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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 601. |
Which one of the following reactions does not form gaseous product ?A. `PbO_(2)+H_(2)O_(2)`B. Acidified `KMnO_(4)+H_(2)O_(2)`C. `PbS+H_(2)O_(2)`D. `Cl_(2)+H_(2)O_(2)`. |
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Answer» Correct Answer - C `PbS+4H_(2)O_(2)toPbSO_(4)+4H_(2)O` |
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| 602. |
All of the following substances react with wter. The pair that yeilds the same gaseous product isA. K and `KO_(2)`B. Ca and `CaH_(2)`C. `Na and Na_(2)D. Ba and `BaO_(2)` |
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Answer» (b) Ca and `CaH_(2)` yield the same product `Ca+2H_(2)O to Ca(OH)_(2)+H_(2)` `CaH_(2)+2H_(2)O to Ca(OH)_(2)+2H_(2)` |
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| 603. |
Which one of the following reactions does not form gaseous product ?A. `PbO_(2)+H_(2)O_(2)rarr`B. `PbS+H_(2)O_(2)rarr`C. `Cl_(2)+H_(2)Orarr`D. `Na_(2)CO_(3)+H_(2)Orarr` |
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Answer» Correct Answer - B `PbS+4H_(2)O_(2)rarrunderset(("solid"))(PbSO_(4))+underset(("Liquid"))(4H_(2)O)` |
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| 604. |
An aqueous solution of `H_(2)O_(2)`A. AlkalineB. NeutralC. Strongly acidicD. weekly acidic. |
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Answer» Correct Answer - D `H_(2)O_(2)rarr "Weakly acidic"` |
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| 605. |
Hydrogen peroxides cannot be concentrated easily becauseA. It is highly volatile in natureB. It is not dissolve in `H_(2)O`C. It decompose at its boiling pointD. It has a very high b.p. |
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Answer» Correct Answer - C Decomposes readily. |
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| 606. |
When zeolite, which is hydrated sodium aluminium silicate, is treated with hard water, the sodium ions are are exchanged withA. `H^(+)` ionB. `Ca^(2+)` ionsC. `SO_(4)^(2-)`D. `OH^(-)` |
| Answer» Correct Answer - B | |
| 607. |
The ionsisation of hydrogen atom givesA. hydride ionB. hydronium ionC. protonD. hydroxyl ion |
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Answer» Correct Answer - C `H(g) to H^(+)(g)+ bare` |
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| 608. |
Hydrogen peroxide in its reaction with `KIO_(4)` and `NH_(2)OH` respectively , is acting as aA. reducing agent , oxidising agentB. reducing agent , reducing agentC. oxidising agent, oxidising agentD. oxidising agent , reducing agent |
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Answer» Correct Answer - A `overset(+7)KIO_(4)+ underset("Reducing agent ")(H_(2)O_(2)) to overset(+5)(KIO_(3))+ H_(2)O + O_(2)` `overset(-1)NH_(2)OH + underset("Oxidising agent ")(3H_(2)O_(2))to overset(+5)(HNO_(3))+ 4H_(2)O` |
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| 609. |
Which of the following easily reacts with water producing hydrogen?A. `PH_(3)`B. `B_(2)H_(6)`C. `CH_(4)`D. `H_(2)S` |
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Answer» Correct Answer - B `B_(2)H_(6)+6H_(2)Orarr2B(OH)_(3)+6H_(2)uparrow` |
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| 610. |
The critical temperature of water is higher than that of `O_(2)` because the `H_(2)O` molecule hasA. fewer electrons than oxygenB. two covalent bondsC. V-shapeD. Dipole moment. |
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Answer» Correct Answer - D Critical temperature of water is more than `O_(2)` due to its dipole moment. (Dipole moment of water `=1*84 D` , Dipole moment of `O_(2)`=0D). |
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| 611. |
Deuteroammonia `(ND_(3))` can be prepared `:`A. be heating a solution of `NH_(4)Cl` in `NaOD`B. by action of heavy water on magnesium nitrideC. by fractionation of ordinary ammoniaD. None of these |
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Answer» Correct Answer - b `Ma_(3)N_(2)+6H_(2)O rarr 3 Mg (OD)_(2) + 2 ND_(3)` |
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| 612. |
How does hydrogen peroxide behave in the reaction with `KIO_(4)` |
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Answer» In this reaction, oxidation state of I decreases from +7 to +5. Therefore, it is gets reduced. This means `H_(2)O_(2)` acts as an oxidising agent `overset(+7)(KIO_(4))+H_(2)O_(2) to overset(+5)(KIO_(3))+H_(2)O+O_(2)` |
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| 613. |
Hydrogen can behave as a metalA. at very high temperatureB. at very low temperatureC. at very high pressureD. at very low pressure. |
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Answer» Correct Answer - C Hydrogen behaves as a metal at very high pressure. |
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| 614. |
The critical temperature of water is higher than that of `O_(2)` because the `H_(2)O` molecule hasA. fewer electrons than oxygenB. two covalent bondsC. `V-` shapeD. dipole moment |
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Answer» Correct Answer - D Dipole `-` dipole attraction gives rise to more tendency for aggregation. |
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| 615. |
Hydrogen can behave as a metalA. At very high temperatureB. At very low temperatureC. At very high pressureD. At very low pressure |
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Answer» Correct Answer - C Hydrogen behaves as a metal at very high pressure. |
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| 616. |
Hydrogen is evolved the action of cold dilute `HNO_(3)` on `:`A. FeB. MnC. CuD. Al. |
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Answer» Correct Answer - B `Mn+2HNO_(3)(Dil.)toMn(NO_(3))_(2)+H_(2)` |
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| 617. |
Which of the following pairs consists of moplecular having the same mass number?A. `H_(2)O ` and `D_(2)O`B. `H_(2)O` and `HTO`C. `D_(2)O` and `HTO`D. `DTO` and `HDO` |
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Answer» Correct Answer - c c |
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| 618. |
Which of the following can effectively remove all types of hardness of waterA. SoapB. Washing sodaC. Slaked limeD. None of these |
| Answer» Correct Answer - A | |
| 619. |
Pick out the correct statementA. By decreasing the temperature pure parahydrogen can be obtainedB. By increaseing the temperature pure orthohydrogen can be obtainedC. By decreasing the temperature pure orthohydrogen can be obtainedD. By increasing the temperature pure parahydrogen can be obtained. |
| Answer» Correct Answer - B | |
| 620. |
Pick the odd one outA. Sodium borohydride reacts very slowly with cold waterB. Sodium borohydride reacts very violently with cold water to produce `H_(2)`C. Solubility of sodium borohydride in water at `25^(@)C` is `10.5 g // mL`D. Melting point of sodium borohydride is `500^(@)C` |
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Answer» Correct Answer - b Reaction of `NaBH_(4)` with cold water is very slow. All other statements except `(b)` are correct. |
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| 621. |
Match the Column I with Column II and select the correct option fom the codes given below . codes.A. `{:(,A,B,C,D),(,4,3,2,1):}`B. `{:(,A,B,C,D),(,1,2,3,4):}`C. `{:(,A,B,C,D),(,1,3,2,4):}`D. `{:(,A,B,C,D),(,4,2,3,1):}` |
| Answer» Correct Answer - A | |
| 622. |
Consider the reactions (A) `H_(2)O_(2)+ 2HI to I_(2)+2H_(2)O` (B) `HOCl + H_(2)O to H_(3)O^(+)+ Cl^(-) + O_(2)` Which of the following statements is correct about `H_(2)O_(2)` with reference to these reactions ? Hydrogen perioxide is …......... .A. an oxidising agent in both (A) and (B)B. an oxidising agent in (A) and reducing agent in (B)C. a reducing agent in (A) and oxidising agent in (B)D. a reducing agent in both (A) and (B) |
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Answer» Correct Answer - B The rule of thumb for oxidising-reducing hebaviour of `H_(2)O_(2)` is :` H_(2)O_(2) ` acts as a reducing agent if `O_(2)` is evolved and `H_(2)O_(2)` acts as an oxidising agent if `O_(2)` is not evolved. Thus, in reaction (A), `H_(2)O_(2)` acts as an oxidising agent since `O_(2)` is not evolved but in reaction (B), it acts a reducing agent because `O_(2)` is evolved , i.e., option (b) is correct. |
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| 623. |
Statement-I: `ZrH_(2)` is a non-stoichiometric hydride Statement-II: The composition of `ZrH_(2)` is exact same as its chemical formula.A. If both Statement-1 `&` Statement-II are True `&` the Statement-II is not a correct explanation of the Statement I.B. If both Statement-I `&` Statement-II are True but Statement-II is not a correct explanantion of the Statement-I.C. If Statement-I is True but the Statement-II is False.D. If Statement-I is False but the Statement-II is True. |
| Answer» Correct Answer - C | |
| 624. |
Which of the following statements is incorrect ?A. `H_(2)O_(2)` can act as an oxidising agentB. `H_(2)O_(2)` can act as a reducing agentC. `H_(2)O_(2)` has acidic propertiesD. `H_(2)O_(2)` has basic properties |
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Answer» Correct Answer - D `H_(2)O_(2)` does not have basic properties. |
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| 625. |
The absorption of hydrogen by platinum is known as :A. HydrogenationB. reductionC. DehydrogenationD. Occlusion |
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Answer» Correct Answer - D Adsorption of hydrogen by metals is known as occlusion and this is known as occluded hydrogen. |
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| 626. |
Which of the following is the best scientific method to test the presence of water in liquid ?A. Smell the liquidsB. Add anhydrous copper sulphate and look for a colour changeC. Taste the liquidD. Litmus paper with the solution |
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Answer» Correct Answer - B Anhy. `CusO_(4)` is colorless, in presence of water it becomes blue. |
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| 627. |
Hydrogen can be produced by heatingA. Cu with `H_(2)SO_(4)`B. Sodium formateC. Sodium oxalateD. None of these. |
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Answer» Correct Answer - B `underset("Sod. formate")(2HCOONa(s))overset(Delta)toH_(2)(g)uarr+underset("Sod. Oxalate")underset(COONa(s))underset(|" ")overset(COONa(underline(s))` Presence of `CO_(3)^(2-) and SO_(4)^(2-)` ions in water reduced the tendency of dissolution of Pb in water as `Pb(OH)_(2)` |
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| 628. |
Calculate the volume strength of 13.6% solution of `H_(2)O_(2)` |
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Answer» Correct Answer - 44.8 According to problem 100 ml of `H_(2) O_(2) ` solution contains `13.6 g H_(2)O_(2) `therefore ` 1000 ml (1 lit) of `H_(2)O_(2)` solution contains 136g `H_(2)O_(2)` We know that `68g H_(2) O_(2)` given 22.4 lit of `O_(2)` at NTP `136g H_(2) O_(2)` given `(22.4)/(68)xx136` litre iof `O_(2)` `=44.8 liter of `O_(2)` lt brgt Thus 1 liter of the solution given 44.8 lit of O_(2) at NTP `therefore ` Volume strenght of the `13.6%` solution of `H_(2)O_(2)`=44.8. |
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| 629. |
The maximum possible number of hydrogen bonds a water molecule can form isA. 1B. 2C. 3D. 4 . |
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Answer» Correct Answer - D Water can from upto 4 hydrogen bonds with 4 other water molecules. Two of these H-bonds are formed by O and one each by two H-atoms. |
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| 630. |
Equivalent weight of `H_(2)O_(2)` isA. 17B. 34C. 68D. 18 |
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Answer» Correct Answer - A `E.W.` of `H_(2)O_(2)=17` `N=(30.36)/(17)=1.78N` Volume strength `=5.6 xx` Normality ltbr. `=5.6 xx 1.78 =0` litre |
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| 631. |
Which is false about `H_2O_2`?A. acts both as an oxidising and reducing agent.B. Two `-OH` bonds lie in the same plane.C. Pale blue liquid.D. Can be oxidised by `O_(3)` |
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Answer» Correct Answer - B Two `-OH` bonds in `H_(2)O_(2)` lie in different planes. |
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| 632. |
How many hydrogen-bonded water molecule(s) are associated in `CuSO_(4).5H_(2)O`? |
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Answer» Only one water molecule, which is outside the brackets (coordination sphere), is hydrogen-bonded. The other four molecules of water are coordinated. |
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| 633. |
Assertion : `CuSO_(4).5H_(2)O` has one hydrogen-bonded molecule of water. Reason : The four molecules of water are coordinated in `CuSO_(4).5H_(2)O`.A. If both assertion and reason are true and reason is the correct explanation of assertion.B. If both assertion and reason are true but reason is not the correct explanation of assertion.C. If assertion is true but reason is false.D. If both assertion and reason are false. |
| Answer» Correct Answer - A | |
| 634. |
which spin isomer would be 100% at OK? |
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Answer» PARA H2 ............. |
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| 635. |
Name the hydrogen ion which resembles anions of group 17. |
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Answer» (H- ) Hydride ion |
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| 636. |
how much energy is required to ionize the H-atom? |
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Answer» 1311.8 KJ/ mole Or 2.18X10-18J/atom |
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| 637. |
Name the compound formed on combination of CO & H2 |
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Answer» CH3OH ...... |
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| 638. |
How can the production of hydrogen from water gas be increased by using water shift reaction? |
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Answer» Water shift reaction is given as C(s) +H2O (g) --------------> CO(g)+H2(g) -121.3kj It is difficult to obtain pure hydrogen from water gas (CO+H2) since CO is difficult to remove. Therefore to increase the production of H2 form water gas CO is oxidized to CO2 by mixing it with more steam and passing over FeCrO4 catalyst at 673K. |
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| 639. |
How is hydrogen Difference from halogens? |
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Answer» Difference from halogens: (1) Less tendency for hydride formation:Hydrogen has less tendency to take upelectron to form hydride ion (H-) as compared to the halogens which from halide ions (X-) very easily. (2) Absence of unshared pairs of electrons (3) Nature of oxides: The oxides of halogens are acidic while hydrogen oxide isneutral. |
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| 640. |
Assertion : Hydrogen cannot be prepared in laboratory. Reason : Hydrogen of high purity is obtained by electrolysing warm aqueous barium hydroxide between Nickel electrods.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False. |
| Answer» Correct Answer - D | |
| 641. |
Define Hard Water. |
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Answer» Presence of calcium and magnesium salts in the form of hydrogen carbonate, chloride and sulphate in water makes water "hard‘. Hard water does not give lather with soap. Hard water forms scum/precipitate with soap. It is harmful for boilers as well, because of deposition of salts in the form of scale. This reduces the efficiency of the boiler. |
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| 642. |
Which pair of species can undergo chemical reaction with each other ?A. CO + NOB. LiH and `H_(2)O`C. `CO_(2)` and HClD. `CAH_(2)+SiH_(4)`. |
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Answer» Correct Answer - B `LiH+H_(2)toLi(OH)+H_(2)`. |
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| 643. |
Which of the following statements do not define the characteristic property of water `"Water is a universal solvent"` ?A. It can dissolve maximum number of compoundsB. It has very low dielectric constantC. It has high liquid rangeD. None of these. |
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Answer» Correct Answer - B Water has high dielectric constant i.e., 82, high liquid range and can dissolve maximum number of compounds. That is why it is used as a universal solvent. |
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| 644. |
Why does water show high boiling point as compared to hydrogen sulphide? Give reasons for your answer. |
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Answer» Due to extensive hydrogen bonding in H2O, it is an associated molecule and thus, its boiling point is much higher than H2S in which no hydrogen bonding exists. |
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| 645. |
Why is hydrogen peroxide stored in wax lined bottles? |
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Answer» Hydrogen peroxide cannot be stored in glass bottles since the rough surface of glass, alkali oxides present in it and exposure to light catalyse its decomposition. Therefore, Hydrogen H2O2 is stored in coloured wax coated plastic or Teflon bottles. |
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| 646. |
The reagent commonly used to determine hardness of water titrimetrically isA. oxalic acidB. disodium salt of EDTAC. sodium citrateD. sodium thiosulphate |
| Answer» Correct Answer - B | |
| 647. |
The reagent commonly used to determine hardness of water titrimetrically is `:`A. oxalic acidB. disodium salt of `EDTA`C. sodium citrateD. sodium thiosulphate |
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Answer» Correct Answer - b B |
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| 648. |
The reagent commonly used to determine hardness of water titrimetrically is `:`A. oxalic acidB. sodium thiosulphateC. disodium salt of EDTAD. sodium citrate. |
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Answer» Correct Answer - C Disodium salt EDTA is used to determine halogens of water titrimatrically. |
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| 649. |
Calculate the hardness of a water sample which contains 0.001 mole of `MgSO_(4)` dissolved perr litre of the solution. |
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Answer» 0.001 mole of `MgSO_(4)-=0.001 ` mole `CaCO_(3)=0.001xx1000 ` mg =100 mg 1L of `H_(2)O-=10^(3) g = 10^(6) ` mg `therefore ` Degree of hardness =100 ppm |
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| 650. |
The process \(\frac{1}{2}\)H2(g) + e– → H– (g) is endothermic (AH = +151 kJmol-1), yet salt like hydrides are known. How do you account for this? |
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Answer» It is true that formation of hydride(H–) ion is an endothermic process, yet alkali and alkaline earth metals from salt like hydrides. This is due to the reason that high lattice energy released (energy released during the formation of solid metal hydrides from their corresponding ions, i.e., M+ and H–) more than compensates the energy needed for the formation of H– ions from H2 gas. |
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