100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS

1.	Ten charges are placed on the circumference of a circle of radius R with constant angular separation between successive charges. Alternate charges 1, 3, 5, 7, 9 have charge (+q) each, while 2, 4, 6, 8, 10 have charge (–q) each. The potential V and the electric field E at the centre of the circle are respectively. (Take V = 0 at infinity)
Answer» The correct option is (1). ΣQ = 0 V = 0 Also, field of one charge will get cancelled due to another symmetrical charge in front of it.

1.

Ten charges are placed on the circumference of a circle of radius R with constant angular separation between successive charges. Alternate charges 1, 3, 5, 7, 9 have charge (+q) each, while 2, 4, 6, 8, 10 have charge (–q) each. The potential V and the electric field E at the centre of the circle are respectively. (Take V = 0 at infinity)

Answer»

The correct option is (1).

ΣQ = 0

V = 0

Also, field of one charge will get cancelled due to another symmetrical charge in front of it.

Discussion

2.	Let f(x) be a quadratic polynomial such that f(–1) + f(2) = 0. If one of the roots of f(x) = 0 is 3, then its other root lies in :(1) (–3, –1)(2) (1, 3) (3) (–1, 0) (4) (0, 1)
Answer» Answer is (3) (–1, 0) f(x) = a(x – 3) (x – α) f(2) = a(α – 2) f(–1) = 4a(1 + α) f(–1) + f(2) = 0 ⇒ a(α – 2 + 4 + 4α) = 0 a ≠ 0 ⇒ 5α = – 2 α = \(\frac{2}{5}\) = - 0.4 α ∈ (–1, 0)

2.

Let f(x) be a quadratic polynomial such that f(–1) + f(2) = 0. If one of the roots of f(x) = 0 is 3, then its other root lies in :(1) (–3, –1)(2) (1, 3) (3) (–1, 0) (4) (0, 1)

Answer»

Answer is (3) (–1, 0)

f(x) = a(x – 3) (x – α)

f(2) = a(α – 2)

f(–1) = 4a(1 + α)

f(–1) + f(2) = 0 ⇒ a(α – 2 + 4 + 4α) = 0

a ≠ 0 ⇒ 5α = – 2

α = \(\frac{2}{5}\) = - 0.4

α ∈ (–1, 0)

Discussion

3.	The position versus time graph of a particle moving along a straight line is shown. What is the total distance travelled by the particle from t=0s to t=10s?A. 2mB. 18 mC. 26mD. 34m
Answer» Correct Answer - D Use the concept of graph.

Discussion

4.	The speed versus time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t = 0 to t = 5 s will be _____.
Answer» Distance travelled = Area under the u-t graph ∴ ΔS = (1/2) x 5 x 8 = 20

4.

The speed versus time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t = 0 to t = 5 s will be _____.

Answer»

Distance travelled = Area under the u-t graph

∴ ΔS = (1/2) x 5 x 8

= 20

Discussion

5.	An iron rod of volume 10–3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be (1) 5 × 102 Am2 (2) 0.5 × 102 Am2 (3) 500 × 102 Am2 (4) 50 × 102 Am2
Answer» The correct option is (1) 5 × 10² Am² . M = φH Magnetic moment = MV H = ni

5.

An iron rod of volume 10–3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be (1) 5 × 102 Am2 (2) 0.5 × 102 Am2 (3) 500 × 102 Am2 (4) 50 × 102 Am2

Answer»

The correct option is (1) 5 × 10² Am² .

M = φH

Magnetic moment = MV

H = ni

Discussion

6.	Orange light of wavelength 6000 × 10–10 m illuminates a single slit of width 0.6 × 10–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ____
Answer» For minima d sinθ = na For n to be maximum sinθ = 1 n = 6 x 10^-5/6 x 10^-7 = 100 Since n = 100 will corresponds to infinity. So No. of minima possible in one side is 99. And in both side it is 198

6.

Orange light of wavelength 6000 × 10–10 m illuminates a single slit of width 0.6 × 10–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ____

Answer»

For minima

d sinθ = na

For n to be maximum sinθ = 1

n = 6 x 10^-5/6 x 10^-7 = 100

Since n = 100 will corresponds to infinity.

So No. of minima possible in one side is 99.

And in both side it is 198

Discussion

7.	When a ball is dropped into a lake from a height 4.9 m above the water level, it hits the water with a velocity v and then sinks to the bottom with the constant velocity v. It reaches the bottom of the lake 4.0 s after it is dropped. The approximate depth of the lake is : (A) 19.6 m (B) 29.4 m (C) 39.2 m (D) 73.5 m
Answer» Correct option is (B) 29.4 m V² = 2 x 9.8 x 4.9 V = 9.8 m/s Depth = distance travelled in 3 seconds = 9.8 x 3 = 29.4 m

7.

When a ball is dropped into a lake from a height 4.9 m above the water level, it hits the water with a velocity v and then sinks to the bottom with the constant velocity v. It reaches the bottom of the lake 4.0 s after it is dropped. The approximate depth of the lake is : (A) 19.6 m (B) 29.4 m (C) 39.2 m (D) 73.5 m

Answer»

Correct option is (B) 29.4 m

V² = 2 x 9.8 x 4.9

V = 9.8 m/s

Depth = distance travelled in 3 seconds

= 9.8 x 3 = 29.4 m

Discussion

8.	Which of the following statements are incorrect ? (A) Co+3 with strong field ligand forms high magnetic moment complex(B) For Co+3 if pairing energy(P) > Δo then the complex formed will have t42g,e2g configuration(C) For [Co(en)3]3+ λabsorbed is less than λabsorbed for [CoF6]3– (D) If Δo = 18000 cm–1 for CO+3 then with same ligands for it Δt = 16000 cm–1(1) A, D (2) B, C (3) A, B (4) A, B, C, D
Answer» The answer is (1) A, D.

Discussion

9.	Compare Ea (activation energy) for a, b, c and d.(1) Eb > Ec > Ed > Ea (2) Ea > Ed > Ec > Eb (3) Ec > Eb > Ea > Ed (4) Ed > Ea > Eb > Ec
Answer» Answer:(1) E_b> E_c > E_d > E_a log k = log A – E_a/2.303 RT slope = – E_a/2.303 R ⇒ E_b > E_c > E_d > E_a

9.

Compare Ea (activation energy) for a, b, c and d.(1) Eb > Ec > Ed > Ea (2) Ea > Ed > Ec > Eb (3) Ec > Eb > Ea > Ed (4) Ed > Ea > Eb > Ec

Answer»

Answer:(1) E_b> E_c > E_d > E_a

log k = log A – E_a/2.303 RT

slope = – E_a/2.303 R ⇒ E_b > E_c > E_d > E_a

Discussion

10.	The electric potential decreases uniformly from V to -V along X-axis in a coordinate system as we moves from a point `(-x_(0), 0)` to `(x_(0), 0)`, then the electric field at the origin:
Answer» Correct Answer - B `E=-((delV)/(delx)hati+(del V)/(del y)hatj+(delV)/(del z)hatk)` Here `(del V)/(del x)=-V/X_(0) :. E_("min")=V/x_(0) hat(i)`

Discussion

11.	Column I shows four current configurations Match each entry of column I with those axes in column II along which the magnetic field at origin has positive component
Answer» Correct Answer - [(A)PR;(B)S;(C)PQR;(D)PR] By Right hand thumb rule

Discussion

12.	The diagrams below depict four different charge distributions. The charge particles are all the same distance from the origin. The electric field at the origin:A. is greatest for situation 1 B. is greatest for situation 3 C. is zero for situation 4 D. is downward for situation 1 E. is downward for situation 3
Answer» C. is zero for situation 4

Discussion

13.	Column I shows different charge distributions and short electric dipole at a distance x from the charge distributions. Column II gives the dependence of force acting on the dipole as of function of x.
Answer» Correct Answer - (A) s (B) r (C) p (D) q (P) Electric field due to uniformly `=sigma/(2 epsi_(0))` Charge thin infinite disc `F_("net")` on dipole `=0` (Q) Electric filed due to uniformaly `=sigma_(x)/epsi_(0)` charged infinite `F_("net")` on dipole `=(rho ql)/epsi_(0)` (R) Electric field due to uniform `=(2kl)/(x)` infinite line of charge `F_("net")` on.dipole `=(-2kl)/(x(x+l)) ~~(-2k lambda l)/x^(2)` (S) Electric field due to uniformly `=(KQ)/x^(2)` charged sphere `F_("net")` on dipole `=(-KQq(2xl))/(x^(2)(x+l)^(2))~~(-KqQ(2xl))/x^(4)` `~~(-2KqQl)/x^(3)`

Discussion

14.	What is the unit of permittivity?
Answer» The SI unit for permittivity is farad per meter (F/m).

Discussion

15.	If the angle `alpha` between two forces of equal magnitude is reduced to `(alpha-pi//3),` then the magnitude of their resultant becomes `(alpha-pi//3),`times of the earlier one. The angle `alpha` isA. `pi//2`B. `2pi//2`C. `pi//4`D. `4pi//5`
Answer» Correct Answer - B `sqrt(F^(2)+F^(2)+2F^(2)cos(alpha(pi)/(3)))=sqrt3xx[sqrt(F^(2)+F^(2)+2F^(2)cosalpha)]` on solving `,alpha=(2pi)/(3)" ""]"`

Discussion

16.	A parallel plate capacitor is charged by certain amount of charge `Q`. The force of interaction between the plates is `F_(0)`. If region between the plates is filled by a dielectric material, the force of interaction between the plates is `F`. The correct statement isA. `F gt F_(0)`B. `F lt F_(0)`C. `F = F_(0)`D. none of these
Answer» Field decreases `k` times in dielectric medium but field at the position of plates remains same, so force of interaction remains same.

Discussion

17.	Two identical loudspeakers are placed on a line at distance `4m` and `6m` from a microphone lying on the line joining them. The output of each speaker at the microphone is `2mW`. If the two speakers are connected in series and excited by the same oscillator and they vibrate in phase with each other, the resultant ouput of the microphone will be (frequency of oscillator `=660 Hz` and speed of sound `=330 m//s`)A. zeroB. `2 mW`C. `4 mW`D. `8 mW`
Answer» Use interference concepts.

Discussion

18.	A cylinder full of water is placed just below a container. Water drops come out of the bottom of container at a regular interval of time and strike water surface in tank with velocity `v_(0)`. If `f_(0)` is the frequency of sound produced, then frequency of sound received by the oberver at rest, isA. `lt f_(0)`B. `= f_(0)`C. `gt f_(0)`D. data insufficient.
Answer» As the source of sound and the observer both are at rest, apparent frequency `=` actual frequency.

Discussion

19.	If an electron enters a space between the plates of a parallel plate capacitor at an angle `theta_(1)` with the plates and leaves at an angle `theta_(2)` to the plates, the ratio of its kinetic energy while entering the capacitor to that while leaving will beA. `(cos^(2)theta_(2))/(cos^(2)theta_(1))`B. `(cos^(2)theta_(1))/(cos^(2)theta_(2))`C. `(sin^(2)theta_(2))/(sin^(2)theta_(1))`D. `(sin^(2)theta_(1))/(sin^(2)theta_(2))`
Answer» If `V_(1)` and `V_(2)` be the speeds of electron while entering the capacitor and while leaving it, then `v_(1)costheta_(1)=v_(2)costheta_(2)rArr(v_(1))/(v_(2))=(costheta_(2))/(costheta_(1))` `((K.E.))/((K.E.)_(2))=((costheta_(2))/(costheta_(1)))^(2)`

Discussion

20.	The greatest and the leat resultant of two forces acting at point are 12N and 8N respectively. Find out the forces.A. `12 N & 8N`B. `4N&8N`C. `3N&9N`D. `10N&2N`
Answer» Correct Answer - D `(F_("net")")_(max)=F_(1)+F_(2)=12N` `(F_("net")")_(max)=F_(1)-F_(2)=8N` on solving `[F_(1)=10N and F_(2)=2N" "]`

Discussion

21.	Three metallic isolated plates are given charges as shown in figure, the sum of the charges on the outer surfaces of the two plates (`1`) and (`3`) is (where `-3Q` and `4Q` are total charges of plates (`1`) and (`3`) respectively.) A. zeroB. `Q//2`C. `-Q//2`D. `-2Q`
Answer» `Q_(outside)=(Q_(1)+Q_(2))/(2)`

Discussion

22.	A charged particle X moves directly towards another charged particle Y. For the X plus Y system, the total momentum is p and the total energy is E.A. If Y is fixed, E is conserved but not p.B. If Y is fixed, neither E nor p is conserved.C. p and E are conserved if both X and Y are free to move.D. (a) is true anly if X and Y have similar charges.
Answer» Correct Answer - A::C a.,c. If the system is isolated (no external forces) `P` and `E` are conserved. Electrostaic forces are internal forces. So (a) is correct. To fix `Y` external forces must act on the system i.e., on `Y`. In that case `p` is not conserved. However these external force do not work as there is no displacement of `Y.E` is conserved. So (c) is correct.

Discussion

23.

Copy and complete the tablePhylumSymmetryCoelemDistinctive featuresCnidaria .........Absent...........AscheiminthesBilateral.................... .............Radial........Water vascular system Hemichordata .........Coelemate .........

Answer»

Phylum	Symmetry	Coelem	Distinctive features
Cnidaria	Radial	Absent	Cnidoblast
Ascheiminthes	Bilateral	Pseudocoelom	Muscular pharynx
Echinodermata	Radial	Coelemate	Water vascular system
Hemichordata	Bilateral	Coelemate	Proboscis, Collar, Trunk

Discussion

24.	Mention a single word for the following. 1. Sexes are not separate. 2. Body wall with three layers. 3. File like rasping organs in Mollusca. 4. Segmentation of animal body. 5. The property of a living organism to emit light. 6. Alternation of generation in Cnidarians.
Answer» 1. Hermaphrodite 2. Triploblastic 3. Radula 4. Metamerism 5. Bioluminescence 6. Metagenesis

24.

Mention a single word for the following. 1. Sexes are not separate. 2. Body wall with three layers. 3. File like rasping organs in Mollusca. 4. Segmentation of animal body. 5. The property of a living organism to emit light. 6. Alternation of generation in Cnidarians.

Answer»

1. Hermaphrodite

2. Triploblastic

3. Radula

4. Metamerism

5. Bioluminescence

6. Metagenesis

Discussion

25.	In the circuit shown above, when then switch S is closed,A. no charge flows through SB. charge flows from A to BC. charge flows from B to AD. charge flows initially from A to B and later from B to A
Answer» Correct Answer - A

Discussion

26.	Which is not a feature of Annelida ? (a) Metameric segmentation (b) Nephridia (c) Pseudocoelom (d) Clitellum
Answer» (c) Pseudocoelom

Discussion

27.

Match the following (a) Operculum i. Ctenophora(b) Parapodiaii. Mollusca(c) Scalesiii. Porifera(d) Comb platesiv. Reptilia(e) Radulav. Annelida(f) Hairsvi. Cyclostomata(g) Choanocytesvii. Mammalia(h) Gill slitsviii. Osteichthyes

Answer»

(a) Operculum	viii. Osteichthyes
(b) Parapodia	v. Annelida
(c) Scales	iv. Reptilia
(d) Comb plates	i. Ctenophora
(e) Radula	ii. Mollusca
(f) Hairs	vii. Mammalia
(g) Choanocytes	iii. Porifera
(h) Gill slits	vi. Cyclostomata

Discussion

28.	Select the following items into their appropriate phylum. Radula, Parapodia, Comb plate, Nephridia, Choanocytes, Flame cells.
Answer» Radula – Mollusca Parapodia – Annelida Comb plate – Ctenophora Nephridia – Annelida Choanocytes – Porifera Flame cells – Platyhelminthes

Discussion

29.	In some animal groups, the body is found divided into compartments with at least some organs/ organ repeated. This characteristic feature is named (a) Segmentation (b) Metamerism (c) Metagenesis (d) Metamorphosis
Answer» (b) Metamerism

Discussion

30.

Arrange the following points in a two column table and give suitable heading for each column. 1. Notochord present 2. Post anal tail absent 3. Pharynx Perforated by gill slits 4. Notochord absent 5. Posts anal tail present 6. Gill slits are absent

Answer»

Chordata	Non Chordata
Notochord present	Post anal tail present
Pharynx perforated by gill slits	Notochord absent
Post anal tail present	Gill slits absent

Discussion

31.	Note the relationship between first two words and suggest suitable words for the 4th place. 1. Planaria: Flartfe cells: Earthworm: ..........2. Jaw present: Gnathostomata:: Jaw absent: ........
Answer» 1. Nephridia 2. Agnatha

31.

Note the relationship between first two words and suggest suitable words for the 4th place. 1. Planaria: Flartfe cells: Earthworm: ..........2. Jaw present: Gnathostomata:: Jaw absent: ........

Answer»

1. Nephridia

2. Agnatha

Discussion

32.

Observe the table given below and fill the blank columns A, B, C and from the animals given in brackets. (Ascaris, Starsh, Fasciola, Earthworm)AcoelomatePseudo coelomateCoelomateA. .........B. .........C. ..........D. .........

Answer»

Acoelomate	Pseudo coelomate	Coelomate
A. Fassciola	B. Ascaris	C. Star fish D. Earthworm

Discussion

33.	Observe the given organisms1. Place these animals in proper phylum. 2. Segmentation in the body is first observed in which of the above phylum?
Answer» 1. (i) Arthropoda, (ii) Porifera, (iii) Annelida 2. Annelida

33.

Observe the given organisms1. Place these animals in proper phylum. 2. Segmentation in the body is first observed in which of the above phylum?

Answer»

1. (i) Arthropoda,

(ii) Porifera,

(iii) Annelida

2. Annelida

Discussion

34.	1. Identify the animal given below.2. Write one well marked property of the above animal.
Answer» 1. Pleurobrachia 2. Bioluminescence is well marked property of pleurobrachia

34.

1. Identify the animal given below.2. Write one well marked property of the above animal.

Answer»

1. Pleurobrachia

2. Bioluminescence is well marked property of pleurobrachia

Discussion

35.

Categorise and classify the following organisms and arrange them in a table with separate columns and provide appropriate headings. Exocoetus, Physalia, Ascaris, Apis, Locusta, Corvus, Pita, Hydra, Sepia, Ancylostoma.

Answer»

Cnidaria	Ascheiminthes	Arthoropoda	Mollusca	Chordata
Physalia	Ascaris	Apis	Pilla	Exocoetus
Hydra	Ancylostoma	Locusta	Sepia	Corvu

Discussion

36.	1. Identify the organism A and B.2. Which features of these organism enable you to identify them?
Answer» 1. A-Tapeworm B – Earthworm 2. Features of these organism: Tapeworm: Scolex is present, suckers and hooks are present. No true segmentation. Earthworm: True segmentation, Absence of Scolex, hook and suckers, Clitellum is present.

36.

1. Identify the organism A and B.2. Which features of these organism enable you to identify them?

Answer»

1. A-Tapeworm

B – Earthworm

2. Features of these organism:

Tapeworm: Scolex is present, suckers and hooks are present. No true segmentation.
Earthworm: True segmentation, Absence of Scolex, hook and suckers, Clitellum is present.

Discussion

37.	1. Which of the following animals exhibit metagenesis? (Ascaris Obelia Earthworm Crab) 2. To which phylum does it belong? 3. Write any two features of the phylum.
Answer» 1. Obelia 2. Cnidaria 3. Two features of the phylum: Presence of Cnidoblasts Cnidarians exhibit two basic forms called polyp and medusa.

37.

1. Which of the following animals exhibit metagenesis? (Ascaris Obelia Earthworm Crab) 2. To which phylum does it belong? 3. Write any two features of the phylum.

Answer»

1. Obelia

2. Cnidaria

3. Two features of the phylum:

Presence of Cnidoblasts
Cnidarians exhibit two basic forms called polyp and medusa.

Discussion

38.	Presence or absence of a cavity between the body wall and the gut wall is very important in classification.1. Identify the different types of body cavities. 2. Give examples to each
Answer» 1. Different types of Body Cavities: a – Coelomate b – Pseudocoelomate c – Acoelomate 2. Examples: Coelomate – Chordates Pseudocoelomate – Aschelminthes Acoelomate – Platyhelminthes

38.

Presence or absence of a cavity between the body wall and the gut wall is very important in classification.1. Identify the different types of body cavities. 2. Give examples to each

Answer»

1. Different types of Body Cavities:

a – Coelomate
b – Pseudocoelomate
c – Acoelomate

2. Examples:

Coelomate – Chordates
Pseudocoelomate – Aschelminthes
Acoelomate – Platyhelminthes

Discussion

39.	From the pictures given below, nd out the poikilothermic animals.
Answer» B and D are poikilothermic animals.

Discussion

40.	Segmentation in the body is first observed in which of the following: (a) Platyhelminthes (b) Aschelminthes (c) Annelida (d) Arthropoda
Answer» Segmentation in the body is first observed in Annelida

Discussion

41.	Shark has to swim continuously, otherwise, it will sink down. Give reason.
Answer» Due to absence of air bladder.

Discussion

42.

Complete the blanks. Character Phyluma. Body is flatb. Body has similar segmentsc. Body has jointed appendagesd. Body is round

Answer»

Character	Phylum
a. Body is at	Platyhelminthes
b. Body has similar segments	Annelida
c. Body has jointed appendages	Arthropoda
d. Body is round	Aschelminthes

Discussion

43.	Arthropodes are organisms with chitinous exoskeleton. Suppose exoskeleton is absent in arthropods. List the difficulties arthropodes has to face.
Answer» 1. Their body will be dried up due to evaporation 2. They couldn’t escape from predators. 3. They couldn’t live in all environments.

43.

Arthropodes are organisms with chitinous exoskeleton. Suppose exoskeleton is absent in arthropods. List the difficulties arthropodes has to face.

Answer»

1. Their body will be dried up due to evaporation

2. They couldn’t escape from predators.

3. They couldn’t live in all environments.

Discussion

44.	In experiments using the metre bridge, post-office box, and potentiometer, a galvanometer is used. Which property of the galvanometer makes it suitable for these experiments? (a) It has a relatively high coil resistance.(b) It indicates rather then measures the magnitude of the current. (c) It can indicate currents flowing through it in either direction. (d) It can be made very sensitive to small currents.
Answer» Correct Answer is: (c) In the three experiments, the jockey is moved according to the direction of the deflection of the galvanometer.

44.

In experiments using the metre bridge, post-office box, and potentiometer, a galvanometer is used. Which property of the galvanometer makes it suitable for these experiments? (a) It has a relatively high coil resistance.(b) It indicates rather then measures the magnitude of the current. (c) It can indicate currents flowing through it in either direction. (d) It can be made very sensitive to small currents.

Answer»

Correct Answer is: (c)

In the three experiments, the jockey is moved according to the direction of the deflection of the galvanometer.

Discussion

45.

In resonance tube first resonance is obtain at 20 cm, then third resonance length will be: (frequency of source = 400 Hz, speed of sound in air = 336 m/s)(a) 60 cm(b) 104 cm.(c) 64 cm(d) 100 cm

Answer»

Correct option is (b) 104 cm.

Wavelength of wave ⇒ λ = v/f = 336/400 = 84 cm

At first resonance

λ/4 = l + e ⇒ 84/4 = 20 + e

⇒ e = 1

So third resonance length

5 λ/4 = l₂+ e

5(21) = l₂+ 1

l₂= 104 cm

Discussion

46.

In a full wave junction diode rectifier, the input ac voltage has rms value of 10V. The transformer used is a step up one having transformation ratio 1:2. Calculate the DC voltage in the rectified output.

Answer»

Here,

Input rms voltage,

V_rms = 10 V

∴ Peak value of input voltage,

E₀= √2.

V_rms = √2 ×10

= 14.14 V

Since, the transformer is a step-up transformer, having transformation ratio 1:2, the maximum value of output voltage of the transformer applied to the diodes will be :

E'₀ = 2 × E₀

= 2 × 14.14

= 28.28 V

∴ DC voltage = \(\frac{2E'_0}{\pi}\)

= \(\frac{2\times 28.28\times 7}{22}\)

= 18 V.

Discussion

47.	Can the potential barrier across a p-n junction be measured by simply connecting a voltmeter across the junction?
Answer» No, because the voltmeter to be used to measure potential difference across the p-n junction must have a very high resistance as compared to junction resistance, which is nearly infinite, if not biased. Apart from it, there are no free charge carriers in the depletion region of p-n junction.

Discussion

48.	The switching function ffor switching network is A. `x+y+z`B. `x.y+x.z`C. `x+y+x.z`D. None of these
Answer» Correct Answer - B The switching function for switching network is `x.y+x.z`.

Discussion

49.	`int cos (log_e x)dx` is equal toA. `(1)/(2)xx[cos(log_ex)+sin(log_ex)]`B. `(x)[cos(log_e x)+sin(log_ex)]`C. `(1)/(2)x[cos(log_e x)-sin(log_e x)]`D. `x[cos (log_ex)-sin(log_ex)]`
Answer» Correct Answer - A Let `l=intcos(log_ex)dx` `=cos(log_eX)x-int((-sinlog_ex)/x)xdx` `= x cos (log_ex)+int sin(log_ex).1dx` `=xcos(log_ex)+xsin(log_ex)-int(cos(log_ex))/(x)x dx` `=xcos(log_ex)+ xsin(log_ex)-l` `rArr 2l=x[cosIog_ex)+sin(log_ex)]` `rArr l=(x)/(2)[cos(log_ex)+sin(log_ex)]`

Discussion

50.	If `A xx(BxxC)=Bxx(CxxA)` and [ABC] = 0, then `A xx(BxxC)` is equal to
Answer» Correct Answer - A `because Axx(BxxC)=Bxx(CxxA)` `rArr (A.C)B-(A.B)C=(B.A)C-B.C)A` `rArr (B.C)A+(A.C)B-(A.B+B.A)C=0` `therefore B.C=0,A.C=0,A.B=0` `rArr B bot C,A bot C,A bot B ` `Axx(BxxC)=(A.C)B-(A.B)C=(0)B-(0)C=0`

Discussion

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Let f(x) be a quadratic polynomial such that f(–1) + f(2) = 0. If one of the roots of f(x) = 0 is 3, then its other root lies in :(1) (–3, –1)(2) (1, 3) (3) (–1, 0) (4) (0, 1)

The position versus time graph of a particle moving along a straight line is shown. What is the total distance travelled by the particle from t=0s to t=10s?A. 2mB. 18 mC. 26mD. 34m

The speed versus time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t = 0 to t = 5 s will be _____.

An iron rod of volume 10–3 m3 and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of 0.5 A is passed through the solenoid, then the magnetic moment of the rod will be (1) 5 × 102 Am2 (2) 0.5 × 102 Am2 (3) 500 × 102 Am2 (4) 50 × 102 Am2

Orange light of wavelength 6000 × 10–10 m illuminates a single slit of width 0.6 × 10–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ____

Compare Ea (activation energy) for a, b, c and d.(1) Eb &gt; Ec &gt; Ed &gt; Ea (2) Ea &gt; Ed &gt; Ec &gt; Eb (3) Ec &gt; Eb &gt; Ea &gt; Ed (4) Ed &gt; Ea &gt; Eb &gt; Ec

The electric potential decreases uniformly from V to -V along X-axis in a coordinate system as we moves from a point `(-x_(0), 0)` to `(x_(0), 0)`, then the electric field at the origin:

Column I shows four current configurations Match each entry of column I with those axes in column II along which the magnetic field at origin has positive component

Column I shows different charge distributions and short electric dipole at a distance x from the charge distributions. Column II gives the dependence of force acting on the dipole as of function of x.

What is the unit of permittivity?

If the angle `alpha` between two forces of equal magnitude is reduced to `(alpha-pi//3),` then the magnitude of their resultant becomes `(alpha-pi//3),`times of the earlier one. The angle `alpha` isA. `pi//2`B. `2pi//2`C. `pi//4`D. `4pi//5`

The greatest and the leat resultant of two forces acting at point are 12N and 8N respectively. Find out the forces.A. `12 N & 8N`B. `4N&8N`C. `3N&9N`D. `10N&2N`

Three metallic isolated plates are given charges as shown in figure, the sum of the charges on the outer surfaces of the two plates (`1`) and (`3`) is (where `-3Q` and `4Q` are total charges of plates (`1`) and (`3`) respectively.) A. zeroB. `Q//2`C. `-Q//2`D. `-2Q`

Copy and complete the tablePhylumSymmetryCoelemDistinctive featuresCnidaria .........Absent...........AscheiminthesBilateral.................... .............Radial........Water vascular system Hemichordata .........Coelemate .........

Mention a single word for the following. 1. Sexes are not separate. 2. Body wall with three layers. 3. File like rasping organs in Mollusca. 4. Segmentation of animal body. 5. The property of a living organism to emit light. 6. Alternation of generation in Cnidarians.

In the circuit shown above, when then switch S is closed,A. no charge flows through SB. charge flows from A to BC. charge flows from B to AD. charge flows initially from A to B and later from B to A

Which is not a feature of Annelida ? (a) Metameric segmentation (b) Nephridia (c) Pseudocoelom (d) Clitellum

Match the following (a) Operculum i. Ctenophora(b) Parapodiaii. Mollusca(c) Scalesiii. Porifera(d) Comb platesiv. Reptilia(e) Radulav. Annelida(f) Hairsvi. Cyclostomata(g) Choanocytesvii. Mammalia(h) Gill slitsviii. Osteichthyes

Select the following items into their appropriate phylum. Radula, Parapodia, Comb plate, Nephridia, Choanocytes, Flame cells.

In some animal groups, the body is found divided into compartments with at least some organs/ organ repeated. This characteristic feature is named (a) Segmentation (b) Metamerism (c) Metagenesis (d) Metamorphosis

Arrange the following points in a two column table and give suitable heading for each column. 1. Notochord present 2. Post anal tail absent 3. Pharynx Perforated by gill slits 4. Notochord absent 5. Posts anal tail present 6. Gill slits are absent

Note the relationship between first two words and suggest suitable words for the 4th place. 1. Planaria: Flartfe cells: Earthworm: ..........2. Jaw present: Gnathostomata:: Jaw absent: ........

Observe the table given below and fill the blank columns A, B, C and from the animals given in brackets. (Ascaris, Starsh, Fasciola, Earthworm)AcoelomatePseudo coelomateCoelomateA. .........B. .........C. ..........D. .........

Observe the given organisms1. Place these animals in proper phylum. 2. Segmentation in the body is first observed in which of the above phylum?

1. Identify the animal given below.2. Write one well marked property of the above animal.

Categorise and classify the following organisms and arrange them in a table with separate columns and provide appropriate headings. Exocoetus, Physalia, Ascaris, Apis, Locusta, Corvus, Pita, Hydra, Sepia, Ancylostoma.

1. Identify the organism A and B.2. Which features of these organism enable you to identify them?

1. Which of the following animals exhibit metagenesis? (Ascaris Obelia Earthworm Crab) 2. To which phylum does it belong? 3. Write any two features of the phylum.

Presence or absence of a cavity between the body wall and the gut wall is very important in classification.1. Identify the different types of body cavities. 2. Give examples to each

From the pictures given below, nd out the poikilothermic animals.

Segmentation in the body is first observed in which of the following: (a) Platyhelminthes (b) Aschelminthes (c) Annelida (d) Arthropoda

Shark has to swim continuously, otherwise, it will sink down. Give reason.

Complete the blanks. Character Phyluma. Body is flatb. Body has similar segmentsc. Body has jointed appendagesd. Body is round

Arthropodes are organisms with chitinous exoskeleton. Suppose exoskeleton is absent in arthropods. List the difficulties arthropodes has to face.

In resonance tube first resonance is obtain at 20 cm, then third resonance length will be: (frequency of source = 400 Hz, speed of sound in air = 336 m/s)(a) 60 cm(b) 104 cm.(c) 64 cm(d) 100 cm

In a full wave junction diode rectifier, the input ac voltage has rms value of 10V. The transformer used is a step up one having transformation ratio 1:2. Calculate the DC voltage in the rectified output.

Can the potential barrier across a p-n junction be measured by simply connecting a voltmeter across the junction?

The switching function ffor switching network is A. `x+y+z`B. `x.y+x.z`C. `x+y+x.z`D. None of these

`int cos (log_e x)dx` is equal toA. `(1)/(2)xx[cos(log_ex)+sin(log_ex)]`B. `(x)[cos(log_e x)+sin(log_ex)]`C. `(1)/(2)x[cos(log_e x)-sin(log_e x)]`D. `x[cos (log_ex)-sin(log_ex)]`

If `A xx(BxxC)=Bxx(CxxA)` and [ABC] = 0, then `A xx(BxxC)` is equal to

Compare Ea (activation energy) for a, b, c and d.(1) Eb > Ec > Ed > Ea (2) Ea > Ed > Ec > Eb (3) Ec > Eb > Ea > Ed (4) Ed > Ea > Eb > Ec