Explore topic-wise InterviewSolutions in Current Affairs.

Former leads to huge immediate profits/selfish gains while latter leads to sustainable approach so that the resource may last for future generations too.

Detailed Answer.

Exploitation of natural resources with short term gains aims at providing all the benefits to the current generation for their growth and development without any consideration for the future. In case of long term perspective, the resources a.re utilized in a more judicious manner so that they are also conserved for the future generations. It ensures uniform distribution among the people.

यौवनारंभ के समय लड़कियों में दिखने वाले परिवर्तन –

1.  जननांगों के आस – पास बाल आना |

2.  वक्षों के आकार में वृद्धि होना |

3.  रजोस्त्राव आरम्भ आना |

शुक्राणुय एवं प्रोस्टेट ग्रंथि नर में होती है तथा इनका स्त्राव शुक्राणुओं को पोषण देता है | प्रोस्टेट ग्रंथि भी एक द्रव स्त्रावित करती है | इसी स्त्राव के माध्यम से शुक्राणु मादा जनन तंत्र में स्थानातरित होते है अतः ये जनन क्रिया के लिए महत्वपूर्ण नर ग्रंथियाँ है

Marketing Products 

1. “Are you tired chasing the rabbit for a long time?” Feel energetic, after a chase. Have “Alice Soup” for refreshment”. 

2. “Cool your body with Cheshire hair oil and feel fresh”. 

3. Want to reach your destination quickly? Go for

“Lae March Hare Cars”.

When the writer realised that every object had a name, each name gave birth to a new thought. Every object that she touched seemed to quiver with life as everything was strange and new to her. As every living word could give her new experience but some of them couldn’t. By trying to touch every living object she could name it. But she could not do it with objects that were invisible.

D) Mr Sanjeeva Reddy had worked with Prime Ministers Nehru and Morarji Desai.

The Centre of mass of sphere cylinder, ring and cube with homogenous mass distribution lies at its geometric centre. It is not necessary that CM (centre of mass) lies inside the body as in the cases of ring or hollow hemisphere.

At the point of intersection of the diagonals of the rectangle.

Not necessarily, For example, the centre of mass of a ring lies at the centre of the ring. i.e., at point, where actually There is no mass.

At the centroid of the triangle, i.e., at the point, where the medians of triangle meet.

(d) The angular acceleration is non-zero and remains same.

The initial velocity is v_i = vê_y and, after reflection from the wall, the final velocity is v_f = -vê_y . The trajectory is described as r = yê_y + aê_z . Hence the change in angular momentum is r x m(v_f - v_i) = 2mvaê_x.

Hence the answer is (b).

It is that point about which volume (in case of solids), area (in case of surface) or length (in case of lines) is uniformly distributed.

The likely position of the centre of mass of the system shown in figure.

(c) C

When a body rotates about a fixed axis, the motion of the body is said to be rotatory motion.

The centre of mass lie outside the body

 (d) A bangle

(d) A bangleA bangle because of its hollow structure centre of mass lie in centre which will       be outside. So, bangle is the correct answer.						

Midway between the two masses.

No, Centre of mass remains unaffected in rotatory motion of body whereas it changes its position in translator motion.

The internal force of brakes converts the rolling friction into sliding friction. When brakes are applied, wheels stop rotating. When they slide, the force of friction comes into play and stops the vehicle. It is an external force.

Correct answer is (a) \(\frac{L}{4}\) 

We know that 

angular momentum L = Mr²

Here, m and co are constants L \(a\) r²

If r becomes \(\frac{r}{2}\) angular momentum becomes \(\frac{1}{4}\) th of its initial value.

No, this statement is true when all the particles of the system are of same mass.

(c) does not shift horizontally

(b) 0.527 Å

Inter atomic distance = 1.13 Å 

Mass of carbon atom = 14 

Mass of oxygen atom = 16 

Let C.M. of molecule lies at a distance of X from oxygen atom-

i.e. m₁ r₁ = m₂r₂ 

16 X = 14(1.13 – X) 

30 X = 15.82 

X = 0.527 Å

(d) \(\frac{1}{5}\) th of its height

(b) inside the square plate

Radian per second (rad s^-1).

(d) force acting on particle

(i) The angular momentum of a particle with respect to a point gives an idea of the strength of its rotational tendency about that point.

(ii) The magnitude of the angular momentum is defined in terms of mass and velocity of the particle and its distance from the reference point, i.e., L = mvr

(iii) The vector concept of the angular momentum is useful. Its direction is the axial direction given by right hand rule. The direction of \(\vec{L}\) is ⊥ to the plane containing \(\vec{r}\) and \(\vec{v}.\)

The centre of mass of an isolated system (no external force acting on the system) will either be at rest or it must be moving with a constant velocity.

Correct answer is (c) m

(d) forces acting on the particles

If s₁ and s₂ are the distances travelled by a body in two successive intervals of t seconds, then the acceleration is given by,

a = (s2 - s1)t² = (200 - 100)/5² = 100/25 = 4ms^-2

we have, s = ut + 1/2 at²

Here, s = s₁ = 100m, a = 4ms^-2, t = 5 s

100 = u × 5 + 1/2 × 4 × 25

OR 5u = 50 ∴ u = 10ms^-1 

S₆ = 45m, S₁₂ = 75m

using S_n = u + a(n – 1/2 )

i.e., S₆ = u + a or 45 = u + 5.5 a ……… (1)

S₁₂ = u + a(12 – 1/2) or 75 = u + a(11.5) …….. (2)

Eq(2) – (1) gives 6 a = 30

Or a = 30/6 = 5 m/s²

From (1), 45 = u + 5 × 5.5

u = 17.5 m/s.

Distance travelled in t = 20s,

S = ut + 1/2 at²

= 17.5 × 20 + 1/2 × 5 × 20²

=1350 m.

f = μR = μmg cosθ  is the force of friction, if θ  is angle made by the slope. If q is small, force of friction is high and there is less chance of skidding. The road straight up would have a larger slope.

If the force is large and sudden, thread CD breaks because as CD is jerked, the pull is not transmitted to AB instantaneously (transmission depends on the elastic properties of the body). Therefore, before the mass moves, CD breaks.

AB, because force on the upper thread will be equal to sum of the weight of the body and the applied force.

Here, v = \(\sqrt{2gh}\)

where, g = 10 m/s² and h = 5 m

v = \(\sqrt {2 × 10 × 5}\) m/s

= 10 ms^-1.

1. R = m(g – a) = 49 N 

so = m = \(\frac{49}{9.8}\) = 5 kg 

R = 5 (9.8 – 5) 

R = 24 N 

2. R = m(g + a) 

R = 5 (9.8 + 5) 

R = 74 N 

3. as a = 0 so R = mg = 49 N

• thread AB breaks down
• CD will break .

m₁ = 5 kg, m₂ = 3 kg, g = 9.8 m/s²

Force on mass m₁,

T₁ − T₂ − m₁g = m₁a

T₁ − T₂ − 5g = 5a

T₁ − T₂ = 59.0 N

Force on mass m₂

T₂ − m₂g = m₂a

T₂ = m₂ (g + a)

= 3(9.8+2)

T₂ = 35.4

T₁ = T₂ + 59.0

or T₁ = 35.4 + 59.0

= 94.4 N

Thread CD will break.

If the force is large and sudden, thread CD breaks because as CD is jerked, the pull is not transmitted to AB instantaneously (transmission depends on the elastic properties of the body).

Therefore, before the mass moves, CD breaks.

The book continues in its state of rest due to inertia.

The people in the city, despairing of succour, worn out by toil and hunger, their hope of salvation wanned from day to day. They stared in horror at that moon, at the camp, at the sharp-looked ridges of the mountains, the black mass of the gorges and the noisy camp of the enemy. Everything spoke to them of death and not a star was there in the sky to give them consolation. Even they were afraid to light the lamps in the houses.

शहर के लोग, मदद पाने में निराश होकर, मेहनत एवं भूख से थककर, संकट से बचाव की उनकी उम्मीद रोज घटती गई। वे भयभीत होकर उस चन्द्रमा की ओर, पहाड़ों के कटे-फटे किनारों की ओर, दरों के काले समूहों की ओर तथा दुश्मन के शोर-शराबे वाले शिविर की ओर घूरते रहते थे। हर चीज उन्हें मृत्यु के बारे में ही कहती तथा आकाश में एक भी तारा उन्हें सांत्वना देने को नहीं होता था। यहाँ तक कि वे घरों में दिये जलाने से भी डरते थे।

The enemy soldiers fell in beside her and started singing the praises of her son. They said he was so clever and brave.

दुश्मन के सिपाही उसके साथ चलने लगे और उसके पुत्र की प्रशंसायें गाने लगे । उन्होंने कहा कि वह कितना चतुर एवं बहादुर था।

The slain man’s mother was proud of his son who died honourably. He was fighting for his country.

मारे गये आदमी की माँ को उस पर गर्व था जिसकी मृत्यु सम्मान से हुई थी। वह अपने देश के लिए लड़ाई लड़ रहा था।

People were afraid to light candles at night because they could be attacked by the enemy soldiers.

लोग रात में मोमबत्तियाँ जलाने से डरते थे क्योंकि दुश्मन सिपाही उन पर हमला कर सकते थे।

(c) allow her to leave the city

The mother was to be blamed for her son’s sins. She huntures her child. Her son became what she had made him.

माँ को पुत्र के पापों के लिये दोषी ठहराना था। वह अपने बच्चे की परवरिश करती है उसका पुत्र वही बना जैसा कि उसने उसे बनाया था।

marianna walked slowly, for her feet were reluctant to tear themselves away from that soil. She bowed to the corpses of the city’s defenders, kicking aside a broken weapon in disgust. She walked as though she carried a precious phial of water beneath her cloak and feared to spill a drop. It seemed to the defenders that with her went their dejection and hopelessness.

मरिअन्ना धीरे-धीरे चली क्योंकि उसके पैर उसकी मातृभूमि से दूर जाने में अनिच्छुक थे। उसने शहर के रक्षकों की लाशों को नमस्कार किया, एक टूटे हथियार को ठोकर मार कर दूर कर दिया। वह इस प्रकार चली जैसे उसने अपने लवादे के नीचे बहुमूल्य पानी की शीशी ले रखी हो और एक भी बूंद गिराने से डरती हो। रक्षकों को ऐसा लगा कि उसके साथ ही उनकी निराशा और नाउम्मीदगी भी चली गयी थी।

The mother’s punishment was that her son had forgotton her. It was more terrible than death.

माँ के लिये दण्ड था कि उसको पुत्र उसे भूल गया था। यह मृत्यु से भी अधिक भयंकर दण्ड था।