This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is volume? |
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Answer» Volume has the units of (length)3 . So volume has units of m3 or cm3 ordm3. A common unit, litre (L) is not an SI unit, is used for measurement of volume of liquids. 1 L = 1000 mL, 1000 cm3 = 1 dm3. |
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| 2. |
Define Density. |
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Answer» Density of a substance is its amount of mass per unit volume.SI unit of density = SI unit of mass/SI unit of volume = kg/m3 or kg m–3 This unit is quite large and a chemist often expresses density in g cm–3. |
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| 3. |
Define Temperature. |
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Answer» There are three common scales to measure temperature—°C (degreecelsius), °F (degree Fahrenheit) and K (kelvin). Here, K is the SI unit. °F = 9/5(°C) + 32 K = °C + 273.15 Note—Temperature below 0 °C (i.e. negative values) are possible in Celsius scale but in Kelvin scale, negative temperature is not possible. |
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| 4. |
What are the Characteristics of compound? |
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Answer» Characteristics of compound :
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| 5. |
What is Compounds? |
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Answer» A compound is a pure substance made up of two or more elements combined in a definite proportion by mass, which could be split by suitable chemical methods. |
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| 6. |
Define unit factor. |
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Answer» Unit factor:- Using dimensional analysis, one can obtain the unit factor to express a quantity in a new unit. In unit factor the nominators and denominators are expressed in different but represent the same or equivalent amounts multiplying by unit factor is the same as multiplying by one. |
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| 7. |
How many atoms are present in the unit cell of (a) simple cubic lattice (b) BCC (c) FCC |
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Answer» (a) 1 (b) 2 and (c) 4 |
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| 8. |
Define the term Elements. |
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Answer» An element is the simplest form of matter that cannot be split into simpler substances or built from simpler substances by any ordinary chemical or physical method. There are 114 elements known to us, out of which 92 are naturally occurring while the rest have been prepared artificially. Elements are further classified into metals, non-metals and metalloids. |
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| 9. |
Define molar mass. |
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Answer» Molar mass:- The mass of 1 mole of any substance is called its molar mass. |
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| 10. |
What are the various types of mixtures? |
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Answer» Mixtures are of two types: (I) Homogeneous – A mixture is said to be homogenous if its composition is uniform throughout. (II) Heterogeneous – A mixture is said to be heterogeneous if its composition is not uniform throughout. |
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| 11. |
Classify following substances as elements, compounds and mixtures: water, tea, silver, steel, carbon dioxide and platinum. |
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Answer» Elements: Silver, platinum Compounds: Water, Carbon dioxide Mixtures: Steel, Tea |
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| 12. |
How many lattice points are there in one unit cell of each of the following lattice?(i) Face-centred cubic (ii) Face-centred tetragonal (iii) Body-centred |
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Answer» Lattice points in face centred cubic or face centred tetragonal |
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| 13. |
Explain the following terms with suitable examples: (i) Schottky defect (ii) Frenkel defect (iii) Interstitials and (iv) F-centres. |
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Answer» (i) Schottky defect: It arises due to the missing of equal number of cations and anions from their normal positions leaving behind a pair of holes. This defect is usually observed in ionic compounds having high coordination number and ions of almost similar size. The density of the crystal is lowered due to the presence of vacancies in the crystal lattice. Schottky defect increases slightly the electrical conductance of the crystal. E.g. NaCl, KCl, CsCl. (ii) Frenkel defect: It arises w’hen an ion, usually cation, leaves its normal site and occupies an interstitial site. This defect is usually observed in ionic ‘ compounds having low co-ordination number , and crystals with anions are much larger in size than the cations. Since no ions are missing from the crystals as whole, it doesn’t affect the density of the crystal. E.g.: AgCl, ZnS, AgBr (iii) Interstitials: Atoms or ions which occupy the normally vacant interstitial positions in a crystal are called interstitials. (iv) F-centres: The electron occupying holes, created by missing of anions from the lattice sites are called F-centres. These F-centres are responsible for colour of compound. |
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| 14. |
Classify following substances as element, compounds and mixtures – water,tea, silver, steel, carbondioxide and platinum. |
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Answer»
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| 15. |
Classify the following substances into elements, compounds and mixtures: (i) Milk (ii) 22-carat gold (iii) Iodized table salt (iv) Diamond (v) Smoke (vi) Steel (vii) Brass (viii) Dry ice (ix) Mercury (x) Air (xi) Aerated drinks (xii) Glucose (xiii) Petrol/Diesel/Kerosene oil (xiv) Steam (xv) Cloud. |
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Answer» Element – (iv), (ix); Compounds – (viii), (xii), (xiv), (xv); Mixtures – (i), (ii), (iii), (v), (vi), (vii), (x), (xi), (xiii). |
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| 16. |
Define Average atomic mass. |
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Answer» Average atomic mass:- The average atomic mass of an element is the average relative mass of its atoms as compared with an atom of carbon taken as 12. |
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| 17. |
How can you determine the atomic mass of an unknown metal if you know its density and the dimension of its unit cell? Explain. |
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Answer» The atomic mass can be determined using the formula \(M = \frac{\rho \times a^3 \times N_0}{Z}\) Where ρ is the density of the metal, a is the dimension of the unit cell, N0 is Avogadro number and Z is the number of atoms in the unit cell. |
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| 18. |
How will you distinguish between the following pairs of terms: (i) Hexagonal close-packing and cubic close-packing?(ii) Crystal lattice and unit cell?(iii) Tetrahedral void and octahedral void? |
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Answer» (i) When a third layer is placed over the second layer in such a way that the spheres cover the tetrahedral or ‘C’ voids, a three dimensional closest packing is obtained where the spheres in every third or alternate layers are vertically aligned (i.e. the third layer is directly above the first, the fourth above the second layer or so on) calling the first layer as layer A and the second layer as layer B, the arrangement is ABAB pattern or hexagonal close packing. When the third layer is placed over the second layer in such a way that spheres cover the octahedral or ‘d’ voids, a layer different from layers A and B is produced. Let us call it as layer C, continuing further, a packing is obtained were the spheres in every fourth layer will be vertically aligned. This pattern of stocking spheres is called ABCABC… pattern or close cube packing (CCP). (ii) A regular three dimensional arrangement of points in space is called crystal lattice. Unit cell is the smallest portion of a crystal lattice which, when repeated in different directions, generates the entire lattice. (iii) Wherever a sphere of the second layer is above the void of the first layer (or vice versa) a tetrahedral void is formed. These voids are called tetrahedral voids because a tetrahedron is formed when the center of these four spheres are joined. The voids which are surrounded by six spheres is called octahedral voids. |
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| 19. |
Separate the pure substances into elements and compounds and divide the mixtures into homogeneous and heterogeneous:(i) graphite (ii) milk (iii) air (iv) diamond (v) petrol (vi) tap water (vii) distilled water (viii) oxygen (ix) 22 carat gold (x) steel (xi) iron (xii) iodized table salt (xiii) wood (xiv) cloud |
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Answer» Homogeneous: air, petrol, tap water, 22 carat gold, cloud and steel Heterogeneous: milk, wood, iodized table salt. |
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| 20. |
1. Name the unit of magnetic moment.2. Match the following.Paramagnetic – Fe3O4Ferromagnetic – O2Antiferromagnetic – CrO2Ferrimagnetic – MnO |
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Answer» 1. Bohr magneton (μB) 2. Match :
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| 21. |
Unit cells can be broadly classified into 2 categories primitive and centred unit cells.(a) What is a unit cell?(b) Name the three types of centred unit cells.(c) The unit cell dimension of a particular crystal system is a = b = c, α = β = γ = 90°. ldentify the crystal system.(d) Give one example for the above crystal system. |
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Answer» (a) The smallest repeating unit of a crystal. (b) Body centred unit cell, Face centred unit cell and End centred unit cell. (c) Cubic crystal system. (d) NaCI (Rock salt struãture) |
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| 22. |
A piece of metal is 3 inch. What is its length in cm? |
| Answer» 3 inch= 3 ×2.54cm/1inch=7.62cm | |
| 23. |
(i) What is meant by the term ‘coordination number’?(ii) What is the coordination number of atoms:(a) in a cubic close-packed structure?(b) in a body-centered cubic structure? |
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Answer» (i) The coordination number of a constituent particles (atom, ion or molecule) in a crystal is the number of constituent particles which are the immediate neighbour of the particle in the crystal. In ionic crystals coordination number of an ion in the crystal is the number of oppositely charged ions surrounding that particular ion. (ii) (a) 12 (b) 8. |
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| 24. |
Express the result of the following calculation to the appropriate number of significant figures: (I) 3.24 ×0.08666/5.0065 (II) 0.58 + 324.65 |
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Answer» (I) 0.281/5.006=0.0561 (II) 0.58 + 324.65= 325.23 |
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| 25. |
Which solid has the weakest intermolecular force? |
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Answer» Ice has the weakest intermolecular force. |
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| 26. |
1. Write the names of A and B?2. Identify and write the name of the shaded parts of A and B? |
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Answer» 1. Names of A and B are :
2. shaded parts of A and B are :
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| 27. |
In crystalline solid, atoms, ions or molecules are held in an orderly array. But some point defect is observed in a crystal, when a vacancy is created by an atom or ion dislocated from its normal position to an interstitial site. What is the defect called? |
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Answer» Frenkel defect. |
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| 28. |
A substance A’ crystallizes in fee lattice.1. Calculate the number of atoms present per unit cell of ‘A’.2. In a crystalline solid AB, some vacancy is produced by missing of equal number of oppositely charged ions. What is the defect called? |
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Answer» 1. The number of atoms present per unit cell of ‘A’.
2. Schottky defect |
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| 29. |
(a) Which of the following is not a characteristic of a crystalline solid?(i) Definite heat of fusion(ii) Isotropic nature(iii) A regular ordered arrangement of constituent particles(iv) A true solid(b) Frenkel defect and Shottky defects are two stoichiometric defects found in crystalline solids.(i) What are stoichiometric defects?(ii) Write any two differences between Frenkel defect and Schottky defect. |
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Answer» (a) (ii) Isotropic nature (ii)
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| 30. |
A cubic solid is made of two elements P and Q. Atoms of Q are at the corners of the cube and P at the body centre. What is the formula of the compound? What are the coordination numbers of P and Q? |
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Answer» As atoms Q are present at the 8 corners of the cube, therefore, number of atoms of in the unit cell = \(\frac{1}{8}\) × 8 = 1 As atoms P are present at the body centre, therefore, number of atoms of x in the unit cell = 1 ∴ Ratio of atoms x:y =1:1 Hence the formula of the compound is PQ coordination number of each of P and Q = 8. |
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| 31. |
What makes a glass different from a solid such as quartz? Under what conditions could quartz be converted into glass? |
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Answer» Glass is an amorphous solid in which the constituent particles (SiO4 tetrahedra) have only short range order and there is no long range order. On melting quartz and then cooling it rapidly, it is converted into glass. |
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| 32. |
Prepare a short profile of Michael Jackson using the hints given below.Born: 1958, America Known as: King of PopFamous as: Singer, Songwriter, Dancer, and Actor Notable works: Bad, Dangerous, Off the wall, etc Died Answer: 2009 |
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Answer» Michael Jackson: Michael Jackson was born in 1958 in America. He was known as the King of Pop. He was famous as a singer, songwriter, dancer, and actor. His notable works are Bad, Dangerous, Off the Wall, etc. He passed away in 2009. |
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| 33. |
Read the lines from the song ‘ We’re the world’ and answer the questions that follow.There comes a time when we heed a certain call When the world must come together as one There are people dying And it’s time to lend a hand to life The greatest gift of all We can’t go on pretending day by day That someone somewhere will soon make a change We all are a part of God’s great big family And the truth, you know, Love is all we need.a. What is the greatest gift of all? b. What do you understand by the expression ‘ lend a hand to life’? c. Name the value that we all need? d. What is the message of the poem? |
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Answer» a. Lend a hand to life b. To help others, people are dying c. Love d. Live in harmony |
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| 34. |
Read the lines from the poem ‘We are the World’ and answer the question that follows.There comes a time when we heed a certain call.When the world must come together There are people dying And it’s time to lend a hand to life The greatest gift of all We can’t go pretending day by day That someone somewhere will soon make a change.We are all part of God’s great big family. And the truth you know; Love is all we need. We are the world, we are the children So let’s start giving There’s a choice we’re making We’re saving our own lives It’s true we’ll make a better day Just you and meGiven below is the summary of the lines. Some words in it are miss¬ing. Choose suitable words from the lines given and complete it.A time …(a)… when the world has to ..(b)…. the call and come…… (c) to help the ……. (d)…… people. We all belong to God’s …….. (e)……… and what we need is …..(f)….. for each other. We should not pretend someone somewhere will make a ……… (g) ……….. . |
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Answer» a. comes b. heed c. together d. dying e. family f. love g. change |
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| 35. |
What might have prompted the lyricists to sing a song like this? |
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Answer» The love for mankind and the suffering people around the world have prompted the lyricists to sing a song like this. |
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| 36. |
Why do you think that we can’t go on pretending forever? |
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Answer» lt is useless to think that someone will soon make a change somewhere. |
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| 37. |
When will a change really come according to the lyricists? |
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Answer» According to lyrisicts a real change will come only when we stand together. |
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| 38. |
If A = \(\begin{pmatrix}3&λ&2 \\1 &2&5\\2&1&1\end{pmatrix}\) is not invertible then λ = ?A. 2 B. 1 C. -1 D. 0 |
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Answer» = \(\begin{pmatrix} 3&λ&2 \\ 1 &2&5\\2&1&1 \end{pmatrix}\) │A│= 0 1(2 x 1 – 5 x 1) - (1 x 1 – 5 x 2) + 2 ( 1 x 1 – 2 x 2) = 0 -3 + 9 λ - 6 = 0 9 λ = 9 λ = 1 |
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| 39. |
The matrix A = \(\begin{pmatrix}ab&b^2 \\-a^2 &-ab\end{pmatrix}\)isA. idempotent B. Orthogonal C. Nilpotent D. None of these |
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Answer» Matrix A is said to be nilpotent since there exist a positive integer k =1 such that Ak is zero matrix. |
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| 40. |
If │A│=3 and A-1 = \(\begin{pmatrix}3&-1 \\-5/ 3 &2/3\end{pmatrix}\)then adj A = ?A. \(\begin{pmatrix}9&3 \\-5 &-2\end{pmatrix}\)B.\(\begin{pmatrix}9&-3 \\-5 &2\end{pmatrix}\)C.\(\begin{pmatrix}-9&3 \\5 &-2\end{pmatrix}\)D. \(\begin{pmatrix}9&-3 \\5 &-2\end{pmatrix}\) |
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Answer» -1= 1|A| adj A adj A = |A| x A-1 = 3 x \(\begin{pmatrix}3&-1 \\-5/ 3 &2/3\end{pmatrix}\) = \(\begin{pmatrix}9&-3 \\-5 &2\end{pmatrix}\) |
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| 41. |
If A = \( \begin{pmatrix}2&-1 \\1 &3\end{pmatrix}\), then A-1 = ?A.\( \begin{pmatrix}3/7&-1/7 \\1/7 &2/7\end{pmatrix}\)B.\( \begin{pmatrix}3/7&1/7 \\-1/7 &2/7\end{pmatrix}\)C.\( \begin{pmatrix}1/3&1/7 \\1/7 &2/7\end{pmatrix}\)D. None of these |
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Answer» 1 = 1/|A| adj A --------- 1 |A| = 3 x 2 – (1) x (-1) = 7 C11 = 3 C12 = -1 C21 = 1 C22 = 2 Cofactor matrix A = \( \begin{pmatrix} 2&1 \\ 4 &3 \end{pmatrix}\) Adj A = \( \begin{pmatrix} 3&-1 \\ 1 &2 \end{pmatrix}\) = \( \begin{pmatrix} 3&1 \\ -1 &2 \end{pmatrix}\) Putting in 1 A-1 = 1/|7| \( \begin{pmatrix} 3&1 \\ -1 &2 \end{pmatrix}\) = \( \begin{pmatrix} 3/7&1/7 \\ -1/7 &2/7 \end{pmatrix}\) |
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| 42. |
If A = \(\begin{pmatrix} 1 & k & 3 \\ 3 & k &-2 \\ 2 & 3 & -4 \end{pmatrix}\)is singular then k = ?((1,k,3),(3,k,-2),(2,3,-4))A. 16/3B. 34/3C. 33/2D. none of these |
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Answer» When a given matrix is singular then the given matrix determinant is 0. |A| = 0 Given, A = \(\begin{pmatrix} 1 & k & 3 \\ 3 & k &-2 \\ 2 & 3 & -4 \end{pmatrix}\) |A| = 0 1(-4k + 6) –k(-12 + 4) +3 (9 -2k)= 0 -4k + 6 +12k -4k + 27 -6k = 0 -2k +33 = 0 k = 33/2, |
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| 43. |
If A = \(\begin{pmatrix}a & b \\c & d \\\end{pmatrix}\)then adj A = ?((a,b),(c,d))A. \(\begin{pmatrix}d& -c \\-b & a \\\end{pmatrix}\)B. \(\begin{pmatrix}-d & b \\c & -a \\\end{pmatrix}\)C. \(\begin{pmatrix}d &-b \\-c & a \\\end{pmatrix}\)D.\(\begin{pmatrix}-d &-b \\c & a \\\end{pmatrix}\) |
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Answer» To find adj A we will first find the cofactor matrix C11 = d C12 = -c C21= -b C22 = a Cofactor matrix A = \(\begin{pmatrix}d& -c \\-b & a \\\end{pmatrix}\) Adj A = \(\begin{pmatrix}d& -c \\-b & a \\\end{pmatrix}\) = \(\begin{pmatrix}d& -c \\-b & a \\\end{pmatrix}\) |
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| 44. |
If A is a square matrix such that │A│≠0 and A2 – A + 2I = 0 then A-1 = ? A. (I-A) B. (I+A)C. 1/2(I - A)D. 1/2 (I + A) |
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Answer» 2 – A + 2I = 0 Multiplying by A-1 A-1A2 – A-1A + 2I A-1 = 0 A- I + 2 A-1 = 0 A-1 = 1/2(I - A) |
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| 45. |
If A = \( \begin{pmatrix}3&1 \\7 &5\end{pmatrix}\) and A2 + xI = yA then the values of x and y areA. X = 6, y = 6 B. X = 8, y = 8 C. X = 5, y = 8 D. X = 6, y = 8 |
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Answer» 2 + xI = yA \( \begin{pmatrix}3&1 \\7 &5\end{pmatrix}\)\( \begin{pmatrix}3&1 \\7 &5\end{pmatrix}\) + x\( \begin{pmatrix}1&0 \\0 &1\end{pmatrix}\) = y \( \begin{pmatrix}3&1 \\7 &5\end{pmatrix}\) \( \begin{pmatrix}16&8 \\56 &32\end{pmatrix}\) + x\( \begin{pmatrix}1&0 \\0 &1\end{pmatrix}\) = y\( \begin{pmatrix}3&1 \\7 &5\end{pmatrix}\) 8\( \begin{pmatrix}2&1 \\7 &4\end{pmatrix}\) + x\( \begin{pmatrix}1&0 \\0 &1\end{pmatrix}\) = y\( \begin{pmatrix}3&1 \\7 &5\end{pmatrix}\) Comparing L.H.S and R.H.S x = 8 y = 8 |
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| 46. |
If A and B are two nonzero square matrices of the same order such that AB = 0 then A. │A│=0 or │B│= 0 B.│A│=0 and │B│= 0 C.│A│≠0 and │B│≠ 0 D. None of these |
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Answer» s AB is a 0 matrix its determinant has to be 0. So │AB│=│A││B│= 0 So │A│=│B│= 0 |
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| 47. |
If A and B are invertible square matrices of the same order then (AB)-1 = ? A. AB-1 B.A-1B C.A-1B-1 D.B-1A-1 |
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Answer» (AB)(AB)-1 = I A -1(AB)(AB)-1 = IA-1 (A-1A)B (AB)-1=A-1 IB(AB)-1 = A-1 B(AB)-1 = A-1 B-1B(AB)-1 = B-1 A-1 I (AB) -1 = B -1A -1 (AB) -1 = B -1A -1 |
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| 48. |
If A and B are invertible matrices of the same order then (AB)-1 = ? A. (A-1 х B-1) B. (A х B-1) C. (A-1 х B) D. (B-1 х A-1) |
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Answer» (AB)(AB)-1 = I A-1(AB)(AB)-1 = IA-1 (A -1A)B (AB) -1=A-1 IB(AB)-1 = A-1 B(AB)-1 = A-1 B-1B(AB)-1 = B-1 A-1 I (AB)-1 = B-1A-1 (AB)-1 = B-1A-1 |
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| 49. |
For any two matrices A and B, A. AB = BA is always true B. AB =BA is never true C. sometimes AB = BA and sometimes AB ≠ BA D. whenever AB exists, then BA exists |
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Answer» If the two matrices A and B are of same order it is not necessary that in every situation AB = BA AB = BA = I only when A = B-1 B = A-1 Other time AB ≠ BA |
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| 50. |
If A is a 3-rowed square matrix and │A│=5 then │adj A│=? A. 5 B. 25 C. 125 D. none of these |
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Answer» The property states that │adj A│= │A│n-1 Here n= 3 and │A│=5 │adj A│= │5|3-1 = │5│2 = 25 |
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