InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
A cylindrical vessel of diameter 14 cm and height 42 cm is fixed symmetrically inside a similar vessel of diameter 16 cm and height of 42 cm. The total space between the two vessels is filled with cork dust for heat insulation purposes. How many cubic cms of the cork dust will be required? |
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Answer» Given, Depth of the cylindrical vessel = Height of the cylindrical vessel = h = 42 cm (common for both) Inner diameter of the cylindrical vessel = 14 cm So, the inner radius of the cylindrical vessel = r1 = 14/2 = 7 cm Outer diameter of the cylindrical vessel = 16 cm So, the outer radius of the cylindrical vessel = r2 = 16/2 = 8 cm Now, The volume of the cylindrical vessel V = π(r22 – r12 ) x h = π(82 – 72 ) x 42 = 22/7 x 15 x 42 V = 1980 cm3 Therefore, the total space between the two vessels is 1980 cm3, which is also the amount of cork dust required. |
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| 352. |
The outer measurements of a closed wooden box are 42cm, 30m and 27cm. If the box is made of 1cm thick wood, determine the capacity of the box |
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Answer» Outer dimensions l = 42cm b = 30cm h = 27cm Thickness of wood = 1cm Inner dimensions l = 42 - (1 + 1) = 40cm b = 30 - 1(1 + 1) = 28cm h = 27 - (1 + 1) = 25cm ∴ Capacity of the box l × b × h = 40 × 28 × 25 = 28000cm2. |
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| 353. |
50 circular plates each of diameter 14 cm and thickness 0.5 cm are placed one above the other to form a right circular cylinder. Find its total surface area. |
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Answer» Given, 50 circular plates each with diameter 14 cm Radius of circular plates = 7cm Thickness of plates = 0.5 cm As these plates are one above the other, the total thickness of all the plates = 0.5 x 50 = 25 cm So, the total surface area of the right circular cylinder formed = 2πr × h + 2πr2 = 2πr (h + r) = 2(22/7) x 7 x (25 + 7) = 2 x 22 x 33 = 1408 cm2 Therefore, the total surface area of the cylinder is 1408 cm2. |
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| 354. |
30 circular plates, each of radius 14 cm and thickness 3 cm are placed one above the another to form a cylindrical solid.Findthe total surface area.volume of the cylinder so formed. |
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Answer» Given, radius of a circular plate, r = 14 cm Thickness of a circular plate = 3 cm Thickness of 30 circular plates = 30 x 3 = 90 cm Since, 30 circular plates are placed one above the another to form a cylindrical solid. Then, Height of the cylindrical solid, h = Thickness of 30 circular plates = 90 cm 1. Total surface area of the cylindrical solid so formed = 2πr(h+ r) = 2 x (22/7) x 14(90+ 14) = 44 x 2 x 104 = 9152 cm2 Hence, the total surface area of the cylindrical solid is 9152 cm2, 2. Volume of the cylinder so formed = πr2h = (22/7) (14)2 x 90 = (22/7) x 14 x 14 x 90 = 22 x 28 x 90 = 55440 cm3 Hence, the volume of the cylinder so formed is 55440 cm3. |
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| 355. |
25 circular plates, each of radius 10.5 cm and thickness 1.6 cm, are placed one above the other to form a solid circular cylinder. Find the curved surface area and the volume of the cylinder so formed. |
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Answer» Radius of each circular plate = 10.5 cm Thickness of each plate = 1.6 cm 25 plates are placed one above the other to form a solid circular cylinder ∴ height of the cylinder formed, h = 25 × 1.6 cm = 40 cm Total curved surface area of the cylinder = 2πrh = \(2\times\frac{22}{7}\times10.5\times40\) = 2640 cm2 Volume of cylinder = πr2 h = π (10.5)2 × 40 = 13860 cm3 |
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| 356. |
Complete the following reactions-(a) CH4+O2→(b) CH4+Cl2+Sunlight → |
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Answer» (a) CH4+O2→CO2+2H2O+Heat+Light (b) CH4+Cl2+Sunlight →CH3Cl+HCl |
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| 357. |
Complete the following chemical equations:(i) CH3COOH+Na2CO3→(ii) CH4+O2→(iii) C2H5OH+Na→ |
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Answer» (i) 2CH3COOH+Na2CO3→2CH3COONa+H2O+CO2 (ii) CH4+2O2→CO2+2H2O (iii) 2C2H5OH+2Na→2C2H5ONa+H2 |
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| 358. |
Consider the following organic compounds :HCHO, C2H5OH, C2H6, CH3COOH, C2H5C1Choose two compounds which can react in the presence of cone. H2S04 to form an ester. Give the name and formula of the ester formed. |
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Answer» C2H5OH and CH3COOH react in the presence of conc. H2SO4 to form an ester. Ethyl ethanoate, CH3COOC2H5 is formed in the reaction. |
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| 359. |
Identify, from the following the hydrocarbons that can undergo addition reactions:C3H4, C2H6, CH4, C2H4. Justify your answer. |
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Answer» C3H4, C2H4 will undergo addition reactions because they are unsaturated compounds. |
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| 360. |
Explain different steps to be followed for organising a health run in your school. |
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Answer» Steps to be followed for organising health run in your school : (i) Committee will be made (ii) Registration (iii) Date/Time (iv) No age group (v) Distance to be mentioned (vi) Refreshment to all participants. (a) Circular will be displayed on students noticeboard. (b) Registration will be done for the participants. (c) Date and time is fixed and informed to all registered. (d) On the day of health run, Chief Guest can be invited. (e) Distance to be covered for health run is 5-10 km. participants may jog/run and walk. (f) After finishing of health run, refreshment must be distributed to all associated with the programme of health run. (g) Proper dispersal of students. The main aim to organise health run for schoolchildren is to create awareness and develop healthy citizens of India. |
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| 361. |
What are the benefits of organising specific sports programmes? |
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Answer» Benefits of Organising health runs and awareness programmes: (a) Health runs reduce the risk of cardio-vascular diseases and ensure proper flow of blood and oxygen throughout the body. (b) Improves respiratory system, it increases the ability of individual to take in more oxygen and throw out more carbon dioxide. (c) It keeps the joints healthy and flexible. These runs improve the range of movement of the joints of our body. (d) Prevents Diabetes, running burns glucose which prevents glucose level from rising too high. (e) Improves the immune system. Health runs help to boost immune system. (f) They make people aware about deadly diseases and also inform us about their causes, symptoms and prevention. (g) Helps to create awareness among people to add fitness programme as part of their lifestyle. (h) Helps to change attitude of people. (i) Such runs also help in raising funds for some charitable organizations. (j) Spread message among the mass to remain healthy and fit by taking part in such runs. |
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| 362. |
What points should be kept in mind before organising Intramural Competitions? |
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Answer» Before conducting the Intramural Competition the following factors have to be taken into consideration: (a) Type of institute - i.e., residential, day-boarding or mixed. (b) Climatic conditions. (c) Infrastructure/facilities available. (d) Estimated finances. (e) Availability of time. (f) Activity as per students interest. (g) Possible help from school staff/students. |
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| 363. |
Highlight the importance of Intramural and Extramural Competitions. |
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Answer» Importance of intramural and extramural Competitions: (a) To provide opportunities to the students at the institution to develop and display their skills in various physical education activities. (b) To provide opportunities to the students for fun, enjoyment and to develop fellowship participation in sports competitions. (c) To provide opportunities to develop leadership and fellowership qualities. (d) To provide opportunity to students to release tension, depression and aggression. (e) To provide a feeling of achievement through sports participation which leads to mental and emotional health. (f) To provide students ample opportunities to develop their physical, mental, emotional and social health through participation in activities. (g) Players are benefitted by getting organizing and administrative experience of conducting intramural and extramural competitions. (h) To provide opportunities to the players of various teams to have exposure to the competition. (i) To provide opportunities to all the students of the same institution or other institutions to join a common platform and socialize. (j) It teaches the participants to respect the game, officials, opponents, spectators and accept victory or defeat with grace. |
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| 364. |
The bond angle in C2H4 is A) 109° 28′ B) 180° C) 104° 27′ D) 120° |
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Answer» Correct option is D) 120° |
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| 365. |
Which compound has an addition reaction with - chlorine? A. C2H4 B. C2H5OH C. C2H6 D. CH3CO2H |
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Answer» C2H4 is an alkene which is an unsaturated compound. It gives addition reaction. |
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| 366. |
Your school is organising 'Run for Unity', explain the responsibilities of accreditation, technical and finance committee. |
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Answer» For organizing 'Run of Unity' responsibilities for (a) Accredition, (b) Technical and, (c) Finance committee are as follows. (a) Accredition Committee: It is over all responsible for organizing The 'Run for unity'. It has a set pattern and code of conduct to organise the event. It makes sure that ethics, rules, regulations are followed throughout the event management. It is an officially recognized body to conduct. (b) Technical Committee: This is the most important committee for conducting the event run smoothly. In this committee event officials are deputed well in advance. Competent persons are deputed and trained to ensure events in orderly manner. (c) Finance Committee: It is responsible for all financial receipts and expenditure, according to the budgetary plan works as per the directions of the school, authorities. |
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| 367. |
Being sports captain of the school, prepare five important committees with their responsibilities to conduct one day Run for Health Race. |
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Answer» To organise one day health run five important committees will be: (a) Organising committee: It is headed by sports captain as overall in-charge of conducting the event. All the aspects of sporting events to be conducted are administered through this committee. (b) Reception committee: The responsibility of reception committee is to see that special invitees are welcomed and taken to the seats reserved for them. They plan to invite the guests well in advance and take care of their reception. (c) Transport committee: It looks after the transportation of School children and officials to the venue of sporting activity being organised. It takes care before, during and after the health run event. (d) Refreshment committee: It is formed to provide refreshment to the participants, officials and all those involved in the entire programme. It must be ensured that everyone gets refreshment. (e) Finance committee: It is responsible for all financial receipts and expenditure, etc. They should work as per budget plan. This committee makes all the payments. They must work as per the directions given by school, authorities. |
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| 368. |
A bookseller sells a book for Rs. 100, gaining Rs. 20. His gain per cent is A. 20% B. 25% C. 22% D. none of these |
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Answer» SP = Rs.100 Gain = Rs.20 CP = SP – Gain = 100 - 20 = Rs.80 \(Gain\%=\frac{Gain\,\times\,100}{CP}\) = \(\frac{20\,\times\,100}{80}\) = 25% |
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| 369. |
Find the single discount which is equivalent to two successive discounts of 20% and 5%. |
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Answer» First Discount = 20% Second Discount = 5% The formula for total discount in case of successive discounts: If the first discount is x% and 2nd discount is y% then, Total Discount = \([(x\,+\,y)-\frac{xy}{100}]\%\) \([(20\,+\,5)-\frac{20\,\times\,5}{100}]\%\) \((25-\frac{100}{100})\%\) = 24% |
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| 370. |
State whether the following statements are true or false. Correct the false statement:1. Rhode Island Red, New Hampshire, Plymouth Rock, Black Rock are varieties of chicken reared for both eggs as well as meat.2. Phloem consists of thick-walled dead cells.3. Stratified squamous epithelium is present in inner surface of mouth, oesophagus, blood vessels and alveoli.4. Broiler chickens are raised for eggs.5. Non-striated muscles bring about contraction and relaxation of heart. |
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Answer» 1. True 2. False. Phloem consists of living cells containing cytoplasm. 3. False. Stratified squamous epithelium is present in the outer layer of skin. 4. False. Broiler chickens are raised for meat. 5. False. Cardiac muscles bring about contraction and relaxation of heart. |
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| 371. |
Is a broiler chicken.(a) Leghorn (b) Lehman (c) Aseel (d) Minorca |
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Answer» Correct option is: (c) Aseel |
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| 372. |
Choose the correctly matched pair. (a) Egg layers – Brahma (b) Broiler types – Leghorn (c) Dual purpose – White Plymouth rock (d) Ornamental breeds – Silkie |
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Answer» (d) Ornamental breeds – Silkie |
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| 373. |
……… is a dual purpose chicken breed? (a) Aseel (b) Silkie (c) Brahma (d) White plymouth rock |
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Answer» Brahma is a dual purpose chicken breed? |
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| 374. |
W-ite on the Broiler breed? |
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Answer» Bioiler type: These are well known for fast growth and soft quality meat. White Plymouth rock: They have white plumage throughout the body. It is commonly used in troiler production. This is an American breed. It is a fast growing breed and well suitable for growing intensively in confined farms. |
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| 375. |
Breeding between a superior male of one breed with a superior female of another breed is called ……(a) Inbreeding (b) Outbreeding (c) Outcrossing (d) Cross breeding |
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Answer» (d) Cross breeding |
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| 376. |
…… is a liquid collected after the passage of water through a column of vermibed. |
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Answer» Vermiwash is a liquid collected after the passage of water through a column of vermibed. |
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| 377. |
Induced breeding technique is used in ……(a) Marine fishery (b) Capture fishery (c) Culture fishery (d) Inland fishery |
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Answer» (b) Capture fishery |
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| 378. |
………….. is a technique in which the semen collected from the male is injected to the reproductive tract of the selected female. |
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Answer» Artificial insemination |
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| 379. |
Choose one of the two alternatives given below and fill in the blanks in the following statements (a) If the net profits earned during the year is Rs. 50,000 and the amount of debtors in the beginning and the end of the year is Rs. 10,000 and Rs.20,000 respectively, then the cash from operating activities will be equal to Rs……………..(Rs. 40,000/ Rs.60,000). |
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Answer» The correct answer is : Rs. 40,000 |
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| 380. |
Find the value (i) 30 (ii) 75-5 (iii) (-2)3-3 (iv) (2/3)2+3-5(v) 20 × 30 (vi) 20 + 50 |
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Answer» (i) 30 30 = 1 (ii) 75-5 75-5 = 70 = 1 (iii) (- 2)3-3 = (- 2)3-3 = (- 2)0 = 1 (iv) (2/3)2+3-5 = (2/3)2+3-5 = (2/3)0 = 1 (v) 20 x 30 20 x 30 = 1 x 1 = 1 (vi) 20+ 50 20 + 50 = 1 + 1 = 2 |
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| 381. |
If P(n) : 2n < n!, n ∈ N, then P(n) is true for all n ≥ ________. |
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Answer» Answer is 4 |
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| 382. |
If xn – 1 is divisible by x – k, then the least positive integral value of k is(A) 1 (B) 2 (C) 3 (D) 4 |
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Answer» Answer is (A) 1 |
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| 383. |
If 10n + 3.4n+2 + k is divisible by 9 for all n ∈ N, then the least positive integral value of k is(A) 5 (B) 3 (C) 7 (D) 1 |
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Answer» Answer is (A) 5 Correct option(A) Explanation: Given 10n + 3.4n+2 +k is exactly divisible by 9, P(1) = 101+3.41+2 +k = 2012 +k is exactly divisible by 9 then the value of k is 5. |
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| 384. |
If P (n) : “49n + 16n + k is divisible by 64 for n ∈ N” is true, then the least negative integral value of k is ______. |
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Answer» For n = 1, P(1) : 65 + k is divisible by 64. Thus k, should be – 1 since, 65 – 1 = 64 is divisible by 64. |
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| 385. |
निम्नांकित संख्याओं में से 7, 11 और 13 से विभाज्य संख्याओं को छाँटकर अलग-अलग कीजिए।329623,63271,492895,25179,38632,96283, 25137 |
Answer»
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| 386. |
ज्ञात कीजिए कि 828, 2340, 38046, 77514, 893408 और 100116 में कौन-सी संख्या 9 से विभाज्य है? |
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Answer» 828, 2340, 100116 संख्याएँ 9 से विभाज्य है। |
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| 387. |
निम्नांकित संख्याओं में 5 से भाग देने पर शेषफल ज्ञात कीजिए।8034, 97446, 85405, 83560 |
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Answer» शेषफल 4,1, 0 तथा 0 |
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| 388. |
ज्ञात कीजिए कि 828, 2340, 38046, 77514, 893408 और 100116 में कौन-सी संख्या 3 से विभाज्य नर्स है? |
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Answer» 893408 (क्योंकि इसके अंकों को जोड़, 32 जो विभाज्य नहीं है।) |
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| 389. |
2 अथवा 5 से विभाज्य 1 से 100 तक के पूर्णाकों का योग होगा।(क) 2550(ख) 3050(ग) 3550(घ) 3600 |
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Answer» सही विकल्प है (ख) 3050 |
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| 390. |
क्या 722722 के अपवर्तक 7, 11और 13 हैं? |
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Answer» हाँ , 722722 के अपवर्तक 7, 11और 13 हैं। |
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| 391. |
Explain on Evolution of DBMS? |
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Answer» 1. The concept of storing the data started before 40 years in various formats. 2. In earlier days they have used punched card technology to store the data. 3. Then files were used. The file systems were known as predecessor of database system. 4. Various access methods in file system were indexed, random and sequential access. 5. The file systems has limitations like duplication, less security. To overcome this, DBMS was introduced. |
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| 392. |
State few advantages of Relational databases? |
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Answer» 1. High Availability 2. High Performance 3. Robust TrAnswer:actions and support 4. Ease of management 5. Less cost |
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| 393. |
IBM’s first DBMS is …………(a) IMS (b) IVS (c) BMS (d) VMS |
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Answer» IBM’s first DBMS is IMS. |
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| 394. |
What is relationship in databases? List its types? |
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Answer» In ER Model, relationship exists between two entities. The various types of relationships are; 1. One-to-One relationship. 2. One-to-Many relationship. 3. Many-to-Many relationship. |
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| 395. |
List any 5 privileges available in MySQL for the User? List of privileges available in MySQL? |
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Answer» Privileges: 1. Select_priv 2. Insert_priv 3. Update_priv 4. Delete_priv 5. Create_priv 6. Alter_priv Action Performed (If Granted): 1. User can select rows from database tables. 2. User can insert rows into database tables. 3. User can update rows of database tables. 4. User can delete rows of database tables. 5. User can create new tables in database. 6. User can make changes to the database structure. |
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| 396. |
Haven’t you conducted an activity to find the pH value of the soil related to different crops? Identify the pH values of soil samples collected from different places. Prepare a list of the crops that are suitable for the soil of each area on the basis of its pH value |
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| 397. |
What is the commercial name of calcium sulphate hemihydrate ? |
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Answer» Plaster of Paris. |
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| 398. |
Baking soda contains A) Sodium chloride B) Sodium bicarbonate C) Potassium chloride D) Sodium hydroxide |
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Answer» The correct answer is B) Sodium bicarbonate. |
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| 399. |
State whether the following statements are true or false. Correct the false statements.(a) Nose can use spectacles.(b) Eyes have to be shut when the Nose wears/puts on spectacles.(c) The Ear was appointed as a judge.(d) Eyes cannot use spectacles. |
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Answer» (a) False. Nose cannot use the spectacles, the spectacles uses the Nose to hold them in place. (b) False. Though this is the verdict of the judge, but this defeats the basic purpose of the existence of the Eyes. (c) True (d) False. Spectacles are meant for the Eyes for providing ability to see since it is a sensory organ. |
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| 400. |
Give reasons for the dispute between the Nose and the Eyes. |
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Answer» The dispute arose because both the Nose and the Eyes have important roles to play for the spectacles. The eyes use the spectacles to see the things and the Nose holds the spectacles to keep them in place. But unfortunately, both of them were not ready to accept the usefulness of each other for the spectacles and each was supposed to serve its own purpose. So, the dispute arose. |
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