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When the great man is wounded, he shows his best effort. He lifts his head with great courage like a snake and lifts its hood to create the fire of anger. His heart fills with great courage like a lion and he notices in the depth of his soul and becomes aware about his hidden powers and shows his best effort.

जब महान आदमी घायल हो जाता है तब वह अपने सर्वोत्तम प्रयास करता है। वह अपना सिर साहस के साथ उठाता है जैसे कि एक साँप अपना फन उठाता है तथा क्रोध की आग उगलता है। उसका दिल शेर की तरह साहस से भर जाता है तथा वह अपनी आत्मा की गहराई में देखता है तथा अपनी छुपी हुई शक्तियों से अवगत हो जाता है और अपने पूरे प्रयास करता है।

The poet addresses the man in the form of soul in the fourth stanza.

चौथे पद्यांश में कवि आदमी को आत्मा के रूप में सम्बोधित करता है।

The poet refers to the dreams of man in which he thinks to complete his expectations.

कवि आदमी के उन सपनों को प्रस्तुत करता है जिसमें वह अपनी भौतिक आशाओं को पूरा करने की सोचता है।

The rhyme scheme in the first stanza is based on ABAB.

प्रथम पद्यांश में तुक योजना ABAB पर आधारित है।

Correct answer is (c) Old age

The poet says that “I am He” because he clears that the soul has no shape and it can neither be called angel and man nor animal. There is no sex of the soul and it is formless. There is no particular explanation about it in books. So the poet calls the man like God.

कवि कहता है कि मैं वह हूँ। क्योंकि वह स्पष्ट करता है कि आत्मा का कोई स्वरूप व शरीर नहीं होता है। इसे ना तो आदमी कह सकते हैं और ना ही देवदूत और ना ही इसे जानवर कह सकते हैं। आत्मा का कोई लिंग भी नहीं होता है तथा उसके बारे में किताबों में भी कोई विशेष व्याख्या नहीं है। इसलिए कवि आदमी को भगवान कहता है।

In the first two stanzas the poet discusses about the troubles and mental conditions of the man and his efforts in adverse situation of life. He clears that the wounded man becomes more powerful like a lion. His heart fills with awareness to prove himself best.

प्रारम्भिक दो पद्यांशों में कवि मानव की परेशानियों तथा उसकी मानसिक स्थिति को दर्शाता है कि मानव विपरीत हालात में कैसे प्रयास करता है। वह कहता है कि घायल व्यक्ति शेर की तरह अधिक शक्तिशाली हो जाता है। उसका दिल पूर्ण जागरूक हो जाता है और वह अपने सर्वोत्तम प्रयास करता है।

The poet delivers an important lesson to the readers that the soul is immortal and the soul exists in the structure of man. In this way the man is immortal and he will remain in this world forever so that the man must love the man in order to become true worshipper of God because God lives in all men and the service of man is the true worship of God who is everywhere.

कवि पाठकों को एक महत्त्वपूर्ण शिक्षा देता है कि आत्मा अमर है तथा आत्मा मानव शरीर में विद्यमान होती है। इस तरह आदमी अमर है तथा वह इस संसार में हमेशा रहेगा। अतः मानव को मानव से प्रेम करना चाहिए ईश्वर का सच्चा उपासक बनने के लिए क्योंकि भगवान सभी लोगों में विद्यमान है तथा मानव की सेवा ही भगवान की सच्ची पूजा है जो कि सब जगह विद्यमान है।

The poet advises the man to love himself because the man is God and God lives in the man and all the nature and natural elements exist in man. He existed in this world before the creation of this world and he will remain in it forever. So the man should love himself because his soul is immortal.

कवि मानव को स्वयं से प्रेम करने की सलाह देता है क्योंकि मानव ही भगवान है तथा भगवान मनुष्य में रहता है तथा पूरी प्रकृति एवं प्रकृति के सभी तत्त्व उसमें विद्यमान हैं। वह इस संसार की उत्पत्ति से पहले भी इसमें विद्यमान था तथा हमेशा के लिए इसमें रहेगा। अतः आदमी को स्वयं से प्रेम करना चाहिए अर्थात् उसे . अपनी आत्मा से प्रेम करना चाहिए जो कि अमर है।

According to the poet the existence of man is very old. He existed in this world before the creation of the sun and moon as well as all the heavenly bodies and the universe. He means to say that the man took birth in this world, at first before the creation of the earth and the space and the natural elements.

कवि के अनुसार मानव का अस्तित्व बहुत पुराना है। वह सूर्य तथा चन्द्रमा की उत्पत्ति से भी पहले इस संसार में विद्यमान था अर्थात् सभी आकाशीय पिण्ड एवं इस ब्रह्माण्ड से पहले। कहने का आशय यह है कि मानव ने पृथ्वी की उत्पत्ति से भी पहले। इस संसार में जन्म लिया तथा इस ब्रह्माण्ड में प्राकृतिक तत्त्वों से भी पहले वह विद्यमान था।

When the man becomes old, his eye sight becomes dim and the sense of distrust develops in his heart. He begins to fear about his fate. The sense of ignorance is created in his heart and mind. In such a situation all of his friends leave him alone and all his dear ones who love him forsake him.

जब आदमी बूढ़ा हो जाता है तब उसकी नेत्र-ज्योति हल्की हो जाती है तथा उसके दिल में अविश्वास पैदा हो जाता है वह अपने भाग्य के प्रति भयभीत हो जाता है। उसके दिल में अज्ञानता के भाव विकसित हो जाते हैं। ऐसी दशा में उसके सभी दोस्त उसे अकेला छोड़ देते हैं तथा उसके सभी प्रेमी जो उसे प्रेम करते हैं, उसे हमेशा के लिए नजरंदाज कर देते हैं।

According to the view of the poet the soul of the human being is immortal. It existed in this world before the creation of the heavenly bodies and it is present now and will remain permanent in this world in near future.

कवि के नजरिये के अनुसार मानव की आत्मा अमर है। यह इस संसार में आकाशीय पिण्डों की उत्पत्ति से भी पहले विद्यमान थी तथा आज भी है और निकट भविष्य में भी विद्यमान रहेगी।

The books written by Confucius and Zuangzi are full of anecdotes. They play important part in China’s classical education. They deeply reveal the spirit in which art was considered.

1. This line means that the brave people work hard while others pass their time in idleness.

2. The gist of the stanza is that nation needs brave, courageous and hard working people. The nation can be built strong by our bravery, courage and hard work.

3. The people who are hard-working and courageous help to build a strong foundation of a nation.

Or

A nation can be made strong by hard work and courage.

4. The poet means by this line that those people raise the nation to a great height.

5. The qualities of brave men are that 

1. they work while others sleep and 

2. they hold courage when others run away.

6. Brave men work hard while others sleep.

The poet R. W. Emerson says that not wealth but only men can make a nation great. If we want our nation to be great, we have to be brave, courageous and hard-working. These qualities would provide a strong base on which a great, strong and glorious building of a nation can stand.

‘The thought’ refers to the concept of grandmother being ‘young and pretty’. The author had seen her for the last twenty years as the ‘same, old, wrinkled’ woman. He couldn’t imagine her in any younger condition. If anybody told him to imagine her as young, it would be totally opposite of his perception of ‘grandmother’. So he says the thought itself was ‘revolting’.

The genetic composition of an organism in Genotype.

Identical or monozygotic twins

Colour blindness.

Non-identical or fraternal twins

A little girl.

I would have never let it tp be killed, similarly to the girl in the story

• Uncle Ram wants to play with Sweety. False 
• Sweety was safe in the girl’s friend’s house. True

Sweety loves to eat carrots and raw vegetables.

White like cotton eyes beautiful like pomegranate seeds, beautiful long ears, sweet.

Sweety: Uncle Ram, Please don’t kill me. I too have life like you. I would also like to live and play. Have mercy on me. Please kindly let me live. (would, kill, kindly, let, have). She would have told him to be compassionate towards dumb animals and not to kill them for there meat.

The robin will come to our house if we throw the bread crumbs in the front open space of our house.

“Never hurt the timid have” To the bright windows of the sky” “Singing as if it were always spring And fluttering on an untired wing. “Nor do these gentle creatures wrong”.

A military tent is made as a combination of right circular cylinder and right circular cone on top.

Given :

Total Height of tent = h = 8.25 m

Base diameter of tent = 30 m, then

Base radius of tent = r = 30/2 m = 15 m

Height of right circular cylinder = 5.5 m

Base radius of cone = 15 m

Let slant height of cone = l m

Now,

Curved surface area of right circular cylindrical part of tent = 2πrh

and

Height of conical part = total height of tent – height of cylindrical part

Height of cone = 8.25 – 5.5 = 2.75 m

l² = h² + r²

= 2.75² + 15²

= 232.5625

or l = 15.25 m

Curved surface area of conical part of the tent = πrl

Total surface area of the tent = Curved surface area of cylindrical part + curved surface area of conical part

Total surface area of tent = 2πrh + πrl

= πr(2h + l)

= 22/7 × 15 × (2 × 5

= 1237.5

Total surface area of tent is 1237.5 m²

Breadth of canvas used = 1.5 m

Length of canvas used x breadth of canvas used = Total surface area of tent

Length of canvas used = 1237.5\1.5 = 825

Length of canvas used is 825 m. Answer!!

Lark flies high “ The little lark goes souring high To the bright windows of the sky”.

Let, f (x) = x³ - 23x² + 142x - 120

The factors of the constant term – 120 are \(\pm\)1, \(\pm\)2, \(\pm\)3, \(\pm\)4, \(\pm\)5, \(\pm\)6, \(\pm\)7, \(\pm\)8, \(\pm\)9, \(\pm\)10, \(\pm\)11,\(\pm\)12, \(\pm\) 15, \(\pm\) 20, \(\pm\) 24, \(\pm\) 30, \(\pm\) 40, \(\pm\) 60, and \(\pm\) 120

Putting x = 1, we have

f (1) = (1)³ – 23 (1)² + 142 (1) – 120

= 1 – 23 + 142 – 120

= 0

So, 

(x – 1) is a factor of f (x)

Let us now divide

f (x) = x³ - 23x² + 142x - 120 by (x - 1) to get the other factors of f (x)

Using long division method, we get

x³ - 23x² + 142x - 120 = (x – 1) (x² – 22x + 120)

x² – 22x + 120 = x² – 10x – 12x + 120

= x (x – 10) – 12 (x – 10)

Hence, 

x³ - 23x² + 142x - 120 = (x – 1) (x - 10) (x - 12)

Let, f (y) = y³ - 7y + 6

The constant term in f (y) is equal to + 6 and factors of \(\pm\) 1, \(\pm\) 2, \(\pm\) 3 and \(\pm\) 6

Putting y = 1 in f (y), we have

f (1) = (1)³ – 7 (1) + 6

= 1 – 7 + 6

= 0

Therefore, 

(y - 1) is a factor of f (y).

Similarly, (y - 2) and (y + 3) are the factors of f (y).

Since, f (y) is a polynomial of degree 3. 

So, 

it cannot have more than three linear factors

Therefore, 

f (y) = k (y – 1) (y - 2) (y + 3)

y³ - 7y + 6 = k (y – 1) (y - 2) (y + 3)

Putting x = 0 on both sides, we get

0 – 0 + 6 = k (0 – 1) (0 - 2) (0 + 3)

6 = 6k

k = 1

Putting k = 1 in f (y) = k (y – 1) (y - 2) (y + 3), we get

f (y) = (y – 1) (y - 2) (y + 3)

Hence,

y³ - 7y + 6 = (y – 1) (y - 2) (y + 3)

Degree of polynomial in:

(i) 7x³ + 4x² - 3x + 12 is 3

(ii) 12 - x + 2x³ is 3

(iii) 5y - \(\sqrt{2}\) is 1

(iv) 7 is 0

(v) 0 is undefined

(i) x² -xy +7y² is a polynomial in two variables x,y.

(ii) x² -2tx + 7t² -x +t is a polynomial in 2 variables x, t.

(iii) t³ -3t² +4t -5 is a polynomial in 1 variables t.

(iv) xy +yz +zx is a polynomial in 3 variables x, y, z. 

(i) x² - xy + 7y² is a polynomial in two variable x, y.

(ii) x² - 2tx + 7y² - x + t is a polynomial in two variable x, t.

(iii) t³ - 3t² + 4t - 5 is a polynomial in one variable t.

(iv) xy + yz + zx is a polynomial in three variable x, y, t.

Given polynomial,

(i) x + x² + 7y² is quadratic as degree of polynomial is 2.

(ii) 3x - 2 is linear as degree of polynomial is 1.

(iii) 2x + x² is quadratic as degree of polynomial is 2.

(iv) 3y is linear as degree of polynomial is 1.

(v) t² + 1 is quadratic as degree of polynomial is 2.

(vi) 7t⁴ + 4t³ + 3t - 2 is bi-quadratic as degree of polynomial is 4.

Given polynomial 

(i) x + x² +4 is quadratic as degree of polynomial is 2.

(ii) 3x -2  is linear as degree of polynomial is 1. 

(iii) 2x + x² is quadratic as degree of polynomial is 2. 

(iv) t² +1 is quadratic as degree of polynomial is 2. 

(v) 7t⁴ +4t³ +3t -2  is bi-quadratic as degree of polynomial is 4. 

Number of bullets fired in one minute = 200

work done by the gun in one minute is,

W = kinetic energy of 200 bullets

W = 200 x (1/2 mv²)

= 200 × (1/2) x 0.02 x (60)²

= 7200J

∴ Power P = w/t, t = 60 seconds

p = 7200/60 = 120 watt.

∴ Power of the gun = 120 watts.

Let the common ratio between their ages be x. Therefore, Hari’s age and Harry’s age will be 5x years and 7x years respectively and four years later, their ages will be (5x + 4) years and (7x + 4) years respectively. According to the situation given in the question,

5x + 4/7x + 4 = 3/4

4( 5x + 4 ) = 3( 7x + 4 )

20x + 16 = 21z + 12

16 - 12 = 21x - 20x

4 = x

Hari’s age = 5x years = (5 × 4) years = 20 years Harry’s age = 7x years = (7 × 4) years = 28 years

Therefore, Hari’s age and Harry’s age are 20 years and 28 years respectively.

The resistance offered by air and the friction of surface oppose the motion so the moving bodies have to stop after sometime. Had there been no friction, no force would have been required to keep a body in the state of uniform motion in a straight line (i.e., linear uniform motion).

Given Hari age =5x
given Harry age=7x
4 years later both of their age is =5x+4
                                              = 7x+4
after this their age are given = 3:4 =3/4
=5x/7x = 3/4  (division methord)
5x+4  
7x+4
=20x+16=21x+12
=21x-20x=16-12
= x=4

Hari’s age = 5x years = (5 × 4) years = 20 years

Harry’s age = 7x years = (7 × 4) years = 28 years

Therefore, Hari’s age and Harry’s age are 20 years and 28 years respectively.

The recoil speed of the gun is inversely proportional to its mass. So, the recoil speed of the heavy gun is lesser than that of the light sun.

The water on a muddy road provides a thin layer between the road and our feet. This layer breaks the interlocking and decreases friction between two surfaces.

The boy who falls on a muddy floor will survive due to reduction of impact of force by prolonging the time of reduction of force from maximum to zero.

Son age be x
Aman age is 3x
ten years ago
son age x-10
aman age 3x -10
A/Q
5(x-10) = 3x -10
 5x -50 = 3x - 10
2x = 40
x =20
3x=60

son present age =20
aman present age = 60

Let , the present age of Ravi be x
Ravi's age after fifteen years = x+15
a\q,

=>x+15 = 4x
=> 4x-x =15
=> 3x =15
=> x = 15/3
=> x = 5

so,present age of Ravi is 5 years.

Let Shobo’s age be x years. Therefore, his mother’s age will be 6x years.

According to the given question,

After 5 years.Shobo's age = Shobo's mother's present age/3

x + 5 = 6x/3

x + 5 = 2x

Transposing x to R.H.S, we obtain

5 = 2x - x

5 = x

6x = 6 x 5 = 30

Therefore, the present ages of Shobo and Shobo’s mother will be 5 years and 30 years respectively.

Let Ravi’s present age be x years.

Fifteen years later, Ravi’s age = 4 × His present age x + 15 = 4x

On transposing x to R.H.S, we obtain

15 = 4x − x

15 = 3x

On dividing both sides by 3, we obtain

15/3 = 3x/3

5 = x

Hence, Ravi’s present age = 5 years

Let Baichung’s father’s age be x years. Therefore, Baichung’s age and Baichung’s grandfather’s age will be (x − 29) years and (x + 26) years respectively.

According to the given question, the sum of the ages of these 3 people is 135 years.

∴ x + x − 29 + x + 26 = 135

3x − 3 = 135

On transposing 3 to R.H.S, we obtain

3x = 135 + 3

3x = 138

On dividing both sides by 3, we obtain

3x/3 = 138/3

x = 46

Baichung’s father’s age = x years = 46 years

Baichung’s age = (x − 29) years = (46 − 29) years = 17 years

Baichung’s grandfather’s age = (x + 26) years = (46 + 26) years = 72 years

Let the runs made by Rohit be x. 

∴ Runs made by Virat = 2x 

According to the given condition, 

x + 2x = 200 – 2 

∴ 3x = 198 

∴ x = 198/3 = 66

∴ Runs made by Virat = 2x = 2 × 66 = 132 

∴ The runs made by Virat and Rohit are 132 and 66 respectively.