

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
1. |
Why are heaters fitted near the floor and air conditioners near the ceiling of a room? |
Answer» 1. Due to air conditioners, air becomes cool so its density increases and it becomes heavy. So it goes down and warm air with less density comes up and take the place of cold air. This cycle goes on and on and the whole room becomes cool. 2. If it is fitted near the floor then cool air of high density can’t go up and upper air with low density cannot come down and cooling of the room does not take place properly so air conditioners are fitted near the ceiling of a room. 3. Heaters are fitted near the floor. Due to heating, air becomes hot which is lighter than cold air. So it goes up and upper air with high density comes down. 4. This cycle goes on and on and the full room becomes warm. So heaters are fitted near the floor. |
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2. |
Why are the Upper layers of water in a pond or a lake hotter than the lower layers during the hot summer? |
Answer» 1. The heat from the sun is reached to the Upper layers of the lakes first. 2. We know that heat transfers in convectional mode in water. . 3. Convectional currents take more time to reach the lower layers as there are in deep. 4. This means it takes more time to transfer of heat to the bottom of the lake or pond. 5. The water of the surface layer is evaporated by absorbing heat and does not heat up quickly. 6. As a result heat does not reach the lower layers of the lake. It is another reason. |
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3. |
In the arrangements A and B shown in Figure 4.7, pins P and Q are fixed to a metal loop and an iron rod with the help of wax. In which case are both the pins likely to fall at different times? Explain. |
Answer» In case ‘B’ the pin P will fall before the pin Q because the heat will reach pin P first. In case ‘A’, the heat travels in both the directions and pins P and Q will fall simultaneously. |
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4. |
The heat energy required to raise the temperature of 20 kg of water from 25° C to 75° C. A) 103 cal B) 104 cal C) 105 cal D) 106 cal |
Answer» Correct option is D) 106 cal |
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5. |
Collect specific heats of various substances. |
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6. |
Calculate the two specific heats of nitrogen from the following data : `gamma = c_(p)//c_(v) = 1.51` density of nitrogen at N.T.P `= 1.234 g litre ^(-1)` and `J = 4.2 xx 10^(7) erg cal^(-1)`. |
Answer» Correct Answer - `3.36 xx 10^(6) erg g^(-1).^(@)C^(-1)` |
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7. |
Calculate difference in specific heats for `1` gram of air at `N.T.P`. Given density of air at N.T.P. is `1.293 g litre^(-1), j=4.2xx10^(7)" erg "cal^(-1)`. |
Answer» Correct Answer - `0.068 cal g^(-1)K^(-1)` |
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8. |
A vessel contains ice and is in thermal equilibrium at `-10^(@)C` and is supplied heat energy at the rate of 20 cal `s^(-1)` for 450 seconds. If the mass of ice is 0.1 kg and due to supply of heat energy, the whole ice just melts find the water equivalent of the vessel. (Take specific heat of ice `=0.5 cal g^(-1)""^(@)C^(-1)` and specific heat of the vessel is `=0.1 cal g^(-1)""^(@)C^(-1)`. Latent heat of fussion = `80 cal g^(-1)` and assume that no heat is transferred to the surroundings) |
Answer» (i) The amount of heat absorbed by the ice at `-10^(@)C` to just melt = Q. `rArr" "Q_(1)=m_(i)S_(i)Delta t+m_(i)L_(F)" (1)"` The actual amount of heat energy supplied `=Q = Rxx t" (2)"` `Q=20xx450` cal Then find the amount of heat absorved by vessel `Q_(2)=Q-Q_(1)" (3)"` `Q_(2)=m_(V)S_(V)(Delta T)" (4)"` Find the value `m_(V)` from (4). Now water equivalent `=M=m_(V)S_(V)` (ii) 50 g |
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9. |
if specific heat capacity of mercury is 0.033 cal `g^(-1)" ".^(@)C^(-1)`, how much heat is gained by 0.05 kg of mercury when its temperature rises from `68^(@)F` to 313K? |
Answer» The initial temperature `=68^(@)F` `[(5)/(9)(68-32)].^(@)C=20C^(@)` Final temperature `=313K=(313-273).^(@)C=40^(@)C` Mass of mercury given `=0.05kg=50g` Specific heat capacity of mercury =0.033 cal `g^(-1).^(@)C^(-1) I.e., heat gained by 1 g of mercury for `1^(@)C` rise =0.033 cal hence, gained by 1 g of mercury for `1^(@)C` rise =0.033`xx50=1.65cal` `therefore` hear gained by 50 g mercury for `20^(@)C` rise =33 cal |
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10. |
Calculate the specific heat capacity at constant volume for a gas. Given specific heat capacity at constant pressure is `6.85 cal mol^(-1) K^(-1), R = 8.31 J mol^(-1)K^(-1)`. `J = 4.18 J cal^(-1)`. |
Answer» Correct Answer - `4.885 cal mol^(-1)K^(-1)` |
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11. |
The heat capacity of a vessel is 300 cal `.^(@)C^(-1)` and the heat capacity of water contained in the vessel is also 300 cal `.^(@)C^(-1)`. How much heat (in joules) is required to raise the temperature of water in the vessel by `126^(@)F`? |
Answer» A rise in temeprature of `9^(@)C` is equal to a rise in temperature of `5.^(@)C`. `therefore`A rise in temperature of 126 `.^(@)F` is on the celsius scale equivalent to `126xx(5)/(9)=14xx5=70.^(@)C` quantity of heat required to raise the temperature of the vessel by `1.^(@)C=300cal` ltBrgt `therefore` Heat requried to raise its temperature by ltBrgt `70.^(@)C=70xx300=21000` cal. similarly heat required to raise the temperature of water by `70.^(@)C=70xx300=21000cal` `therefore` the total heat required `=(21000+21000)cal=42000cal` `=4200xx4.2=176.4kJ` |
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12. |
Calcualte the resulting temperatures when 20 g of boiling water is poured into an ice-cold brass vesel (specific heat=0.1 cal/`g^(@)`C) of mass 100 g.A. `66.66^(@)`CB. `6.66^(@)`CC. `0.66^(@)`CD. `50^(@)`C |
Answer» Correct Answer - a | |
13. |
The specific heat capacity of water is ____ `cal//g^(@)C`A. 10B. 1C. 1.5D. 0.5 |
Answer» Correct Answer - B | |
14. |
What is the specific heat of a substance called? |
Answer» The specific heat of a substance is the amount of heat required to raise the temperature of the unit mass of the substance by one unit. S = \(\frac a{m\Delta T}\) |
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15. |
The specific heat of a substance at temperature at `t^(@)`c is `s=at^(2)+bt+c`. Calculate the amount of heat required to raise the temperature of m g of the substance from `0^(@)`C to `t_(0)^(@)`CA. `(mt_(0)^(3)a)/3 + (bt_(0)^(2))/2+ct_(0)`B. `(mt_(0)^(3)a)/3 + (mbt_(0)^(2))/2 + mct_(0)`C. `(mt_(0)^(3)a)/3 + (mbt_(0)^(2))/2`D. None of these |
Answer» `DeltaH = intmsdt` `=(m)int_(0)^(t_(0))(at^(2)+bt+c)dt = m[(at_(0)^(3))/3 +(bt_(0)^(2))/2 + ct_(0)]` |
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16. |
Which principle is used to measure the specific heat capacity of a substance? |
Answer» The principle of heat exchange is used to measure the specific heat capacity of a substance. This principle is as follows: If a system of two objects is isolated from the environment by keeping it inside a heat resistant box, then no energy can leave the box or enter the box. In this situation, heat energy lost by the hot object = heat energy gained by the cold object. |
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17. |
The substance with the lowest specific heat is A) lead B) mercuryC) kerosene oil D) water |
Answer» Correct option is A) lead |
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18. |
‘ Same amount of heat is supplied to two liquids A and B. The liquid B shows greater rise in temperature. What can you say about the specific heat of B as compared to A? A) Specific heat of B is less than that of A B) Specific heat of B is greater than that of A C) Can’t say D) Specific heat of B is same as that of A |
Answer» A) Specific heat of B is less than that of A |
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19. |
The advantage of alcohol is thermometric liquid is due to itsA. low boiling pointB. low freezing point.C. high vapour pressure.D. All the above |
Answer» Correct Answer - B Because of its low freezing point `(-130^(@)C)`, it cfan be used to record very low temperature. |
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20. |
Why do we use cooking utensils made up of copper. |
Answer» Cooking utensils are made of metals such as copper, aluminium, brass, steel etc., so that heat is easily conducted through the base to their contents. But they are provided with handles of bad conductors (such as ebonite or wood) to hold them easily as handles will not conduct heat from the utensil to our hand. |
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21. |
What happens to the water when wet clothes dry? |
Answer» When wet clothes dry, the water molecules from wet clothes, after evaporation, change into water vapour and mix with water molecules present in surrounding air, in the form of water vapour. |
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22. |
Which of the following properties are suitable for making cooking utensils?A. High specific heat and high conductivity.B. Low specific heat and low conductivityC. High specific heat and low conductivity.D. Low specific heat and high conductivity. |
Answer» Correct Answer - D Low specific heat and high conductivity ar thhe properties which are suitable for making utensils. |
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23. |
The lower and upper fixed points of a fauly thermomenter ar `-2^(@)C` and `102^(@)C`, respectively. If the thermometer reads `50^(@)C` on this thermometer, find the correct temperature onn the celsium scale. |
Answer» The relation to be used is `((S-LFP)/(UFP-LFP))_("correct scale")=((S-LFP)/(UFP-LFP))_("fautly scale")implies((S-0)/(100-0))=(50-(-2))/(102-(-2))` `(S)/(100)=(52)/(104)` `S=(52)/(104)xx100=50^(@)C` |
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24. |
Why is cooking fast in a pressure cooker compared to open vessel? |
Answer» 1. Boiling point of liquid increases with external pressure. 2. Pressure cooker gives external pressure to the water in it. 3. So, while cooking in pressure cooker it increases boiling point of water more than 100°C. 4. So that, cooking is fast in pressure cooker compared to open vessel. |
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25. |
Bose took 100 kg of paraffin oil and supplied `4180xx10^(3)`J of heat energy to it. Because of this, the temperature of the oil was found to increase from 300 K to x. With this data, Bose found the value of x. Find his answer. [Assume that there is no loss of energy to the surroundings and take the specific heat of water as `4.18 J g^(-1)""^(@)C^(-1)`( and water equivalent of 100 kg paraffin oil = 50 kg)]. |
Answer» `Delta theta =75^(@)C` `m=200 g` `s=1 cal g^(-1)^(@)C^(-1)` `therefore Q=msDelta theta =(200 g) (1 cal g^(-1)^(@)C^(-1))(75^(@)C)` `=15000 cal` The heat supplied = (Heat supply rate ). (time) The heat utilized = (thermal efficiency) (heat supplied) `rArr" "1500 cal =(80)/(100)xx250 cal s^(-1) xxts` `rArr" "t=75` seconds. |
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26. |
Calcualte the mass of stea that should be passed though 60 g of water at `20^(@)C`, such that the final temperature is `40^(@)C`. (take specific latent heat of steam is 2250 J `g^(-1)`). |
Answer» let mass of stea be m gm heat given out by stea to form water at `100^(@)C=3xx2250" J "g^(-1)` heat given out by water at `100^(@)C` `=ms_(u)Delta theta=mxx4.2xx(100-40)` `=242" m "J" "g^(-1)` Total heat given out `=2250m+252m` `=2502" m J "g^(-1)` Heat gained by water at `20^(@)C=60xx4.2xx(40-20)` `=5040J` `therefore`Heat lost by a body=Heat gained by a body ltBrgt `2502m=5040` ltBrgt `m=(5040)/(2502)=2g` |
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27. |
Give scientific reasons:Even though heat is supplied to boiling water, there is no increase in its temperature. |
Answer» Once water starts boiling, all the heat supplied to it is used in conversion of water into steam at the boiling point of water. Hence, there is no rise in its temperature. |
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28. |
Why are burns caused by steam at 100°C more painful than that of water at 100°C? |
Answer» 1. Water at 100°C takes additional heat energy to convert from liquid state to vapour (steam) state. This energy is called latent heat of vapourisation. 2. Hence, steam at 100°C contains more heat energy than that of water at 100°C. 3. So, burns caused by steam at 100°C are more painful than that of water at 100°C. |
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29. |
Give scientific reasons:Burns from steam are worse those from boiling water at the same temperature. |
Answer» 1. A given quantity of steam contains more heat than the same quantity of boiling water at the same temperature. 2. When steam comes in contact with one’s body, it releases extra heat of 540 calories per gram and causes a more serious burn than that caused by boiling water. |
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30. |
Why are gaps left between successive rails on a railway track ? |
Answer» The rails of railway track are made of steel. While laying the railway track, a small gap is left between the two successive length of rails. The reason is that the rails expand in summer. The gap is provided to allow for this expansion. If no gap is left, the expansion in summer will cause the rails to bend sideways. This may result in a train accidents. |
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31. |
What is the amount of heat 1 kg of ice from `-5^(@)C" to "5^(@)C` (Given, specific heat of ice `=2.095 Kj kg^(1)""^(@)C^(-1)`, specific heat of water `=4.2 J g^(-1)""^(@)C^(-1),` specifc latent heat of fusion of ice `=336 J g^(-1)`) |
Answer» (i) Find the total amount heat required convert 1 kg of ice at `0^(@)C` to water at `100^(@)C` `Q_(1)=m_(i)L_(F)+m_(i)S_(W)(DeltaT)=mL_(F)+mS_(W)(100)" (1)"` Find the amount of steam that gets condensed into water `100^(@)C` Consider the efficiency of the calorimeter as 90% `rArr" Then ",(90)/(100)(m_(S)L_(V))=Q_(1)" (2)"` Find the value of `m_(S)` from (2). Find the ratio of `(m_(s))/(m_(W))`. Heat last to the surroundings is `=(1)/(10)m_(s)L_(V).` (ii) `0.49,84 kJ` |
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32. |
Railway lines are laid with gaps to allow for expansion. If the gap betweeen steel rails 60 m long be 3.60 cm at `10^(@)C`, then at what temperature will the lines just touch? Coefficient of linear expansion of steel `=11xx10^(-6) .^(@)C^(-1)`. |
Answer» Correct Answer - `6 xx 10^(-3)m` |
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33. |
A steel tape is callibrated at `20^@ C`. On a cold day when the temperature is `-15^@ C`, what will be the percentage error in the tape ? |
Answer» Correct Answer - `-0.039%` |
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34. |
Specific heat of Cu is 0.095, iron 0.115, brass 0.092 and water 1. Which of the above can be heated quickly when they are kept in sunlight with same masses? A) Iron B) Brass C) Copper D) Water |
Answer» Correct option is B) Brass |
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35. |
A brass disc has a hole of diameter 2.5 cm at `27^(@)C`. Find the change in the diameter of the hole of the disc when heated to `327^(@)C`. Given coefficient of linear expansion of brass = ` 1.9 xx 10^(-5) .^(@)C^(-1)` |
Answer» Correct Answer - `0.10016m` |
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36. |
Woolen clothes keep us warm during winter because ____A. wool is a poor conductor of heatB. wool is a good conductor of heatC. air trapped in between the fibres prevents the heat flowD. both a and c |
Answer» Correct Answer - d Woolen clothes keep us warm during winter because wool is a poor conductor of heat and at the same time air trapped in between the fibres minimizes heat flow .here air acts as a thermal insulator |
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37. |
In the process of boiling,A. Kinietic and potential energy of water molecules increasesB. kinetic energy of molecules increases and potential energy of molecules decreases.C. potential energy of molecules increases and kinetic energy of molecules remains same.D. Kinetic energy of molecules increases and potential energy of molecules remains the same. |
Answer» Correct Answer - C | |
38. |
The change in temperature of a body is `20^(@)C`, then the change in temperature of Kelvin scale is :-A. 293 KB. 25 KC. 20 KD. 253 K |
Answer» Correct Answer - C | |
39. |
A: At high altitude regions the cooking of food becomes difficult B: Water boils at lower temperature when the presure is low.A. Both A and B are wrong.B. A and B are correct and B is not the correct explanation of A.C. A and B are correct and B is the correct explanation of A.D. A is correct but B is wrong. |
Answer» Correct Answer - C | |
40. |
When an air bubble rises from the bottom to the surface of a lake, its radius becomes double. Find the depth of the lake, given that the atmospheric pressure is equal to the pressure due to a column of water 10 m high. Assume constant temperature and disregard surface tension. (a) 30 m (b) 40 m (c) 70 m (d) 80 m |
Answer» Correct Answer is: (c) 70 m |
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41. |
A closed vessel is maintained at a constant temperature. It is first evacuated and then vapour is injected into it continuously. The pressure of the vapour in the vessel (a) increases continuously (b) first increases and then remains constant (c) first increases and then decreases (d) none of the above |
Answer» Correct Answer is: (b) first increases and then remains constant |
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42. |
A gas has volume V and pressure p. The total translational kinetic energy of all the molecules of the gas is(a) 3/2 pV only if the gas is monoatomic (b) 3/2 pV only if the gas is diatomic (c) > 3/2 pV if the gas is diatomic (d) 3/2 pV in all cases |
Answer» Correct Answer is: (d) 3/2 pV in all cases |
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43. |
The root-mean-square (rms) speed of oxygen molecules (O2) at a certain absolute temperature is v. If the temperature is doubled and the oxygen gas dissociates into atomic oxygen, the rms speed would be (a) v (b) √2v (c) 2v (d) 2√2v |
Answer» Correct Answer is: (c) 2v c = √(3RT/M) Here, T becomes double and M becomes half. |
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44. |
The average translational kinetic energy of O2 (molar mass 32) at a particular temperature is 0.048 eV. The average translational kinetic energy of N2 (molar mass 28) molecules in eV at the same temperature is (a) 0.0015 (b) 0.003 (c) 0.048 (d) 0.768 |
Answer» Correct Answer is: (c) 0.048 |
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45. |
Number of divisions in Celsius scale is A) 100 B) 212 C) 180 D) 32 |
Answer» The correct option is A) 100. |
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46. |
How can we use laboratory and clinical thermometers? |
Answer» Using of a laboratory thermometer: 1. Place the mercury bulb of the thermometer in a liquid, so that the bulb immerses in it. 2. Wait for some time till the mercury level shows a constant reading. 3. And take the reading at the level of the mercury. Using of a clinical thermometer: 1. Wash the clinical thermometer properly with an antiseptic solution. 2. To lower the mercury level, hold the thermometer firmly and give some jerks. 3. Ensure that it falls below 35 °C. 4. Now place the bulb of the thermometer under your friend’s tongue. 5. After one or two minutes, take the thermometer out and note the reading. 6. This is your body temperature. 7. Don’t hold the thermometer by the bulb while reading it. |
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47. |
What is latent heat of vapourisation? |
Answer» At constant temperature the heat energy required to change one gram of liquid into gaseous state. |
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48. |
A constant volume thermometer registers o pressure of `1.500 xx 10^4` Pa at the triple point of water and a pressure of `1.500 xx 10^4` Pa at the normal boiling point. What is the temperature at the normal boiling point? |
Answer» Correct Answer - `190.4K` |
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49. |
At what temperature (in `^(@)C`, the fahrenheit and celsius scale gives same reading?A. 40B. `-40`C. 8D. `-8` |
Answer» Correct Answer - b | |
50. |
The temperature at which Centrigrade thermometer and Kelvin thermometer gives the same reading, isA. `4^(@)`B. `273^(@)`C. not possibleD. 0 |
Answer» Correct Answer - c) | |