This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Name the high speed, time bound, express service for delivery of letters and documents offered by Department of Posts. |
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Answer» The service is name as Speed Posts. |
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| 2. |
Every envelope to be dispatched is ______ to calculate the correct amount of ______ to be affixed on it |
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Answer» Every envelope to be dispatched is Weighed, to calculate the correct amount of postage/stamp to be affixed on it. |
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| 3. |
Describe any two indexing techniques which are used for locating records efficiently. |
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Answer» (a) Card Index: It consists of a number of cards of a standard size, each concerned with one item of index. The heading is written on the top edge of the card and the remaining space is used to indicating the place where the corresponding record is kept. This lower portion of the card also carries certain essential information. (b) Loose Leaf Index: In this type of index, the pages on which the index is prepared are not bound. Here the pages are fitted on to a metal hinges and screwed. Thus, wherever required some pages can be taken out and/or additional pages can be inserted. (c) Bound Book Index: In this form of index, a bound book or a register is divided into various sections. Each section is allotted an alphabet. Names of the parties and the persons starting from a particular alphabet are written in the concerned section. At the outer margin of the page letter groups are shown by cut outs so that the initial letters of all the sections are visible at a glance. All entries relating to a particular letter of the alphabet are arranged in the same section or pages reserved for the same letter of the alphabet in a strict alphabetical order. |
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| 4. |
The electron energy in hydrogen atom is given by `E_(n)=(-2.18xx10^(-8))//n^(2)J`. Calculate the energy required to remove an electron completely from the `n=2` orbit. What is the longest wavelength of light in cm that can be used to cause this transition? |
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Answer» The energy in the second Bohr orbit `E_(2)=(21.7xx10^(-19))/((2)^(2))J=-5.44xx10^(-19)J` For the removal of electron has to be moved to an infinite distance for which `n=oo` and `E_(oo)=(-2.177xx10^(-18)J)/((oo)^(2))=0` `DeltaE=E_(oo)-E_(2)=0-(-5.44xx10^(-19)J)` `=5.44xx10^(-19)J` =Energy needed to remove the electron from second Bohr orbit of `H` atom Energy of photon, `E=hv`=Ionisation energy `:.DeltaE=hv=(hc)/lambda=5.44xx10^(-19)J` and `lambda=(hc)/(DeltaE)=(6.6xx10^(-34)J sxx3xx10^(8) m s^(-1))/(5.44xx10^(-19)J)` `=3.64xx10^(-7) m=364xx10^(-9) m=3640 Å` |
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| 5. |
Mention any two advantages of using E Mail. |
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| 6. |
Write any three advantages of using Mail Room Equipment and Machines. |
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Answer» (a) Increase in the speed of operations: Hand Operated Sealing Machines can seal about 100 envelopes a minute while electrically operated ones can operate at a speed of 15000 envelopes in an hour. (b) Simplification of fixing of postage and avoidance of misuse of postage stamps: With Postal Franking Machine, there is less risk of misappropriation of postal stamps, avoidance of errors in stamping and simplification in keeping the account of stamps used. (c) Improvement in efficiency and accuracy: A Letter Opening Machine operates manually or electrically at a great speed and can open 100 to 500 letters per minute and work of opening of mail can be efficiently managed. (d) Saving of time: An Automatic Numbering & Dating Machine is used for stamping on the incoming mail. In this machine, the next serial numbers and date automatically changes after every use with the help of self-inking stamp pad thus saving a lot of time. |
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| 7. |
How do leaves of plants help in excretion? |
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Answer» Many plants store waste materials in the vacuoles of mesophyll cells and epidermal cells. When old leaves fall, the waste materials are excreted along with the leaves. |
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| 8. |
The last member of the family of inert gases is(a) argon (b) radon (c) xenon (d) neon |
| Answer» (b) Radon is the last member of family | |
| 9. |
We’d better _____ to the manager. A) to talk B) talking C) talked D) talk |
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Answer» Correct option is D) talk |
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| 10. |
We began _____ about next year’s holiday two months ago. A) talked B) talking C) talks D) talk |
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Answer» Correct option is B) talking |
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| 11. |
The drunk was _____ against a lamp-post _____ to himself. A) leaning / talking B) leaning / talked C) leaned / talking D) leaned / talked |
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Answer» Correct option is A) leaning / talking |
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| 12. |
Janet is fortunate _____ a scholarship. A) to have been given B) being given C) having been given D) be given |
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Answer» Correct option is A) to have been given |
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| 13. |
I didn’t expect _____ by him to his marriage ceremony. A) be invited B) being invited C) to be invited D) would be invited |
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Answer» Correct option is C) to be invited |
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| 14. |
Amit, after giving a 12% discount on the marked price, sells an article for Rs. 369.60. If he had not given any discount he would have gained 20%. Find the cost price of the item.1. Rs. 3202. Rs. 4003. Rs. 3804. Rs. 350 |
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Answer» Correct Answer - Option 4 : Rs. 350 Given: After giving 12% discount on the marked price, the selling price of the article is 369.60 Concept Used: Marked Price (MP) / Cost Price (CP) = (100 + profit %) / (100 - discount %) Calculation: Let, the marked price of the article is 100% He gave a discount of 12% ⇒ After discount selling price of the article (100 - 12) = 88% Accordingly, 88% → 369.60 ⇒ 1% → 369.60/88 ⇒ 100% → (369.6/88) × 100 = 420 Marked price of the article = Rs. 420 If he had not given any discount he would have gained 20% that means then discount % should be 0% MP / CP = (100 + 20) / (100 - 0) ⇒ MP / CP = 120 / 100 ⇒ 420 / CP = 6 / 5 ⇒ CP = 350 ∴ The cost price of the item is Rs. 350. |
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| 15. |
A man sells his goods at 12% profit. If he buys it for Rs. 800 less and sells it for Rs. 600 less, he would gain 8% more. Find the initial cost price of the goods?1. Rs. 45002. Rs. 42003. Rs. 48004. Rs. 4000 |
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Answer» Correct Answer - Option 1 : Rs. 4500 Given: Initial profit % = 12% Original CP - New CP = Rs. 800 Original SP - New SP = Rs. 600 New Profit % = 12% + 8% = 20% Formula used: Profit % = [(SP - CP)/CP] × 100 Calculation: The initial profit % = 12% = 12/100 = 3/25 Here, 3 is the profit and 20 is CP. Let, CP = 25x Profit = 3x ∴ SP = 25x + 3x = 28x New CP = 25x - 800 ------(1) New SP = 28x - 600 ------(2) ∵ New Profit % = [(New SP - New CP)/New CP] × 100 ⇒ 20 =[(28x - 600 - 25x + 800)/20x - 800] × 100 ⇒ 20/100 = (3x + 200)/(25x - 800) ⇒ 1/5 = (3x + 200)/(25x - 800) ⇒ 25x - 800 = 15x + 1000 ⇒ 10x = 1800 ⇒ x = 180 ∴ Original CP = 25x = 25 × 180 = Rs. 4500 |
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| 16. |
On selling a bike for Rs. 2500 a seller incurs a loss of 20%. What price would have caused him to lose 30%?1. Rs. 2186.52. Rs. 2187.53. Rs. 2185.54. Rs. 2188.5 |
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Answer» Correct Answer - Option 2 : Rs. 2187.5 Given: SP of the bike = Rs. 2500 Loss% = 20% Formula: Loss = CP – SP Loss % = (Loss/CP) × 100 Calculation: CP of the bike = 2500 × (100/80) = Rs. 3125 ∴ New SP of the bike = 3125 × (70/100) = Rs. 2187.5 |
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| 17. |
A merchant has 120 kg of rice. He sells a part of it at a profit of 10% and the rest at a profit of 25%. He gains 15% on the whole. The quantity of rice sold at a profit of 25% is1. 50 kg2. 55 kg3. 40 kg4. 30 kg |
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Answer» Correct Answer - Option 3 : 40 kg The total amount of rice = 120 kg He sells a part of it at a profit of 10 %, let this part is ‘x’ kg. He sells the rest at a profit of 25%, i.e. he sells (120 – x) at 25% He gains a profit of 15% on the whole. Let the cost price is = y ⇒ 1.1 xy + 1.25 (120 – x)y = 1.15 × 120 y ⇒ 1.1 x + 1.25 (120 – x) = 1.15 × 120 ⇒ 1.1x + 150 – 1.25 x = 138 ⇒ 0.15 x = 12 ⇒ x = 80 kg The quantity of rice sold at a profit at 25% = 120 – x = 40 kg |
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| 18. |
I ________ you to drive carefully today. The roads are icy. A) propose B) recommend C) refer D) regard E) suggest |
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Answer» Correct option is B) recommend |
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| 19. |
By selling a sofa set for Rs. 25,800 and a table for Rs. 5,000, a shopkeeper gains 10% on the whole transaction. However, if he sells the sofa set for Rs. 22,500 and the table for its original cost, he loses 5%. What is the original cost of the table?1. Rs. 3,5002. Rs. 3,8343. Rs. 4,7504. Rs. 4,100 |
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Answer» Correct Answer - Option 4 : Rs. 4,100 Given: SP of sofa set for 1st transaction = Rs. 25,800 SP of table for 1st transaction = Rs. 5,000 Gain in 1st transaction = 10% SP of sofa set in 2nd transaction = Rs. 22,500 SP of table for 2nd transaction = CP Loss in 2nd transaction = 5% Formula used: Profit = SP – CP Loss = CP – SP Profit % = (SP – CP)/CP × 100 Loss % = (CP – SP)/CP × 100 Calculation: Total SP in 1st transaction = SP of sofa set + SP of table ⇒ Total SP in 1st transaction = 25800 + 5000 ⇒ Total SP in 1st transaction = 30800 Profit % = (SP – CP)/CP × 100 ⇒ 10 = (30800 – CP)/CP × 100 ⇒ CP = (30800 – CP)10 ⇒ CP = 308000 – 10CP ⇒ 11CP = 308000 ⇒ CP = 28000 Total CP = Rs. 28,000 Loss = 5% of 28000 ⇒ Loss = 5/100 × 28000 = 1400 As, table is sold at cost price in 2nd transaction CP of sofa set = 22500 + 1400 = 23900 CP of table = Total CP – CP of sofa set ⇒ CP of table = 28000 – 23900 ⇒ CP of table = 4100 ∴ Cost price of table is Rs. 4100 |
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| 20. |
Find the words which are out of the logic list:A) table B) bookcase C) tram D) sofa E) furniture |
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Answer» Correct option is C) tram |
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| 21. |
Explain costing of embroidered garments such as Bedsheet & pillow cover sets, cushion cover, table set, sofa cover etc. |
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Answer» Cost is the financial value acquired by the resources which are used to prepare a product. Costing is the method of estimating and then evaluating the total cost of producing a product or garment, together with the cost of raw materials, the ornamentation or embroidery done on it, labour charges, marketing and transportation, as well as the general expenses of operating the business. Merchandisers should have a thorough knowledge of costing. Since embroidery is mostly done for garments, the cost of the garment must be kept in mind, which depends on (i) Fabric (ii) Trimmings (iii) Garment design (iv) Surface Embellishments: printing, embroidery, appliqué, etc. (v) Cost of Transportation (vi) Production time (vii) Labor (viii) Estimated profit of the manufacturing organization All the costing depends upon parameters which are unique and fluctuate often. Finally, the finished products are labelled with its cost and are checked with buyer’s specifications. Key factors that directly affect embroidery costing, are (a) Quantity of embroidery work It is a key point, which affects embroidery costing to a great extent. Every embroiderer should accurately know the quantity of work to be done in an article, otherwise embroidery takes more cost. Before fixing the cost of embroidery, the quantity of embroidery should be evaluated. This includes considering where would the embroidery be placed on the fabric, how many times it will be repeated, is it a big-sized embroidery or a smaller one, etc. (b) Completion time Time plays an important role in fixing embroidery cost. Different types of embroidery take different time to complete, which directly affects embroidery costing. (c) Quality of raw materials Embroidery is produced by using various types of thread and other raw material. The cost of raw materials may not always be the same at all places. Also, bulk purchase of raw material is likely to be cheaper. That affects the cost of embroidery too. If we use expensive raw materials, embroidery cost increases and vice versa. For example, metallic and silk embroidery threads are costlier than cotton thread work. (d) Nature of embroidery It is another important point which should be kept in mind during the costing of embroidered fabric. Each embroidery type needs different amount of costing i.e. the cost of chain stitch embroidery is not the same as that of zardozi work. This is because the raw material used in zardozi includes the use of dabka, stones, thread as well as chain, compared to chain stitch. (e) Nature of workmanship Costing is greatly dependent on the workmanship. Intricate work needs heavily skilled craftsmanship, more time, and more efforts of the worker whereas a regular article can be produced by using lesser efforts in less time. (f) Customer’s specification Sometimes costing of any work depends on the customer’s requirements. Just as in the garment industry, the customer’s specifications are of importance, similarly in an embroidery unit too. |
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| 22. |
Where do you find a T.V., a sofa and a coffee table? |
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Answer» Correct answer is in the living room |
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| 23. |
Where do you find bicycles, the car and various odds and ends? |
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Answer» Correct answer is in the garage |
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| 24. |
Where do you find coat hangers and clean clothes? |
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Answer» Correct answer is in the closet |
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| 25. |
(a) Dispersion of light(b) Scattering of light(c) Total internal reflection of light(d) Reflection of light from the earth |
| Answer» (b) Scattering of light | |
| 26. |
I ________ photographs. A) enjoy taking B) enjoy to take C) amuse taking D) amuse to take |
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Answer» Correct option is A) enjoy taking |
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| 27. |
A vertical automobile radio antenna is sensitive to electric fields that are polarized: A. horizontally B. in circles around the antenna C. vertically D. normal to the antenna in the forward direction E. none of the above |
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Answer» C. vertically |
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| 28. |
Of the following human eyes are most sensitive to: A. red light B. violet light C. blue light D. green light E. none of these (they are equally sensitive to all colors) |
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Answer» D. green light |
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| 29. |
Select the correct statement: A. ultraviolet light has a longer wavelength than infrared B. blue light has a higher frequency than x rays C. radio waves have higher frequency than gamma rays D. gamma rays have higher frequency than infrared waves E. electrons are a type of electromagnetic wave |
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Answer» D. gamma rays have higher frequency than infrared waves |
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| 30. |
The learners will be able to differentiate between the small and capital letters in print.(a) CABBAGE(b) river |
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Answer» Correct answer is (b) river |
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| 31. |
Pick the wrong answer in the context with rainbow.(1) Rainbow is combined effect of dispersion, refraction and reflection of sunlight.(2) When the light rays undergo two internal reflections in a water drop, a secondary rainbow is formed. (3) The order of colours is reversed in the secondary rainbow.(4) An observer can see a rainbow when his front is towards the sun. |
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Answer» Correct option is (4) An observer can see a rainbow when his front is towards the sun. To see the rainbow the sun should be on his backside. |
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| 32. |
Write the following words in the small letters.UMRELLA \(\longrightarrow\)MOUNTAIN, PAPPER, VEGETABLES |
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Answer» umbrella = mountain, paper, vegetables |
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| 33. |
Statement-1: A hot air balloon is being carried away due north, flags on its bucket will fly due South. Statement-2: The flag on a moving vehicle points in direction of wind flow relative to the vehicle.A. Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.B. Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.C. Statement-1 is true, statement-2 is false.D. Statement -1 is false, statement -2 is true. |
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Answer» Correct Answer - D Flags in the bucket indirection of velocity of wind relative to balloon which is zero. Hence flags will not fly. |
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| 34. |
When the key `E` is pressed at time `t = 0`, which of the following statements about the current `I` in the resistor `AB` of the given circuit is true. A. `I = 2 mA` at all `t`B. `I` oscillates between `1 mA` and `2 mA`C. `I = 1 mA` at all `t`D. At `t = 0, I = 2 mA` and with time it goes to `1 mA` |
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Answer» Correct Answer - C (c ) At time `t = 0`, i.e.,when capactior is charging, current `I = (2)/(1000) = 1 mA` When capacitor is full charged, no current will pass through it, hence current through the circuit `I = (2)/(2000) = 1 mA` |
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| 35. |
In the figure shown, the capacity of the consider `C` is `2 nu F`. The current in `2 Omega` resistor is A. `9 A`B. `0.9 A`C. `(1)/(9) A`D. `(1)/(0.9) A` |
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Answer» Correct Answer - B (b) No current flows through the capacitor branch in steady state. Total current supplied by the battery `I = (6)/(2.8 + 1.2) = (3)/(2)` Current through `2 Omega` resistor `= (3)/(2) xx (3)/(5) = 0.9 A` |
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| 36. |
Arrange the following type of radiations in increasing order of frequency: a. Radiation from microwave oven b. Amber light from traffic signal c. Radiation from FM ragio d. Consmic rays from outer space and e. X-rays |
| Answer» Cosmic rays `lt "X-rays" lt "amber colour" lt "Microwave" lt "FM"` | |
| 37. |
Two point white dots are 1mm apart on a black paper. They are viewed by eye of pupil diameter 3mm. Approximately, what is the maximum distance at which these dits can be resolved by the eye? [Take wavelelngth of light =500nm]A. `5 m`B. `1 m`C. `6 m`D. `3 m` |
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Answer» Correct Answer - A (a) We know `(y)/(D) ge 1.22 (lambda)/(d)` `implies D le (y D)/(1.22 lambda) = (10^(-3) xx 3 xx 10^(-3))/(1.22 xx 5 xx 10^(-7))` `= (30)/(6.1) = 5 m :. D_(max) = 5 m` |
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| 38. |
The equation of current in a purely inductive circuit is 5sin (49 πt - 30°) . If the inductance is 30 mH then the equation for the voltage across the inductor, will be : {let π = 22/7}(A) 1.47 sin(49 πt - 30°) (B) 1.47 sin(49 πt + 60°) (C) 23.1sin(49 πt - 30°) (D) 23.1sin(49 πt + 60°) |
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Answer» (D) 23.1sin(49 πt + 60°) V0 = i0 XL = i0 (WL) = (5) (49π) (30 x 10) = 23.1 Voltage will lead current by 90°. ∴ V = 23.1 sin (49 πt + 60°) |
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| 39. |
If the cell of emf 5 volt shown in the figure gives a power of 10W. Q, find the powers consumed by the resistors `2 Omega` and `1 Omega` A. `2W, 18W`B. `8W, 49W`C. `8W, 18W`D. `2W, 49W` |
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Answer» Since the cell gives out a power of `10W` , a current `2A` must flow through the cell towards left. `:.` Power consumed in `2Omega` resistor `=2^(2)xx2=8W` Total current flowing `1Omega=7Amp` . `:.` Power consumed by `1Omega=7^(2)xx1=49W` |
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| 40. |
Several electric bulbs designed to be used on a 220V electric supply line, are rated 10W. How many lamps can be connected in parallel with each other across the two wires of 220V line, if the maximum allowable current is 5A ? |
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Answer» Given: V = 220 V Power of each bulb, P = 10 W Current, I = 5 A Let the number of bulbs = n. We have, R = \(\frac{V^2}{P}\) = \(\frac{220 \times \ 220}{10}\) = 4840 Ω ∴ Resistance of 1 bulb = 4840Ω For a flow of 5A current, we need to find the equivalent resistance of the circuit. ∴ Req =\(\frac{V}{l}\) = \(\frac{220}{5}\) = 44Ω In parallel combination, \(\frac{1}{R_{eq}}\) = \(\frac{1}{R}\) + \(\frac{1}{R}\) + \(\frac{1}{R}\) +............... (n times) Or, \(\frac{1}{R_{eq}}\) = n x \(\frac{1}{R}\) ∴ n = \(\frac{R}{R_{eq}}\) = \(\frac{4840}{44}\) = 110 ∴ 110 lamps have to be connected in parallel. |
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| 41. |
Which of the following are true with regard to positron emission tomography (PET)? a. It detects single gamma rays produced following the collision of a positron with a negative beta particle b. The radio nuclides used in PET are normally produced in a cyclotron c. It results in lower noise levels than conventional gamma imaging d. It provides detailed anatomical information e. Scintillation detectors are usually made of NaI |
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Answer» a. False. Following the collision of a positron with an electron, two gamma photons (511 keV) are produced, which travel in opposite directions. The simultaneous detection of these photons along the line of response will lead to the registration of the event. b. True. The tracer used most commonly is glucose labelled with Fl-18 (18-FDG), which has a very short half-life. Generators can also be used to produce radio cnuclides, for example the Ge-68/Ga-68 generator. c. True. d. False. PET images provide functional and physiological information and are therefore often fused with computed tomography (CT) or magnetic resonance imaging (MRI) to provide anatomical information. e. False. Scintillation detectors are most commonly made up of bismuth germanate or lutetium yttrium ortho silicate (LYSO), which have a high detection efficiency and are able to absorb and convert photons with 511 keV into light. |
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| 42. |
Concerning resolution within the image: a. Spatial resolution is the ability to distinguish adjacent objects as being separate b. Spatial resolution may be measured in line pairs mm-1 c. The spatial resolution of X-ray films is less than that of an image intensifier d. The spatial resolution of X-ray films is greater than that of computed tomography e. Spatial resolution may be determined by the properties of the radiographic film |
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Answer» a. True. b. True. c. False. It is much greater (e.g. 2–4 line pairs mm-1 for fluoros copy compared with more than 10 line pairs mm-1 with X-ray films). d. True. e. True. |
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| 43. |
Concerning linear tomography: a. The thickness of the plane in focus may be in the order of several mm b. The level of the imaged plane within the patient is altered by raising or lowering the pivot position c. Blurring increases with decreasing distance from the focal plane d. The tomographic angle is usually in the order of 40 e. Contrast is improved by imaging thin slices |
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Answer» a. True. b. True. c. False. It is those structures closest to the focal plane that are most sharply imaged. d. True. e. False. Contrast is reduced. |
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| 44. |
A small metal ball of diameter `4 mm` and density `10.5 g//cm^(3)` in dropped in glycerine of density `1.5 g//cm^(3)`. The ball attains a terminal velocity of `8cm s^(-1)`. The coefficient of viscosity of glycerine isA. 4.9 poiseB. 9.8 poiseC. 98 posieD. 980 posie |
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Answer» Correct Answer - 2 `V_(T)= (2)/(9)(r^(2)g)/(eta) (rho_(s) - rho_(L))` `rArr eta =(2r^(2)g)/(9v)(rho_(s)- rho_(L))` `=(2 xx0.2xx0.2xx9xx980)/(9xx8)` `=9.8 ` poise. |
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| 45. |
Which of the following could be the value of resistivity of copper? (A) 1.7 x 10-8 ohm-cm (B) 1.7 x 10-6 ohm-cm (C) 1.6 x 10-5 ohm-cm (D) 1.7 x 10-4 ohm-cm |
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Answer» (B). 1.7 x 10-6 ohm-cm |
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| 46. |
Two vectors A=3i+4j and B=3j+4k are acting simultaneously at a point find resultanat vector what is magnitude of the resultant |
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Answer» Resultant vector A +B = 3i+7j+4k Magnitude of the resultant |A+B|= (3^2+7^2+4^2)^1/2=74^(1/2) |
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| 47. |
Two resistances R1 and R2 give combined resistance of 4.5 ohms when in series and 1 ohm when in parallel. The resistances are (A)3 ohms and 6 ohms (B)3 ohms and 9 ohms (C)1.5 ohms and 3 ohms (D)1.5 ohms and 0.5 ohms. |
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Answer» (C)1.5 ohms and 3 ohms |
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| 48. |
These fibres have high strength, resistant to chemicals and can withstand high temperature without degradation. For example, they are used for bullet proof vests. a. Natural fibres b. Man made fibre c. High performance fibres d. Blended fibres |
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Answer» c. High performance fibres High performance fibres have high strength, resistant to chemicals and can withstand high temperature without degradation. For example, they are used for bullet proof vests. |
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| 49. |
P4O6 reacts with cold water to give …… (a) H3PO3(b) H4P2O7(c) HPO3(d) H3PO4 |
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Answer» P4O6 reacts with cold water to give H3PO3 |
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| 50. |
P4O6 reacts with cold water to give |
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Answer» P4O6 reacts with cold water to give H3PO3. |
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