |
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Answer» propanol hit like if you find it useful |
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| 1876. |
5. Write IUPAC names of the following compounds |
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Answer» Is this 100% right |
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| 1877. |
A carbohydrate contains 40% carbon and 6.hydrogen. Determine its molecular formula,molecular weight is 180.Ans: CH |
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Answer» Use the method of mass percentage |
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| 1878. |
(29. )(carbohydrate contains 40% carbon and 6.66%hydrogen. Determine its molecular formula, if itsmolecular weight is 180. [Ans: CH12O |
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| 1879. |
2.10(a) Explain Bohr's model of atom and write down its limitations.(h) Write down the electronic configuration of Cr. Felt and Cuin s. p. d. f notation |
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Answer» please post photo clearly |
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| 1880. |
29, A carbohydrate contains 40% carbon and 6.65%hydrogen. Determine its molecular formula, if itsmolecular weight is 180. Ans: CH1,06112 |
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| 1881. |
Q2] Define comentationas write observed electronic Commcu (2:29)12nic configuration of |
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Answer» Coagulation, also known as clotting, is the process by which blood changes from a liquid to a gel, forming a blood clot. ... The mechanism of coagulation involves activation, adhesion and aggregation of platelets along with deposition and maturation of fibrin Want the answer for the 3rd question Answer for 3rd question?? |
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| 1882. |
24. A mixture of O2 and gas "Y" (mole. wt. 80) in the mole ratio a : b has a mean molecular weight 40. What would be mearmolecular weight, if gases are mixed in the ratio b: a under identical conditions? (gaes are non-reacting)-(1) 40(3(4(2) 48(3) 62(4)72MThe value ofy for the compound that analyzed |
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| 1883. |
write the electronic configuration of k+ions. |
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Answer» No..of electron in k= 19no..of electron in k+ = 18electronic configuration of k+ is in imageIn k+ electronic configuration is 1s2 ,2s2 ,2p6, 3s2 3p6 |
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| 1884. |
The vapour density of a gas A is twice that of agas B. If the molecular weight of B is M, themolecular weight of A will be: |
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| 1885. |
At 400 K, the root mean square (rms) speed of a gas X(molecular weight 40) is equal to the most probablespeed of gas Y at 60 K. The molecular weight of the gas Yis(2009) |
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| 1886. |
13. The equivalent weight of MnCl2 is half of itsmolecular weight when it is converted to |
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Answer» net oxidation state of Mn in MnCl2 is Mn+(Cl2)=0 so,Mn+(-1)2=0 (net charge of Cl=-1 Mn=2 now net charge of Mn in MnO2= Mn+(-2)2 (net charge on O=-2 Mn=4 MnCl2-----MnO2 equivalent weight =molecular weight (let M)/change in the oxidation state equivalent weight=M/(4-2) =M/2 Thus equivalent weight of MnCl2 is half the molecular weight when it is converted to MnO2 |
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| 1887. |
49. Define configuration. |
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Answer» Conformation is the set of possible shapes a molecule can have by means of rotation about single bonds only. Configuration is the relative position of the atoms in a molecule that can be changed exclusively by cleaving and forming new chemical bonds. |
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| 1888. |
what is electric configuration |
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Answer» In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. |
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| 1889. |
that iea) mean velocityb) root mean Velocity 4 its termula care) |
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Answer» (i)mean velocity. The timeaverageof thevelocityof a fluid at a fixed point, over a somewhat arbitrary time interval T counted from some fixed time t0. For example, themean velocityof the u component is. The timeaverageof any other quantity can be defined in this manner. |
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| 1890. |
(b) Why carboxylic acids do not give the characteristic reactions of carbonyl group? |
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Answer» Thecarbonylcarbon in ketones and aldehydes is more electrophilic than incarboxylic acids.This is because the lone pairs on oxygen atom attached to hydrogen atom in the -COOHgroupare involved in resonance thereby making the carbon atom less electrophilic. |
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| 1891. |
Why are carboxylic acids more acidic than alcohols or phenols although all of them have hydrogen attached to a oxygen atom? |
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Answer» Carboxylic acids are acidic due to resonance stabilization of carboxylate anion and in phenols, acidic character is present due to resonance stabilization of phenoxide anion. Carboxylic acid are more acidic than phenols because the negative charge in carboxylate anion is more spread out as compared to the phenoxide ion as there are two electronegative O-atoms in carboxylate anion in comparison to one in phenoxide ion. In the resosnce structures of carboxylate anion, the negative charge is present on the O-atoms while in resonance of phenoxide ion negative charge is also present on electropositive carbon atom, which leads to less stability of phenoxide ion than carboxylate anion. |
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| 1892. |
13.1 How do you account for the 0132 Write IUPAC names of the following compounds(a) CH,CH-C(CH)(b) CH,-CH-C-C-CH3-CH2-CH-CH-CH2CH3(f) CHs(CH,), CHICH2,CH3онCH,-CH(CHs2lg)CH3-CH = CH-CH2-CH-CH-CH-CH2-CH-CH2C.H,ITTPAC names for |
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| 1893. |
Consideringthestate of hybridization of carbonatoms, find out the molecule among the followingwhich is linear ?(a) CH3- CH2- CH2- CH3(b) CH3 -CH= CH- CH2(c) CH3-C= C-CH3(d) CH2 =CH -CH2-C =CH |
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Answer» answer is option c because C2 and C3 are sp hybridised Thank You Rukmini |
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| 1894. |
Give IUPAC names of the following compounds.i) CH3 -CH-CH2-CH CH-CHa | | | CH CH3 CH3CH3C,H05CH,CH,CH,Cliv)v) CH3-CH-CH-CH | | CH3 Brvi) CH3-CH2-CH- C-H | || OH Oyi) CH2 = CH-CH = CH2 |
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| 1895. |
27 Write IUPAC names ofcompounds.CHi) CH2 - CH2 -C-CH,CICH |
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Answer» 1-chloro-2,2-dimethyl-butane 1- chloro, (2,2)- dimethylbutane 1-chloro-2,2methyl butane |
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| 1896. |
Considering the state of hybridization of carbonatoms, find out the molecule among the followingwhich is linear?(a) CH3-CH2 CH2 CH3(b) CH3 CH CH CH3(c) CH3-CC CH3(d) CH2 CH- CH2 C CH |
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Answer» option C as C2 and C3 is sp hybridised Thank You Kanak |
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| 1897. |
Give reason: Why is the strap of your school bag broad? |
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Answer» Because it is easy to carry.A wider strapdistributes the force throughoutagreater surface area. You can doacomparison usingasimple physics equation. So take two differentstrapsand measure the area of them. |
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| 1898. |
) Tetrahedral, spExercise 12.What is the shape of SF4?Exercise 13. |
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| 1899. |
3.How will you separate wheat grains and straw pieces? |
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Answer» By winnowing which is a blow of current that causes the lighter particles like straw pieces to fly off. |
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| 1900. |
Inference:1. Acidic materials (pH less than 7) .2. Basic materials (pH more than 7)3. Neutral Materials (pH 74. |
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