100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS

1.	Which protocol gives a full route table update every 30 seconds?(a) IEGRP(b) RIP(c) ICMP(d) IP
Answer» Correct choice is (b) RIP To explain: RIP gives a full route table update every 30 seconds. The broadcasted routing table can be used by other routers to find the shortest path among the network devices.

Discussion

2.	Julie has created a dictionary containing names and marks as key value pairs of 6 students. Write a program, with separate user defined functions to perform the following operations:● Push the keys (name of the student) of the dictionary into a stack, where the corresponding value (marks) is greater than 75.● Pop and display the content of the stack.For example: If the sample content of the dictionary is as follows:R={"OM":76, "JAI":45, "BOB":89, "ALI":65, "ANU":90, "TOM":82}The output from the program should be: TOM ANU BOB OMOR Alam has a list containing 10 integers. You need to help him create a program with separate user defined functions to perform the following operations based on this list. ● Traverse the content of the list and push the even numbers into a stack. ● Pop and display the content of the stack.For Example: If the sample Content of the list is as follows: N=[12, 13, 34, 56, 21, 79, 98, 22, 35, 38]Sample Output of the code should be: 38 22 98 56 34 12
Answer» (first option) R={"OM":76, "JAI":45, "BOB":89, "ALI":65, "ANU":90, "TOM":82} def PUSH(S,N): S. append(N) def POP(S): if S!=[]: return S.pop() else: return None ST=[ ] for k in R: if R[k]>=75: PUSH(ST,k) while True: if ST!=[ ]: print(POP(ST),end=" ") else: break OR (second option) N=[12, 13, 34, 56, 21, 79, 98, 22, 35, 38] def PUSH(S,N): S. append(N) def POP(S): if S!=[ ]: return S.pop() else: return None ST=[ ] for k in N: if k%2==0: PUSH(ST,k) while True: if ST!=[ ]: print(POP(ST),end=" ") else: break

2.

Julie has created a dictionary containing names and marks as key value pairs of 6 students. Write a program, with separate user defined functions to perform the following operations:● Push the keys (name of the student) of the dictionary into a stack, where the corresponding value (marks) is greater than 75.● Pop and display the content of the stack.For example: If the sample content of the dictionary is as follows:R={"OM":76, "JAI":45, "BOB":89, "ALI":65, "ANU":90, "TOM":82}The output from the program should be: TOM ANU BOB OMOR Alam has a list containing 10 integers. You need to help him create a program with separate user defined functions to perform the following operations based on this list. ● Traverse the content of the list and push the even numbers into a stack. ● Pop and display the content of the stack.For Example: If the sample Content of the list is as follows: N=[12, 13, 34, 56, 21, 79, 98, 22, 35, 38]Sample Output of the code should be: 38 22 98 56 34 12

Answer»

(first option)

R={"OM":76, "JAI":45, "BOB":89,

"ALI":65, "ANU":90, "TOM":82}

def PUSH(S,N):

S. append(N)

def POP(S):

if S!=[]:

return S.pop()

else:

return None

ST=[ ]

for k in R:

if R[k]>=75:

PUSH(ST,k)

while True:

if ST!=[ ]:

print(POP(ST),end=" ")

else:

break

OR

(second option)

N=[12, 13, 34, 56, 21, 79, 98, 22, 35, 38]

def PUSH(S,N):

S. append(N)

def POP(S):

if S!=[ ]:

return S.pop()

else:

return None

ST=[ ]

for k in N:

if k%2==0:

PUSH(ST,k)

while True:

if ST!=[ ]:

print(POP(ST),end=" ")

else:

break

Discussion

3.	Write a statement in Python to declare a dictionary whose keys are 1, 2, 3 and values are Monday, Tuesday and Wednesday respectively.
Answer» Answer is: Day={1:'monday',2:'tuesday',3:'wednesday'}

3.

Write a statement in Python to declare a dictionary whose keys are 1, 2, 3 and values are Monday, Tuesday and Wednesday respectively.

Answer»

Answer is:

Day={1:'monday',2:'tuesday',3:'wednesday'}

Discussion

4.	Let ABC be a right triangle with ∠B = 900. Let E and F be respectively the mid-points of AB and AC. Suppose the incentre I of triangle ABC lies on the circumcircle of triangle AEF. Find the ratio BC/AB.
Answer» Draw ID ⊥ AC. Then ID = r, the inradius of ΔABC. Observe EF \|\| BC and hence ∠AEF = ∠ABC = 90⁰. Hence ∠AIF = 90^º. Therefore ID² = FD x DA. If a > c, then FA > DA and we have DA = s a; and FD = FA DA = b/2 - (s - a). Thus we obtain r² = (b + c - a)(a - c)/4. But r = (c + a - b)/2. Thus we obtain (c + a - b)2 = (b + c - a)(a - c). Simplication gives 3b = 3a + c. Squaring both sides and using b² = c² + a^2, we obtian 4c = 3a. Hence BC=BA = a=c = 4/3. (If a ≤ c, then I lies outside the circumcircle of AEF).

4.

Let ABC be a right triangle with ∠B = 900. Let E and F be respectively the mid-points of AB and AC. Suppose the incentre I of triangle ABC lies on the circumcircle of triangle AEF. Find the ratio BC/AB.

Answer»

Draw ID ⊥ AC. Then ID = r, the inradius of ΔABC. Observe EF || BC and hence ∠AEF = ∠ABC = 90⁰. Hence ∠AIF = 90^º. Therefore ID² = FD x DA. If a > c, then FA > DA and we have

DA = s a; and FD = FA DA = b/2 - (s - a).

Thus we obtain

r² = (b + c - a)(a - c)/4.

But r = (c + a - b)/2. Thus we obtain

(c + a - b)2 = (b + c - a)(a - c).

Simplication gives 3b = 3a + c. Squaring both sides and using b² = c² + a^2, we obtian 4c = 3a. Hence BC=BA = a=c = 4/3.

(If a ≤ c, then I lies outside the circumcircle of AEF).

Discussion

5.	Which element is used in electric heater ?(a) Copper (b) Platinum(c)Tungsten (d) Nichrome
Answer» Correct answer is (d) Nichrome

Discussion

6.	S.l unit of pole strength is:(a) N (b) N/A-m (c) A-m (d) T
Answer» Correct answer is (b) N/A-m

Discussion

7.	Permeability μ of a ferromagnetic substance:(a) μ >> 1(b) μ = 1(c) μ < 1(d) μ = 0
Answer» Correct answer is (a) μ >> 1

Discussion

8.	Give one example each of 2° and 3° amine with IUPAC names.
Answer» 2° (secondary amine)(CH₃)₂NH - Dimethylamine 3° (Tertiary amine) - (CH₃)₃N - Dimethyl amine

8.

Give one example each of 2° and 3° amine with IUPAC names.

Answer»

2° (secondary amine)(CH₃)₂NH - Dimethylamine

3° (Tertiary amine) - (CH₃)₃N - Dimethyl amine

Discussion

9.	Which of the following has maximum depression in freezing point?(A) K2SO4(B) NaCl(C) Urea(D) Glucose
Answer» Answer (B) NaCl

Discussion

10.	Among the following carbocations : (I) `Ph_(2)overset(+)"C"CH_(2)Me (II) PhCH_(2)CH_(2)overset(+)"C"HPh` `"(III) "Ph_(2)CHoverset(+)"C"HMe" (IV) "Ph_(2)C(Me)overset(+)"C"H_(2)` the order of stability is :A. `IVgtIIgtIgtIII`B. `IgtIIgtIIIgtIV`C. `IIgtIgtIVgtIII`D. `IgtIVgtIIIgtII`
Answer» Correct Answer - B

Discussion

11.	The designation of a sub-shell with `n=4` and `l=3` isA. (a)`4s`B. (b)`4p`C. (c )`4d`D. (d)`4f`
Answer» Correct Answer - D `n=4, 1=3` means 4f sub-shell n=4,l=3 means 4f sub-shell

Discussion

12.	Which of the following is not a linear species?A. (a)`NO_(2)^(+)`B. (b)`C_(2)H^(-)`C. (c )`Ag(CN)_(2)^(-)`D. (d)`BH_(2)^(-)`
Answer» Correct Answer - D `BH_(2)^(-)-sp^(2)` hybridization - Angular shape

Discussion

13.	The decreasing basic character of the following is : (I) `Ph O^(Ө)` (II) `CH_3 S^(Ө)` (III) `overset (Ө) O H` (IV) `MeO^(Ө)`.A. (a)`Igt IIgt IIIgt IV`B. (b)`IIIgt IVgt IIgt I`C. (c )`IVgt IIIgt IIgt I`D. (d)`Igt IIgt IVgt III`
Answer» Correct Answer - B Acidity: `PhOH gt CH_(3)SH gt MeOH gt H_(2)O` Basicity: `PHO^( Theta) lt CH_(3)S^( Theta) lt MeO^( Theta) lt overset( Theta)OH`.

Discussion

14.	Convert the following into basic units: a. `28.7 p m` b. `15.15 p m` c. `25365 mg`
Answer» a. `28.7 "pm"=28.7 "pm"xx(10^(-12)m)/(1 "pm")=2.87xx10^(-11) m` b. `15.15 mus=15.15 musxx(10^(-6)s)/(1 mus)=1.515xx10^(-5)s` c. `24=5365 mg=25365 mgxx(1g)/(1000 mg)xx(1 kg)/(1000 g)` `=2.5365xx10^(-2) kg`

Discussion

15.	The correct match of the compoun in column a with the description in column B is:A. `PtoA,QtoB,RtoC`B. `PtoB,QtoA,RtoC`C. `PtoB,QtoC,RtoA`D. `PtoC,QtoB,RtoA`
Answer» Correct Answer - B

Discussion

16.	Which of the following is aromatic?A. B. C. D.
Answer» `(4n+2)e^(-)` and complete delocalisation of `pi` bond and ione piar.

Discussion

17.	Consider the following equilibrium `H_(2)O(g)+CO(g)hArrH_(2)(g)+CO_(2)(g),K_(1)=2` `FeO(s)+CO(g)hArrFe(s)+CO_(2)(g),K_(2)=4` Then K for reaction: `Fe(s)+H_(2)O(g)hArrFeO(s)+H_(2)(g)`A. 2B. 1C. `(1)/(3)`D. `sqrt(2)`
Answer» `H_(2)O(g)+CO(p)hArrH_(2)(g)+CO_(2)(g)`….(i) `FeO(s)+CO(g)hArrFe(s)+CO_(2)(g)`…(ii) Required reaction: `Fe(s)+H_(2)O(g)hArrFeO(s)+H_(2)(g)`…(iii) Equation iii=Equation i-Equation ii `K_(3)=(K_(1))/(K_(2))=(2)/(4)=(1)/(2)`

Discussion

18.	Which of the following reduction methods is not suitable for preparing an alcohol ?A. `CH_3COOC_2H_5+NaBH_4to`B. `CH_3COOC_2H_5+Na//EtOHto`C. `CH_3CH_2COCl+LiAlH_4to`D. `CH_3COOH+H_2overset(Ni)to`
Answer» Correct Answer - A `NaBH_4` does not reduce esters.

Discussion

19.	In which fo the following reaction the product formed by anti markonikoff rule is observed:A. `ClCH=CH_(2)overset(HCl)to`B. `CH_(3)CH=CH_(2)overset(HCl)to`C. `CH_(3)OCH=CH_(2)overset(HCl)to`D. none of these
Answer» Correct Answer - B

Discussion

20.	`underset((2)H^(o+)//H_(2)O)overset((1) PhMgBr)to` product `(3^(@)` alcohol) Number of equivalent of `PhMgBr` consumed in above reaction is/are:A. `1`B. `2`C. `4`D. `3`
Answer» Correct Answer - C

Discussion

21.	In which of the following reaction ethyl benzene obtained in good yield:A. B. C. D.
Answer» Correct Answer - B

Discussion

22.	Which of the following is a step in the mechanism of the reaction shown? `CH_(2)=CH-CH_(3)+HBroverset("Peroxide")tounderset(Br)underset(\|)CH_(2)-CH_(2)-CH_(3)`A. B. C. D.
Answer» Correct Answer - B

Discussion

23.	10.30 mg of O2 is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of O2 in ppm is__________.
Answer» 1030 gm of sea water contains = 10.3 × 10^–3 gm 10⁶ gm of sea water contains = (10.3 x 10^-3)/1030 x 10⁶ = 10ppm ppm = (10.3 x 10^-3)/1030 x 10⁶ = 10

23.

10.30 mg of O2 is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of O2 in ppm is__________.

Answer»

1030 gm of sea water contains = 10.3 × 10^–3 gm

10⁶ gm of sea water contains = (10.3 x 10^-3)/1030 x 10⁶ = 10ppm

ppm = (10.3 x 10^-3)/1030 x 10⁶ = 10

Discussion

24.	The isotopic masses of `._(1)^(2)H` and `._(2)^(4)He` are `2.0141` and `4.0026` amu respectively and the velocity of light in vacuum is `2.998xx10^(8) m//s`. Calculate the quantity of energy (in `J`) liberated when two mole of `._(1)^(2)H` undergo fusion to form one mole of `._(2)^(4)He`
Answer» Correct Answer - `2.3xx10^(12)J` `DeltaE=Deltamxxc^(2)` `._(1)H^(2)+``_(1)H^(2)rarr ` `._(2)He^(4)` Mass defect `=Deltam` `=` Mass of `2(._(1)H^(2))-` Mass of `He` `=2xx2.0141-4.0026` `=4.0282-0026` `=0.0256g` `=0.256xx10^(-3)kg` `c=` speed of light `=2.998xx10^(8)m s^(-1)` `DeltaE=Deltamxxc^(20` `=0.0256xx10^(-3)xx(2.998xx10^(8))^(2)` `=0.23xx10^(13)J=2.3xx10^(12)J`

Discussion

25.	Calculate the binding energy per nucleon of `Li` isotope, which has the isotopic mass of `7.016 am u`. The individual masses of neutron and proton are `1.008665 am u` and `1.007277 am u`, respectively and the mass of electron `= 0.000548 am u`.
Answer» Correct Answer - `5.6MeV` Nuclear binding energy `:` The nuclear binding energy can be defined in the following ways `:` `a.` The energy needed to break a nucleus into its constituent nucleons `(` isolated protons and neutrons `0` is called nuclear binding energy. `b.` The energy liberated when nucleons get packed together to form the nucleus is called nuclear binding energy. `c.` The energy equivalent of mass defect `(DeltaE=Deltamc^(2))` in the formation of nucleus from protons and neutrons is called nuclear binding energy. Num `:` Lithium nuclei `._(3)Li^(7)` Number of protons `=3 ` Number of neutrons `=703=4` Mass defect `=Deltam=[Zm_(H)+(A-Zm_(n)]-M` `Deltam=3xx1.007277+4xx1.008665-7.016` `=3.021831+4.03466-7.016` `=7.056491-7.016` `=0.040491 am u` Total Be `=0.040491xx931.5` `=37.717MeV`. `BE//` nucleon`=(37.717)/(7)=5.6MeV`

Discussion

26.	The isotopic composition of rubidium is `Rb^(85):73%` and `Rb^(87):28%Rb^(87)` is weakly radioactive and decay by `beta^(c-)-` emission with a decay constant of `1.1xx10^(-11) ` per year. A sample of the mineral pollucite was found to contain `450g Rb` and `0.72mg ` of `Sr^(87)`. Estimate the age of mineral pollucite stating any assumption made.
Answer» Correct Answer - `5xx10^(8)years` `._(37)Rb^(87) rarr` `._(38)Sr^(87)+``_(-1)e^(0)` Is is assumed that all the `Sr^(87)` originated by radioactive decay of `Rb^(87)` `t_(1//2)` or `Rb=(0.693)/(K)=(0.693)/(1.1xx10^(-11)year^(-1))` `=0.63xx10^(11)years` Weight of `Rb^(87)` in the mineral pollucite `=450mgxx(28)/(100)=126mg` Weight of `Rb^(87)=126 mg ` which is present today is equal to `(a-x0` Weight of `Sr^(87)=0.72mg` is the weight obtained after disintegration of `Rb^(87)=x` `(` This has to be converted into weight of `Rb^(87))` `87mg` of `Sr` is obtained from `87mg `of `Rb`. `0.72mg` of `Sr` is obtained from `0.72 mg ` of `Rb`. `:. (a-x)=126mg` ` x=0.72mg` `a=126.72mg` `t=(2.303)/(K)log``(a)/(a-x)` `=(2.303)/(1.1xx10^(-11))log``(126.72)/(126)` `=2.09xx10^(11)log 1.0057` `=2.09xx10^(11)xx0.0024` `=0.005xx10^(11)years` `=5xx10^(8)years`

Discussion

27.	Carborundum is -A. BNB. `SiO_(4)`C. SiCD. `CS_(2)`
Answer» Correct Answer - 3 Sic=carborundum.

Discussion

28.	The probability that `sin^(-1)(sin x)+cos^(-1)(cos y)` is an integer `x, y in (1,2,3,4)`,isA. `1/16`B. `3/16`C. `15/16`D. None of these
Answer» Correct Answer - 2 For `sin^(-1)(sinx) + cos^(-1) (cos y) "to be an integer x should lie between" [(-(pi)/(2),(pi)/(2))] "and y should lie between" [0,pi]` `rArr x= 1 and y= 1,2,3` `therefore "Required probability" = 3/16`

Discussion

29.	What is the symmetry of medusa?A. BilateralB. RadialC. AsymmetricalD. Biradial
Answer» Correct Answer - B The medusa of Obelia shows radial symmetry. It is a free-swimming, umbrella-like sexual generation. It is formed by blastostyle. It brings about sexual reproduction and dispersal of species.

Discussion

30.	Caryopsis fruit is found in :-A. wheatB. groundnutC. coconutD. mango
Answer» Correct Answer - A Caryopsis is present in wheat. It is a type of simple dry fruit. It is also called as grain. In such fruits the ovary wall and seed coat fuse making it difficult to separate the two.

Discussion

31.	A Galvanometer is an instrument that can be used to construct an ammeter for measuring current. It can be used to convert to a voltmeter. It can also be used as a multimeter. In all cases resistance must be connected to galvanometer either in series or in parallel to effect the change. To turn into an ammeter a low resistance in parallel of suitable value and to convert to a voltmeter a resistance is connected in series. You are given a galvanometer for which a current of 10 mA is required for full deflection. The internal resistance of the galvanometer is 100 ohm.Then answer the following questions.In voltmeter circuit the current in resistor R must be(1) Negligible so that it only has small effect on voltage reading(2) Substantial but does not have any effect on voltage reading(3) Substantial, but does have some effect on voltage reading (4) None of these
Answer» Correct option (1) Negligible so that it only has small effect on voltage reading Explanation: As resistance of voltmeter is very high.

31.

A Galvanometer is an instrument that can be used to construct an ammeter for measuring current. It can be used to convert to a voltmeter. It can also be used as a multimeter. In all cases resistance must be connected to galvanometer either in series or in parallel to effect the change. To turn into an ammeter a low resistance in parallel of suitable value and to convert to a voltmeter a resistance is connected in series. You are given a galvanometer for which a current of 10 mA is required for full deflection. The internal resistance of the galvanometer is 100 ohm.Then answer the following questions.In voltmeter circuit the current in resistor R must be(1) Negligible so that it only has small effect on voltage reading(2) Substantial but does not have any effect on voltage reading(3) Substantial, but does have some effect on voltage reading (4) None of these

Answer»

Correct option (1) Negligible so that it only has small effect on voltage reading

Explanation:

As resistance of voltmeter is very high.

Discussion

32.	When a metallic surface is illuminated with monochromatic light of wavelength `lambda`, the stopping potential is `5 V_0`. When the same surface is illuminated with the light of wavelength `3lambda`, the stopping potential is `V_0`. Then, the work function of the metallic surface isA. `(hc)/(6 lamda)`B. `(hc)/(5 lamda)`C. `(hc)/(4 lamda)`D. `(2 hc)/(4 lamda)`
Answer» Correct Answer - A `(hc)/(lamda) = 5eV_(0) +phi rArr (hc)/(3 lamda) = eV_(0) +phi` `rArr (2hc)/(3 lamda) = 4eV_(0) rArr phi = (hc)/(6 lamda)`

Discussion

33.	A medium wave radio transmitter operating at a wavelength of 492 m has a tower antenna of height 124 m. What is the radiation resistance of the antenna(a) 25 Ω(b) 36.5 Ω(c) 50 Ω(d) 73 Ω
Answer» The correct option is (b) Explanations: Medium wave Radio transmitter operating at λ = 492 m Height of antenna = 124 m ≅ λ /4 Thus it is a quarter wave monopole hence ^Rrad ≅ 36.5 Ω

33.

A medium wave radio transmitter operating at a wavelength of 492 m has a tower antenna of height 124 m. What is the radiation resistance of the antenna(a) 25 Ω(b) 36.5 Ω(c) 50 Ω(d) 73 Ω

Answer»

The correct option is (b)

Explanations:

Medium wave Radio transmitter operating at

λ = 492 m

Height of antenna = 124 m ≅ λ /4

Thus it is a quarter wave monopole hence

^Rrad ≅ 36.5 Ω

Discussion

34.	If a/3 = b/4 = c/7 then (a + b + c)/c is1. 72. 23. 1/24. 1/7
Answer» Correct Answer - Option 2 : 2 Given: a/3 = b/4 = c/7 Calculations: a/3 = b/4 = c/7 = k (let) a = 3k , b = 4k , c = 7k So, (a+b+c)/c = (3k + 4k + 7k)/7k ⇒ 14k/7k ⇒ 2 ∴ The correct choice is option 2.

34.

If a/3 = b/4 = c/7 then (a + b + c)/c is1. 72. 23. 1/24. 1/7

Answer» Correct Answer - Option 2 : 2

Given:

a/3 = b/4 = c/7

Calculations:

a/3 = b/4 = c/7 = k (let)

a = 3k , b = 4k , c = 7k

So,

(a+b+c)/c = (3k + 4k + 7k)/7k

⇒ 14k/7k

⇒ 2

∴ The correct choice is option 2.

Discussion

35.	If p1 = Price in the current year, q1 = quantity in the current year, po = price in the base year, q0 = quantity in the base year, the formula of Laspeyres Price index is given as:1. \(\frac{∑_{p_1q_0}}{∑_{p_0q_0}}\)2. \(\frac{∑_{p_0q_1}}{∑_{p_1q_0}}\)3. \(\frac{∑_{p_0q_0}}{∑_{p_1q_1}}\)4. \(\frac{∑_{p_1q_0}}{∑_{p_0q_1}}\)
Answer» Correct Answer - Option 1 : \(\frac{∑_{p_1q_0}}{∑_{p_0q_0}}\) Laspeyres Method: 1. The Laspeyres Price Index is a weighted aggregate price index, where the weights are determined by quantities in the base period. 2. The formula for constructing the index is: \(P_{01}=\frac{∑_{p_1q_0}}{∑_{p_0q_0}}\times100\) Steps for calculating Laspeyres Price Index: Step 1: Multiply the current year prices of various commodities with base year weights and obtain \(\sum_{p_1q_0}\). Step 2: Multiply the base year prices of various commodities with base year weights and obtain \(\sum_{p_0q_0}\) Step 3: Divide \(\sum_{p_1q_0}\) by \(\sum_{p_0q_0}\) and multiply the quotient by 100. This gives us the price index. Laspeyres Index attempts to answer the question "What is the change in the aggregate value of the base period list of goods when valued at given period prices?"

35.

If p1 = Price in the current year, q1 = quantity in the current year, po = price in the base year, q0 = quantity in the base year, the formula of Laspeyres Price index is given as:1. \(\frac{∑_{p_1q_0}}{∑_{p_0q_0}}\)2. \(\frac{∑_{p_0q_1}}{∑_{p_1q_0}}\)3. \(\frac{∑_{p_0q_0}}{∑_{p_1q_1}}\)4. \(\frac{∑_{p_1q_0}}{∑_{p_0q_1}}\)

Answer» Correct Answer - Option 1 : \(\frac{∑_{p_1q_0}}{∑_{p_0q_0}}\)

Laspeyres Method:

1. The Laspeyres Price Index is a weighted aggregate price index, where the weights are determined by quantities in the base period.

2. The formula for constructing the index is:

\(P_{01}=\frac{∑_{p_1q_0}}{∑_{p_0q_0}}\times100\)

Steps for calculating Laspeyres Price Index:

Step 1: Multiply the current year prices of various commodities with base year weights and obtain \(\sum_{p_1q_0}\).

Step 2: Multiply the base year prices of various commodities with base year weights and obtain \(\sum_{p_0q_0}\)

Step 3: Divide \(\sum_{p_1q_0}\) by \(\sum_{p_0q_0}\) and multiply the quotient by 100. This gives us the price index.

Laspeyres Index attempts to answer the question "What is the change in the aggregate value of the base period list of goods when valued at given period prices?"

Discussion

36.	Which of the following are noncellular organisms that are characterized by having an inert crystalline structure outside the living cell:- (1) Bacteria (2) Mycoplasma (3) Virus (4) Lichen
Answer» Correct option is (3) Virus

Discussion

37.	Which one of the following statement is true about bacteriophages ?(1) They are generally single stranded RNA viruses. (2) They are generally double stranded DNA viruses (3) They are generally single stranded DNA viruses. (4) They are generally double stranded RNA viruses
Answer» Correct option is (2) They are generally double stranded DNA viruses

Discussion

38.	Which among these does not affect the selection of sports equipment for the school
Answer» Answer: Weather condition

Discussion

39.	What will the passible knee problem
Answer» Common knee problems include sprained or strained ligaments, cartilage tears, tendonitis and arthritis.

Discussion

40.	Define the terms load and effort in a simple machine
Answer» The weight lifted by a machine is called Load. It is denoted by 'W'. Effort is an applied force to bring desired change to the position (push or lift) of the load.

40.

Define the terms load and effort in a simple machine

Answer»

The weight lifted by a machine is called Load. It is denoted by 'W'.

Effort is an applied force to bring desired change to the position (push or lift) of the load.

Discussion

41.	What are the factors affecting the mechanical advantage of a machine
Answer» The energy that you put into making the machine do work is a product of force and displacement. If you have to go further with your input force, than the object is moved, then your advantage is increased. If you go twice as far, you should expect an advantage of 2. Three times further, the advantage should be 3. Simple as that. Anything you do to make your force go a long way when the machine force goes only a short way because of it will make your advantage greater.

41.

What are the factors affecting the mechanical advantage of a machine

Answer»

The energy that you put into making the machine do work is a product of force and displacement.

If you have to go further with your input force, than the object is moved, then your advantage is increased.

If you go twice as far, you should expect an advantage of 2. Three times further, the advantage should be 3. Simple as that.

Anything you do to make your force go a long way when the machine force goes only a short way because of it will make your advantage greater.

Discussion

42.	A student burns a non-metal and the gas so produced is dissolved in water. What would the student do next to chemical properties of the product formed?
Answer» Sulfer is a non-metal elements on burning in the presence at oxygen, it is forms SO₂ and SO₃non-metal oxides. S₈(g) + O₂(g) \(\overset{Burn}{\longrightarrow}\) SO₂ + SO₃ On dissolving these non-metal oxide in water, they are formed corresponding acids. SO₂(g) + H₂O(l) → \(\underset{\text{Sulfurous acid}}{H_2SO_3(aq)}\) SO₃(g) + H₂O(l) → \(\underset{\text{Sulfuric acid}}{H_2SO_4(aq)}\) Hence, non-metal oxides in water acidic in nature.

42.

A student burns a non-metal and the gas so produced is dissolved in water. What would the student do next to chemical properties of the product formed?

Answer»

Sulfer is a non-metal elements on burning in the presence at oxygen, it is forms SO₂ and SO₃non-metal oxides.

S₈(g) + O₂(g) \(\overset{Burn}{\longrightarrow}\) SO₂ + SO₃

On dissolving these non-metal oxide in water, they are formed corresponding acids.

SO₂(g) + H₂O(l) → \(\underset{\text{Sulfurous acid}}{H_2SO_3(aq)}\)

SO₃(g) + H₂O(l) → \(\underset{\text{Sulfuric acid}}{H_2SO_4(aq)}\)

Hence, non-metal oxides in water acidic in nature.

Discussion

43.	What is pond ecosystem?
Answer» A pond ecosystem is a system of organisms that live together in a pond. A pond ecosystem can be defined in three ways: A closed community of organisms in a body of water. An enclosed body of water that houses numerous different creatures. A biological system that includes water and plant and animal life interacting with each other. So, to summarize, a pond ecosystem is: A community of organisms living together… Within a body of water that can be either… Artificially enclosed or…. Naturally enclosed. A distinct community with its own ecology.

43.

What is pond ecosystem?

Answer»

A pond ecosystem is a system of organisms that live together in a pond. A pond ecosystem can be defined in three ways:

A closed community of organisms in a body of water.
An enclosed body of water that houses numerous different creatures.
A biological system that includes water and plant and animal life interacting with each other.

So, to summarize, a pond ecosystem is:

A community of organisms living together…
Within a body of water that can be either…
Artificially enclosed or….
Naturally enclosed.
A distinct community with its own ecology.

Discussion

44.	The maximum prescribed concntration of copper in dringking water is - (1) 5 ppm (2) 0.5 ppm (3) 3 ppm (4) 0.05
Answer» Correct option (3) 3 ppm Explanation: The prescribed conc. of Cu in drinking water is 3ppm

44.

The maximum prescribed concntration of copper in dringking water is - (1) 5 ppm (2) 0.5 ppm (3) 3 ppm (4) 0.05

Answer»

Correct option (3) 3 ppm

Explanation:

The prescribed conc. of Cu in drinking water is 3ppm

Discussion

45.	The maximum prescribed concntration of copper in dringking water is - (1) 5 ppm (2) 0.5 ppm (3) 3 ppm (4) 0.05
Answer» Correct option (3) 3 ppm Explanation: The prescribed conc. of Cu in drinking water is 3ppm

45.

The maximum prescribed concntration of copper in dringking water is - (1) 5 ppm (2) 0.5 ppm (3) 3 ppm (4) 0.05

Answer»

Correct option (3) 3 ppm

Explanation:

The prescribed conc. of Cu in drinking water is 3ppm

Discussion

46.	The covalent alkaline earth metal halide (X = Cl, Br, I) is (1) BeX2 (2) SrX2 (3) MgX2 (4) CaX2
Answer» Correct option (1) BeX₂ Explanation: Halides of Be are covalent

46.

The covalent alkaline earth metal halide (X = Cl, Br, I) is (1) BeX2 (2) SrX2 (3) MgX2 (4) CaX2

Answer»

Correct option (1) BeX₂

Explanation:

Halides of Be are covalent

Discussion

47.	The vapour pressure of pure liquid M & N are 700 mm of Hg and 450 mm of Hg respectively. Which of the following option is correct?Given: XN, XM = mole fraction of N & M in liquid phaseYN, YM = mole fraction of N & M in vapour phase
Answer» Correct option: (3) Explanation: Mole fraction of more volatile component increase in vapour phase. (P_N^° < P_M^°)

47.

The vapour pressure of pure liquid M & N are 700 mm of Hg and 450 mm of Hg respectively. Which of the following option is correct?Given: XN, XM = mole fraction of N & M in liquid phaseYN, YM = mole fraction of N & M in vapour phase

Answer»

Correct option: (3)

Explanation:

Mole fraction of more volatile component increase in vapour phase. (P_N^° < P_M^°)

Discussion

48.	A large glass slabe `(mu=5//3)` of thickness 8cm is placed over a point source of light on a plane surface. It is seen that light emerges out of th etop surface fo the slab from a circular area of radius R cm. What is the value of R?
Answer» Correct Answer - 6

Discussion

49.	A particle moves so that its position vector is given by `vec r = cos omega t hat x + sin omega t hat y`, where `omega` is a constant which of the following is true ?A. Velocity vector is parallel to position vectorB. Velocity vector is perpendicular to position vectorC. Acceleration vector is directed towards the originD. Acceleration vector is directed away from the origin
Answer» Correct Answer - B::C `vec(r)=a cos omegat hat(i) + a sin omega t hat(j)` velocity `=vec(v)=(dvec(r))/(dt)=-a omega sin omega t hat(i)+a omega cos omega t hat(j)` Acceleration `=(d^(2)vec(r))/(dt^(2))=-a omega^(2) cos omegat hat(i)-a omega^(2) sin omega t hat(j)=-omega^(2)vec(r)`

Discussion

50.	Given magnetic field equation is B = 3 × 10–8 sin(ωt + kx + ϕ)j then appropriate equation for electric field (E) will be:
Answer» Answer is (2) E₀/B₀ = C (speed of light in vacuum) E₀ = B₀C = 3 x 10^-8 x 3 x 10⁸ = 9 N/C So E = 9 sin(ωt + kx + ϕ)

50.

Given magnetic field equation is B = 3 × 10–8 sin(ωt + kx + ϕ)j then appropriate equation for electric field (E) will be:

Answer»

Answer is (2)

E₀/B₀ = C (speed of light in vacuum)

E₀ = B₀C = 3 x 10^-8 x 3 x 10⁸

= 9 N/C

So E = 9 sin(ωt + kx + ϕ)

Discussion

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